R11,R12,R14- Steroids in the treatment of asthma and copd 1

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/29

flashcard set

Earn XP

Description and Tags

mechanisms,steroid families ,glucacorticoids

30 Terms

1
New cards

Why are steroids important?

Respiratory Theme

• Biosynthesis

• Adrenocorticoids

• Pharmaceutical derivatives used in respiratory diseases

Endocrinology Theme

• Adrenal diseases

• Sex Hormones

Cardiovascular Theme

• Statins

Note - some molecules aren’t steroids by structure but work the same way

2
New cards

What is the key structure of a steroid?

  • 6,6,6,5 Ring

  • A modified tail which differs across different types of steroids


3
New cards

What are the ways to discuss the steroid structures?

1. Lettered: A, B, C, D

  • A is a six membered the ring bearing the oxygen

  1. Numbered

  • Starts from the A ring, at the top of the skeleton, works its way round, then goes to the side chains last

  • Side chains are at position 17; they can have alpha or beta positions= chiral

  • up solid - beta; away dashed- alpha


<p><strong>1. Lettered: A, B, C, D </strong></p><ul><li><p>A is a six membered the ring bearing the oxygen </p></li></ul><ol start="2"><li><p><strong>Numbered </strong></p></li></ol><ul><li><p>Starts from the A ring, at the top of the skeleton, works its way round, then goes to the side chains last </p></li><li><p>Side chains are at position 17; they can have alpha or beta positions= chiral </p></li><li><p>up solid - beta; away dashed- alpha </p></li></ul><p></p>
4
New cards

How does the arrangement of steroid rings affect their structure and function?

  • Steroids contain four fused rings (A, B, C and D): three 6-membered rings and one 5-membered ring.

  • The B/C and C/D ring junctions are trans in the typical steroid structure.

  • The A/B ring junction can be either cis or trans, affecting the overall 3D shape of the steroid.

Ring arrangement

Structure

Examples

Cis A/B

Rings are bent, giving a less flat structure

Bile acids

Trans A/B

Rings form a more extended, relatively flat structure

Many adrenocorticoids and sex hormones

Key point: The cis or trans arrangement changes the steroid's 3D shape, which influences how it interacts with receptors and its biological function.

<ul><li><p>Steroids contain four fused rings (A, B, C and D): three 6-membered rings and one 5-membered ring.</p></li><li><p>The <strong>B/C and C/D ring junctions are trans </strong>in the typical steroid structure.</p></li><li><p>The <strong>A/B ring junction can be either cis or trans</strong>, affecting the overall 3D shape of the steroid.</p></li></ul><table style="min-width: 75px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><th colspan="1" rowspan="1"><p>Ring arrangement</p></th><th colspan="1" rowspan="1"><p>Structure</p></th><th colspan="1" rowspan="1"><p>Examples</p></th></tr><tr><td colspan="1" rowspan="1"><p>Cis A/B</p></td><td colspan="1" rowspan="1"><p>Rings are bent, giving a less flat structure</p></td><td colspan="1" rowspan="1"><p>Bile acids</p></td></tr><tr><td colspan="1" rowspan="1"><p>Trans A/B</p></td><td colspan="1" rowspan="1"><p>Rings form a more extended, relatively flat structure</p></td><td colspan="1" rowspan="1"><p>Many adrenocorticoids and sex hormones</p></td></tr></tbody></table><p>Key point: The cis or trans arrangement changes the steroid's 3D shape, which influences how it interacts with receptors and its biological function.</p>
5
New cards

How are steroids made ?

Multi-step biosynthesis ( the mevalonate pathway) - makes multiple products along the way, more than one way of making the molecules

• Starting material is acetyl coenzyme A

• Step one – synthesis of mevalonate

• Step two – synthesis of isopentenyl pyrophosphate

• Step three – synthesis of squalene

• Step four – cyclisation to lanosterol

• Step five – synthesis of cholesterol


This always goes up in multiples of 5 carbons




<p><strong>Multi-step biosynthesis ( the mevalonate pathway)</strong> - makes multiple products along the way, more than one way of making the molecules</p><p>• Starting material is <strong>acetyl coenzyme A</strong></p><p>• <strong>Step one</strong> – synthesis of mevalonate</p><p>• <strong>Step two </strong>– synthesis of isopentenyl pyrophosphate</p><p>•<strong> Step three </strong>– synthesis of squalene</p><p>• <strong>Step four</strong> – cyclisation to lanosterol</p><p>• <strong>Step five</strong> – synthesis of cholesterol</p><p></p><p>This always goes up in multiples of 5 carbons</p><p><br></p><p></p>
6
New cards

Describe the first step - synthesis of mevalonate from acetyl-CoA?

  • uses 3 molecules of acetyl-CoA

  • 2 part: claisen and aldol reaction which occur at the acetyl-CoA synthase

  • HMG-CoA reductase removes mevalonate from the enzyme


<ul><li><p>uses 3 molecules of acetyl-CoA</p></li><li><p>2 part: claisen and aldol reaction which occur at the acetyl-CoA synthase </p></li><li><p>HMG-CoA reductase removes mevalonate from the enzyme </p></li></ul><p></p>
7
New cards

Describe the Claisen ester condensation in steroid biosynthesis?

  1. Enol is formed - enzyme acts as a base and removes a hydrogen from the carbon (CH3) on one of the acetyl-CoA molecules; this makes an enol, which is electron-rich and can attack an electrophile


  1. Nucleophilic attack - the enol attacks teh electrophilic carbon (C=O) of a second acetyl-CoA molecule, making a bond between teh carbons ( tetrahedral intermediate )


  1. Elimination of CoA - the tetrahedral intermediate collapses, reforming the (C=O) bond. The CoA-containing group leaves as CoA-SH because it is a good leaving group. This produces acetoacetyl-CoA, a four-carbon β-keto thioester.


  1. Two acetyls are joined together


<ol><li><p><strong>Enol is formed</strong> - enzyme acts as a base and removes a hydrogen from the carbon (CH3) on one of the acetyl-CoA molecules; this makes an enol, which is electron-rich and can attack an electrophile </p></li></ol><p></p><ol start="2"><li><p><strong>Nucleophilic attack - the </strong>enol attacks teh electrophilic carbon (C=O) of a second acetyl-CoA molecule, making a bond between teh carbons ( tetrahedral intermediate ) </p></li></ol><p></p><ol start="3"><li><p><strong>Elimination of CoA - </strong>the tetrahedral intermediate collapses, reforming the (C=O) bond. The CoA-containing group leaves as CoA-SH because it is a good leaving group. This produces acetoacetyl-CoA, a four-carbon β-keto thioester.</p></li></ol><p></p><ol start="4"><li><p><strong>Two acetyls are joined together </strong></p></li></ol><p></p>
8
New cards

Describe the mechanism of the aldol reaction in steroid biosynthesis.

Step 1: Formation of the enol - The third acetyl-CoA molecule is converted into its enol/enolate form by an enzyme. This makes the α-carbon nucleophilic (electron-rich), allowing it to attack an electrophile.


Step 2: Nucleophilic attack (aldol addition)

  • The enol/enolate attacks the electrophilic carbonyl carbon (C=O) of acetoacetyl-CoA, formed in the previous Claisen condensation reaction.

  • A new carbon–carbon bond forms, joining the third acetyl-CoA to acetoacetyl-CoA.

  • The carbonyl oxygen is protonated (gains H⁺), forming an OH group.

  • This produces a six-carbon intermediate containing three acetyl units.


Step 3: Hydrolysis

  • One thioester bond is broken by hydrolysis (addition of water).

  • This releases CoA-SH and forms a carboxylic acid group (COOH).

  • The final product is HMG-CoA, which contains six carbon atoms



<p><strong>Step 1:</strong> Formation of the enol - The third acetyl-CoA molecule is converted into its enol/enolate form by an enzyme. This makes the α-carbon nucleophilic (electron-rich), allowing it to attack an electrophile.</p><p></p><p><strong>Step 2: Nucleophilic attack (aldol addition)</strong></p><ul><li><p>The enol/enolate attacks the electrophilic carbonyl carbon (C=O) of acetoacetyl-CoA, formed in the previous Claisen condensation reaction.</p></li><li><p>A new carbon–carbon bond forms, joining the third acetyl-CoA to acetoacetyl-CoA.</p></li><li><p>The carbonyl oxygen is protonated (gains H⁺), forming an OH group.</p></li><li><p>This produces a six-carbon intermediate containing three acetyl units.</p></li></ul><p></p><p><strong>Step 3: Hydrolysis</strong></p><ul><li><p>One thioester bond is broken by hydrolysis (addition of water).</p></li><li><p>This releases CoA-SH and forms a carboxylic acid group (COOH).</p></li><li><p>The final p<strong>roduct is HMG-CoA, </strong>which contains six carbon atoms</p></li></ul><p></p><p></p>
9
New cards

Describe the synthesis of isopentenyl pyrophosphate from mevalonate (step2)

1. First phosphorylation: Mevalonate reacts with ATP, which donates a phosphate group to the hydroxyl group at carbon 5, forming 5-phosphomevalonate. ATP is converted to ADP.


2. Second phosphorylation: Another ATP molecule donates a second phosphate group, forming 5-pyrophosphomevalonate (mevalonate-5-diphosphate). ATP is again converted to ADP.


3. Decarboxylation and elimination: The molecule undergoes ATP-dependent decarboxylation, releasing CO₂, followed by elimination of the hydroxyl group and formation of a C=C double bond. This produces isopentenyl pyrophosphate (IPP), a five-carbon molecule.


Note: this reaction requires two molecules of ATP to install two phophates produces ipp

<p><strong>1. First phosphorylation</strong>: Mevalonate reacts with ATP, which donates a phosphate group to the hydroxyl group at carbon 5, forming 5-phosphomevalonate. ATP is converted to ADP.</p><p></p><p><strong>2. Second phosphorylation:</strong> Another ATP molecule donates a second phosphate group, forming 5-pyrophosphomevalonate (mevalonate-5-diphosphate). ATP is again converted to ADP.</p><p></p><p><strong>3. Decarboxylation and elimination:</strong> The molecule undergoes ATP-dependent decarboxylation, releasing CO₂, followed by elimination of the hydroxyl group and formation of a C=C double bond. This produces isopentenyl pyrophosphate (IPP), a five-carbon molecule.</p><p></p><p>Note: this reaction requires two molecules of ATP to install two phophates produces ipp</p>
10
New cards
<p>Describe the synthesis of squalene via condensation (step 3) - to make monoterpenes geranyl phosphate </p>

Describe the synthesis of squalene via condensation (step 3) - to make monoterpenes geranyl phosphate

The formation of geranyl pyrophosphate (GPP) involves enzymatic isomerisation, formation of an allylic carbocation, electrophilic addition and elimination.

1. Enzymatic isomerisation: Isopentenyl pyrophosphate (IPP) is converted into dimethylallyl pyrophosphate (DMAPP) by rearranging the position of the C=C double bond. This reaction is reversible equilibrium favoured forwardly

2. Formation of an allylic carbocation: DMAPP loses its pyrophosphate group (PPi), which acts as a leaving group, producing a positively charged allylic carbocation.

3. Resonance stabilisation: The positive charge is delocalised across the allylic system through resonance, making the carbocation more stable.

4. Electrophilic addition: The allylic carbocation acts as an electrophile, while the C=C double bond of another IPP molecule acts as a nucleophile. The double bond attacks the carbocation, forming a new C–C bond and joining the two five-carbon units.

5. Elimination: A proton (H⁺) is removed from the intermediate, allowing a new C=C double bond to form, producing geranyl pyrophosphate (GPP).

<p>The <strong>formation of geranyl pyrophosphate (GPP) involves enzymatic isomerisation, formation of an allylic carbocation,</strong> electrophilic addition and elimination.</p><p><strong>1. Enzymatic isomerisation</strong>: Isopentenyl pyrophosphate (IPP) is converted into dimethylallyl pyrophosphate (DMAPP) by rearranging the position of the C=C double bond. This reaction is reversible equilibrium favoured forwardly </p><p><strong>2. Formation of an allylic carbocation:</strong> DMAPP loses its pyrophosphate group (PPi), which acts as a leaving group, producing a positively charged allylic carbocation.</p><p><strong>3. Resonance stabilisation: </strong>The positive charge is delocalised across the allylic system through resonance, making the carbocation more stable.</p><p><strong>4. Electrophilic addition: </strong>The allylic carbocation acts as an electrophile, while the C=C double bond of another IPP molecule acts as a nucleophile. The double bond attacks the carbocation, forming a new C–C bond and joining the two five-carbon units.</p><p><strong>5. Elimination:</strong> A proton (H⁺) is removed from the intermediate, allowing a new C=C double bond to form, producing geranyl pyrophosphate (GPP).</p>
11
New cards

Describe the synthesis of farnesyl phosphate - step 3

Part 1: Formation of farnesyl pyrophosphate (FPP)

1. Formation of an allylic carbocation: Geranyl pyrophosphate (GPP, C₁₀) loses its pyrophosphate group (PPi), which acts as a leaving group, forming an allylic carbocation.


2. Resonance stabilisation: The positive charge is delocalised through resonance, stabilising the allylic carbocation.


3. Electrophilic addition: The allylic carbocation acts as an electrophile, while the C=C double bond of isopentenyl pyrophosphate (IPP, C₅) acts as a nucleophile. The double bond attacks the carbocation, forming a new carbon–carbon bond and extending the carbon chain.


4. Elimination: A proton (H⁺) is removed, allowing a new C=C double bond to form, producing farnesyl pyrophosphate (FPP, C₁₅).

<p>Part 1: Formation of farnesyl pyrophosphate (FPP)</p><p><strong>1. Formation of an allylic carbocation:</strong> Geranyl pyrophosphate (GPP, C₁₀) loses its pyrophosphate group (PPi), which acts as a leaving group, forming an allylic carbocation.</p><p></p><p><strong>2. Resonance stabilisation:</strong> The positive charge is delocalised through resonance, stabilising the allylic carbocation.</p><p></p><p><strong>3. Electrophilic addition:</strong> The allylic carbocation acts as an electrophile, while the C=C double bond of isopentenyl pyrophosphate (IPP, C₅) acts as a nucleophile. The double bond attacks the carbocation, forming a new carbon–carbon bond and extending the carbon chain.</p><p></p><p><strong>4. Elimination:</strong> A proton (H⁺) is removed, allowing a new C=C double bond to form, producing farnesyl pyrophosphate (FPP, C₁₅).</p>
12
New cards

Daescribe the final synthesis step of squalene using farsenyl phosphate

Part 2: Formation of squalene

1. Condensation: Two molecules of farnesyl pyrophosphate (C₁₅) combine in a head-to-head condensation reaction catalysed by squalene synthase.

2. Reduction: NADPH provides reducing power, allowing the intermediate to be converted into squalene (C₃₀), with the release of pyrophosphate groups.

3. Final product: Squalene is a 30-carbon molecule that acts as a precursor for cholesterol and other steroids

<p>Part 2: Formation of squalene</p><p>1. Condensation: Two molecules of farnesyl pyrophosphate (C₁₅) combine in a head-to-head condensation reaction catalysed by squalene synthase.</p><p>2. Reduction: NADPH provides reducing power, allowing the intermediate to be converted into squalene (C₃₀), with the release of pyrophosphate groups.</p><p>3. Final product: Squalene is a 30-carbon molecule that acts as a precursor for cholesterol and other steroids</p>
13
New cards

Describe the cyclisation of squalene to lanosterol and cholesterol (step 4 and 5 )

The conversion of squalene into cholesterol involves epoxidation, cyclisation and further structural modifications.

1. Epoxidation: Squalene (C₃₀) is converted into 2,3-oxidosqualene by the enzyme squalene epoxidase, which introduces an epoxide (a three-membered ring containing oxygen).


2. Cyclisation: The enzyme oxidosqualene cyclase converts oxidosqualene into lanosterol by folding the molecule and forming four fused carbon rings, producing the characteristic steroid ring structure.


3. Formation of cholesterol: Lanosterol undergoes further modifications, including removal of three carbon atoms, rearrangement of double bonds and reduction reactions, to produce cholesterol (C₂₇).

<p>The conversion of squalene into cholesterol involves epoxidation, cyclisation and further structural modifications.</p><p><strong>1. Epoxidation: </strong>Squalene (C₃₀) is converted into 2,3-oxidosqualene by the enzyme squalene epoxidase, which introduces an epoxide (a three-membered ring containing oxygen).</p><p></p><p><strong>2. Cyclisation:</strong> The enzyme oxidosqualene cyclase converts oxidosqualene into lanosterol by folding the molecule and forming four fused carbon rings, producing the characteristic steroid ring structure.</p><p></p><p><strong>3. Formation of cholesterol:</strong> Lanosterol undergoes further modifications, including removal of three carbon atoms, rearrangement of double bonds and reduction reactions, to produce cholesterol (C₂₇).</p>
14
New cards

what is the steroid families that you can make using cholesterol?

knowt flashcard image
15
New cards

describe the synthesis of pregnenolone from choletsrol ( loss of a side chain)

• Stimulated by adrenocorticotropic hormone (ACTH)

•1st step – multi-hydroxylation by cytochrome P450 monooxygenase - introduces OH groups on the side chain (requires NADPH and O2)

•2nd step – cleavage of the bond between hydroxyl groups by desmolase

<p>• Stimulated by adrenocorticotropic hormone (ACTH)</p><p><strong>•1st step</strong> – multi-hydroxylation by cytochrome P450 monooxygenase - introduces OH groups on the side chain  (requires NADPH and O2)</p><p><strong>•2nd step</strong> – cleavage of the bond between hydroxyl groups by desmolase</p>
16
New cards

Describe the synthesis of progesterone from pregnenolone

•1st step – oxidation of the ring alcohol to a ketone

•2nd step – isomerisation of the double bond it moves form the B ring to the A ring ,common double bond in the 4,5-ring allows extended conjugation and different types of reactions

<p><strong>•1st step</strong> – oxidation of the ring alcohol to a ketone</p><p><strong>•2nd step</strong> – isomerisation of the double bond it moves form the B ring to the A ring ,common double bond in the 4,5-ring allows extended conjugation and different types of reactions </p>
17
New cards

How are corticoids synthesised ( adrenocorticoids)

  • In the adrenal cortex

  • The levels are determined by feedback

2 types:

Glucocorticoids

• Responsible for the synthesis of carbohydrates from proteins

• Involved in the deposition of glycogen in the liver

• Very important in inflammatory processes

  • useful drug targets


Mineralocorticoids

• Control the electrolyte balance (diuresis)

• Promote retention of sodium and chloride

• Promote loss of potassium

  • used less



<ul><li><p>In the adrenal cortex </p></li><li><p>The levels are determined by feedback </p></li></ul><p><strong>2 types: </strong></p><p><strong>Glucocorticoids </strong></p><p>• Responsible for the synthesis of carbohydrates from proteins</p><p>• Involved in the deposition of glycogen in the liver</p><p>• Very important in inflammatory processes</p><ul><li><p>useful drug targets </p></li></ul><p></p><p><strong>Mineralocorticoids</strong></p><p>• Control the electrolyte balance (diuresis)</p><p>• Promote retention of sodium and chloride</p><p>• Promote loss of potassium</p><ul><li><p>used less </p></li></ul><p></p><p></p>
18
New cards

Describe the synthesis of cortisol from progesterone

Step 1 – Hydroxylation at carbon 17 (C17):

  • Progesterone undergoes hydroxylation at the 17α-position.

  • An –OH group is added at the α-position (pointing away from us).

  • This forms 17α-hydroxyprogesterone.


Step 2 – Hydroxylation at carbon 21 (C21):

  • 17α-hydroxyprogesterone undergoes hydroxylation at carbon 21, on the side chain.

  • An –OH group is added to the side chain.

  • This forms 11-deoxycortisol.


Step 3 – Hydroxylation at carbon 11 (C11):

  • 11-deoxycortisol undergoes hydroxylation at the 11β-position.

  • An –OH group is added in the β-position (pointing towards us).

  • This produces cortisol.


- Enzymes involved: All three hydroxylation reactions are catalysed by cytochrome P450 enzymes, which require NADPH and oxygen (O₂).

<p><strong>Step 1 – Hydroxylation at carbon 17 (C17):</strong></p><ul><li><p>Progesterone undergoes hydroxylation at the 17α-position.</p></li><li><p>An –OH group is added at the α-position (pointing away from us).</p></li><li><p>This forms 17α-hydroxyprogesterone.</p></li></ul><p></p><p><strong> Step 2 – Hydroxylation at carbon 21 (C21):</strong></p><ul><li><p>17α-hydroxyprogesterone undergoes hydroxylation at carbon 21, on the side chain.</p></li><li><p>An –OH group is added to the side chain.</p></li><li><p>This forms 11-deoxycortisol.</p></li></ul><p></p><p><strong> Step 3 – Hydroxylation at carbon 11 (C11):</strong></p><ul><li><p>11-deoxycortisol undergoes hydroxylation at the 11β-position.</p></li><li><p>An –OH group is added in the β-position (pointing towards us).</p></li><li><p>This produces cortisol.</p></li></ul><p></p><p>- <strong>Enzymes involved:</strong> All three hydroxylation reactions are catalysed by cytochrome P450 enzymes, which require NADPH and oxygen (O₂).</p>
19
New cards

What are glucocorticoids uses in ?

Glucocorticoids have a role in

  • rheumatoid arthritis

  • skin diseases

  • respiratory diseases


Cortisol (hydrocortisone) has significant mineralocorticoid activity

Need to minimise mineralocorticoid activity to design effective drugs

20
New cards

what structural components are needed for a glucocorticoid?

  • C21 pregnane skeleton (2-carbon side chain)

  • 17 beta COCH2OH side chain

  • 11beta hydroxyl

  • keto at the 3 position (generally)

  • 4-5 double bond

  • 17-alpha hydroxyl (generally)


Generally - still important but some don’t have these characteristics

<ul><li><p>C21 pregnane skeleton (2-carbon side chain)</p></li><li><p>17 beta COCH2OH side chain</p></li><li><p>11beta  hydroxyl</p></li><li><p>keto at the 3 position (generally)</p></li><li><p>4-5 double bond</p></li><li><p>17-alpha hydroxyl (generally)</p></li></ul><p></p><p>Generally - still important but some don’t have these characteristics </p>
21
New cards

what is structural components are needed for a mineralocorticoid?

Mineralocorticoids

  • C21 pregnane skeleton

  • 17 BETA COCH2OH side chain

  • keto at position 3 (generally)

  • 4-5 double bond


<p>Mineralocorticoids</p><ul><li><p>C21 pregnane skeleton</p></li><li><p>17 BETA  COCH2OH side chain</p></li><li><p>keto at position 3 (generally)</p></li><li><p>4-5 double bond</p></li></ul><p></p>
22
New cards

Where do glucocorticoids work /bind at?

Nuclear receptor

  • N-terminus

  • Central DNA-binding domain

  • C-terminal ligand-binding domain


Ligand-binding domain

  • All steroid receptors have 11α-helices and 4β-strands

  • Glucocorticoids bind in an area formed from :

-α-helices 3, 4, 5, 6, 7

-β-strands 1 and 2

  • All key binding interactions are via H-bonding

note - changing any part of steroid ,changes binding cause nearly everything has a n interaction


<p>Nuclear receptor</p><ul><li><p>N-terminus</p></li><li><p>Central DNA-binding domain</p></li><li><p>C-terminal ligand-binding domain</p></li></ul><p></p><p><strong>Ligand-binding domain</strong></p><ul><li><p>All steroid receptors have 11α-helices and 4β-strands</p></li><li><p>Glucocorticoids bind in an area formed from :</p></li></ul><p>-α-helices 3, 4, 5, 6, 7</p><p>-β-strands 1 and 2</p><ul><li><p>All key binding interactions are via H-bonding</p></li></ul><p>note - changing any part of steroid ,changes binding cause nearly everything has a n interaction </p><p></p>
23
New cards

what is cortisol, and what is it used for?

  • Highly effective, particularly for skin diseases

  • But oral use shows mineralocorticoid systemic side effects

note - need to find a way to reduce mineralocorticoid activity


<ul><li><p>Highly effective, particularly for skin diseases</p></li><li><p>But oral use shows mineralocorticoid systemic side effects</p></li></ul><p>note - need to find a way to reduce mineralocorticoid activity </p><p></p>
24
New cards

`What changes are made to make synthetic corticosteroids - 1 ?

Introduction of a 1,2 double bond

  • Changes the shape of the A ring, making it flatter

  • Increases glucocorticoid

  • Decreases mineralocorticoid


<p>Introduction of a 1,2 double bond</p><ul><li><p>Changes the shape of the A ring, making it flatter </p></li><li><p>Increases glucocorticoid</p></li><li><p>Decreases mineralocorticoid</p></li></ul><p></p>
25
New cards

What changes are made to make synthetic corticosteroids - 2?

Introduction of a 9α-fluoro substituent

  • increases lipophilicity,stays longer in lung tissue

  • increases glucocorticoid (10x)

  • also increases mineralocorticoid (300 - 600x)

  • Chloro also works

  • Also reduces metabolism, so increases duration of action


<p>Introduction of a 9α-fluoro substituent</p><ul><li><p>increases lipophilicity,stays longer in lung tissue </p></li></ul><ul><li><p>increases glucocorticoid (10x)</p></li><li><p>also increases mineralocorticoid (300 - 600x)</p></li><li><p>Chloro also works</p></li><li><p>Also reduces metabolism, so increases duration of action</p></li></ul><p></p>
26
New cards

What changes are made to make synthetic corticosteroids - 3 ?

Introduction of a 9α-fluoro substituent and a position 16 substituent:

  • Substituent can be a or b

  • Substituent can be Methyl or hydroxyl - chnages ability to bond

  •  increased glucocorticoid (overall)

  •  decreased mineralocorticoid

  • Believed to reduce ability to bind at mineralocorticoid receptor

Introduced in 1958



<p>Introduction of a 9α-fluoro substituent and a position 16 substituent:</p><ul><li><p>Substituent can be a  or b </p></li><li><p>Substituent can be Methyl or hydroxyl - chnages ability to bond </p></li><li><p> increased  glucocorticoid (overall)</p></li><li><p> decreased mineralocorticoid</p></li><li><p>Believed to reduce ability to bind at mineralocorticoid receptor</p></li></ul><p>Introduced in 1958</p><p></p><p></p>
27
New cards

What can you do to improve pharmacokinetics?

Formulation as esters

  • For inhalation and topical use

  • Generally the dipropionate

  • Increases lipophilicity , reduces activity ( once in the body and cleaved it is highly effective )

  • Easily cleaved in situ


<p>Formulation as esters</p><ul><li><p>For inhalation and topical use</p></li><li><p>Generally the dipropionate</p></li><li><p>Increases lipophilicity , reduces activity ( once in the body and cleaved it is highly effective )</p></li><li><p>Easily cleaved in situ</p></li></ul><p></p>
28
New cards

What does introducing a substituent at position 16 affect?

Introduction of a substituent at position 16

  • Possible to combine the changes to the A ring and a substituent at the 16 position

  • No halogen

  • Formulated as an acetal to enhance lipophilicity

Active drug, not a prodrug – 21-OH free

<p>Introduction of a substituent at position 16</p><ul><li><p>Possible to combine the changes to the A ring and a substituent at the 16 position</p></li><li><p>No halogen</p></li><li><p>Formulated as an acetal to enhance lipophilicity</p></li></ul><p>Active drug, not a prodrug – 21-OH free</p>
29
New cards

What does modifying the side chain affect?

Modification of side chain

  • In combination with the 3 other changes

  • Major synthetic change to side chain - Strong electrostatic interaction with Asn 564

  • Additional incorporation of fluorine at 6α - increases glucocorticoid binding only ,6α methyl also works here but less good

Examples of ante-drugs (stable in lung but not in. circulation)

<p>Modification of side chain</p><ul><li><p>In combination with the 3 other changes</p></li><li><p>Major synthetic change to side chain - Strong electrostatic interaction with Asn 564</p></li><li><p>Additional incorporation of fluorine at 6α - increases glucocorticoid binding only ,6α methyl also works here but less good</p></li></ul><p>Examples of ante-drugs (stable in lung but not in. circulation)</p>
30
New cards

drug design sar of glucocorticoids

knowt flashcard image