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∀ε>0 ∃N(ε)∈N ∀n>N(ε):∣an−a∣<ε
∀K>0 ∃N(K)∈N ∀n>N(K):an>K
an=O(bn)⟺∃C>0:bnan≤C
an=o(bn)⟺n→∞limbnan=0
n→∞limbnan=1