Trigonometry

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89 Terms

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How are sin⁡θ\sin\theta, cos⁡θ\cos\theta and tan⁡θ\tan\theta defined in a right triangle?

sin⁡θ=oppositehypotenuse\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}, cos⁡θ=adjacenthypotenuse\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}, tan⁡θ=oppositeadjacent=sin⁡θcos⁡θ\tan\theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{\sin\theta}{\cos\theta}.

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How are sin⁡θ\sin\theta and cos⁡θ\cos\theta defined on the unit circle?

The point at angle θ\theta (measured counterclockwise from the positive x-axis) on the unit circle is (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta).

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How are csc⁡θ\csc\theta, sec⁡θ\sec\theta and cot⁡θ\cot\theta defined?

csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}, sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}, cot⁡θ=1tan⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{1}{\tan\theta} = \frac{\cos\theta}{\sin\theta}.

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How do you convert between degrees and radians?

180∘=π180^\circ = \pi rad, so θrad=θdeg⋅π180\theta_{\text{rad}} = \theta_{\text{deg}} \cdot \frac{\pi}{180} and θdeg=θrad⋅180π\theta_{\text{deg}} = \theta_{\text{rad}} \cdot \frac{180}{\pi}.

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What are sin⁡\sin, cos⁡\cos and tan⁡\tan of 00?

sin⁡0=0\sin 0 = 0, cos⁡0=1\cos 0 = 1, tan⁡0=0\tan 0 = 0.

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What are sin⁡\sin, cos⁡\cos and tan⁡\tan of π6\frac{\pi}{6} (30∘)(30^\circ)?

sin⁡π6=12\sin\frac{\pi}{6} = \frac{1}{2}, cos⁡π6=32\cos\frac{\pi}{6} = \frac{\sqrt{3}}{2}, tan⁡π6=13=33\tan\frac{\pi}{6} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}.

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What are sin⁡\sin, cos⁡\cos and tan⁡\tan of π4\frac{\pi}{4} (45∘)(45^\circ)?

sin⁡π4=cos⁡π4=22\sin\frac{\pi}{4} = \cos\frac{\pi}{4} = \frac{\sqrt{2}}{2}, tan⁡π4=1\tan\frac{\pi}{4} = 1.

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What are sin⁡\sin, cos⁡\cos and tan⁡\tan of π3\frac{\pi}{3} (60∘)(60^\circ)?

sin⁡π3=32\sin\frac{\pi}{3} = \frac{\sqrt{3}}{2}, cos⁡π3=12\cos\frac{\pi}{3} = \frac{1}{2}, tan⁡π3=3\tan\frac{\pi}{3} = \sqrt{3}.

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What are sin⁡\sin, cos⁡\cos and tan⁡\tan of π2\frac{\pi}{2} (90∘)(90^\circ)?

sin⁡π2=1\sin\frac{\pi}{2} = 1, cos⁡π2=0\cos\frac{\pi}{2} = 0, and tan⁡π2\tan\frac{\pi}{2} is undefined.

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What are sin⁡π\sin\pi, cos⁡π\cos\pi, sin⁡3π2\sin\frac{3\pi}{2} and cos⁡3π2\cos\frac{3\pi}{2}?

sin⁡π=0\sin\pi = 0, cos⁡π=−1\cos\pi = -1, sin⁡3π2=−1\sin\frac{3\pi}{2} = -1, cos⁡3π2=0\cos\frac{3\pi}{2} = 0.

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Which trig functions are positive in each quadrant?

Quadrant I: all. Quadrant II: sin⁡\sin (and csc⁡\csc). Quadrant III: tan⁡\tan (and cot⁡\cot). Quadrant IV: cos⁡\cos (and sec⁡\sec). Mnemonic: "All Students Take Calculus".

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What is a reference angle and how is it used?

The acute angle between the terminal side of θ\theta and the x-axis. The trig value of θ\theta equals the value at the reference angle, with the sign set by the quadrant.

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What are the periods of sin⁡\sin, cos⁡\cos and tan⁡\tan?

sin⁡\sin and cos⁡\cos have period 2π2\pi, tan⁡\tan (and cot⁡\cot) has period π\pi.

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Which trig functions are even and which are odd?

cos⁡(−x)=cos⁡x\cos(-x) = \cos x and sec⁡(−x)=sec⁡x\sec(-x) = \sec x are even. sin⁡(−x)=−sin⁡x\sin(-x) = -\sin x, tan⁡(−x)=−tan⁡x\tan(-x) = -\tan x, csc⁡\csc and cot⁡\cot are odd.

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What are the domain and range of sin⁡x\sin x and cos⁡x\cos x?

Domain R\mathbb{R}, range [−1,1][-1, 1].

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What are the domain and range of tan⁡x\tan x?

Domain: all x≠π2+kπx \neq \frac{\pi}{2} + k\pi, k∈Zk \in \mathbb{Z} (vertical asymptotes there). Range: R\mathbb{R}.

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For y=Asin⁡(Bx−C)+Dy = A\sin(Bx - C) + D, what are the amplitude, period, phase shift and vertical shift?

Amplitude ∣A∣\lvert A \rvert, period 2π∣B∣\frac{2\pi}{\lvert B \rvert}, phase shift CB\frac{C}{B} (to the right if positive), vertical shift DD.

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What do the graphs of sin⁡x\sin x and cos⁡x\cos x look like?

Both are waves between −1-1 and 11 with period 2π2\pi. sin⁡x\sin x starts at 00 and rises to 11 at π2\frac{\pi}{2}. cos⁡x\cos x starts at its maximum 11. cos⁡x=sin⁡(x+π2)\cos x = \sin\left(x + \frac{\pi}{2}\right), so the cosine graph is the sine graph shifted left by π2\frac{\pi}{2}.


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What are the three Pythagorean identities?

sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1, 1+tan⁡2x=sec⁡2x1 + \tan^2 x = \sec^2 x, 1+cot⁡2x=csc⁡2x1 + \cot^2 x = \csc^2 x.

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What are the cofunction identities?

sin⁡(π2−x)=cos⁡x\sin\left(\frac{\pi}{2} - x\right) = \cos x, cos⁡(π2−x)=sin⁡x\cos\left(\frac{\pi}{2} - x\right) = \sin x, tan⁡(π2−x)=cot⁡x\tan\left(\frac{\pi}{2} - x\right) = \cot x.

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What are sin⁡(π−x)\sin(\pi - x), cos⁡(π−x)\cos(\pi - x), sin⁡(π+x)\sin(\pi + x) and cos⁡(π+x)\cos(\pi + x)?

sin⁡(π−x)=sin⁡x\sin(\pi - x) = \sin x, cos⁡(π−x)=−cos⁡x\cos(\pi - x) = -\cos x, sin⁡(π+x)=−sin⁡x\sin(\pi + x) = -\sin x, cos⁡(π+x)=−cos⁡x\cos(\pi + x) = -\cos x.

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What is the sum/difference formula for sin⁡(a±b)\sin(a \pm b)?

sin⁡(a±b)=sin⁡acos⁡b±cos⁡asin⁡b\sin(a \pm b) = \sin a \cos b \pm \cos a \sin b.

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What is the sum/difference formula for cos⁡(a±b)\cos(a \pm b)?

cos⁡(a±b)=cos⁡acos⁡b∓sin⁡asin⁡b\cos(a \pm b) = \cos a \cos b \mp \sin a \sin b (note the sign flips).

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What is the sum/difference formula for tan⁡(a±b)\tan(a \pm b)?

tan⁡(a±b)=tan⁡a±tan⁡b1∓tan⁡atan⁡b\tan(a \pm b) = \frac{\tan a \pm \tan b}{1 \mp \tan a \tan b}.

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What is the double-angle formula for sin⁡2x\sin 2x?

sin⁡2x=2sin⁡xcos⁡x\sin 2x = 2\sin x \cos x.

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What are the three forms of the double-angle formula for cos⁡2x\cos 2x?

cos⁡2x=cos⁡2x−sin⁡2x=2cos⁡2x−1=1−2sin⁡2x\cos 2x = \cos^2 x - \sin^2 x = 2\cos^2 x - 1 = 1 - 2\sin^2 x.

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What is the double-angle formula for tan⁡2x\tan 2x?

tan⁡2x=2tan⁡x1−tan⁡2x\tan 2x = \frac{2\tan x}{1 - \tan^2 x}.

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What are the power-reduction formulas for sin⁡2x\sin^2 x and cos⁡2x\cos^2 x?

sin⁡2x=1−cos⁡2x2\sin^2 x = \frac{1 - \cos 2x}{2}, cos⁡2x=1+cos⁡2x2\cos^2 x = \frac{1 + \cos 2x}{2}. Essential for integrating even powers of sin⁡\sin and cos⁡\cos.

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What are the half-angle formulas for sin⁡x2\sin\frac{x}{2} and cos⁡x2\cos\frac{x}{2}?

sin⁡x2=±1−cos⁡x2\sin\frac{x}{2} = \pm\sqrt{\frac{1 - \cos x}{2}}, cos⁡x2=±1+cos⁡x2\cos\frac{x}{2} = \pm\sqrt{\frac{1 + \cos x}{2}}, with the sign chosen by the quadrant of x2\frac{x}{2}.

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What is the half-angle formula for tan⁡x2\tan\frac{x}{2} (sign-free forms)?

tan⁡x2=sin⁡x1+cos⁡x=1−cos⁡xsin⁡x\tan\frac{x}{2} = \frac{\sin x}{1 + \cos x} = \frac{1 - \cos x}{\sin x}.

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What are the triple-angle formulas for sin⁡3x\sin 3x and cos⁡3x\cos 3x?

sin⁡3x=3sin⁡x−4sin⁡3x\sin 3x = 3\sin x - 4\sin^3 x, cos⁡3x=4cos⁡3x−3cos⁡x\cos 3x = 4\cos^3 x - 3\cos x.

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What are the product-to-sum formulas?

sin⁡acos⁡b=12[sin⁡(a+b)+sin⁡(a−b)]\sin a \cos b = \frac{1}{2}[\sin(a+b) + \sin(a-b)], cos⁡acos⁡b=12[cos⁡(a−b)+cos⁡(a+b)]\cos a \cos b = \frac{1}{2}[\cos(a-b) + \cos(a+b)], sin⁡asin⁡b=12[cos⁡(a−b)−cos⁡(a+b)]\sin a \sin b = \frac{1}{2}[\cos(a-b) - \cos(a+b)].

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What are the sum-to-product formulas for sin⁡a±sin⁡b\sin a \pm \sin b?

sin⁡a+sin⁡b=2sin⁡a+b2cos⁡a−b2\sin a + \sin b = 2\sin\frac{a+b}{2}\cos\frac{a-b}{2}, sin⁡a−sin⁡b=2cos⁡a+b2sin⁡a−b2\sin a - \sin b = 2\cos\frac{a+b}{2}\sin\frac{a-b}{2}.

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What are the sum-to-product formulas for cos⁡a±cos⁡b\cos a \pm \cos b?

cos⁡a+cos⁡b=2cos⁡a+b2cos⁡a−b2\cos a + \cos b = 2\cos\frac{a+b}{2}\cos\frac{a-b}{2}, cos⁡a−cos⁡b=−2sin⁡a+b2sin⁡a−b2\cos a - \cos b = -2\sin\frac{a+b}{2}\sin\frac{a-b}{2}.

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How do you write asin⁡x+bcos⁡xa\sin x + b\cos x as a single sine (harmonic addition)?

asin⁡x+bcos⁡x=Rsin⁡(x+φ)a\sin x + b\cos x = R\sin(x + \varphi), where R=a2+b2R = \sqrt{a^2 + b^2}, cos⁡φ=aR\cos\varphi = \frac{a}{R}, sin⁡φ=bR\sin\varphi = \frac{b}{R}. Pick the quadrant of φ\varphi from the signs of both cos⁡φ\cos\varphi and sin⁡φ\sin\varphi, not from tan⁡φ=ba\tan\varphi = \frac{b}{a} alone.

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What is the general solution of sin⁡x=c\sin x = c for −1≤c≤1-1 \le c \le 1?

x=arcsin⁡c+2kπx = \arcsin c + 2k\pi or x=π−arcsin⁡c+2kπx = \pi - \arcsin c + 2k\pi, k∈Zk \in \mathbb{Z}, where arcsin⁡c∈[−π2,π2]\arcsin c \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] is the principal value.

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What is the general solution of cos⁡x=c\cos x = c for −1≤c≤1-1 \le c \le 1?

x=±arccos⁡c+2kπx = \pm\arccos c + 2k\pi, k∈Zk \in \mathbb{Z}, where arccos⁡c∈[0,π]\arccos c \in [0, \pi] is the principal value.

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What is the general solution of tan⁡x=c\tan x = c?

x=arctan⁡c+kπx = \arctan c + k\pi, k∈Zk \in \mathbb{Z}, where arctan⁡c∈(−π2,π2)\arctan c \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) is the principal value.

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What is the Law of Sines?

In any triangle with sides a,b,ca, b, c opposite angles A,B,CA, B, C: asin⁡A=bsin⁡B=csin⁡C=2R\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = 2R, where RR is the circumradius.

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What is the Law of Cosines?

c2=a2+b2−2abcos⁡Cc^2 = a^2 + b^2 - 2ab\cos C (and similarly for the other sides). It reduces to Pythagoras when C=π2C = \frac{\pi}{2}.

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What is the area of a triangle in terms of two sides and the included angle?

Area=12absin⁡C\text{Area} = \frac{1}{2}ab\sin C.

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What are the domain and range of arcsin⁡x\arcsin x?

Domain [−1,1][-1, 1], range [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right].

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What are the domain and range of arccos⁡x\arccos x?

Domain [−1,1][-1, 1], range [0,π][0, \pi].

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What are the domain and range of arctan⁡x\arctan x?

Domain R\mathbb{R}, range (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) (horizontal asymptotes y=±π2y = \pm\frac{\pi}{2}).

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What is arcsin⁡x+arccos⁡x\arcsin x + \arccos x?

arcsin⁡x+arccos⁡x=π2\arcsin x + \arccos x = \frac{\pi}{2} for all x∈[−1,1]x \in [-1, 1].

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What is cos⁡(arcsin⁡x)\cos(\arcsin x) and sin⁡(arccos⁡x)\sin(\arccos x)?

Both equal 1−x2\sqrt{1 - x^2}, the nonnegative root, because arcsin⁡x∈[−π2,π2]\arcsin x \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] where cos⁡≥0\cos \ge 0, and arccos⁡x∈[0,π]\arccos x \in [0, \pi] where sin⁡≥0\sin \ge 0.

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What is sec⁡(arctan⁡x)\sec(\arctan x) and sin⁡(arctan⁡x)\sin(\arctan x)?

sec⁡(arctan⁡x)=1+x2\sec(\arctan x) = \sqrt{1 + x^2}, sin⁡(arctan⁡x)=x1+x2\sin(\arctan x) = \frac{x}{\sqrt{1 + x^2}}.

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What are the key features of the graphs of arcsin⁡x\arcsin x, arccos⁡x\arccos x and arctan⁡x\arctan x?

arcsin⁡\arcsin: increasing, odd, from (−1,−π2)\left(-1, -\frac{\pi}{2}\right) to (1,π2)\left(1, \frac{\pi}{2}\right) through the origin. arccos⁡\arccos: decreasing, from (−1,π)(-1, \pi) to (1,0)(1, 0) through (0,π2)\left(0, \frac{\pi}{2}\right). arctan⁡\arctan: increasing, odd, horizontal asymptotes y=±π2y = \pm\frac{\pi}{2}. Each is the reflection of the restricted original function in y=xy = x.

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How do you solve sin⁡(kx)=c\sin(kx) = c on an interval such as [0,2π)[0, 2\pi)?

Let u=kxu = kx, so uu runs over [0,2kπ)[0, 2k\pi). Find every solution for uu in that wider interval, then divide by kk. Expect up to 2k2k solutions, not just 2.

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How do you solve an equation like 2sin⁡2x−sin⁡x−1=02\sin^2 x - \sin x - 1 = 0?

Substitute t=sin⁡xt = \sin x: 2t2−t−1=02t^2 - t - 1 = 0 gives t=1t = 1 or t=−12t = -\frac{1}{2}. Discard any root outside [−1,1][-1, 1], then solve each: x=π2+2kπx = \frac{\pi}{2} + 2k\pi, x=−π6+2kπx = -\frac{\pi}{6} + 2k\pi, x=7π6+2kπx = \frac{7\pi}{6} + 2k\pi.

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How do you solve an equation that mixes cos⁡2x\cos^2 x and sin⁡x\sin x, such as 2cos⁡2x+3sin⁡x=32\cos^2 x + 3\sin x = 3?

Use cos⁡2x=1−sin⁡2x\cos^2 x = 1 - \sin^2 x to write it in one function: 2sin⁡2x−3sin⁡x+1=02\sin^2 x - 3\sin x + 1 = 0, so sin⁡x=1\sin x = 1 or sin⁡x=12\sin x = \frac{1}{2}. Solutions: x=π2+2kπx = \frac{\pi}{2} + 2k\pi, x=π6+2kπx = \frac{\pi}{6} + 2k\pi, x=5π6+2kπx = \frac{5\pi}{6} + 2k\pi.

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Why should you not divide both sides of a trig equation by sin⁡x\sin x or cos⁡x\cos x?

You lose the solutions where that factor is zero. Factor instead: sin⁡xcos⁡x=sin⁡x⇒sin⁡x(cos⁡x−1)=0\sin x\cos x = \sin x \Rightarrow \sin x(\cos x - 1) = 0, so sin⁡x=0\sin x = 0 or cos⁡x=1\cos x = 1.

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What is lim⁡x→0sin⁡xx\lim_{x \to 0} \frac{\sin x}{x}?

lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 (xx in radians).

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What is lim⁡x→01−cos⁡xx\lim_{x \to 0} \frac{1 - \cos x}{x} and lim⁡x→01−cos⁡xx2\lim_{x \to 0} \frac{1 - \cos x}{x^2}?

lim⁡x→01−cos⁡xx=0\lim_{x \to 0} \frac{1 - \cos x}{x} = 0 and lim⁡x→01−cos⁡xx2=12\lim_{x \to 0} \frac{1 - \cos x}{x^2} = \frac{1}{2}.

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What are the derivatives of sin⁡x\sin x, cos⁡x\cos x and tan⁡x\tan x?

(sin⁡x)′=cos⁡x(\sin x)' = \cos x, (cos⁡x)′=−sin⁡x(\cos x)' = -\sin x, (tan⁡x)′=sec⁡2x=1+tan⁡2x(\tan x)' = \sec^2 x = 1 + \tan^2 x.

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What are the derivatives of csc⁡x\csc x, sec⁡x\sec x and cot⁡x\cot x?

(csc⁡x)′=−csc⁡xcot⁡x(\csc x)' = -\csc x \cot x, (sec⁡x)′=sec⁡xtan⁡x(\sec x)' = \sec x \tan x, (cot⁡x)′=−csc⁡2x(\cot x)' = -\csc^2 x.

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What are the derivatives of arcsin⁡x\arcsin x, arccos⁡x\arccos x and arctan⁡x\arctan x?

(arcsin⁡x)′=11−x2(\arcsin x)' = \frac{1}{\sqrt{1 - x^2}}, (arccos⁡x)′=−11−x2(\arccos x)' = -\frac{1}{\sqrt{1 - x^2}}, (arctan⁡x)′=11+x2(\arctan x)' = \frac{1}{1 + x^2}.

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What are ∫sin⁡x dx\int \sin x \, dx and ∫cos⁡x dx\int \cos x \, dx?

∫sin⁡x dx=−cos⁡x+C\int \sin x \, dx = -\cos x + C, ∫cos⁡x dx=sin⁡x+C\int \cos x \, dx = \sin x + C.

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What are ∫tan⁡x dx\int \tan x \, dx and ∫cot⁡x dx\int \cot x \, dx?

∫tan⁡x dx=−ln⁡∣cos⁡x∣+C\int \tan x \, dx = -\ln\lvert\cos x\rvert + C, ∫cot⁡x dx=ln⁡∣sin⁡x∣+C\int \cot x \, dx = \ln\lvert\sin x\rvert + C.

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What are ∫sec⁡x dx\int \sec x \, dx and ∫csc⁡x dx\int \csc x \, dx?

∫sec⁡x dx=ln⁡∣sec⁡x+tan⁡x∣+C\int \sec x \, dx = \ln\lvert\sec x + \tan x\rvert + C, ∫csc⁡x dx=−ln⁡∣csc⁡x+cot⁡x∣+C\int \csc x \, dx = -\ln\lvert\csc x + \cot x\rvert + C.

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What are ∫sin⁡2x dx\int \sin^2 x \, dx and ∫cos⁡2x dx\int \cos^2 x \, dx?

∫sin⁡2x dx=x2−sin⁡2x4+C\int \sin^2 x \, dx = \frac{x}{2} - \frac{\sin 2x}{4} + C, ∫cos⁡2x dx=x2+sin⁡2x4+C\int \cos^2 x \, dx = \frac{x}{2} + \frac{\sin 2x}{4} + C.

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What are ∫dxa2−x2\int \frac{dx}{\sqrt{a^2 - x^2}} and ∫dxa2+x2\int \frac{dx}{a^2 + x^2}?

∫dxa2−x2=arcsin⁡xa+C\int \frac{dx}{\sqrt{a^2 - x^2}} = \arcsin\frac{x}{a} + C, ∫dxa2+x2=1aarctan⁡xa+C\int \frac{dx}{a^2 + x^2} = \frac{1}{a}\arctan\frac{x}{a} + C.

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Which trig substitution do you use for a2−x2\sqrt{a^2 - x^2}, a2+x2\sqrt{a^2 + x^2} and x2−a2\sqrt{x^2 - a^2}?

a2−x2\sqrt{a^2 - x^2}: x=asin⁡θx = a\sin\theta. a2+x2\sqrt{a^2 + x^2}: x=atan⁡θx = a\tan\theta. x2−a2\sqrt{x^2 - a^2}: x=asec⁡θx = a\sec\theta.

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What is the Weierstrass substitution t=tan⁡x2t = \tan\frac{x}{2}?

sin⁡x=2t1+t2\sin x = \frac{2t}{1 + t^2}, cos⁡x=1−t21+t2\cos x = \frac{1 - t^2}{1 + t^2}, dx=2 dt1+t2dx = \frac{2\,dt}{1 + t^2}. It turns rational functions of sin⁡\sin and cos⁡\cos into rational functions of tt.

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What are the derivatives of sin⁡u\sin u, cos⁡u\cos u and tan⁡u\tan u where u=u(x)u = u(x) (chain rule)?

ddxsin⁡u=cos⁡u⋅u′\frac{d}{dx}\sin u = \cos u \cdot u', ddxcos⁡u=−sin⁡u⋅u′\frac{d}{dx}\cos u = -\sin u \cdot u', ddxtan⁡u=sec⁡2u⋅u′\frac{d}{dx}\tan u = \sec^2 u \cdot u'.

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What are the derivatives of arcsin⁡u\arcsin u, arccos⁡u\arccos u and arctan⁡u\arctan u where u=u(x)u = u(x) (chain rule)?

u′1−u2\frac{u'}{\sqrt{1 - u^2}}, −u′1−u2-\frac{u'}{\sqrt{1 - u^2}}, u′1+u2\frac{u'}{1 + u^2}.

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How do you differentiate sin⁡y\sin y and cos⁡(xy)\cos(xy) implicitly with respect to xx?

Treat yy as a function of xx and use the chain rule: ddxsin⁡y=cos⁡y⋅dydx\frac{d}{dx}\sin y = \cos y \cdot \frac{dy}{dx}, ddxcos⁡(xy)=−sin⁡(xy)(y+xdydx)\frac{d}{dx}\cos(xy) = -\sin(xy)\left(y + x\frac{dy}{dx}\right).

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How do you integrate ∫sin⁡mxcos⁡nx dx\int \sin^m x\cos^n x\,dx?

Odd power of sin⁡\sin: save one sin⁡x\sin x, convert the rest with sin⁡2x=1−cos⁡2x\sin^2 x = 1 - \cos^2 x, let u=cos⁡xu = \cos x. Odd power of cos⁡\cos: save one cos⁡x\cos x, convert the rest with cos⁡2x=1−sin⁡2x\cos^2 x = 1 - \sin^2 x, let u=sin⁡xu = \sin x. Both even: use the power-reduction formulas.

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How do you integrate ∫tan⁡mxsec⁡nx dx\int \tan^m x\sec^n x\,dx?

Even power of sec⁡\sec: save sec⁡2x\sec^2 x, convert the rest with sec⁡2x=1+tan⁡2x\sec^2 x = 1 + \tan^2 x, let u=tan⁡xu = \tan x. Odd power of tan⁡\tan: save sec⁡xtan⁡x\sec x\tan x, convert the rest with tan⁡2x=sec⁡2x−1\tan^2 x = \sec^2 x - 1, let u=sec⁡xu = \sec x.

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What is ∫duuu2−a2\int \frac{du}{u\sqrt{u^2 - a^2}}?

∫duuu2−a2=1a arcsec∣u∣a+C\int \frac{du}{u\sqrt{u^2 - a^2}} = \frac{1}{a}\,\text{arcsec}\frac{\lvert u \rvert}{a} + C.

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How do you integrate ∫dxx2+2x+5\int \frac{dx}{x^2 + 2x + 5}?

Complete the square: x2+2x+5=(x+1)2+4x^2 + 2x + 5 = (x + 1)^2 + 4. With u=x+1u = x + 1 this is ∫duu2+4=12arctan⁡x+12+C\int \frac{du}{u^2 + 4} = \frac{1}{2}\arctan\frac{x + 1}{2} + C.

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What is lim⁡x→0sin⁡(ax)bx\lim_{x \to 0} \frac{\sin(ax)}{bx}?

ab\frac{a}{b}. Rewrite it as ab⋅sin⁡(ax)ax\frac{a}{b} \cdot \frac{\sin(ax)}{ax} and use lim⁡t→0sin⁡tt=1\lim_{t \to 0} \frac{\sin t}{t} = 1.

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Which technique fits ∫x1+x4 dx\int \frac{x}{1 + x^4}\,dx?

Substitute u=x2u = x^2, du=2x dxdu = 2x\,dx: 12∫du1+u2=12arctan⁡(x2)+C\frac{1}{2}\int \frac{du}{1 + u^2} = \frac{1}{2}\arctan(x^2) + C.

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Which technique fits ∫sin⁡3xcos⁡2x dx\int \sin^3 x\cos^2 x\,dx?

Odd power of sin⁡\sin: write sin⁡3x=(1−cos⁡2x)sin⁡x\sin^3 x = (1 - \cos^2 x)\sin x and let u=cos⁡xu = \cos x: −∫(1−u2)u2 du=−cos⁡3x3+cos⁡5x5+C-\int (1 - u^2)u^2\,du = -\frac{\cos^3 x}{3} + \frac{\cos^5 x}{5} + C.

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Which technique fits ∫9−x2 dx\int \sqrt{9 - x^2}\,dx?

Trig substitution x=3sin⁡θx = 3\sin\theta, dx=3cos⁡θ dθdx = 3\cos\theta\,d\theta, 9−x2=3cos⁡θ\sqrt{9 - x^2} = 3\cos\theta, giving 9∫cos⁡2θ dθ9\int \cos^2\theta\,d\theta. Power reduction then gives 92arcsin⁡x3+x29−x2+C\frac{9}{2}\arcsin\frac{x}{3} + \frac{x}{2}\sqrt{9 - x^2} + C.

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What are the Taylor series of sin⁡x\sin x and cos⁡x\cos x about 00?

sin⁡x=x−x33!+x55!−⋯=∑n=0∞(−1)nx2n+1(2n+1)!\sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!}, cos⁡x=1−x22!+x44!−⋯=∑n=0∞(−1)nx2n(2n)!\cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n}}{(2n)!}.

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What are the small-angle approximations?

For small xx (radians): sin⁡x≈x\sin x \approx x, tan⁡x≈x\tan x \approx x, cos⁡x≈1−x22\cos x \approx 1 - \frac{x^2}{2}.

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What is Euler's formula?

eiθ=cos⁡θ+isin⁡θe^{i\theta} = \cos\theta + i\sin\theta.

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How are cos⁡θ\cos\theta and sin⁡θ\sin\theta expressed with complex exponentials?

cos⁡θ=eiθ+e−iθ2\cos\theta = \frac{e^{i\theta} + e^{-i\theta}}{2}, sin⁡θ=eiθ−e−iθ2i\sin\theta = \frac{e^{i\theta} - e^{-i\theta}}{2i}.

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What is the polar (trigonometric) form of a complex number z=a+biz = a + bi?

z=r(cos⁡θ+isin⁡θ)=reiθz = r(\cos\theta + i\sin\theta) = re^{i\theta}, where r=∣z∣=a2+b2r = \lvert z \rvert = \sqrt{a^2 + b^2} and θ=arg⁡z\theta = \arg z with tan⁡θ=ba\tan\theta = \frac{b}{a} (quadrant chosen by the signs of a,ba, b).

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What is de Moivre's theorem?

(cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθ(\cos\theta + i\sin\theta)^n = \cos n\theta + i\sin n\theta for integer nn, equivalently (reiθ)n=rneinθ(re^{i\theta})^n = r^n e^{in\theta}.

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How do you find the nn-th roots of z=reiθz = re^{i\theta}?

zk=r1/neiθ+2kπnz_k = r^{1/n} e^{i\frac{\theta + 2k\pi}{n}} for k=0,1,…,n−1k = 0, 1, \ldots, n-1. They are equally spaced on a circle of radius r1/nr^{1/n}.

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What is the 2D rotation matrix for a counterclockwise rotation by θ\theta?

R(θ)=(cos⁡θ−sin⁡θsin⁡θcos⁡θ)R(\theta) = \begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}, with det⁡R(θ)=1\det R(\theta) = 1 and R(θ)−1=R(θ)T=R(−θ)R(\theta)^{-1} = R(\theta)^T = R(-\theta).

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How is the angle between two vectors u\mathbf{u} and v\mathbf{v} found?

cos⁡θ=u⋅v∥u∥ ∥v∥\cos\theta = \frac{\mathbf{u} \cdot \mathbf{v}}{\lVert\mathbf{u}\rVert\,\lVert\mathbf{v}\rVert}, and in R3\mathbb{R}^3 also ∥u×v∥=∥u∥ ∥v∥sin⁡θ\lVert\mathbf{u} \times \mathbf{v}\rVert = \lVert\mathbf{u}\rVert\,\lVert\mathbf{v}\rVert\sin\theta.

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How are Cartesian and polar coordinates related?

x=rcos⁡θx = r\cos\theta, y=rsin⁡θy = r\sin\theta, r=x2+y2r = \sqrt{x^2 + y^2}, tan⁡θ=yx\tan\theta = \frac{y}{x}. Choose the quadrant of θ\theta from the signs of xx and yy.

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What are the slope and area formulas for a polar curve r=f(θ)r = f(\theta)?

Slope: dydx=r′sin⁡θ+rcos⁡θr′cos⁡θ−rsin⁡θ\frac{dy}{dx} = \frac{r'\sin\theta + r\cos\theta}{r'\cos\theta - r\sin\theta}. Area swept from α\alpha to β\beta: A=12∫αβr2 dθA = \frac{1}{2}\int_\alpha^\beta r^2\,d\theta.

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How do you differentiate a parametric curve x=x(t)x = x(t), y=y(t)y = y(t)?

dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt} and d2ydx2=ddt(dydx)dx/dt\frac{d^2y}{dx^2} = \frac{\frac{d}{dt}\left(\frac{dy}{dx}\right)}{dx/dt}. Example: for x=cos⁡tx = \cos t, y=sin⁡ty = \sin t, dydx=−cot⁡t\frac{dy}{dx} = -\cot t.

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How are sinh⁡x\sinh x and cosh⁡x\cosh x defined, and what is their main identity?

sinh⁡x=ex−e−x2\sinh x = \frac{e^x - e^{-x}}{2}, cosh⁡x=ex+e−x2\cosh x = \frac{e^x + e^{-x}}{2}, tanh⁡x=sinh⁡xcosh⁡x\tanh x = \frac{\sinh x}{\cosh x}, and cosh⁡2x−sinh⁡2x=1\cosh^2 x - \sinh^2 x = 1 (note the minus sign, unlike cos⁡2+sin⁡2\cos^2 + \sin^2).

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What are the derivatives of sinh⁡x\sinh x, cosh⁡x\cosh x and tanh⁡x\tanh x?

(sinh⁡x)′=cosh⁡x(\sinh x)' = \cosh x, (cosh⁡x)′=sinh⁡x(\cosh x)' = \sinh x (no minus sign), (tanh⁡x)′=sech2x=1−tanh⁡2x(\tanh x)' = \text{sech}^2 x = 1 - \tanh^2 x.