Grade 9 General Mathematics: Linear Functions and Equations Review

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Flashcards covering key vocabulary, linear relationships, rate of change, slope calculations, slope-intercept conversions, and graph representations from Grade 9 General CA3 Term 1 review notes.

23 Terms

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Rate of Change

The ratio that describes how much one quantity changes in relation to another quantity, calculated as ΔyΔx\frac{\Delta y}{\Delta x}.

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Linear Function Rate of Change (Example 3)

A constant rate of change of −23-\frac{2}{3}, confirming that the relationship shown in the table with coordinates (11,−5)(11, -5), (8,−3)(8, -3), (5,−1)(5, -1), (2,1)(2, 1), and (−1,3)(-1, 3) is linear.

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Nonlinear Relationship (Example 4)

A relationship where the rate of change is not constant across data pairs (e.g., changing from 37\frac{3}{7} to 27\frac{2}{7}), showing that the function is not linear.

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Slope-Intercept Form

A linear equation written in the form y=mx+by = mx + b, where mm is the slope of the line and bb is the yy-intercept.

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Slope-Intercept Form of −10x+2y=12-10x + 2y = 12

y=5x+6y = 5x + 6, obtained by adding 10x10x to both sides and dividing every term by 22.

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Slope-Intercept Form of 4y+12x=164y + 12x = 16

y=−3x+4y = -3x + 4, obtained by subtracting 12x12x from both sides and dividing every term by 44.

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Slope-Intercept Form of −5x+15y=−30-5x + 15y = -30

y=13x−2y = \frac{1}{3}x - 2, obtained by adding 5x5x to both sides and dividing every term by 1515.

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Slope-Intercept Form of 6x−3y=−186x - 3y = -18

y=2x+6y = 2x + 6, obtained by subtracting 6x6x from both sides and dividing every term by −3-3.

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Slope-Intercept Form of −2x−8y=24-2x - 8y = 24

y=−14x−3y = -\frac{1}{4}x - 3, obtained by adding 2x2x to both sides and dividing every term by −8-8.

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Slope-Intercept Form of −4x−10y=−7-4x - 10y = -7

y=−25x+710y = -\frac{2}{5}x + \frac{7}{10}, obtained by adding 4x4x to both sides and dividing every term by −10-10.

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Equation of the Line through (0,−3)(0, -3) and (2,1)(2, 1)

y=2x−3y = 2x - 3, which has a yy-intercept of −3-3 and a slope of m=1−(−3)2−0=2m = \frac{1 - (-3)}{2 - 0} = 2.

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Equation of the Line through (0,2)(0, 2) and (2,−4)(2, -4)

y=−3x+2y = -3x + 2, which has a yy-intercept of 22 and a slope of m=−4−22−0=−3m = \frac{-4 - 2}{2 - 0} = -3.

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Equation of the Line through (0,−1)(0, -1) and (2,−3)(2, -3)

y=−x−1y = -x - 1, which has a yy-intercept of −1-1 and a slope of m=−3−(−1)2−0=−1m = \frac{-3 - (-1)}{2 - 0} = -1.

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Slope Formula

The formula used to find the slope mm of a line passing through points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2): m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.

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Slope of the Line through (−1,3)(-1, 3) and (4,1)(4, 1)

−25-\frac{2}{5}, calculated using 1−34−(−1)=−25\frac{1 - 3}{4 - (-1)} = \frac{-2}{5}.

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Slope of the Line through (−2,−5)(-2, -5) and (4,−5)(4, -5)

00, indicating a horizontal line where there is zero vertical change (Δy=0\Delta y = 0).

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Slope of the Line through (−3,4)(-3, 4) and (−3,−2)(-3, -2)

Undefined, indicating a vertical line where there is zero horizontal change (Δx=0\Delta x = 0), resulting in division by zero.

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Graph of 5x+2y=85x + 2y = 8

A line with a negative slope of −52-\frac{5}{2}, a yy-intercept at (0,4)(0, 4), and an xx-intercept at (1.6,0)(1.6, 0).

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Graph of 4x+9y=274x + 9y = 27

A line with a negative slope of −49-\frac{4}{9}, a yy-intercept at (0,3)(0, 3), and an xx-intercept at (6.75,0)(6.75, 0).

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Graph of y=7y = 7

A horizontal line with a slope of 00 that crosses the yy-axis at (0,7)(0, 7).

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Graph of y=−23y = -\frac{2}{3}

A horizontal line with a slope of 00 located below the xx-axis, crossing the yy-axis at (0,−23)\left(0, -\frac{2}{3}\right).

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Graph of 21=7y21 = 7y

A horizontal line equivalent to y=3y = 3, having a slope of 00 and crossing the yy-axis at (0,3)(0, 3).

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Graph of 3y−6=2x3y - 6 = 2x

A line rewritten as y=23x+2y = \frac{2}{3}x + 2, with a positive slope of 23\frac{2}{3}, a yy-intercept at (0,2)(0, 2), and an xx-intercept at (−3,0)(-3, 0).