CHEM 111 12.1-12.4

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/11

flashcard set

Earn XP

Description and Tags

vocab + formulas

12 Terms

1
New cards

spontaneous process:

  • occurs naturally under SPECIFIC CONDITIONS

  • T dependent!


2
New cards

non-spontaneous process

  • does NOT occur naturally under these conditions


3
New cards

direction of spontaneity determined by. . .

  1. Enthalpy

  2. Entropy


4
New cards

enthalpy

  • release of heat promotes spontaneity

  • formation of stronger bonds than the ones broken = more spontaneity


5
New cards

entropy (S)

  • configurational freedom of a system

  • more possible configurations → the state is more probable


6
New cards

microstate

  • specific configuration of the locations and energies of the particles in a system


<ul><li><p>specific configuration of the locations and energies of the <span style="line-height: normal;">particles in a system</span></p></li></ul><p></p>
7
New cards

Entropy equation

S = K ln W

S = entropy

k = boltsamnn constant (1.38 × 10-23) J/K

W = # micro states possible

8
New cards

Relationship between change in S and change in enthalpy

  • change of entropy of surroundings is DIRECTLY proportional to change of enthalpy of the system


<ul><li><p>change of entropy of surroundings is DIRECTLY proportional to change of enthalpy of the system</p></li></ul><p></p>
9
New cards

2nd Law of Thermodynamics:

ALL spontaneous changes = increase in entropy (S) of universe

  • ΔSuniverse > 0 for a spontaneous process

  • ΔSuniverse < 0 for a nonspontaneous process (spontaneous in the

reverse direction).

  • ΔSuniverse = 0 for a process at equilibrium


<p>ALL spontaneous changes = increase in entropy (S) of universe</p><ul><li><p><span style="line-height: normal;">Δ</span><span>S</span><span style="line-height: normal;">universe </span>&gt; 0 for a spontaneous process</p></li><li><p class="p1"><span style="line-height: normal;">ΔSuniverse &lt; 0 for a nonspontaneous process (spontaneous in the</span></p></li></ul><p class="p1">reverse direction).</p><ul><li><p class="p1"><span style="line-height: normal;">Δ</span><span>S</span><span style="line-height: normal;">universe </span>= 0 for a process at equilibrium</p></li></ul><p></p>
10
New cards

3rd Law of Thermodynamics:

  • The entropy of a pure perfect crystalline substance at zero Kelvin is zero


11
New cards

absolute 0:

0 Kelvins

12
New cards

Standard Entropy

value is for. . .

  • 1 mol of a substance at P = 1 bar & T = 298K

  • (aq) species at 1M concentration

  • calculating standard entropy change of a process