Evaluating Functions

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/24

flashcard set

Earn XP

Description and Tags

Vocabulary practice cards covering algebraic and graphical evaluation of functions, as well as solving for input values given specific function outputs.

25 Terms

1
New cards

Evaluating Functions

The mathematical process of determining the output value f(x)f(x) for a given input value of xx, or solving for the input variable xx given a specified output value.

2
New cards

f(−1)f(-1) given f(x)=x2−8x−12f(x) = x^2 - 8x - 12

−3-3, calculated by substituting x=−1x = -1 into the expression: f(−1)=(−1)2−8(−1)−12=1+8−12=−3f(-1) = (-1)^2 - 8(-1) - 12 = 1 + 8 - 12 = -3.

3
New cards

f(5)f(5) given f(x)=−4x+20f(x) = -4x + 20

00, calculated by substituting x=5x = 5 into the expression: f(5)=−4(5)+20=−20+20=0f(5) = -4(5) + 20 = -20 + 20 = 0.

4
New cards

f(−12)f(-12) given f(x)=23x+7f(x) = \frac{2}{3}x + 7

−1-1, calculated by substituting x=−12x = -12 into the expression: f(−12)=23(−12)+7=−8+7=−1f(-12) = \frac{2}{3}(-12) + 7 = -8 + 7 = -1.

5
New cards

f(7)f(7) given f(x)=∣9−2x∣f(x) = |9 - 2x|

55, calculated by evaluating the absolute value expression: f(7)=∣9−2(7)∣=∣9−14∣=∣−5∣=5f(7) = |9 - 2(7)| = |9 - 14| = |-5| = 5.

6
New cards

f(−4)f(-4) given f(x)=2x2+x−10f(x) = 2x^2 + x - 10

1818, calculated by substituting x=−4x = -4 into the expression: f(−4)=2(−4)2+(−4)−10=2(16)−4−10=32−14=18f(-4) = 2(-4)^2 + (-4) - 10 = 2(16) - 4 - 10 = 32 - 14 = 18.

7
New cards

f(−2)f(-2) given f(x)=x3+4xf(x) = x^3 + 4x

−16-16, calculated by substituting x=−2x = -2 into the expression: f(−2)=(−2)3+4(−2)=−8−8=−16f(-2) = (-2)^3 + 4(-2) = -8 - 8 = -16.

8
New cards

f(6)f(6) given f(x)=15−52xf(x) = 15 - \frac{5}{2}x

00, calculated by substituting x=6x = 6 into the expression: f(6)=15−52(6)=15−15=0f(6) = 15 - \frac{5}{2}(6) = 15 - 15 = 0.

9
New cards

f(−8)f(-8) given f(x)=∣−20−x2∣f(x) = |-20 - x^2|

8484, calculated by evaluating the absolute value expression: f(−8)=∣−20−(−8)2∣=∣−20−64∣=∣−84∣=84f(-8) = |-20 - (-8)^2| = |-20 - 64| = |-84| = 84.

10
New cards

f(3)f(3) given f(x)=−5x2+20f(x) = -5x^2 + 20

−25-25, calculated by substituting x=3x = 3 into the expression: f(3)=−5(3)2+20=−5(9)+20=−45+20=−25f(3) = -5(3)^2 + 20 = -5(9) + 20 = -45 + 20 = -25.

11
New cards

f(7)f(7) given f(x)=−x2+5x+13f(x) = -x^2 + 5x + 13

−1-1, calculated by substituting x=7x = 7 into the expression: f(7)=−(7)2+5(7)+13=−49+35+13=−1f(7) = -(7)^2 + 5(7) + 13 = -49 + 35 + 13 = -1.

12
New cards

Value of xx when f(x)=−61f(x) = -61 for f(x)=−3x−7f(x) = -3x - 7

x=18x = 18, determined by setting the function equal to −61-61: −61=−3x−7→−54=−3x→x=18-61 = -3x - 7 \rightarrow -54 = -3x \rightarrow x = 18.

13
New cards

Value of xx when f(x)=20f(x) = 20 for f(x)=14−2xf(x) = 14 - 2x

x=−3x = -3, determined by setting the function equal to 2020: 20=14−2x→6=−2x→x=−320 = 14 - 2x \rightarrow 6 = -2x \rightarrow x = -3.

14
New cards

Value of xx when f(x)=29f(x) = 29 for f(x)=x−262f(x) = \frac{x - 26}{2}

x=84x = 84, determined by setting the function equal to 2929: 29=x−262→58=x−26→x=8429 = \frac{x - 26}{2} \rightarrow 58 = x - 26 \rightarrow x = 84.

15
New cards

Value of xx when f(x)=5f(x) = 5 for f(x)=−x−11f(x) = -x - 11

x=−16x = -16, determined by setting the function equal to 55: 5=−x−11→16=−x→x=−165 = -x - 11 \rightarrow 16 = -x \rightarrow x = -16.

16
New cards

Value of xx when f(x)=−72f(x) = -\frac{7}{2} for f(x)=14x−8f(x) = \frac{1}{4}x - 8

x=18x = 18, determined by setting the function equal to −72-\frac{7}{2}: −72=14x−8→92=14x→x=18-\frac{7}{2} = \frac{1}{4}x - 8 \rightarrow \frac{9}{2} = \frac{1}{4}x \rightarrow x = 18.

17
New cards

Value of xx when f(x)=−139f(x) = -139 for f(x)=8x+61f(x) = 8x + 61

x=−25x = -25, determined by setting the function equal to −139-139: −139=8x+61→−200=8x→x=−25-139 = 8x + 61 \rightarrow -200 = 8x \rightarrow x = -25.

18
New cards

Value of xx when f(x)=−14f(x) = -14 for f(x)=3x−29f(x) = 3x - 29

x=5x = 5, determined by setting the function equal to −14-14: −14=3x−29→15=3x→x=5-14 = 3x - 29 \rightarrow 15 = 3x \rightarrow x = 5.

19
New cards

Value of xx when f(x)=−2f(x) = -2 for f(x)=−35x−17f(x) = -\frac{3}{5}x - 17

x=−25x = -25, determined by setting the function equal to −2-2: −2=−35x−17→15=−35x→x=−25-2 = -\frac{3}{5}x - 17 \rightarrow 15 = -\frac{3}{5}x \rightarrow x = -25.

20
New cards

Value of xx when f(x)=−25f(x) = -25 for f(x)=−11−16xf(x) = -11 - \frac{1}{6}x

x=84x = 84, determined by setting the function equal to −25-25: −25=−11−16x→−14=−16x→x=84-25 = -11 - \frac{1}{6}x \rightarrow -14 = -\frac{1}{6}x \rightarrow x = 84.

21
New cards

Value of xx when f(x)=89f(x) = 89 for f(x)=−5x+9f(x) = -5x + 9

x=−16x = -16, determined by setting the function equal to 8989: 89=−5x+9→80=−5x→x=−1689 = -5x + 9 \rightarrow 80 = -5x \rightarrow x = -16.

22
New cards
<p>Value of $$f(-4)$$ from the graph of $$f(x)$$ (Card U)</p>

Value of f(−4)f(-4) from the graph of f(x)f(x) (Card U)

−3-3, found by locating x=−4x = -4 on the horizontal axis and finding the corresponding vertical coordinate on the line.

23
New cards
<p>Value of $$f(2)$$ from the graph of $$f(x)$$ (Card V)</p>

Value of f(2)f(2) from the graph of f(x)f(x) (Card V)

00, found by locating x=2x = 2 on the horizontal axis where the parabolic curve crosses the horizontal xx-axis.

24
New cards
<p>Value of $$x$$ when $$f(x) = 4$$ from the graph of $$f(x)$$ (Card W)</p>

Value of xx when f(x)=4f(x) = 4 from the graph of f(x)f(x) (Card W)

x=−1x = -1, found by locating 44 on the vertical f(x)f(x)-axis and identifying the corresponding horizontal coordinate on the line.

25
New cards
<p>Value of $$x$$ when $$f(x) = -3$$ from the graph of $$f(x)$$ (Card X)</p>

Value of xx when f(x)=−3f(x) = -3 from the graph of f(x)f(x) (Card X)

x=0x = 0, found by locating −3-3 on the vertical f(x)f(x)-axis where the curve intersects the vertical axis.