Introduction to Sturm-Liouville Systems

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/11

flashcard set

Earn XP

Description and Tags

Flashcards covering the introductory concepts of Sturm-Liouville boundary value problems, including ordinary differential equation classifications, eigenvalue/eigenfunction definitions, and worked boundary value problem examples on various intervals.

12 Terms

1
New cards

What constitutes an nn-th order ordinary differential equation, and how many arbitrary constants does its general solution contain?

An nn-th order ordinary differential equation is an equation involving a real-valued function y(x)y(x) of a real variable xx along with its nn lowest derivatives, written in the form y(n)=F(y(n−1),...,y′,y,x)y^{(n)} = F(y^{(n-1)}, \text{...}, y', y, x). Its general solution contains nn arbitrary constants.

2
New cards

What is the distinction between an initial value problem and a boundary value problem (separated end-point problem)?

In an initial value problem, all nn conditions are specified at a single value x0x_0 of the independent variable, giving rise to a unique solution. In a boundary value problem, conditions are specified at different values of the independent variable, such as at the boundaries x=ax = a and x=bx = b of an interval [a,b][a, b].

3
New cards

What is the general solution to the differential equation d2ydx2(x)+λy(x)=0\frac{d^2y}{dx^2}(x) + \lambda y(x) = 0 when λ=−α2<0\lambda = -\alpha^2 < 0 with α>0\alpha > 0?

The general solution is y−(x)=Acosh⁡(αx)+Bsinh⁡(αx)y_-(x) = A \cosh(\alpha x) + B \sinh(\alpha x), where AA and BB are arbitrary constants.

4
New cards

What are the general solutions to d2ydx2(x)+λy(x)=0\frac{d^2y}{dx^2}(x) + \lambda y(x) = 0 for the cases λ=0\lambda = 0 and λ=ω2>0\lambda = \omega^2 > 0 (ω>0\omega > 0)?

For λ=0\lambda = 0, integrating twice yields y0(x)=cx+dy_0(x) = cx + d for arbitrary constants cc and dd. For λ=ω2>0\lambda = \omega^2 > 0, the general solution is y+(x)=Esin⁡(ωx)+Fcos⁡(ωx)y_+(x) = E \sin(\omega x) + F \cos(\omega x) for arbitrary constants EE and FF.

5
New cards

In the context of the differential equation −d2ydx2=λy-\frac{d^2y}{dx^2} = \lambda y, how are eigenvalues and eigenfunctions defined?

The values of the parameter λ\lambda for which non-trivial solutions (y(x)≢0y(x) \not\equiv 0) exist that satisfy the given boundary conditions are called eigenvalues, and the corresponding non-trivial solutions are called eigenfunctions.

6
New cards

What are the eigenvalues and eigenfunctions for d2ydx2+λy=0\frac{d^2y}{dx^2} + \lambda y = 0 on [0,π][0, \pi] subject to y(0)=0y(0) = 0 and y(π)=0y(\pi) = 0 (Example 1.3)?

There are no non-trivial solutions for λ≤0\lambda \le 0. For λ>0\lambda > 0, the condition sin⁡(ωπ)=0\sin(\omega \pi) = 0 yields countably infinitely many positive eigenvalues λn=n2\lambda_n = n^2 with eigenfunctions yn(x)=Ensin⁡(nx)y_n(x) = E_n \sin(nx) for n∈Nn \in \mathbb{N}.

7
New cards
<p>In Example 1.5 ($$\frac{d^2y}{dx^2} + \lambda y = 0$$ on $$[0, \pi]$$ with $$y(0) + y'(0) = 0$$ and $$y(\pi) = 0$$), what transcendental equation and negative eigenvalue are represented by this plot?</p>

In Example 1.5 (d2ydx2+λy=0\frac{d^2y}{dx^2} + \lambda y = 0 on [0,π][0, \pi] with y(0)+y′(0)=0y(0) + y'(0) = 0 and y(π)=0y(\pi) = 0), what transcendental equation and negative eigenvalue are represented by this plot?

The plot illustrates the transcendental equation tanh⁡(απ)=α\tanh(\alpha \pi) = \alpha derived from the negative case λ=−α2<0\lambda = -\alpha^2 < 0. It shows a single strictly positive root α=α∗>0\alpha = \alpha^* > 0, yielding exactly one negative eigenvalue λα∗=−(α∗)2\lambda_{\alpha^*} = -(\alpha^*)^2 with eigenfunction yα∗(x)=sinh⁡(α∗(x−π))y_{\alpha^*}(x) = \sinh(\alpha^*(x - \pi)).

8
New cards
<p>In Example 1.5, what transcendental equation is shown in this plot for $$\lambda = \omega^2 > 0$$, and where do the intersections occur?</p>

In Example 1.5, what transcendental equation is shown in this plot for λ=ω2>0\lambda = \omega^2 > 0, and where do the intersections occur?

The plot shows the transcendental equation tan⁡(ωπ)=ω\tan(\omega \pi) = \omega. The curves intersect once in each interval (n,n+12)(n, n + \frac{1}{2}) for n∈Nn \in \mathbb{N}, yielding countably infinitely many positive eigenvalues λn=ωn2\lambda_n = \omega_n^2 with corresponding eigenfunctions yn(x)=sin⁡(ωn(π−x))y_n(x) = \sin(\omega_n(\pi - x)).

9
New cards

For d2ydx2+λy=0\frac{d^2y}{dx^2} + \lambda y = 0 on the symmetric interval [−π,π][-\pi, \pi] with y(−π)=0y(-\pi) = 0 and y(π)=0y(\pi) = 0 (Example 1.6), what condition on ω\omega produces non-trivial solutions when λ=ω2>0\lambda = \omega^2 > 0?

Setting the determinant of the coefficients to zero yields −2sin⁡(ωπ)cos⁡(ωπ)=−sin⁡(2ωπ)=0-2\sin(\omega \pi)\cos(\omega \pi) = -\sin(2\omega \pi) = 0, which requires ω=n2\omega = \frac{n}{2} for n∈Nn \in \mathbb{N}.

10
New cards

In Example 1.6 on [−π,π][-\pi, \pi] with y(−π)=0y(-\pi) = 0 and y(π)=0y(\pi) = 0, what are the resulting sequences of eigenvalues and eigenfunctions for even and odd nn?

For even n=2kn = 2k (k∈Nk \in \mathbb{N}), the eigenfunctions are odd: yk(x)=sin⁡(kx)y_k(x) = \sin(kx) with λk=k2\lambda_k = k^2. For odd n=2k−1n = 2k - 1 (k∈Nk \in \mathbb{N}), the eigenfunctions are even: yk−1/2(x)=cos⁡((k−12)x)y_{k - 1/2}(x) = \cos((k - \frac{1}{2})x) with λk−1/2=(k−12)2\lambda_{k - 1/2} = (k - \frac{1}{2})^2.

11
New cards

For the boundary value problem d2ydx2+λy=0\frac{d^2y}{dx^2} + \lambda y = 0 on [−π,π][-\pi, \pi] with periodic boundary conditions y(−π)=y(π)y(-\pi) = y(\pi) and y′(−π)=y′(π)y'(-\pi) = y'(\pi) (Example 1.7), is λ=0\lambda = 0 an eigenvalue?

Yes. When λ=0\lambda = 0, the general solution y(x)=cx+dy(x) = cx + d satisfies y(−π)=y(π)  ⟹  −cπ+d=cπ+dy(-\pi) = y(\pi) \implies -c\pi + d = c\pi + d, forcing c=0c = 0 and leaving y(x)=dy(x) = d. The condition y′(−π)=y′(π)y'(-\pi) = y'(\pi) is automatically satisfied, giving eigenvalue λ=0\lambda = 0 with eigenfunction y0(x)=1y_0(x) = 1.

12
New cards

In Example 1.7 with boundary conditions y(−π)=y(π)y(-\pi) = y(\pi) and y′(−π)=y′(π)y'(-\pi) = y'(\pi), what are the positive eigenvalues and the multiplicity of each eigenvalue for n∈Nn \in \mathbb{N}?

The positive eigenvalues are λn=n2\lambda_n = n^2 for n∈Nn \in \mathbb{N}. Each has multiplicity two because there are two linearly independent eigenfunctions, sin⁡(nx)\sin(nx) and cos⁡(nx)\cos(nx), spanning the corresponding two-dimensional eigenspace.