03 the force- velocity relation and fibre types

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What factors determine human muscle fibre type distribution according to the slide?

  • Genetics: Fibre type distribution is partly genetically determined.

  • Short-term: Short-term shifts in fibre type are possible through training.

  • Long-term: Scientific studies for longer periods are currently missing



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Why is zero force (F = 0) at maximum shortening velocity (vmax) a theoretical laboratory condition, and why do real-life movements always have F > 0?


  • Laboratory Condition (In Vitro): Tested on isolated single muscle fibers with zero attached external load/mass. All internal energy is consumed by shortening the tissue itself, leaving zero external force output (F = 0).

  • Real-Life Movement (In Vivo): Muscles must always overcome and accelerate the mass of limb segments or body parts (e.g., arm, torso in push-ups). Because mass is always present, human movements always operate at F > 0 (and thus P > 0), never reaching the absolute unloaded boundary of vmax


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  • Question: What fundamental biological constraint is introduced on according to the "Force-velocity relation"?



  • Core Topic: The mechanical relationship between the force (F) a muscle can generate and the velocity (v) at which it shortens or lengthens

  • Fundamental Trade-off: Represents an active speed-strength limit: a muscle cannot generate maximum force and maximum velocity simultaneously


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How was Archibald V. Hill's (1938) isotonic release experiment conducted, and what parameters were measured?

  • Experimental Setup: An isolated muscle is attached to a lever system with an adjustable stop (Hub-Einsteller), an attached load, and an electromagnetic release mechanism (Release-Mechanik)

  • The last = external load mass is the last the muscle is pulling against

  • Procedure: Electrical stimulation activates the muscle until it reaches maximum isometric force (F0). The release mechanism then suddenly frees the lever to a lower load (F1)

  • Measurements: A revolving drum (kymograph) records the rapid force drop (∆ F) and length change (∆ l) over time to calculate shortening velocity (v = ∆l/∆t)


If their is on the left side a low mass last → muscle contract fast = high velocity

<ul><li><p><strong>Experimental Setup</strong>: An isolated muscle is attached to a lever system with an adjustable stop (<em>Hub-Einsteller</em>), an attached load, and an electromagnetic release mechanism (<em>Release-Mechanik</em>)</p></li><li><p>The last = external load mass is the last the muscle is pulling against</p></li><li><p><strong>Procedure</strong>: Electrical stimulation activates the muscle until it reaches maximum isometric force (F0). The release mechanism then suddenly frees the lever to a lower load (F1)</p></li><li><p><strong>Measurements</strong>: A revolving drum (<em>kymograph</em>) records the rapid force drop (∆ F) and length change (∆ l) over time to calculate shortening velocity (v = ∆l/∆t)</p></li></ul><p></p><p>If their is on the left side a low mass last → muscle contract fast = high velocity </p>
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What do the two lower diagrams on the "Hills experiment" slide illustrate regarding tendon compliance and extension (∆ l SE)?

  • Left Graph (Compliance vs. Force): At low forces, the series elastic element (SE / tendon & aponeurosis) exhibits high compliance (it is soft/flexible). As muscle force increases, compliance drops sharply (the tendon becomes rigid/stiff)

  • Right Graph (Force vs. ∆ l SE Extension): Shows the non-linear, exponential force-extension curve of tendons. At higher forces, progressively greater force is required to produce incremental tendon stretching (∆ l SE)


<ul><li><p><strong>Left Graph (Compliance vs. Force)</strong>: At low forces, the series elastic element (SE / tendon &amp; aponeurosis) exhibits high compliance (it is soft/flexible). As muscle force increases, compliance drops sharply (the tendon becomes rigid/stiff)</p></li><li><p><strong>Right Graph (Force vs. </strong>∆ l SE<strong> Extension)</strong>: Shows the non-linear, exponential force-extension curve of tendons. At higher forces, progressively greater force is required to produce incremental tendon stretching (∆ l SE)</p></li></ul><p></p>
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<p>How are the axes defined on the picture, where is the isometric contraction point located, and which exercise examples represent v = 0?</p>

How are the axes defined on the picture, where is the isometric contraction point located, and which exercise examples represent v = 0?

  • X-axis: Normalized contraction velocity (v/vmax)

  • Y-axis (left / primary): Normalized muscle force (F/F0 or T/T0), where 1.0 equals maximum isometric force (F0)

  • Y-axis (right / secondary): Normalized mechanical power (T x v/T0 x vmax) for the red power curve

  • Isometric Point: located at the Y-intercept (v=0, F/F0 = 1.0). Muscle length remains constant

  • Lecture Example: Planking or Bavarian beer mug holding (Bierkrugstemmen): maximum isometric force (F0), zero movement velocity (v=0), zero mechanical power (P=0)


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How do concentric and eccentric force outputs differ, and why does concentric force drop to zero at vmax?

  • Concentric (v > 0, Right): Muscle shortens. Force drops hyperbolically even at small contraction speeds

  • Eccentric (v < 0, Left): Muscle is forced to lengthen under load; force rises above isometric capacity to 1.4-1.8 • F0

  • Drop at vmax: At maximum shortening velocity (vmax), filaments slide so fast that myosin cross-bridges cannot detach, cock, and reattach quickly enough to build tension, dropping net force to zero (F = 0)


  • Bei Isometrie (v = 0) ist die Kraft maximal, aber die mechanische Leistung ist null!


<ul><li><p><strong>Concentric (</strong>v &gt; 0<strong>, Right)</strong>: Muscle shortens. Force drops hyperbolically even at small contraction speeds</p></li><li><p><strong>Eccentric (</strong>v &lt; 0<strong>, Left)</strong>: Muscle is forced to lengthen under load; force rises above isometric capacity to 1.4-1.8 • F0</p></li><li><p><strong>Drop at </strong>vmax: At maximum shortening velocity (vmax), filaments slide so fast that myosin cross-bridges cannot detach, cock, and reattach quickly enough to build tension, dropping net force to zero (F = 0)</p></li></ul><p></p><ul><li><p>Bei Isometrie (v = 0) ist die <strong>Kraft maximal</strong>, aber die <strong>mechanische Leistung ist null</strong>!</p></li></ul><p></p>
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What does the upper blue line dictate at the force-velocity relation diagramm , and can a muscle operate outside of it?

  • Upper Bound Envelope: Represents the maximum physical force limit of the muscle at 100% activation (a = 1.0)

  • Constraint: A muscle can never operate above/outside this blue curve. It operates on the line during maximal activation or below it during submaximal activation (a < 1.0)


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How is mechanical muscle power derived from work and duration?

  • Work (W): Generated by force along a displacement (W = ∫ F dl)

  • Power (P): Work generated in a unit of duration (P = work/duration = ∫ F dl/dt (distance/duration)

  • Derivation: Since velocity v = dl/dt, mechanical power simplifies to P = F • v


<ul><li><p><strong>Work (</strong>W<strong>)</strong>: Generated by force along a displacement (W = ∫ F dl)</p></li><li><p><strong>Power (</strong>P<strong>)</strong>: Work generated in a unit of duration (P = work/duration = ∫ F dl/dt (distance/duration)</p></li><li><p><strong>Derivation</strong>: Since velocity v = dl/dt, mechanical power simplifies to P = F • v</p></li></ul><p></p>
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Why is mechanical power P = 0 at both boundary ends, where is peak power achieved, and how do bicycle gears illustrate this?

  • At v = 0(Isometric): P = F0•0 =0 (High force, zero movement = zero power)

  • At v = vmax (Max Speed): P = 0 • vmax = 0 (Max speed, zero load = zero power)

  • Peak Power (Pmax): Forms an inverted U-curve (red line), peaking at approx. 30% vmax and 30% F0

  • Bicycle Gears Example:

    • High gear uphill: High pedaling force (F → F0), cadence stalls (v → 0) → Power drops to zero

    • Very low gear: High cadence (v → vmax), zero resistance (F → 0) → Power drops to zero

    • Optimal gear: Matches the sweet spot (~ 30%) for maximum mechanical power output


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How does the 3D surface model unify the force-length and force-velocity relationships?

  • Unification: Combines the Force-Length curve (Gordon et al., 1966) and the Force-Velocity curve (Hill, 1938) into a single 3D state space (Lieber, 2010 / Uchida & Delp, 2021)

  • Cross-Sections:

    • Slice at constant velocity (v^M = 0) → yields the classic Force-Length curve

    • Slice at constant length (l^M = 1) → yields the Force-Velocity curve


<ul><li><p><strong>Unification</strong>: Combines the <strong>Force-Length curve</strong> (Gordon et al., 1966) and the <strong>Force-Velocity curve</strong> (Hill, 1938) into a single 3D state space (Lieber, 2010 / Uchida &amp; Delp, 2021)</p></li><li><p><strong>Cross-Sections</strong>:</p><ul><li><p style="text-align: left;">Slice at constant velocity (v^M = 0) → yields the classic Force-Length curve</p></li><li><p>Slice at constant length (l^M = 1) → yields the Force-Velocity curve</p></li></ul></li></ul><p></p>
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How does neural activation (a) scale the 3D force-length-velocity surface across the four diagrams?

  • Neural Drive: The nervous system controls muscle force through motor unit recruitment and firing rates, modeled by muscle activation (a € [0, 1.0])

  • At a = 0: Completely relaxed muscle → surface is entirely flat (0 N force capacity)

  • Scaling (a = 0 → 0.33 → 0.67 → 1.0): Increasing neural drive scales the height of the entire 3D surface upwards, expanding the muscle's maximal force capacity envelope across all lengths and speeds


<ul><li><p><strong>Neural Drive</strong>: The nervous system controls muscle force through motor unit recruitment and firing rates, modeled by muscle activation (a € [0, 1.0])</p></li><li><p><strong>At </strong>a = 0: Completely relaxed muscle → surface is entirely flat (0 N force capacity)</p></li><li><p><strong>Scaling (</strong>a = 0 → 0.33 → 0.67 → 1.0<strong>)</strong>: Increasing neural drive scales the height of the entire 3D surface upwards, expanding the muscle's maximal force capacity envelope across all lengths and speeds</p></li></ul><p></p>
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How are Slow-Twitch (ST) and Fast-Twitch (FT) fibres distinguished in histological preparation?



  • Slow-Twitch (ST): Stained blue ("ST - blau") → many mitochondria; tiny; dense network of capillaries (to ensure the oxygen supply for the aerobic metabolism)

  • Fast-Twitch (FT): Stained yellow/brown ("FT - gelb/braun") → less mitochondria; big; low capillarity (in their immediate vicinity)



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How does hypertrophy affect appearance according to st and ft fibres?

  • Hypertrophy Effect: Hypertrophy increases individual fibre cross-sectional area (thickness). If ST fibres enlarge, the histological section shows a larger relative area of blue.


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Which fibre type transitions are easy vs. hard?

  • Type IIX <—> Type IIA (Easy/Fast): Shifts within fast-twitch subtypes occur readily with endurance or strength training.

  • Type I (ST) <—>Type II (FT) (Hard/Slow): Complete transitions between slow-twitch and fast-twitch major types are extremely difficult, very slow, and mostly constrained by genetics.


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How do force-velocity properties differ between Type 1 (Slow-Twitch) and Type 2 (Fast-Twitch) muscle fibres?

  • Type 1 (Slow-Twitch): Lower maximal shortening velocity (vmax)

  • Type 2 (Fast-Twitch: 2A, 2B, 2X): Significantly higher maximal shortening velocity (vmax) and higher maximal power output


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How does fatigue affect the force-velocity relationship in fast (EDL) versus slow (Soleus) muscles?

  • Fast EDL Muscle: Shows a large drop in absolute force under fatigue

  • Slow Soleus Muscle: Maintains force much better under fatigue (fatigue-resistant)

  • Normalized Curves: When normalized (P/P0 vs V/Vmax), the curve shapes remain nearly identical


Black point line = fresh muscle compared to white point line = used muscle

P0,F0= gleich immer die isometrische Form = dafür steht die null, weil 0,2Vx0F=0


<ul><li><p><strong>Fast EDL Muscle</strong>: Shows a <strong>large drop in absolute force</strong> under fatigue</p></li><li><p><strong>Slow Soleus Muscle</strong>: Maintains force much better under fatigue (fatigue-resistant)</p></li><li><p><strong>Normalized Curves</strong>: When normalized (P/P0 vs V/Vmax), the curve shapes remain nearly identical</p></li></ul><p></p><p>Black point line = fresh muscle compared to white point line = used muscle</p><p>P0,F0= gleich immer die isometrische Form = dafür steht die null, weil 0,2Vx0F=0</p><p></p>
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What fibre type distribution pattern is found in paravertebral back muscles (Schilling, 2005)?

  • Deep Muscle Regions: Higher percentage of oxidative fibres (>90% oxidative) for posture stabilization.

  • Superficial Muscle Regions: Higher percentage of glycolytic fibres (>90% glycolytic) for rapid movement torques



<ul><li><p><strong>Deep Muscle Regions</strong>: Higher percentage of <strong>oxidative fibres (&gt;90% oxidative)</strong> for posture stabilization.</p></li></ul><ul><li><p><strong>Superficial Muscle Regions</strong>: Higher percentage of <strong>glycolytic fibres (&gt;90% glycolytic)</strong> for rapid movement torques</p></li></ul><p><br></p>
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How do the fast EDL (Extensor Digitorum Longus) and slow Soleus muscles compare in maximal shortening velocity (vmax), and why is velocity measured in L0/s?

  • EDL (Fast EDL): Reaches a high maximal contraction velocity of approx. 5-6, L0/s. (Small, very fast muscle, e.g. cat)

  • Soleus (Slow Soleus): Reaches a lower maximal contraction velocity of approx. 2.5-3, L0/s (large, slow postural muscle, e.g. elephant )

  • conclusion: The small, fast muscle (EDL) reaches twice as many own muscle lengths per second shortening as the large, slow muscle (soleus)



  • Meaning of L0/s: Muscle lengths per second (L0 = optimal muscle length). Normalizing by L0 allows fair comparison of intrinsic contraction speeds between muscles of different physical sizes


<ul><li><p><strong>EDL (Fast EDL)</strong>: Reaches a high maximal contraction velocity of approx. 5-6, L0/s. (Small, very fast muscle, e.g. cat)</p></li><li><p><strong>Soleus (Slow Soleus)</strong>: Reaches a lower maximal contraction velocity of approx. 2.5-3, L0/s (large, slow postural muscle, e.g. elephant )</p></li><li><p><strong>conclusion</strong>: The small, fast muscle (EDL) reaches twice as many own muscle lengths per second shortening as the large, slow muscle (soleus)</p></li></ul><p></p><p></p><ul><li><p><strong>Meaning of </strong>L0/s: Muscle lengths per second (L0 = optimal muscle length). Normalizing by L0 allows fair comparison of intrinsic contraction speeds between muscles of different physical sizes</p></li></ul><p></p>
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On the "force-velocity for slow and fast fibres" slide, what do the Y-axis intercepts at 0.5 L/s0.5 \text{ L/s} and 1.5 L/s1.5 \text{ L/s} represent when force P/P0=0P/P_0 = 0?

  • 0.5 L/s Intercept (Type 1 / Slow-Twitch): Represents the maximal unloaded shortening velocity (vmax) of slow-twitch fibres.

  • 1.5 L/s Intercept (Type 2 / Fast-Twitch: 2A, 2B, 2X): Represents the maximal unloaded shortening velocity (vmax) of fast-twitch fibres.

  • Key Takeaway: Under zero load (P/P0 → 0), fast-twitch muscle fibres contract approx. 3 times faster (1.5 L/s) than slow-twitch fibres (0.5L/s)


<ul><li><p>0.5 L/s <strong>Intercept (Type 1 / Slow-Twitch)</strong>: Represents the maximal unloaded shortening velocity (vmax) of slow-twitch fibres.</p></li><li><p>1.5 L/s <strong>Intercept (Type 2 / Fast-Twitch: 2A, 2B, 2X)</strong>: Represents the maximal unloaded shortening velocity (vmax) of fast-twitch fibres.</p></li><li><p><strong>Key Takeaway</strong>: Under zero load (P/P0 → 0), fast-twitch muscle fibres contract <strong>approx. 3 times faster</strong> (1.5 L/s) than slow-twitch fibres (0.5L/s)</p></li></ul><p></p>