Topology of the Complex Plane, Differentiability, etc

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53 Terms

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distance between z and w (complex numbers)

d(z,w)=∣z−w∣d\left(z,w\right)=\left|z-w\right|

  • this “distance function” is used to define limits as it can describe “nearness”


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Open disk definition

Δ(z0,ϵ)={z∈C:∣z−z0∣<ϵ}\Delta\left(z_0,\epsilon\right)=\left\lbrace z\in C:\left|z-z_0|<\epsilon\right.\right\rbrace

  • center at z0z_0

  • radius of ϵ\epsilon


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deleted open disk definition

Δ∗(z0,ϵ)=Δ(z0,ϵ) ¬{z0}\Delta^{\ast}\left(z_0,\epsilon\right)=\Delta\left(z_0,\epsilon\right)\ \lnot\left\lbrace z_0\right\rbrace

  • center at z0z_0

  • radius of ϵ\epsilon


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interior point on A

A⊆C,zo∈CA\subseteq C,z_{o}\in C
we say z0z_0 is an interior point on A if there exists an ϵ\epsilon > 0 such that Δ(z0,ϵ)⊆A\Delta\left(z_0,\epsilon\right)\subseteq A

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exterior point of A

we say z0z_0 is an exterior point of A if there exists an ϵ>0\epsilon>0

such that Δ(z0,ϵ)⊆A∁===Δ(z0,ϵ)∩A=0\Delta\left(z_0,\epsilon\right)\subseteq A^{\complement}===\Delta\left(z_0,\epsilon\right)\cap A=0

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boundary point on A

we say z0z_0 is a boundary point on A if for every ϵ>0\epsilon>0 we have

Δ(z0,ϵ)∩A≠0\Delta\left(z_0,\epsilon\right)\cap A\ne0 AND Δ(z0,ϵ)∩A∁≠0\Delta\left(z_0,\epsilon\right)\cap A^{\complement}\ne0

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limit point of A

we say z0z_0 is a limit point of A if, given any ϵ\epsilon > 0 we have

Δ∗(z0,ϵ)∩A≠{}\Delta^{\ast}\left(z_{0,}\epsilon\right)\cap A\ne\left\lbrace\right\rbrace

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Open set definition

Let A⊆CA\subseteq C

We say A is open if every point of A is an interior point

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closed set definition

Let A⊆CA\subseteq C

We say A is closed if every point of A∁A^{\complement} is an interior point

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convergence of a sequence definition (lim)

Let znz_{n} be a sequence of complex numbers. We say znz_n converges to z0z_0 if, given any ϵ>0\epsilon>0 there exists an integer k such that for all n≥kn\ge k the distance ∣zn−z0∣<ϵ\left|z_{n}-z_0\right|<\epsilon

In that case we write lim⁡n→∞(zn)=z0\lim_{n\to\infty}\left(z_{n}\right)=z_0

If such a z0z_0 does not exist we say lim⁡n→∞(zn) DNE\lim_{n\to\infty}\left(z_{n}\right)\ DNE

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requirement for limit of function f (deleted open disk)

Let A⊆CA\subseteq C and let z0z_0 be a limit point of A

Let f:A→Cf:A\to C be a function

We say f has a limit at z0z_0 if there exists a point w0∈Cw_0\in C such that, given any ϵ>0\epsilon>0 there exists a δ>0\delta>0 such that

f[A∩Δ∗(z0,δ)]⊆Δ(w0,ϵ)f\left\lbrack A\cap\Delta^{\ast}\left(z_0,\delta\right)\right\rbrack\subseteq\Delta\left(w_0,\epsilon\right)


in that case we write lim⁡z→z0f(z)=ω0\lim_{z\to z_0}f\left(z\right)=\omega_0

otherwise DNE

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lim f(z) = w_0 <=>

  ⟺  lim⁡z→z0∣f(z)−w0∣\iff\lim_{z\to z_0}|f(z)-w_0|

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limit and modulus correlary


if lim⁡z→z0f(z)=w0\lim_{z\to z_0}f\left(z\right)=w_0 then lim⁡z→z0∣f(z)∣=∣w0∣\lim_{z\to z_0}\left|f\left(z\right)\right|=\left|w_0\right|

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lim[f(z) + g(z)] = ?

lim⁡z→z0f(z)+lim⁡z→z0g(z)\lim_{z\to z_0}f\left(z\right)+\lim_{z\to z_0}g\left(z\right)

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lim[f(z) - g(z)] = ?

lim⁡z→z0f(z)−lim⁡z→z0g(z)\lim_{z\to z_0}f\left(z\right)-\lim_{z\to z_0}g\left(z\right)

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lim [f(z) g(z)] = ?

lim⁡z→z0f(z)⋅lim⁡z→z0g(z)\lim_{z\to z_0}f\left(z\right)\cdot\lim_{z\to z_0}g\left(z\right)

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lim[f(z)/g(z)] = ?

lim⁡z→z0f(z)lim⁡z→z0g(z)\frac{\lim_{z\to z_0}f\left(z\right)}{\lim_{z\to z_0}g\left(z\right)}

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Continuous function definition

Let A⊆CA\subseteq C and let z0∈A,f:A→Cz_0\in A,f:A\to C be a function

We say f is continuous if, at z0z_0 , given any ϵ>0\epsilon>0 , there exists a δ>0\delta>0 such that

z∈Δ(z0,δ)∩A⇒f(z)∈Δ(f(z0),∈)z\in\Delta\left(z_0,\delta\right)\cap A\Rightarrow f\left(z\right)\in\Delta\left(f\left(z_0\right),\in\right)

i.e. f is continuous at z0z_0 if

lim⁡z→z0f(z)=f(z0)\lim_{z\to z_0}f\left(z\right)=f\left(z_0\right)

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discontinuous function definition

We say f is discontinuous at z0z_0 if z0∈Dom(f)z_0\in Dom\left(f\right) AND either

1) lim⁡z→z0f(z) DNE\lim_{z\to z_0}f\left(z\right)\ DNE OR

2) lim⁡z→z0f(z)≠z0\lim_{z\to z_0}f\left(z\right)\ne z_0

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continuity properties of two continuous functions

Let f and g be continuous functions at z0z_0 . The following functions are also continuous:

f±g,f⋅g,∣f∣,f‾,Re⁡(f(z)),Im⁡(f(z)),fgf\pm g,f\cdot g,\left|f\right|,\overline{f},\operatorname{Re}\left(f\left(z\right)\right),\operatorname{Im}\left(f\left(z\right)\right),\frac{f}{g} when g(z0)≠0g\left(z_0\right)\ne0

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continuity of a composition of functions definition

Let f and g be functions such that f is continuous at z0z_0 and g is continuous at f(z0)f(z_0) . Then the function g(f(z))g(f(z)) is continuous at z0z_0

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where are polynomial functions continuous?

everywhere

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Where is Arg(z) continuous?

C¬(−∞,0]C\lnot\left(-\infty,0\right\rbrack

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What forms are valid to use LaHopital’s?

00,∞∞\frac00,\frac{\infty}{\infty}

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where is e^z continuous

everywhere on C

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Differentiable definition

let f:A→Cf:A\to C where A⊆CA\subseteq C is an open set

f is differentiable at z0z_0 if

lim⁡z→z0f(z)−f(z0)z−z0\lim_{z\to z_0}\frac{f\left(z\right)-f\left(z_0\right)}{z-z_0}

exists

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A^n - B^n factoring formula

(An−Bn)=(A−B)(An−1+An−2B+An−3B2+⋯+ABn−2+Bn−1)\left(A^{n}-B^{n}\right)=\left(A-B\right)\left(A^{n-1}+A^{n-2}B+A^{n-3}B^2+\cdots+AB^{n-2}+B^{n-1}\right)


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if f is differentiable at z_0, then it is ____

continuous at z0z_0

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critical point for a function f (definition)

z0z_0 is a critical point for f if f’(z0)=0f’(z_0)=0

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analytic function definition

a function is analytic (holomorphic or regular) in an open set if it has a derivative at every point in the set

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entire definition

a function is entire if it is analytic on the whole complex plane

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T or F: if a function is continuous at a point, it is differentiable at that point

False

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T or F: if a function is differentiable at a point, it is continuous at that point

True

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T or F: if f is not continuous at a point, it can still be differentiable at that point

False

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Cauchy Riemann Equations

ux(x,y)=vy(x,y)u_{x}\left(x,y\right)=v_{y}\left(x,y\right)

uy(x,y)=−vx(x,y)u_{y}\left(x,y\right)=-v_{x}\left(x,y\right)

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T or F: if either of the CR equations don’t hold at z_0, the function is not differentiable at z_0

True

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T or F: if the CR equations hold at z_0, the function is differentiable at z_0

False

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CR-related requirements to ensure f is differentiable at z_0

Let A⊆CA\subseteq C be an open set and let z0=x0+iy0∈Az_0=x_0+iy_0\in A .

Let f:A→Cf:A\to C be a function such that u(x,y)=Re⁡(f(z)),v(x,y)=Im⁡(f(z)),z=x+iyu\left(x,y\right)=\operatorname{Re}\left(f\left(z\right)\right),v\left(x,y\right)=\operatorname{Im}\left(f\left(z\right)\right),z=x+iy

if

1) u and v are C1C^1 functions on some open neighborhood of z0z_0 AND

2) the CR equations are satisfied at z0z_0

then f is differentiable at z_0 and

f′(z0)=ux(x0,y0)+ivx(x0,y0)=1i[uy(x0,y0+ivy(x0,y0))]f^{\prime}\left(z_0\right)=u_{x}\left(x_0,y_0\right)+iv_{x}\left(x_0,y_0\right)=\frac{1}{i}\left\lbrack u_{y}\left(x_0,y_0+iv_{y}\left(x_0,y_0\right)\right)\right\rbrack

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constant function definition using differentiability

Let f:(a,b)→Rf:\left(a,b\right)\to\mathbb{R} be a differentiable function. If f’(x)=0f’(x)=0 for all x∈(a,b)x\in(a,b) then f is constant on (a,b)

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Mean value theorem for real numbers

Let f:[a,b]→Rf:[a,b]\to R be a function such that

1) f is continuous on [a,b] AND

2) f is differentiable on (a,b)

then there exists a point ξ∈(a,b)\xi\in\left(a,b\right) such that f(b)−f(a)b−a=f′(ξ)\frac{f\left(b\right)-f\left(a\right)}{b-a}=f^{\prime}\left(\xi\right)

⟹f(b)−f(a)=f′(ξ)(b−a)\Longrightarrow f\left(b\right)-f\left(a\right)=f^{\prime}\left(\xi\right)\left(b-a\right)

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Does the mean value theorem hold for complex numbers?

Not at all. e^z is an example

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What must a set have to be a domain?

it must be open and connected

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constant function definition using CR eqns

Let u(x,y)u(x,y) be a real valued function defined on a domain D⊆CD\subseteq C such that

ux(x,y)=uy(x,y)=0u_x(x,y)=u_y(x,y)=0

for all z=x+iy∈Dz=x+iy\in D then u is constant on D

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constant function definition using analyticity

let ff be an analytic function defined on a domain D. If

f’=0f’=0 for all z∈Dz\in D

then f is constant

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branch of an inverse function definition

Let f:A→Cf:A→C be an analytic function and let D⊆f(A)D\subseteq f\left(A\right) be a domain

A branch of f−1f^{-1} is defined as a continuous function g:D→Ag:D→A such that

f(g(z))=zf\left(g\left(z\right)\right)=z for all z∈Dz\in D

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T or F: a branch of f−1f^{-1} is univalent on the domain

True, always

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differentiability of a branch of an inverse function requirements/definition

Let f:A→Cf:A→C be an analytic function and let gg be a branch of f−1f^{-1} on domain DD

Let z0∈Dz_0\in D and let w0=g(z0)w_0=g(z_0)

if f’(w0)≠0f’(w_0)≠0

then gg is differentiable at z0z_0

Moreover: g′(z0)=1f′(w0)=1f′(g(z))g^{\prime}\left(z_0\right)=\frac{1}{f^{\prime}\left(w_0\right)}=\frac{1}{f^{\prime}\left(g\left(z_{}\right)\right)}

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requirement for gg, a branch of f−1f^{-1} to be analytic

f′(w0)≠0f^{\prime}\left(w_0\right)\ne0 for all w∈g(D)w\in g\left(D\right)

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Two most important inverse relations

1) The root relations

2) The logarithmic relations

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pthp^{th} root function branch definition

Let p∈Z≥2p\in\mathbb{Z_{\ge2}} and let DD be a domain. A branch of the pthp^{th} root function is an analytic function

g:D→Cg:D→C such that

[g(z)]p=z\left\lbrack g(z)]^{p}\right.=z for all z∈Dz\in D

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identity (=1) relation of branch of pthp^{th} root function

p[g(z)]p−1⋅g′(z)=1p\left\lbrack g\left(z\right)\right\rbrack^{p-1}\cdot g^{\prime}\left(z\right)=1

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Is zero in the domain of a branch of the pthp^{th} root function?

No, using the identity relation we get 0 = 1.

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g’(z)g’(z) as a branch of the pthp^{th} root function relation/definition

g′(z)=g(z)pzg^{\prime}\left(z\right)=\frac{g\left(z\right)}{pz}