GEE 141 Fundamentals of Surveying Midterm Reviewer

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/22

flashcard set

Earn XP

Description and Tags

Comprehensive practice flashcards covering fundamental surveying definitions, error analysis, coordinate calculations, traverse adjustments, and worked review problems.

23 Terms

1
New cards

What type of survey is conducted specifically to determine land boundaries?

Cadastral survey (boundary survey).

2
New cards

How is a bearing that is less than 90∘90^\circ classified, and how is a quadrant bearing expressed?

It is an acute bearing angle. A quadrant bearing is expressed from N or S toward E or W, with an angle from 0∘0^\circ to 90∘90^\circ.

3
New cards

What is the surveying term for a direction measured clockwise from north from 0∘0^\circ to 360∘360^\circ?

Azimuth.

4
New cards

What term describes the angular difference between true north and magnetic north?

Magnetic declination (magnetic variation).

5
New cards

What is the angle between the extension of the previous traverse line and the next line called?

Deflection angle.

6
New cards

What is the reference line from which bearings and azimuths are measured?

Meridian.

7
New cards

Why does using a tape that is too short result in measured distances that are longer than the true distance?

A short tape must be used more times; each nominal tape length represents a shorter actual length, so the recorded total is too large.

8
New cards

Under what condition is it true that angular misclosure must be distributed equally to each traverse angle?

Only when the angles are of equal precision (equal weight).

9
New cards

What are the algebraic signs of latitude and departure for a line with a bearing of S 30∘30^\circ E?

Latitude is negative (South) and departure is positive (East).

10
New cards

What cardinal direction corresponds to an azimuth of 270∘270^\circ?

Due west.

11
New cards

What is the formula for the tape temperature correction (CtC_t)?

Ct=α(Tm−Ts)LC_t = \alpha(T_m - T_s)L, where corrected distance equals measured distance plus CtC_t.

12
New cards

What is the formula for calculating the temperature-adjusted tape length (LactualL_{\text{actual}})?

Lactual=Lnominal[1+α(Tm−Ts)]L_{\text{actual}} = L_{\text{nominal}}[1 + \alpha(T_m - T_s)]

13
New cards

What is the formula to convert degrees, minutes, and seconds (DMS) to decimal degrees?

D+M60+S3600D + \frac{M}{60} + \frac{S}{3600}

14
New cards

How is an azimuth (Az\text{Az}) converted to a quadrant bearing for angles between 90∘–180∘90^\circ\text{–}180^\circ and 180∘–270∘180^\circ\text{–}270^\circ?

For 90∘–180∘90^\circ\text{–}180^\circ: S(180∘−Az)E\text{S}(180^\circ - \text{Az})\text{E}; for 180∘–270∘180^\circ\text{–}270^\circ: S(Az−180∘)W\text{S}(\text{Az} - 180^\circ)\text{W}.

15
New cards

What are the trigonometric formulas used to calculate Latitude and Departure?

Lat=Lcos⁡(Az)\text{Lat} = L \cos(\text{Az}) (North is ++, South is −-) and Dep=Lsin⁡(Az)\text{Dep} = L \sin(\text{Az}) (East is ++, West is −-).

16
New cards

What is the formula for linear error of closure (LELE)?

LE=(∑Lat)2+(∑Dep)2LE = \sqrt{(\sum \text{Lat})^2 + (\sum \text{Dep})^2}

17
New cards

According to the Bowditch (compass) rule, what are the formulas for corrections to latitude (CLat,iC_{\text{Lat},i}) and departure (CDep,iC_{\text{Dep},i})?

CLat,i=−(∑Lat)(LiPerimeter)C_{\text{Lat},i} = -(\sum \text{Lat})\left(\frac{L_i}{\text{Perimeter}}\right) and CDep,i=−(∑Dep)(LiPerimeter)C_{\text{Dep},i} = -(\sum \text{Dep})\left(\frac{L_i}{\text{Perimeter}}\right)

18
New cards

To lay out a true 500 m500\,\text{m} line when Ts=28∘CT_s = 28^\circ\text{C}, field temperature Tm=12∘CT_m = 12^\circ\text{C}, and α=0.0000116 m/(m⋅∘C)\alpha = 0.0000116\,\text{m}/(\text{m}\cdot^\circ\text{C}), what measurement should be read on the tape?

Approximately 500.093 m500.093\,\text{m} (computed as 5001+αΔT=5001−0.0001856=500.0928 m\frac{500}{1 + \alpha \Delta T} = \frac{500}{1 - 0.0001856} = 500.0928\,\text{m}).

19
New cards

What is the bearing in degrees, minutes, seconds and in decimal degrees for an azimuth of 128∘13′46′′128^\circ 13' 46''?

S 51∘46′14′′ E\text{S } 51^\circ 46' 14''\text{ E} or S 51.77056∘ E\text{S } 51.77056^\circ\text{ E}.

20
New cards

What is the procedure for computing the correction per angle for the interior angles of a triangle with equal precision?

Sum the measured angles (∑θ\sum \theta), calculate the angular misclosure as 180∘−∑θ180^\circ - \sum \theta, and distribute it equally by computing Correction per angle=180∘−∑θ3\text{Correction per angle} = \frac{180^\circ - \sum \theta}{3}.

21
New cards

In a traverse with a perimeter of 2556.00 m2556.00\,\text{m} and a linear closure error of 89.927 m89.927\,\text{m}, what is the relative precision?

Approximately 1:28.41 : 28.4 (from 2556.0089.927=28.42\frac{2556.00}{89.927} = 28.42).

22
New cards

What does a relative precision of 1:10001 : 1000 indicate?

About 11 unit of closure error for every 10001000 units of traverse length.

23
New cards

How must the signs and magnitudes of Bowditch corrections relate to total misclosure and line lengths?

Bowditch corrections are proportional to each line's length and opposite in sign to the total misclosure.