ap chem kinetics

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Last updated 4:09 PM on 9/30/26
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25 Terms

1
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thermodynamics vs kinetics

thermo: tells us if a reaction can occur

kinetics; tells us how quickly the reaction occurs


*some reactions that are thermodynamically feastible are kinetically so slow as to be impossible


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collision theory

  • explains why different reactions occur at different rates, and suggests ways to change the rate of a reaction

  • for a chemical reaction to occur, the reacting particles must collide with one another

  • 2 factors


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2 factors for whether reaction occurs when molec collide

  1. is there sufficient energy

  2. is there proper orientation

only a small portion of collisions produce a reaction


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increasing temp

increases reaction speed, inc kinetic energy

(heat them up, speed them up)

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activation energy EA

energy that must be overcome to produce a chemical reaction


<p>energy that must be overcome to produce a chemical reaction</p><p></p>
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endo/exothermic reaction

endo

  • reaction in which a system ABSORBS heat from its surroundings, positive delta H

exo

  • reaction in which a system RELEASES heat to its surroundings, negative delta H


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rate of reaction depends on

rate of reaction depends on EA, delta h has no effect on rate of reaction


*higher the EA, the slower the reaction at a given temperature

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maxwell boltzman distribution curve

probale speeds that molecule possess


y-axis: no of molecules / proportion of molec

x-axis: velocity v in m/s


  • as temperature increases, the fraction of molecules with enough energy to surmount the activation energy barrier also increases


<p>probale speeds that molecule possess </p><p></p><p><strong>y-axis:</strong> no of molecules / proportion of molec</p><p><strong>x-axis:</strong> velocity v in m/s</p><p></p><ul><li><p>as temperature increases, the fraction of molecules with enough energy to surmount the activation energy barrier also increases </p></li></ul><p></p>
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molecular orientation

atoms that are forming new bonds between them — MUST come in contact (and with sufficient energy) in order for a bond to form

<p>atoms that are forming new bonds between them — MUST come in contact (and with sufficient energy) in order for a bond to form </p>
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Catalysts

substance that speeds up a reaction without being consumed (ex. enzymes)

  • produces a new reaction pathway with a lower activation energy for both the forward and reverse reaction

*catalysts will not be shown in balanced equation but may show up in the rate law


<p>substance that speeds up a reaction without being consumed (ex. enzymes)</p><ul><li><p>produces a new reaction pathway with a <strong>lower activation energy</strong> for both the forward and reverse reaction</p></li></ul><p>*catalysts will not be shown in balanced equation but may show up in the rate law </p><p></p>
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homogenous/heterogenous catalysts

homo

  • present in the same phase as the reacting molecules (usually liquid phase)

hetero

  • exists in a different phase

  • usually involves gaseous reactants being absorbed, penetration on the surface of a solid catalyst (such as a car’s catalytic convertor) — called surface catalyst

  • either new reaction intermediate is formed or probability of successful collisions is increased



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the big 5 affecting reaction rates

  1. Temperature

  2. Adding a catalyst/inhibitor

  3. Concentration: increase moles inc particles that can collide

  4. Surface area: inc by crushing a substance, more contact → more collisions

  5. pressure (only gas state): inc moles of substance, dec the volume, closer together


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reaction rate of reactant

Rate = -delta[A]/ delta t


negative bc [ ] decreases

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Rate Law

standard form: Rate = k[A]m[B]n



*Rate laws must be experimentally determined - you CANNOT use the balanced equation to determine a rate law

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k, rate constant

faster the reaction, the larger the k value

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shortcut for determining units of k is as follows

k = Lx/(molx*time)

value of x will be one less than the order of reaction


reaction 3rd order: k = L2/(mol2*time)

reaction 2nd order: k = L1/(mol1*time)

reaction 1st order: k = 1/time

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integrated rate law

  • expresses how the [ ] of the reactant depends on time

  • instead of changing initial [ ] and using multiple experiments, one experiment is done and [ ] changes over time are measured

  • looking for the linear relationship of how a single reactant changes over time

  • can only determine the exponent for one reactant at a time


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zero order integrated rate law

[A]t - [A]0 = -kt


graph of [A] versus time produces a straight line with slope -k

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first order integrated rate law

ln[A]t - ln[A]0 = -kt

ln(At/A0) = -kt


graph of ln[A] vs time produces a straight line with slope -k

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half life constant only in

only in 1st order reactions is half life independent of initial concentration (so it is constant for that reaction)

  • half life for 0 and 2nd order reaction depends on the initial concentration (so you would just use the full equation)


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half life (t1/2)

radioactive decay is first order. Half-life (t1/2) is the length of time required for the [ ] of a reactant to decrease to half of its initial value

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half life equation

t1/2 = 0.693/k

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fast reaction, short t1/2
short reaction, long t1/2

  1. LARGE k

  2. SMALL k


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second order integrated rate law

 1     -      1  = kt

[A]t       [A]0


graph of 1/[A] vs time produces a straight line with slope k

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HALF LIFE FORMULAS

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