Medical Physics: Specific Gravity & Pressure

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Vocabulary flashcards covering the concepts, definitions, formulas, and unit conversions of Specific Gravity and Pressure in Medical Physics.

20 Terms

1
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How is Specific Gravity (S.GS.G) defined?

It is the ratio of the density of a substance to the density of water at 4∘C4^\circ\text{C}.

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What is the density of water (ρw\rho_w) at 4∘C4^\circ\text{C} in both kg/m3kg/m^3 and g/cm3g/cm^3?

ρw=1000 kg/m3=1 g/cm3\rho_w = 1000\,kg/m^3 = 1\,g/cm^3

3
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Why is Specific Gravity (S.GS.G) a dimensionless quantity without units?

Because it is a ratio of two densities.

4
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What is the general formula for pressure (PP) in terms of perpendicular force (FF) and area (AA)?

P=FAP = \frac{F}{A}

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What is the formula for pressure (PP) when the acting force is the weight (W=mgW = mg) of an object?

P=mgAP = \frac{mg}{A}

6
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Is pressure classified as a vector quantity or a scalar quantity?

Scalar quantity.

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What is the formula for pressure when an inclined force FF acts at an angle θ\theta with the surface?

P=Fsin⁡(θ)AP = \frac{F\sin(\theta)}{A}

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What is the formula for the pressure exerted by an object of mass mm on a surface inclined at an angle θ\theta?

P=mgcos⁡(θ)AP = \frac{mg\cos(\theta)}{A}

9
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What happens to the pressure exerted on an inclined plane as the angle of inclination increases?

The pressure decreases.

10
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What is the equivalence between 1 Pa1\,Pa and dyn/cm2dyn/cm^2, and how does PaPa relate to Joules and cubic meters?

1 Pa=10 dyn/cm21\,Pa = 10\,dyn/cm^2, and Pa=Jm3Pa = \frac{J}{m^3}

11
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Specific Gravity (S.GS.G)

The dimensionless ratio of the density of a substance to the density of water at 4⊥∘C4^\bot\circ\text{C}, expressed as S.G=ρsubstanceρwaterS.G = \frac{\rho_{\text{substance}}}{\rho_{\text{water}}}.

12
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Density of Water at 4∘C4^\circ\text{C} (ρw\rho_w)

The standard reference density value for water, equal to 1000 kg/m31000\,kg/m^3 or 1 g/cm31\,g/cm^3.

13
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Pressure (PP)

A scalar physical quantity defined as the perpendicular force acting per unit area of a surface (P=FAP = \frac{F}{A}).

14
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Pascal (PaPa)

The SI unit of pressure, defined as one newton per square meter (1 Pa=1 N/m21\,Pa = 1\,N/m^2).

15
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Pressure Under Gravitational Force (PP)

The pressure calculated when the acting force is weight (F=W=mgF = W = mg), expressed as P=mgAP = \frac{mg}{A}, where g=9.8 m/s2g = 9.8\,m/s^2.

16
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Normal-Angle Inclined Force Pressure

The pressure produced when an applied force forms an angle θ\theta with the normal (perpendicular) to the surface: P=Fcos⁡(θ)AP = \frac{F\cos(\theta)}{A}, where F⊥=Fcos⁡(θ)F_\perp = F\cos(\theta).

17
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Surface-Angle Inclined Force Pressure

The pressure produced when an applied force forms an angle θ\theta with the surface itself: P=Fsin⁡(θ)AP = \frac{F\sin(\theta)}{A}, where F⊥=Fsin⁡(θ)F_\perp = F\sin(\theta).

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Pressure on an Inclined Surface

The pressure exerted by an object on a ramp inclined at angle θ\theta, given by P=mgcos⁡(θ)AP = \frac{mg\cos(\theta)}{A}; as the angle of inclination increases, the pressure decreases.

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Dyne per Square Centimeter Conversion (dyn/cm2dyn/cm^2)

A pressure unit conversion derived from 1 N=105 dyn1\,N = 10^5\,dyn and 1 m2=104 cm21\,m^2 = 10^4\,cm^2, resulting in 1 Pa=10 dyn/cm21\,Pa = 10\,dyn/cm^2.

20
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Energy Density Pressure Equivalent

An alternative expression showing that pressure is equivalent to energy per unit volume: 1 J/m3=1 (N⋅m)/m3=1 N/m2=1 Pa1\,J/m^3 = 1\,(N\cdot m)/m^3 = 1\,N/m^2 = 1\,Pa.