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What is the first ionisation energy of an element?
the energy required to remove one mole of its most loosely held electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions
Why does the first ionisation energy of atoms generally increase across a period
the nuclear charge increases but the shielding remains the same
Why is the first ionisation energy of boron (1s2 2s2 2p1) less than that of beryllium (1s2 2s2 )
B has one more proton in the nucleus than Be but there are also 2 extra inner sub-shell electrons. These cancel out the charge of two more of the protons, leaving an effective nuclear charge of only +1. This is less than Be (+2) so the electrons are less strongly attracted to the nucleus and thus less difficult to remove.
why do first ionisation energies decrease down a group?
the effective nuclear charge stays the same but the number of inner shells increases. The repulsion between these inner shells and the outer electrons makes them less stable, pushes them further from the nucleus and makes them easier to remove.
why does helium have the highest first ionization energy of all the elements?
its valence electrons are held extremely close to the nucleus with a strong positive charge and virtually no electron shielding
why is the successive ionisation energy of an atom always greater than the preceding one
As more electrons are removed from an atom, the number of electrons remaining in the atom decreases. The repulsion between these electrons therefore decreases, while the number of protons remains the same. The remaining electrons are thus more stable and increasingly difficult to remove.
why is the second ionisation energy of sodium much greater than the first
removing the second electron requires breaking into a stable, full octet shell
why does atomic size decrease across a period?
Atomic size decreases across a period because the number of protons increases while electrons are added to the same energy level, increasing effective nuclear charge and pulling electrons closer to the nucleus.
why does atomic size increase down a group?
Each successive element down a column has an extra occupied main energy level placing the valence electrons further away from the nucleus
The amount of energy required to remove an electron from an atom depends on what?
the number of protons in the nucleus of the atom and on the electronic configuration of that atom.

Explain the trends in this graph
lowkey need a essay
What is nuclear charge?
the number of protons in the nucleus
What is shielding?
the way inner-shell electrons block outer valence electrons from feeling the full positive pull of protons in the nucleus
what is effective nuclear charge?
the net positive charge experienced by an electron in a multi-electron atom
It is always less than the actual nuclear charge (Z) because inner-shell core electrons shield the outer electrons from the full pull of the positive protons
When considering trends in ionisation energies, which four factors should be considered?
nuclear charge
shielding
effective nuclear charge
electron repulsion
What is the formula for effective nuclear charge?
Zeff = Z - S
Z: atomic number
S: core electron count
Why does ionisation energy decrease from group || to group |||
in group III the electrons are removed from a p-orbital, so it is shielded by the s-electrons in the outer shell. Thus the effective nuclear charge decreases.
why do first ionisation energies decrease from group V to group VI
the electron removed from the group VI atom is paired, so there is more repulsion between the electrons and the electron is easier to remove.

What is second (successive) ionisation energy
The second ionisation energy is the minimum amount of energy required to remove one electron from each ion in one mole of gaseous 1+ ions, forming one mole of gaseous 2+ ions
M(g)+ —> M(g)2+ + e-
How can third ionisation energy be defined
The third ionization energy is the energy required to remove the third electron from a gaseous, an ion with a +2 charge to form a tripositive cation +3 charge
M(g)2+ —> M(g)3+ + e
How can the nth ionisation energy be defined
the energy required for the process;
M(g)(n-1)+ —> M(g)n+ + e