CHEMISTRY REACTIONS

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25 Terms

1
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elimination reactions are favored in what type of temperature

High

2
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addition reactions are favored, and what type of temperature

low

3
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<p>in Hydrohalogination, what are the reagent that could be used?</p>

in Hydrohalogination, what are the reagent that could be used?

hBr Hcl Hi

4
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<p>im hydrogination were will the regent move to</p><p>what if we recated it with ROOR?</p>

im hydrogination were will the regent move to

what if we recated it with ROOR?

the more subsitued end

when reacted with ROOR, it would go to the least substituted and making the anti-mark Konikoff

5
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<p>in hydrohalogination, if a new Chiral center is made, what is important to remember when predicting the product</p>

in hydrohalogination, if a new Chiral center is made, what is important to remember when predicting the product

you should have two products two sets of enatiomerz

6
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<p>for acid catalyst hydration, what reagent do you need? ALKANE</p>

for acid catalyst hydration, what reagent do you need? ALKANE

H30+

7
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<p>oxidationdemeruiratio what type of agent is needed? ALKANE</p><p>what does the mechanism look like?</p>

oxidationdemeruiratio what type of agent is needed? ALKANE

what does the mechanism look like?

HG(Oac)2 and H20

OH bond is added to the more substituted end of the double bond

<p>HG(Oac)2 and H20</p><p>OH bond is added to the more substituted end of the double bond</p>
8
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<p>IN HYBROBORATION OXIDATION WHAT TYPE OF REAGENT DO YOU NEED? ALKANE</p><p>In in this reaction, where does the agent go?</p>

IN HYBROBORATION OXIDATION WHAT TYPE OF REAGENT DO YOU NEED? ALKANE

In in this reaction, where does the agent go?

BH3THF

H2O2, NAOH


three agent is gonna go to the least substituted and in an anti-or Konikoff fashion however, it'll add on the syn addition

<p>BH3THF</p><p>H2O2, NAOH</p><p></p><p>three agent is gonna go to the least substituted and in an anti-or Konikoff fashion however, it'll add on the syn addition</p>
9
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in catalytic hydrogenation using

(PH3P)3RHCL WHAT CAN BE SAID ABOUT THE PRODUCT WHEN USING THIS SPECIFIC REGagent

The product is gonna be added in a syn fashion

10
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<p>for the following two reactions, explain what the products would look like for the second reaction Explain why the two reactions are different</p>

for the following two reactions, explain what the products would look like for the second reaction Explain why the two reactions are different

for the first reaction, the BR are going to be added in in a trans edition for the second one one BR is gonna be added to the least substituted end and in a Trans fashion with an OH bond on the more sub end

11
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what is the reagent needed to form an epoide?

give a brief description of what the product would look like

RCO3H

two OH BOMDS ADDED TRANZ

<p>RCO3H</p><p>two OH BOMDS ADDED TRANZ </p>
12
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<p>based on the reaction above, give a brief description of what the products would look like</p>

based on the reaction above, give a brief description of what the products would look like

removing a bond as we go and adding two X every time we remove a bond

<p>removing a bond as we go and adding two X every time we remove a bond</p>
13
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when doing HYDROHALGENATION OF ALKYNES why is BR special?

you can only get E OR Z using BR and these types of reactions

14
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<p>in <span>HAlOgenAtion of ALKYNES WHAT TYPE OF REAGENT DO YOU NEED</span></p><p><span>in what way does the reagent add onto the bonds?</span></p>

in HAlOgenAtion of ALKYNES WHAT TYPE OF REAGENT DO YOU NEED

in what way does the reagent add onto the bonds?

you can use BR or CL but the second step needs to be CCL

The agents are going to add in a TRANZ FASHION

15
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<p>IN ACID CATALYED HYDRATION OF ALKYLES </p><p>What type of reagent do you need?</p><p>what is the outcome of this?</p>

IN ACID CATALYED HYDRATION OF ALKYLES

What type of reagent do you need?

what is the outcome of this?

HGSO4 H2SO4 H20

u form ketone

<p>HGSO4 H2SO4 H20</p><p>u form  ketone</p>
16
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<p>IN BASE CATALYED HYDRATION OF ALKYLES</p><p>What type of reagent do you need?</p><p>what is the outcome of this?</p>

IN BASE CATALYED HYDRATION OF ALKYLES

What type of reagent do you need?

what is the outcome of this?

R2BH H2O2 NAOH

YOU'RE GONNA FORM AN ALDEHYDE IN A ANTIMARK FASHOON

<p>R2BH H2O2 NAOH</p><p>YOU'RE GONNA FORM AN ALDEHYDE IN A ANTIMARK FASHOON</p>
17
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<p>describe what the product would look like</p>

describe what the product would look like

knowt flashcard image
18
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<p>for dissolving metals in alkynesss what type of reagent do you need?</p>

for dissolving metals in alkynesss what type of reagent do you need?

NA NH3(l)

<p>NA NH3(l)</p>
19
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<p>based on the information given above, explain whether the acid is strong enough to protonate the base</p>

based on the information given above, explain whether the acid is strong enough to protonate the base

no, technically based on the information The PKA of the conjugate base is bigger than its acid MEANING THAT THE REACTION FAVORS THE REACTANTS MEANING THAT IT'S NOT STRONG ENOUGH

<p>no, technically based on the information The PKA of the conjugate base is bigger than its acid MEANING THAT THE REACTION FAVORS THE REACTANTS MEANING THAT IT'S NOT STRONG ENOUGH</p>
20
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When is a chemical reaction considered thermodynamically favorable?

When Gibbs Free Energy (\Delta G) is negative (\Delta G < 0).

21
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Why are alkene addition reactions generally favored at low temperatures?

Addition is exothermic (\Delta H < 0, favorable) but decreases entropy (\Delta S < 0, unfavorable because two molecules become one). At low temperatures, the enthalpy term dominates, making \Delta G negative.

22
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Why are elimination reactions favored at high temperatures?

Elimination increases entropy (\Delta S > 0, splitting one molecule into two). At high temperatures, the -T\Delta S term dominates and drives \Delta G negative.

23
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Is radical chlorination exothermic or endothermic, and is it selective or non-selective?

Strongly exothermic, with an early transition state. It has low selectivity and chlorinates positions almost randomly.

24
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Is radical bromination exothermic or endothermic, and is it selective or non-selective?


Back: Endothermic, with a late transition state. It has high selectivity and heavily favors forming the most stable radical (tertiary).

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How does the Hammond Postulate explain the difference in selectivity between chlorination and bromination?

Exothermic steps have early transition states that resemble reactants (low selectivity), while endothermic steps have late transition states that resemble radical products (high selectivity based on radical stability).