12.1 Vetors in the Plane (Wk 0+1)

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/12

encourage image

There's no tags or description

Looks like no tags are added yet.

13 Terms

1
New cards

Denote points on a line and in the plane, geometrically and algebraically. When is each view more useful?

  • Points on a line: use the real line.

    • Geometrically, a point PP sits at a coordinate such as 32\tfrac{3}{2}.

    • Algebraically, R={a:a real numbers}\mathbb{R}=\{a : a \text{ real numbers}\} (bold R in the textbook). A point has a coordinate, e.g. P=32P=\tfrac32.

    • P∈RP\in\mathbb{R} reads “PP in R\mathbb{R}”, i.e. “PP is an element/point in R\mathbb{R}”.

  • Points in the plane: use Cartesian (or rectangular) coordinates, i.e. the xy-plane.

    • Geometrically, a point has two coordinates, e.g. P=(1,2)P=(1,2).

    • Algebraically, R2={(a,b):a,b both real numbers}\mathbb{R}^2=\{(a,b): a,b \text{ both real numbers}\}.

    • P∈R2P\in\mathbb{R}^2 means “P=(a,b)P=(a,b) for some real numbers a,ba,b”, e.g. P=(1,2)∈R2P=(1,2)\in\mathbb{R}^2.

  • Takeaway: geometry is usually more intuitive, while algebra works better for computation.


2
New cards

Define a vector in the plane. Name its parts, its notation, and the formula for its length.

  • A vector in the plane has two points, PP and QQ.

    • PP is the initial point / tail / basepoint.

    • QQ is the terminal point / head / tip.

    • It is denoted PQ→\overrightarrow{PQ} or v⃗\vec v.

  • The length (magnitude) of v⃗\vec v is the distance from PP to QQ, written ∥PQ→∥\|\overrightarrow{PQ}\|.

  • Formula: if P=(a1,b1)P=(a_1,b_1) and Q=(a2,b2)Q=(a_2,b_2), then
    ∥v⃗∥=∥PQ→∥=(a2−a1)2+(b2−b1)2\|\vec v\|=\|\overrightarrow{PQ}\|=\sqrt{(a_2-a_1)^2+(b_2-b_1)^2}

  • Notes’ example: P=(−1,2)P=(-1,2), Q=(2,1)Q=(2,1), v⃗=PQ→\vec v=\overrightarrow{PQ}.


3
New cards

What is a position vector? How is it written, and what is the zero vector?

  • Special case: P=OP=O (the origin), so v⃗=OQ→\vec v=\overrightarrow{OQ}. A vector starting at OO is a position vector.

  • For Q=(a,b)∈R2Q=(a,b)\in\mathbb{R}^2, write OQ→=⟨a,b⟩\overrightarrow{OQ}=\langle a,b\rangle. Example: Q=(2,2)Q=(2,2).

  • If Q=OQ=O, then OO→=⟨0,0⟩\overrightarrow{OO}=\langle 0,0\rangle is denoted 0⃗\vec 0.

  • Notation pitfall: the letter OO is for the origin, and 0⃗\vec 0 is the number zero (as a vector).


4
New cards

Define parallel vectors and equivalent vectors. What is the key fact about vectors based at the origin?

  • Parallel: two vectors v⃗,w⃗\vec v,\vec w of non-zero length are parallel if the lines through them are parallel. Parallel vectors have either the same or opposite directions.

  • Equivalent: v⃗,w⃗\vec v,\vec w are equivalent if they have the same length and same direction. Then w⃗\vec w is a translation of v⃗\vec v.

  • ★ Key fact: every vector v⃗\vec v is equivalent to a unique vector based at the origin.


5
New cards

How do you compute the components of PQ→\overrightarrow{PQ}, and how is PQ→\overrightarrow{PQ} written?

  • If P=(a1,b1)P=(a_1,b_1) and Q=(a2,b2)Q=(a_2,b_2), then PQ→\overrightarrow{PQ} is equivalent to OR→=⟨a2−a1, b2−b1⟩\overrightarrow{OR}=\langle a_2-a_1,\,b_2-b_1\rangle.

  • a2−a1a_2-a_1 is the x-component and b2−b1b_2-b_1 is the y-component.

  • Notes’ example: P=(−1,2)P=(-1,2), Q=(1,1)Q=(1,1), R=(2,−1)R=(2,-1), so PQ→\overrightarrow{PQ} is equivalent to OR→\overrightarrow{OR}.

  • In most applications only length and direction matter, so components are sufficient.

  • ★ Writing rule: with a=a2−a1a=a_2-a_1 and b=b2−b1b=b_2-b_1,
    PQ→=⟨a,b⟩\overrightarrow{PQ}=\langle a,b\rangle


6
New cards

Define the negative, addition and subtraction of vectors, geometrically and algebraically.

  • Negative −v⃗-\vec v:

    • Geometric: same length as v⃗\vec v, opposite direction.

    • Algebraic: if v⃗=⟨a,b⟩\vec v=\langle a,b\rangle, then −v⃗=⟨−a,−b⟩-\vec v=\langle -a,-b\rangle.

  • Addition v⃗+w⃗\vec v+\vec w:

    • Geometric: move w⃗\vec w to w⃗′\vec w' so the tail of w⃗′\vec w' is the head of v⃗\vec v. The head of v⃗+w⃗\vec v+\vec w is the head of w⃗′\vec w'.

    • Example: if v⃗=PQ→\vec v=\overrightarrow{PQ} and w⃗=QR→\vec w=\overrightarrow{QR}, then v⃗+w⃗=PR→\vec v+\vec w=\overrightarrow{PR}.

    • Algebraic: if v⃗=⟨a,b⟩\vec v=\langle a,b\rangle and w⃗=⟨c,d⟩\vec w=\langle c,d\rangle, then v⃗+w⃗=⟨a+c, b+d⟩\vec v+\vec w=\langle a+c,\,b+d\rangle.

  • Subtraction:

    • Geometric: v⃗−w⃗=v⃗+(−w⃗)\vec v-\vec w=\vec v+(-\vec w).

    • Algebraic: v⃗−w⃗=⟨a−c, b−d⟩\vec v-\vec w=\langle a-c,\,b-d\rangle.


7
New cards

Define scalar multiplication and state the length formula and the direction rules.

  • For v⃗=⟨a,b⟩\vec v=\langle a,b\rangle and λ∈R\lambda\in\mathbb{R}: λv⃗=⟨λa,λb⟩\lambda\vec v=\langle\lambda a,\lambda b\rangle.

  • Geometrically, λv⃗\lambda\vec v is parallel to v⃗\vec v with length ∣λ∣ ∥v⃗∥|\lambda|\,\|\vec v\|.

    • If λ>0\lambda>0: same direction as v⃗\vec v.

    • If λ<0\lambda<0: opposite direction.

    • Notes’ examples: 2v⃗2\vec v and −3v⃗-3\vec v.

  • Length formula: ∥λv⃗∥=∣λ∣ ∥v⃗∥\|\lambda\vec v\|=|\lambda|\,\|\vec v\|.


8
New cards

State the basic properties (laws) of vector operations.

  • Commutative law: v⃗+w⃗=w⃗+v⃗\vec v+\vec w=\vec w+\vec v.

  • Associative law: u⃗+(v⃗+w⃗)=(u⃗+v⃗)+w⃗\vec u+(\vec v+\vec w)=(\vec u+\vec v)+\vec w.

  • Distributive law for scalars: λ(v⃗+w⃗)=λv⃗+λw⃗\lambda(\vec v+\vec w)=\lambda\vec v+\lambda\vec w.


9
New cards

What are i⃗\vec i and j⃗\vec j, and how do you write any plane vector as a linear combination of them?

  • i⃗=⟨1,0⟩\vec i=\langle1,0\rangle and j⃗=⟨0,1⟩\vec j=\langle0,1\rangle.

  • Any v⃗=⟨a,b⟩\vec v=\langle a,b\rangle satisfies
    v⃗=⟨a,0⟩+⟨0,b⟩=a⟨1,0⟩+b⟨0,1⟩=ai⃗+bj⃗\vec v=\langle a,0\rangle+\langle0,b\rangle=a\langle1,0\rangle+b\langle0,1\rangle=a\vec i+b\vec j

  • We say v⃗\vec v can be written as a linear combination of i⃗,j⃗\vec i,\vec j.


10
New cards

Define a general linear combination. When is every vector one, and why?

  • A linear combination of v⃗,w⃗\vec v,\vec w has the form rv⃗+sw⃗r\vec v+s\vec w for some r,s∈Rr,s\in\mathbb{R}.

  • Claim: if v⃗,w⃗\vec v,\vec w are both non-zero and not parallel, then any u⃗\vec u is a linear combination of v⃗,w⃗\vec v,\vec w.

  • Proof from the notes:

    1. Write v⃗=OP→\vec v=\overrightarrow{OP}, w⃗=OQ→\vec w=\overrightarrow{OQ}, u⃗=OR→\vec u=\overrightarrow{OR}.

    2. Draw a line through RR parallel to OQ→\overrightarrow{OQ}, meeting line OPOP at SS.

    3. Then OR→=OS→+SR→\overrightarrow{OR}=\overrightarrow{OS}+\overrightarrow{SR}, with OS→∥OP→\overrightarrow{OS}\parallel\overrightarrow{OP} and SR→∥OQ→\overrightarrow{SR}\parallel\overrightarrow{OQ}.

    4. So there are r,s∈Rr,s\in\mathbb{R} with OS→=rOP→\overrightarrow{OS}=r\overrightarrow{OP} and SR→=sOQ→\overrightarrow{SR}=s\overrightarrow{OQ}.

    5. Hence OR→=rOP→+sOQ→\overrightarrow{OR}=r\overrightarrow{OP}+s\overrightarrow{OQ}, i.e. u⃗=rv⃗+sw⃗\vec u=r\vec v+s\vec w.


11
New cards

What is a unit vector? Give its general form and the formula for the unit vector in the direction of v⃗\vec v.

  • A unit vector has length 1. Its endpoint is on the unit circle {(a,b):a2+b2=1}\{(a,b): a^2+b^2=1\}.

  • It has the form e⃗θ=⟨cos⁡θ,sin⁡θ⟩\vec e_\theta=\langle\cos\theta,\sin\theta\rangle.

  • For any non-zero v⃗\vec v, e⃗v\vec e_v is the vector with the same direction as v⃗\vec v and length 1:
    e⃗v=1∥v⃗∥ v⃗\vec e_v=\frac{1}{\|\vec v\|}\,\vec v


12
New cards

State the Triangle Inequality and its equality condition.

  • Theorem: for any two vectors v⃗,w⃗\vec v,\vec w,
    ∥v⃗+w⃗∥≤∥v⃗∥+∥w⃗∥\|\vec v+\vec w\|\le\|\vec v\|+\|\vec w\|

  • Equality holds only if v⃗=0⃗\vec v=\vec 0, or w⃗=0⃗\vec w=\vec 0, or w⃗=λv⃗\vec w=\lambda\vec v for λ>0\lambda>0.


13
New cards

Prove the Triangle Inequality, and explain every equality case.

  • Setup: write v⃗=PQ→\vec v=\overrightarrow{PQ} and w⃗=QR→\vec w=\overrightarrow{QR}, so v⃗+w⃗=PR→\vec v+\vec w=\overrightarrow{PR}. The formula becomes the distance inequality ∥PR→∥≤∥PQ→∥+∥QR→∥\|\overrightarrow{PR}\|\le\|\overrightarrow{PQ}\|+\|\overrightarrow{QR}\|.

  • If P,Q,RP,Q,R form a triangle: the inequality of triangles is strict, ∣PR∣<∣PQ∣+∣QR∣|PR|<|PQ|+|QR| (no equality).

  • If P,Q,RP,Q,R do not form a triangle, either two points are equal:

    • P=QP=Q: v⃗=0⃗\vec v=\vec 0, equality.

    • Q=RQ=R: w⃗=0⃗\vec w=\vec 0, equality.

    • P=RP=R: 0≤∣PQ∣+∣QP∣0\le|PQ|+|QP|, which is not an equality in general.

  • Or they lie on the same line: equality iff QQ is between PP and RR, i.e. ∣PR∣=∣PQ∣+∣QR∣|PR|=|PQ|+|QR|. Then v⃗,w⃗\vec v,\vec w are parallel with the same direction, so there is λ>0\lambda>0 with w⃗=λv⃗\vec w=\lambda\vec v.