Physics 3 Midterm 1 EquationsWrite the equation for Electric Force (magnitude-only form).

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15 Terms

1
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Electric Force equation


F = (1/4蟺系0) * (|q1q2|/r2)

<p></p><p>F = (1/4蟺系<sub>0</sub>) * (|q<sub>1</sub>q<sub>2</sub>|/r<sup>2</sup>)</p>
2
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Electric Force to Electric Field equation

F0 = q0E

<p>F<sub>0</sub> = q<sub>0</sub>E</p>
3
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Electric Field equation

E = (1/4蟺系0) * (|q|/r2)r虃

<p>E = (1/4蟺系<sub>0</sub>) * (|q|/r<sup>2</sup>)r虃</p>
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Torque on an electric dipole

饾湉 = p x E

<p>饾湉 = p x E</p>
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Work and the Potential Energy

Wa鈫抌 = -螖U

<p>W<sub>a鈫抌</sub> = -螖U</p>
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Electric Flux (over a closed surface area) to the net charge enclosed

桅E = 鈭瓻 dA = Qencl/系0

<p>桅<sub>E</sub> = 鈭瓻 dA = Q<sub>encl</sub>/系<sub>0</sub></p>
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Potential Energy between two charges and the distance between them

U = (1/4蟺系0) * qq0/r

<p>U = (1/4蟺系<sub>0</sub>) * qq<sub>0</sub>/r</p>
8
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Potential generated at a certain distance by a charge

V = (1/4蟺系0) * q/r

<p>V = (1/4蟺系<sub>0</sub>) * q/r</p>
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Difference in Potential, Electric Field, and line integral

Va - Vb = a鈭玝 E dl

<p>V<sub>a</sub> - V<sub>b</sub> = a鈭玝 E dl</p>
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General definition of Capacitance

C = Q/Vab

<p>C = Q/V<sub>ab</sub></p>
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Capacitance specifically for the parallel plate geometry

C =系0(A/d)

<p>C =系<sub>0</sub>(A/d)</p>
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Equation for energy contained in the electric field of a capacitor

U = Q2/2C = (1/2)CV2 = (1/2)QV

<p>U = Q<sup>2</sup>/2C = (1/2)CV<sup>2</sup> = (1/2)QV</p>
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Equation relating power, voltage, and current

P = VabI = I2R = Vab2/R

<p>P = V<sub>ab</sub>I = I<sup>2</sup>R = V<sub>ab</sub><sup>2</sup>/R</p>
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Kirchhoff鈥檚 rules

鈭慖 = 0 (Junction Rule)

鈭慥 = 0 (Loop Rule)

<p>鈭慖 = 0 (Junction Rule)</p><p>鈭慥 = 0 (Loop Rule)</p>
15
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Equation for charge as a function of time of an RC charging circuit

q = Qf(1 - e-t/RC)

<p>q = Q<sub>f</sub>(1 - e<sup>-t/RC</sup>)</p>