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Alkene + Br₂ or Cl₂ in an inert solvent: product?
Vicinal dihalide: one halogen on each former double-bond carbon. Anti addition. No rearrangements. Common solvents: CH₂Cl₂, CCl₄.
Alkene + Br₂/H₂O or Cl₂/H₂O: product?
Halohydrin: OH and halogen on adjacent carbons. OH favors the more substituted carbon; halogen goes on the other. Anti addition. No rearrangements.
Alkene + Br₂ in an alcohol solvent, ROH: product?
Add OR and Br across C=C. OR favors the more substituted carbon. Anti addition. The solvent acts as the nucleophile.
Alkene → Markovnikov alcohol without rearrangement: reagents?
1. Hg(OAc)₂, H₂O, THF 2. NaBH₄, NaOH. Called oxymercuration–reduction. OH goes on the more substituted carbon; H goes on the other.
What happens during oxymercuration, before NaBH₄?
Add OH and HgOAc across C=C. OH goes on the more substituted carbon. Typically anti addition, through a mercurinium ion.
What does NaBH₄ do in oxymercuration–reduction?
Sodium borohydride replaces C–HgOAc with C–H. OH stays attached. The overall sequence is not reliably syn or anti.
Alkene → anti-Markovnikov alcohol: reagents?
1. BH₃·THF 2. H₂O₂, NaOH. Called hydroboration–oxidation. OH goes on the less substituted carbon. Net syn addition of H/OH. No rearrangements.
Where do B and H attach during hydroboration?
B → less substituted carbon. H → more substituted carbon. They add syn, in one concerted step, without a carbocation.
What happens during oxidation of an organoborane?
H₂O₂/NaOH replaces C–B with C–OH, with retention of configuration. The H previously added to carbon stays there.
How many alkene molecules can one BH₃ react with?
Up to three, because BH₃ has three B–H bonds. This forms R₃B, a trialkylborane. Crowding can limit further additions
Alkene + 1. O₃ 2. DMS: product?
Reductive ozonolysis. Cut C=C and put C=O on each original double-bond carbon. A carbon originally bearing H gives an aldehyde; one bearing two carbon groups gives a ketone.
Ozonolysis with oxidative workup: what changes?
Use O₃ followed by H₂O₂/H₂O; your course also shows water workup generating peroxide. Aldehydes become carboxylic acids. Ketones remain ketones.
What happens when a cycloalkene undergoes ozonolysis?
Cut the ring at C=C and put C=O on both cut carbons. A ring containing one double bond usually opens into one molecule with two carbonyl groups.
Terminal alkyne R–C≡CH + HgSO₄, H₂SO₄, H₂O: product?
Markovnikov hydration → enol → methyl ketone: R–C(=O)–CH₃. Exception: acetylene, HC≡CH, gives ethanal.
Terminal alkyne + 1. bulky borane 2. H₂O₂, NaOH: product
Anti-Markovnikov hydration → enol → aldehyde: R–CH₂–CHO. Common bulky boranes: disiamylborane or 9-BBN.
Do internal alkynes give aldehydes after hydroboration–oxidation?
They give ketones. Unsymmetrical internal alkynes can give regioisomer mixtures; symmetrical ones give one constitutional carbonyl product
Why use a bulky borane for an alkyne?
To favor one addition and limit a second addition to the remaining double bond
How do I convert an enol into its carbonyl tautomer?
The OH-bearing carbon becomes C=O; the neighboring alkene carbon gains H; C=C becomes C–C. Keep the carbon skeleton connected.
Is enol → carbonyl conversion resonance?
No. It is tautomerization: proton transfers and bond changes produce a different constitutional isomer. Most simple examples favor the carbonyl form.
What is the key intermediate in halogenation/halohydrin formation?
A halonium ion, such as a bromonium ion. A nucleophile opens it from the opposite face, explaining anti addition.
What is the key intermediate in oxymercuration?
A mercurinium ion. There is no free carbocation, so ordinary hydride and alkyl shifts do not occur.
What is the difference between an inert solvent and a nucleophilic solvent?
An inert solvent mainly dissolves the reactants. A nucleophilic solvent, such as water or an alcohol, can attack the intermediate and become part of the product.
What does regioselective mean?
Preference for where groups attach. Example: OH favors one of the two former double-bond carbons.
What does stereospecific mean?
Different starting stereoisomers give different stereoisomeric products because of the reaction’s mechanism.
What do syn and anti describe?
The newly added groups: syn = same face; anti = opposite faces. Always identify which two groups you are comparing.