When is a function **continuous**? (==definition of continuity==)
1. f(a) is defined and a real # 2. *lim* f(x) \[as x→a-\] = *lim* f(x) \[as x→a+\] … therefore, *lim* f(x) \[as x→a\] **exists** 3. f(a) = *lim* f(x) \[as x→a\]
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==Intermediate Value Theorem (IVT)==
If our function f(x) is **continuous** on \[a,b\] (the interval), and K is in between f(a) and f(b), then there must be a c-value on (a,b) such that f(c)=K
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How do you solve ***infinite limits***?
i.e. *lim* f(x) \[as x→c\] = #/0
Determine if f(x) tends towards +/- ∞
* Find VA * Make a chart of x and f(x) * Plug in x-values leading up to **vertical asymptote** and see if f(x) increases or decreases
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How do you solve ***limits at infinity***?
i.e. *lim* f(x) \[as x→ +/- ∞\] = L (**horizontal asymptote**)
Find L, or the HA
* Try direct substitution FIRST * Convert each term of the fraction to (1/x) or a variation of it * Divide each term by the HIGHEST POWER that x is raised to in the *denominator* * When you have a radical, divide by highest power OUTSIDE radical
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==**Definition of a Derivative**== at ANY POINT
*lim* f(x+Δx)−f(x)/Δx \[as Δx→0\] = f’(x) … slope of tangent line
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==**Definition of a Derivative**== at x=c
*lim* f(x)−f(c)/(x−c) \[as x→c\] = f’(c) … slope of tangent line at x=c
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Equation of Tangent Line to f(x) at x=c
y - ∗∗f∗∗**(c)** = **f’(c)**⋅(x - ∗∗c∗∗)
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If a function is __differentiable__, does that mean it’s __continuous__?
YES
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If a function is __continuous__, does that mean it’s __differentiable__?
NO \~ think sharp turns/cusps
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What makes a function **NOT** differentiable?
1. Discontinuous 2. Sharp turns/cusps 3. Vertical tangent line, or VA
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Rule for **basic differentiation**
d/dx \[xⁿ\] = n⋅xⁿ⁻¹
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d/dx \[eˣ\] = ???
eˣ
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d/dx \[lnx\] = ???
1/x
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d/dx \[sinx\] = ???
cosx
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d/dx \[cosx\] = ???
\-sinx
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d/dx \[tanx\] = ???
sec²x
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d/dx \[cotx\] = ???
\-csc²x
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d/dx \[secx\] = ???
secxtanx
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d/dx \[cscx\] = ???
\-cscxcotx
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“Find the x-values at which f(x) has a **horizontal** tangent line”
SLOPE = 0
f’(x) = 0 … set derivative to 0 and find x
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***product rule***
d/dx \[f(x)g(x)\] = ???
f(x)g’(x) + g(x)f’(x)
1 d2 + 2 d1
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***quotient rule***
d/dx \[f(x)/g(x)\] = ???
(g(x)f’(x) - f(x)g’(x)) / (g(x))²
(low dhigh - high dlow) / (low)²
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***chain rule***
d/dx \[f(g(x))\] = ???
f’(g(x))⋅g’(x)
deriv of outer(leave inner)⋅deriv of inner
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ln(1) = ???
0
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ln(e) = ???
1
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ln(ab) = ???
lna + lnb
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ln(a/b) = ???
lna - lnb
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lnaⁿ
n⋅lna
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d/dx \[ln(u)\] = ???
u’/u
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d/dx \[eᵘ\] = ???
eᵘ⋅u’
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Position (==partical motion==)
s(t) = -16t² + Vot + So
Height above ground, water, etc (ft)
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Velocity (==partical motion==)
v(t) = s’(t) = -32t + Vo
Rate of change of __position__ over __time__ (ft/sec)
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Acceleration (==partical motion==)
a(t) = v’(t) = s”(t) = -32
Change in __velocity__ over __time__ (ft/sec²)
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Average Velocity (==particle motion==)
s(b)-s(a) / (b-a)
change in position / change in time
Δx / Δt
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Steps for ***implicit differentiation*** (w/ respect to x)
1. Always differentiate both sides with respect to x 2. Group all the dy/dx terms on 1 side, and everything else on the other side 3. Factor out dy/dx 4. Divide to solve for dy/dx
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What is a ***related rate***?
Rates of change of 2 or more variables at the same time.
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\ Steps to solve ***related rate*** problems?
1. Make a sketch (label variables & any length/quantity that is CONSTANT) 2. Write out what we __KNOW__ (given) and what we __WANT__ (asked to find) 3. Write an equation that relates all variables 4. Differentiate implicitly w/ respect to TIME 5. Substitute known values & solve for WANT (required rate of change) 6. Write a conclusion that puts the answer back in terms of the problem & includes the *what*, *when*, *how much*
1. The ___ is changing by ___ when ___
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Where are the only 2 places where ***absolute extrema*** can occur?
1. endpoints 2. critical points (f’(x)=0, und)
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How do you find ***Absolute Max/Min***?
==THE CANDIDATES TEST==!!!
* find critical points * find y-values at critical points AND end points * determine abs max/min
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==Mean Value Theorem (MVT)==
If a function is continuous AND differentiable on \[a,b\] (interval), then there must be some c-value on (a,b) such that f(b)-f(a) / (b-a) = f’(c).
\* IN OTHER WORDS: *slope of the secant* = *slope of the tangent*; *the average ROC* = *the instantaneous ROC*
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How do you find the **slope of a secant**, or the **average ROC**?
f(b)-f(a) / (b-a) = answer
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Relative Maximum
f’ is changing from + to -
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Relative Minimum
f’ is changing from - to +
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How do you find ***Relative Max/Min*** using the ==**1ST DERIVATIVES TEST**==?
1. Find critical points 2. Create a table w/ x-value intervals based on the critical points 3. Test values to see if f’ is + or - 4. Draw a conclusion w/ justification from the table
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Table Connecting f, f’, f”
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How do you find ***concavity intervals***?
\* Same process as ==1st Derivatives Test==!!! (only use f” instead, and determine if f is inc/dec)
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Point of Inflection (POI)
Where the graph of f changes concavity; where f” changes signs (+/-)
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How do you find ***Relative Max/Min*** using the ==**2ND DERIVATIVES TEST**==?
If f’(c)=0, and…
* f”(c)>0, then **REL MIN** at x=c (concave up) * f”(c)<0, then **REL MAX** at x=c (concave down)
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Rule for **basic integration**
∫xⁿ dx = (xⁿ⁺¹ / n+1) +c
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∫cosx dx = ???
sinx +c
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∫sinx dx = ???
\-cosx +c
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∫secxtanx dx = ???
secx +c
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∫cscxcotx dx = ???
\-cscx +c
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∫sec²x dx = ???
tanx +c
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∫csc²x dx = ???
\-cotx +c
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“Solve the differentiable equation”
Find f(x) with c as a #
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When finding area using **Riemann Sums**, how will we determine the height of each rectangle?
* Determined by the y-value of f(x) * Depends on if we’re using *right*, *left*, *midpoint*
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Formula for Riemann Sums using rectangles
A = b₁h₁ + b₂h₂ + …
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Formula for Riemann Sums using trapezoids
A = ½(b₁+b₂)h₁ + ½(b₂+b₃)h₂ + …
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Justification for **OVER/UNDER-ESTIMATE** w/ Riemann Sum rectangles
Because f(x) is inc/dec
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Justification for **OVER/UNDER-ESTIMATE** w/ Riemann Sum trapezoids
Because f(x) is concave up/down
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Trapezoidal Riemann *under-estimate*?
concave DOWN
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Trapezoidal Riemann *over-estimate*?
concave UP
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Integration units?
multiply
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Derivative units?
divide
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Average Value for Integrals
1/(b-a) ∫f(x) dx \[from a→b\]
\ \* what goes IN the integrand is what you are taking the average of!
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==Net Change Theorem==
F(b) = F(a) + ∫F’(x) dx \[from a→b\]
final amount = total change in amount from a to b
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==Fundamental Theorem of Calculus (FTC)==
∫f’(x) dx \[from a→b\] = f(b) - f(a)
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==2nd Fundamental Theorem of Calculus (2nd FTC)==
d/du ∫f(t) dx \[from a→u\] = f(u)⋅u’
\ \* taking the derivative of an integral
a=constant, u=function in terms of x
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Tips for finding “u” in **U-Substitutions**
1. Functions being raised to a power 2. Arguments of trig functions that aren’t just “x” or “θ” 3. Trig function whose derivative is also in integrand
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∫(1/x) dx = ???
ln|x| +c
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∫(1/u) du = ???
ln|u| +c
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Tips for success when **integrating natural log (ln)**
1. Use log properties to simplify 2. Most times, denom=u 3. Use __LONG DIVISION__ if degrees are equal OR num>denom 4. If num<denom, use regular u-sub
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∫eᵘ du = ???
eᵘ +c
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How do you find inverses?
Switch x & y, then solve for y
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Rule for **derivative of an inverse**
g’(x) = ???
1 / (f’(g(x))
x = x-value of inverse, y-value of original
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y = aᵘ
y’ = ???
(lna)⋅aᵘ⋅u’
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y=logₐu
u’ / (lna)u
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Steps for ==**Natural Log Differentiation**==
\* with y=au, use when both a and u are __FUNCTIONS__ (have x-variable)
1. Take natural log of both sides 2. Simplify w/ log properties 3. Take derivative of both sides w/ respect to x 4. Multiply both sides by “y”
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∫aᵘ du = ???
aᵘ / (lna) +c
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d/dx \[arcsinu\] = ???
u’ / √1-u²
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d/dx \[arctanu\] = ???
u’ / 1+u²
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d/dx \[arcsecu\] = ???
u’ / |u|⋅√u²-1
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d/dx \[arccosu\] = ???
\-u’ / √1-u²
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d/dx \[arccotu\] = ???
\-u’ / 1+u²
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d/dx \[arccscu\] = ???
\-u’ / |u|⋅√u²-1
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∫du / √a²-u² = ???
arcsin(u/a) +c
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∫du / a²+u² = ???
(1/a)arctan(u/a) +c
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∫du / u⋅√u²-a² = ???
(1/a)arcsec(|u|/a) +c
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Tips to **Integrate Inverse Trig**
1. Multiply by equivalent form of 1 2. Separate into 2 fractions 3. If you have (constant/polynomial), COMPLETE THE SQUARE! 4. Add and subtract the same quantity
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How to solve differential equations using **Separation of Variables**
\*must have product or quotient of x and y
1. Rewrite equation to get just dy & y on one side, and just dx & x on the other 2. Integrate both sides 3. Plug in the initial condition (a,b) to get your +c value 4. Then solve for y