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I=∫mI2dm [kg*m²]
I=IG+md2 [kg*m²]
k=mI
ΣFx=m(aG)x
ΣFy=m(aG)y
ΣMG=0
ΣFn=m(aG)n
ΣFt=m(aG)t
ΣMG=0
ΣFn=m(aG)n=mω2rG
ΣFt=m(aG)t=mαrG
ΣMG=IGα
ΣFn=m(aG)n
ΣFt=m(aG)t
ΣMG=IGα
T=21mvG2+21IGω2; the kinetic energy is equal to the sum of translational and rotational kinetic energy.
UF=∫FcosθdS
UF=(Fccosθ)ΔS
UW=−WΔy
US=−(21ks22−21ks12)
W=M⋅θ; the work done is the energy transferred when the couple moment causes an object to rotate.
T1+ΣU1−2=T2
T1+V1=T2+V2
Planar bodies include translational and kinetic energy, and work can be done by torques (moments), while particles only include translational kinetic energy.
HG=IGω ; HG=r×p ; [kg*m²']
General plane motion combines both linear momentum p=mvG, measures translational motion, and angular momentum HG=IGω, measures rotational motion.
ΣMO=HO˙
1-D: Σ∫Mdt=Iω2−Iω1
2-D: Σ∫MOdt=(HO)2−(HO)1
Σ(HO)1=Σ(HO)2; from t1 to t2 the particles angular momentum stays constant.
Interpret equations Hp=−yˉm(vG)x+xm(vG)y+IGω; ΣMp=−yˉm(aG)x+xm(aG)y+IGα. What's the relationship between Hp and ΣMp?
ΣMp=Hp˙; aG=vG˙, α=ω˙