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how to find critical points
take partial derivatves solve for zero, crit points satisfy both equations
max min saddle
max:fxx<0
min;fxx>0
saddle:D<0
D=fxx*fyy-(fxy)2
linearization of f(x,y) from (x,y) to(x1,y1)
f(x,y)+fx(x,y)(x1-x)+fy(x,y)(y1-y)
freshen up on lambda
please bc you know its going to be worth like 20%
tangent plane
take partial derivateves, plug in the point(abc) for slope of each section
fx(x-a)+fy(y-b)+fz(z-c)=0
level set
2d splices of a 3d surface, check points and what theyre supost to equal, prob eaisest if you set one too zero
drawing rotational symetry
draw the plane with a loopy arrow around the axis of symmetry
make parametric
f(x,y,z)=r(u,v)
isolate a varible and set the others to u and v then plug in the restulting equation the that varibles portion of the vector equation
Duhatf(x,y)
dot product of the gradient of f(x,y) and uhat
uhat dot the gradient will be greatest when uhat points
in the same direction as the gradient
chainrule
same,
dxof the outside with the inside plugged in * dx of the inside