Equation of a straight line

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Last updated 5:17 PM on 6/7/26

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4 Terms

1

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Formula

y-b=m(x-a)

2

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(4, 1) (11, 20)

m=y2-y1/x2-x1

-20–1/11-4

-21/7 =-3

y-b=m(x-a)

m=-3 point (4,1)

y-1=-3(x-4)

y-1=-3x+12

y=-3x+13

3

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Find the midpoint of the points (-5, 11) and (-12,15)

(-12x+x/2 , 15+y/2) = (-5, 11)

-12+x/2 = -5 and 15+y/2 = 11

x=2 and y=7

(2,7)

4

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Method I’ve forgot the name of (-1, -1) (3, 2)

_/x_2-x₁)²+(y₂-y₁)²

_/((3-(-1))²+(2-(-1))²

_/4²+3²

_/16+9

=_/25

=5