Exam 2 Definitions and Theorems

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/77

encourage image

There's no tags or description

Looks like no tags are added yet.

78 Terms

1
New cards

R is a

Complete Archimedean ordered field

2
New cards

Field axioms

For additive and multiplicative, closure, commutativity, associativity, identity, and inverse & the distributive law

3
New cards

Order axioms

For all x, y, z \in R exactly one of the following holdv x=y, x<y, x>y; if x<y, y<z, then x<z; if x<y, then x+z<y+z; if x<y & z>0, then xz<yz

4
New cards

What other set is an ordered field?

Rational numbers

5
New cards

Theorem about relations of x, y, epsilon

Let x, y \in R s.t. \forall \epsilon > 0 in R, x<=y+\epsilon, then x<=y

6
New cards

Theorem about absolute value

Let x, y \in R, a>=0\in R. Then, |x|>=0, |x|<=a \iff -a<=x<=a, |xy|=|x||y|, |x+y|<=|x|+|y|

7
New cards

Triangle Inequality

\forall a,b,c\in R |a-c|<=|a-b|+|b-c|

8
New cards

Upper Bound for S\subset R

m s.t. m>=s \forall s\in S

9
New cards

Bounded Above set S

An upper bound exists for the set S

10
New cards

Lower Bound for S\subset R

m s.t. m<=s \forall s\in S

11
New cards

Bounded Below set S

An lower bound exists for the set S

12
New cards

Bounded set

A set that is bounded above and below

13
New cards

Maximum of S

An upper bound m\in S

14
New cards

Minimum of S

A lower bound m\in S

15
New cards

Supremum of S

(S\subset R and S is non-empty) The least upper bound of S if S is bounded above m=sup(s) \iff \forall s\in S, m>=s and if m>m’, then \exists s’\in S s.t. s’>m’

16
New cards

Infimum of S

(S\subset R and S is non-empty) The greatest lower bound of S if S is bounded above m=sup(s) \iff \forall s\in S, m<=s and if m’>m, then \exists s’\in S s.t. s’<m’

17
New cards

Complete Axiom

Every non-empty subset S of R that is bounded above has a least upper bound in R

18
New cards

What differentiates Q from R?

Q does not have the complete axiom

19
New cards

Theorem about sets of sums

Let A, B\subset R and define C={a+b:a\in A, b\in B}. If A and B have suprema, C has a supremum and sup(C)=sup(A)+sup(B)

20
New cards

Archimedean Property

N is unbounded in R

21
New cards

Equivalent statements to the Archimedean Property

For each z\in R, \exists n\in N s.t. n>z; for each x>0 and each y\in R, \exists n\in N s.t. n*x>y; for each x>0 in R \exists n\in N s.t. 0<1/n<x

22
New cards

Density of Q in R

If x, y\in R with x<y, then \exists r\in Q s.t. x<r<y

23
New cards

Lemma for the density of irrational numbers

If x≠0 is rational and y is irrational, then xy is irrational.

24
New cards

Theorem about irrational numbers

For x, y\in R, where x<y, then \exists irrational number w s.t. x<w<y

25
New cards

Sequence

A function whose domain is N (S: N→R)

26
New cards

A series (sn) converges to s if…

\forall \epsilon > 0, \exists m\in N s.t. \forall n>= m, |sn-s| < \epsilon

27
New cards

Limit of (sn)

s, where sn converges to s

28
New cards

Divergent sequence

A sequence that doesn’t converge to a real number

29
New cards

Bounded sequences (sn)

The set {sn:n\inN} is bounded (think (sn) can be put in an interval)

30
New cards

Theorem about bounded sequences

Every convergent sequence is bounded

31
New cards

Theorem about limits

If a sequence converges, then its limit is unique.

32
New cards

Theorem about algebraic relations

Spp (sn), (tn) convergent seq w/ sn→s and tn→t. Then, lim(sn+tn)=s+t, lim(ksn)=ks, lim(k+sn)=k+s \forall k\in R, lim(sntn)=st, lim(sn/tn)=s/t, provided tn, t≠0

33
New cards

Theorem on comparison of sequences

Spp (sn), (tn) convergent seq. w/ sn→s, tn→t. If sn<=tn \forall n, then s<=t

34
New cards

Corollary to comparison of series

(tn) convergent seq, tn→t w/ tn>=0, then tn>=0

35
New cards

Ratio test

For (sn) seq., sn>0 and (s(n+1)/sn)→L, if L<1, then sn→0

36
New cards

(sn) diverges to +\infty

\forall M\in R, \exists N \in N s.t. \forall n>=N, sn>M

37
New cards

Thm on divergent series

For (sn) seq. >0, lim sn=+\infty iff lim(1/sn)=0

38
New cards

(sn) is increasing

sn<=s(n+1) \forall n\in N

39
New cards

(sn) is decreasing

sn>=s(n+1) \forall n\in N

40
New cards

(sn) is monotone

It is increasing or decreasing

41
New cards

Monotone Convergence Theorem

A monotone sequence is convergent iff it is bounded

42
New cards

A seq. is Cauchy

if \forall \epsilon >0, \exists N\inN s.t. \forall m,n>=N, |sm-sn|<\epsilon

43
New cards

Theorem about Cauchy

A sequence is convergent iff it is Cauchy

44
New cards

Lemma about Cauchy

Every Cauchy sequence is bounded

45
New cards

Theorem connecting Cauchy to real numbers

The following are equivalent: The completeness axiom holds for R and every Cauchy sequence is convergent

46
New cards

Definition of the real numbers

Limits of Cauchy sequences of rational numbers

47
New cards

Lemmas on comparison of sup and inf

For non-empty A\in R that is bounded, infA<=supA. For B\subset A, supB<=supA and infB>=infA

48
New cards

Defn of limsup(xn)

lim(yn)=lim(n→\infty){sup{xk:k>=n}}

49
New cards

Corollary on limsup/liminf

liminf(xn)<=limsup(xn)

50
New cards

Theorem on convergence and limsup/liminf

(xn)→x \iff limsup(xn)=liminf(xn)=x

51
New cards

Theorem between convergence and Cauchy

A sequence of real numbers converges iff it is Cauchy

52
New cards

Theorem between Completeness Axiom and Cauchy

If every Cauchy sequence converges, Completeness Axiom holds

53
New cards

Lemma on non-unique decimal expansion

0.999..=1

54
New cards

Corollary on uniqueness of decimal expansions

If we forbid decimal expansions with all 9s, then decimal/Cauchy sequence expansions are unique

55
New cards

Theorem about the real numbers

The real numbers are uncountable

56
New cards

Definition of topology

Adding a structure of place/location to sets

57
New cards

Definition of neighborhood/\epsilon-neighborhood of x

Set of the form N(x, \epsilon):={y\in R: |x-y|<\epsilon} where x, \epsilon \in R and \epsilon>0

58
New cards

Radius of N(x, \epsilon)

\epsilon

59
New cards

Deleted \epsilon-neighborhood of x

N*(x, \epsilon):={y\in R: 0<|x-y|<\epsilon} (equivalent to N(x, \epsilon)\{x})

60
New cards

Interior Point of S\subset R

A point x\in R if \exists a nghd N of x s.t. N\subset S

61
New cards

Boundary Point of S\subset R

A point x\in R s.t. \forall nghd N of x, we have NnS ≠ \emptyset and Nn(R\S) ≠ \emptyset

62
New cards

Interior of S

The set of all interior points of S (int(S))

63
New cards

Boundary of S

The set of all boundary points of S (bd(S))

64
New cards

Lemma on interior/boundary points

Every point of S is either an interior point or boundary point

65
New cards

A set S\in R is open if:

One of the following, equivalent statements is true: int(S)=S; every point is an interior point; \forall x\in S, \exists \epsilon>0 s.t. N(x, \epsilon)\subset S

66
New cards

A set S\in R is closed if:

(R\S) is open

67
New cards

Lemma about open/closed sets

These traits are not mutually exclusive - a set can be neither open nor closed

68
New cards

Theorem about open sets

The union of any collection of open sets is open and the intersection of finitely many open sets is open

69
New cards

Corollary on closed sets

The intersection of any collection of closed sets is closed and the union of finitely many closed sets is closed

70
New cards

Accumulation Point of S

A point x\inR s.t. every deleted nghd of x contains a point in S

71
New cards

S’

The set of accumulation points of S

72
New cards

Isolated Point of S

x\inS and x\inS’

73
New cards

Closure of S\inR

SuS’ (denoted cl(S))

74
New cards

Theorem about closed sets

S closed iff S contains all accumulation points; cl(S) is closed; S closed iff S=cl(S); cl(S)=Su bd(S)

75
New cards

Open Cover of S\subsetR

Collection of open sets {U_i}_i\inI where Ui is open for every index i\inI s.t. S\subset\cup_i\inIU_i

76
New cards

The open cover {U_i} admits a finite subcover if

\exists some N\in\mathbb{N} s.t. S\subset\cup_i=1^N U_i

77
New cards

Compact set S\subset R

Every open cover of S admits a finite sub-cover

78
New cards

Theorem about compact sets

Compact iff bounded and closed