nucleophilic substitution and elimination reactions (copy)

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20 Terms

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2 most common reactions in ochem

substitution: nucleophile attacks an α carbon to trade place with a halogen

elimination: a base attacks a β proton to form a double bond

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what do nucleophiles and bases have in common?

they both have at least one pair of electrons

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2 reasons why alkyl halides undergo substitution and elimination reactions

  1. the halogen creates a partial positive on the alpha carbon, making it susceptible to a nuc. attack

  2. the halogen is a good leaving group


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what makes a halogen a good leaving group

pKa< 0

conjugate bases of strong acids

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α vs β carbon

α carbon: the carbon connected to the halogen/substituent

β carbon: the carbon connected to the α carbon

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primary, secondary, and tertiary alkyl halides

primary 1o: 1 β carbon attached to an α carbon

secondary 2o: 2 β carbons attached to an α carbon

tertiary 3o: 3 β carbons attached to an α carbon

<p><strong>primary 1<sup>o</sup></strong>: 1 β carbon attached to an α carbon</p><p><strong>secondary 2<sup>o</sup></strong>: 2 β carbons attached to an α carbon</p><p><strong>tertiary 3<sup>o</sup></strong>: 3 β carbons attached to an α carbon</p>
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S reactions

SN1: S: substitution, N: nucleophilic, 1: unimolecular (1st order)

  • stepwise: (1) loss of a leaving group, (2) nucleophilic attack at α carbon

  • Rate = k[substrate]

  • does not require backside attack resulting in racemization


SN2: S: substitution, N: nucleophilic, 2: bimolecular (2nd order)

  • concerted: loss of the leaving group and nucleophilic attack happen at the same time

  • Rate = k[substrate][nucleophile]

  • aprotic solvent preferred

  • requires backside attack resulting in inversion of configuration


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why do nucleophiles attack from the back in SN2 reactions?

steric hinderance: electron density repels the nuc from the front side

SN2 prefers 1o because a lack of steric hinderance from β carbons

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what factors make a strong nucleophile

polarizability, charge, and solvent

anions are strong nucleophiles

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E reactions

E1: E: elimination, 1: 1st order

  • Rate = k[base]

  • stepwise: (1) loss of a leaving group, (2) nucleophilic attack at β proton

  • does not require backside attack


E2: E: elimination, 2: 2nd order

  • Rate = k[alkyl halide][base]

  • concerted: loss of the leaving group and nucleophilic attack happen at the same time

  • protic solvent preferred

  • requires backside attack


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how E and Z are related to cis and trans structures

(Z) cis

(E) trans

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how do alkyl groups stabilize pi carbon bonds

via hyperconjugation

mono-substituted (least stable): a pi bond with 1 substituent

di-substituted: a pi bond with 2 substituents

tri-substituted: a pi bond with 3 substituents

tetra-substituted (most stable): a pi bond with 4 substituents

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weak base

weak nucleophile

3o: SN1 and E1

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weak base

strong nucleophile

1o: Sn2

2o: Sn2

3o: Sn1

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strong base

strong nucleophile

1o: Sn2 (E2 minor)

2o: E2 (Sn2 minor)
3o: E2

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strong base

weak nucleophile

1o: E2

2o: E2
3o: E2

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NaH, DBN, DBU, t-BuO-

strong base

non nucleophilic

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HO-, MeO-, EtO-

strong base

strong nucleophile

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I-, Br-, Cl-, RS-, HS-, RSH, H2S

weak base

strong nucleophile

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H2O, MeOH, EtOH

weak base

weak nucleophile