D.2 Electrical Fields

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Last updated 7:47 AM on 9/29/26
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15 Terms

1
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What is the elementary charge?

The magnitude of charge of a proton or electron.

  • 1e = 1.6×10-19C


2
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Conservation of charge

(Net) Charge cannot be created or destroyed and can only be transferred.

3
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Coloumb’s Law

The force of attraction or repulsion between two charges is proportional to each charge and inversely proportional to distance between their centres squared.

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Force of attraction or repulsion formula

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What does permittivity (ε₀) refer to?

The ability of a substance to store electrical energy in an electric field.


6
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What is an electrical field, what do the arrows and density of the field lines show?

  • An electrical field is a region where a charge experiences a force.

  • The arrows show the direction of the force on a positive test charge.

  • The density of the field lines indicates the relative strength of the field.


<ul><li><p>An electrical field is a region where a charge experiences a force.</p></li><li><p>The arrows show the direction of the force on a positive test charge.</p></li><li><p>The density of the field lines indicates the relative strength of the field.</p></li></ul><p></p>
7
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What is electric field strength and its formula?

The force per unit charge acting a positive test charge at that point in the field.

<p>The force per unit charge acting a positive test charge at that point in the field.</p>
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Alternative Electric field strength formula

  • It is positive in value when repelling and negative in value when attractive.


<ul><li><p>It is positive in value when repelling and negative in value when attractive.</p></li></ul><p></p>
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Predict the graph of E (Electric Field strength) against r



<p></p><p></p>
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<p>Why is the electric field inside a conducting sphere 0?</p>

Why is the electric field inside a conducting sphere 0?

As electric fields from many far charges on the right cancel those from few close charges on the left.

<p>As electric fields from many far charges on the right cancel those from few close charges on the left.</p>
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<p>What would the field look like between parallel charged plates?</p>

What would the field look like between parallel charged plates?

  • The field lines will be parallel and equally spaced in the middle (uniform field)

  • There will be ‘edge effects’ as they bulge out near the sides of the plate


<ul><li><p>The field lines will be parallel and equally spaced in the middle (uniform field)</p></li><li><p>There will be ‘edge effects’ as they bulge out near the sides of the plate</p></li></ul><p></p>
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Uniform Electrical field strength between two parallel plates formula

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Milkan’s Oil drop Experiment setup

  • There were two parallel plates set at a specific distance from each other with a known adjustable voltage between them creating an electric field with a known magnitude and direction.

  • He drilled a very small hole in the centre into the top plate. A fine mist of oil is sprayed into a chamber above the two plates, the drops pass into a region between two metal plates and are viewed using a microscope.


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Milkan’s Oil drop Experiment Steps 1-4

Step 1:

  • A fine mist of oil is sprayed into a chamber above the plates:

    • Oil is used instead of water as it doesn’t evaporate quickly. Which means the mass of the drop remains constant.

  • As the drop passes through the spray nozzle they are charged by friction they can also be ionised by X-rays. Some drops lose electrons and become and vice versa.

Step 2:

  • When no voltage was applied the drop fall at terminal velocity

  • Since air is much less dense than oil the buoyancy force becomes negligible.

    • The viscous drag is balancing the weight force

    • 6πηrv = mg = (ρV)g , 6πηrv = ρ(4/3πr3)g , v = 2ρr2g/9η , r = √(9ηv/2ρg )

Step 3:

  • With the radius now known the mass of the drop could be calculated

    • m = ρ(4/3πr3)

Step 4:

  • When the correct voltage is applied the drop hovers.

    • Electrostatic force is balancing the weight force

    • F = Eq = (V / d)q  , F= mg , (V / d)q = mg , q =mgd / V




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Milkan’s Oil drop Experiment conclusions

By comparing the charges for each oil drop to the smallest charge he discovered he deduced they were all multiples of 1.6 × 10-19C.