Math 521 Midterm 2

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Last updated 12:49 PM on 10/9/26
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39 Terms

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sequence convergence

xn converges to x∈R if ∀ε>0, ∃N∈N s.t. n≥N |xn-x|<ε

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showing that xn converges to x; ex- show 1/n converges to 0

|(1/n)-0|=1/n; as n≥N, (1/n)≤(1/N)<ε. Proof: Let ε>0. By AP ∃N∈N s.t. N>(1/ε) aka (1/N)<ε. Let n≥N, then |(1/n)-0|=(1/n)≤(1/N)<ε. Thus 1/n converges to 0

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sequence bounded

a sequence xn is bdd iff ∃M>0 s.t. ∀n∈N, |xn|≤M

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Algebraic Limit Theorem

suppose xn and yn are sequences s.t. xn→x and yn→y. (xn+yn)→(x+y); ∀c∈R, cxn→cx; xnyn→xy; if xn≠0 ∀n∈N and x≠0 then (1/xn)=(1/x)

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order limit theorem

if xn≥yn ∀n∈N and xn→x and yn→y then x≥y

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squeeze theorem

let xn, yn and zn be sequences. suppose ∃N0∈N s.t. n≥N0 and xn≤yn≤zn and xn→w and zn→w then yn→w

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binomial theorem

(1+x)n=1 + nx + (nx2(n-1))/2! + (nx3(n-1)(n-2))/3! + …

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bernoulli inequality

(1+x)n≥(1+nx)

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theorem with |b|

if |b|<1 then bn→0

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abs value sequence convergence

|an|→0 iff an→0

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monotone sequence

xn is monotone if xn≤xn+1 or xn+1≤xn

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monotone convergence theorem

let xn be a monotone sequence of real numbers. xn converges iff xn is bounded

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subsequence def

if xn is a sequence and nk is a strictly increasing sequence of natural numbers, then xnk is a subsequence of xn

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well-ordering property of N

if n1<n2<n3<… is a strictly increasing sequence of natural numbers then ∀k∈N, nk≥k

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convergence and subsequence theorem

if xn→x then every subsequence xnk→x

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cauchy

A sequence xn is cauchy if ∀ε>0 ∃N∈N s.t. ∀n,m ≥ N, |xn-xm|<ε

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open neighborhood

Let a∈R and ε>0. The set Vε(a)={x∈R : |x-a|<ε}=(a-ε,a+ε) is an open neighborhood of a of radius ε

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limit point (neighborhood)

x∈R is a limit point of set E if ∀ε>0 ∃q∈E q≠x s.t. q∈Vε(x) (AKA |q-x|<ε)

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limit point (sequence)

x is a limit point of set E IFF ∃xn with xn∈(E\{x}) ∀n s.t. xn→x

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isolated point def

if p∈E and p is not a limit point of E, then p is an isolated point

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closed set

a set E is closed if every limit point of E is an element of E

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interior point

p is an interior point of E if ∃ε>0 s.t. Vε(p)⊆E

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open set

a set E is open if every point in E is an interior point

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complement open/closed

E is open IFF Ec is closed; F is closed IFF Fc is open

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{Ga} open sets

U(Ga) is open

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{Fa} closed sets

∩(Fa) is closed

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G1…GN

if G1…GN are open then ∩(Gj) is open (j=1 to N)

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F1…FN

if F1…FN are closed then U(Fj) is closed (j=1 to N)

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E closure is

E U E’ = E union (set of limit points of E)

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in E closure, theorem

p∈Eclosure IFF ∃xn of elements in E s.t. xn→p

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theorem, let E⊆R (closure stuff)

Eclosure is closed; E=Eclosure IFF E is closed; if F is closed and E⊆F then Eclosure⊆F; hold for all E⊆R, no need to prove one of them first

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open AND closed sets

E is open and closed IFF E=∅ or E=R

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open cover of E

a collection of open sets {Ga} s.t. E⊆U(Ga)

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compact def

a set K is compact if every open cover of K has a finite subcover; If {Ga} is an open cover of K, then then ∃a1,a2,…aN s.t. K⊆U(Gaj) (j=1 to N)

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Let E⊆R, the following are equivalent (compactness stuff)

E is compact; E is closed and bounded; Every infinite subset of E has a limit point in E; Every sequence in E has a subsequence that converges to an element in E; one of the statements must hold and then the rest hold

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closed subsets of compact sets theorem

closed subsets of compact sets are compact

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Bolanzo-Weierstrass Theorem

if xn is a bounded sequence then it has a convergent subsequence

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Cauchy criterion / Completeness of R

xn converges IFF xn is a cauchy sequence