CHM261 Exam 2 Study Guide: Solutions, Redox, and Quantum Mechanics

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/29

flashcard set

Earn XP

Description and Tags

Comprehensive practice flashcards for CHM261 Exam 2 covering solution chemistry, net ionic reactions, titration stoichiometry, redox numbers and activity series, and quantum mechanics.

30 Terms

1
New cards

What is the key difference between an empirical formula and a molecular formula?

An empirical formula is the simplest, lowest whole-number mathematical ratio of atoms present in a compound (such as CH2O\text{CH}_2\text{O}), whereas a molecular formula gives the actual number of atoms of each element in a single molecule of a compound (such as C6H12O6\text{C}_6\text{H}_{12}\text{O}_6) and is always a whole-number multiple of the empirical formula.

2
New cards

Why is C5H10O5\text{C}_5\text{H}_{10}\text{O}_5 classified as a molecular formula rather than an empirical formula?

Because its subscripts share a common factor of 55 and can be mathematically reduced down to the simpler whole-number ratio CH2O\text{CH}_2\text{O}. An empirical formula cannot be reduced any further.

3
New cards

What are the two primary analytical functions of mass spectrometry mentioned in the study guide?

It is used to determine the precise molecular weights of compounds and to measure the relative natural abundances of isotopes.

4
New cards

In combustion analysis, how are the quantities of carbon and hydrogen determined?

All carbon is converted to CO2\text{CO}_2, where the mass gained by the CO2\text{CO}_2 trap isolates the exact amount of carbon. All hydrogen is converted to H2O\text{H}_2\text{O}, where the mass gained by the water trap yields the hydrogen content.

5
New cards

Why can oxygen content not be measured directly via combustion analysis, and how is its mass determined?

Oxygen cannot be measured directly because oxygen gas is continuously supplied from an external source to burn the sample. Its mass must be calculated by subtracting the masses of carbon and hydrogen from the original sample mass.

6
New cards

How do unsaturated, saturated, and supersaturated solutions differ in solute capacity?

An unsaturated solution can dissolve additional solute; a saturated solution contains the maximum possible amount of dissolved solute at dynamic equilibrium at a specific temperature; and a supersaturated solution has been heated to force extra solute to dissolve beyond saturation.

7
New cards

How is molarity (MM) defined, and what is its formula?

Molarity is defined as the moles of solute per liter of total solution: M=Moles of soluteVolume of solution in litersM = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}}

8
New cards

How many grams of sodium nitrate (NaNO3\text{NaNO}_3, molar mass = 84.99 g/mol84.99\,\text{g/mol}) are needed to prepare 500 mL500\,\text{mL} of a 0.250 M0.250\,\text{M} solution?

10.62 g10.62\,\text{g}. Step 1: Convert volume: 500 mL×1 L1000 mL=0.500 L500\,\text{mL} \times \frac{1\,\text{L}}{1000\,\text{mL}} = 0.500\,\text{L}. Step 2: Calculate moles: Moles=0.250 M×0.500 L=0.125 mol\text{Moles} = 0.250\,\text{M} \times 0.500\,\text{L} = 0.125\,\text{mol}. Step 3: Convert moles to mass: Mass=0.125 mol×84.99 g/mol=10.62 g\text{Mass} = 0.125\,\text{mol} \times 84.99\,\text{g/mol} = 10.62\,\text{g}.

9
New cards

What is the dilution equation, and what fundamental principle does it demonstrate?

The dilution equation is M1×V1=M2×V2M_1 \times V_1 = M_2 \times V_2. It demonstrates that when solvent is added to a concentrated solution, the total moles of solute remain constant while the volume increases, decreasing the concentration.

10
New cards

What is the final concentration of HNO3\text{HNO}_3 when 45 mL45\,\text{mL} of a 4.0 M4.0\,\text{M} solution is diluted with pure water to a total volume of 200 mL200\,\text{mL}?

0.90 M0.90\,\text{M}. Rearranging the dilution equation gives: M2=M1×V1V2=4.0 M×45 mL200 mL=0.90 MM_2 = \frac{M_1 \times V_1}{V_2} = \frac{4.0\,\text{M} \times 45\,\text{mL}}{200\,\text{mL}} = 0.90\,\text{M}.

11
New cards

How do strong electrolytes, weak electrolytes, and nonelectrolytes differ in aqueous dissociation and conductivity?

Strong electrolytes dissociate completely into ions and conduct electricity strongly; weak electrolytes dissociate only partially into ions and conduct electricity poorly; nonelectrolytes dissolve as intact, uncharged molecules, producing no ions and conducting no electricity.

12
New cards

Why does a solution of calcium nitrate (Ca(NO3)2\text{Ca}(\text{NO}_3)_2) conduct electricity more strongly than solutions of ethanol (C2H5OH\text{C}_2\text{H}_5\text{OH}) or acetic acid (CH3COOH\text{CH}_3\text{COOH})?

Ethanol is a nonelectrolyte (00 ions), and acetic acid is a weak acid that dissociates minimally. Calcium nitrate is a soluble strong electrolyte that dissociates completely into three ions (1 Ca2+1\,\text{Ca}^{2+} and 2 NO3−2\,\text{NO}_3^-) per formula unit, yielding the highest concentration of mobile charge carriers.

13
New cards

What are spectator ions in an aqueous reaction?

Spectator ions are ions that appear identical and unchanged on both the reactant and product sides of a chemical equation, meaning they do not participate in the actual chemical change.

14
New cards

When aqueous solutions of MgSO4(aq)\text{MgSO}_4(aq) and Ba(NO3)2(aq)\text{Ba}(\text{NO}_3)_2(aq) are mixed, what is the net ionic equation and what are the spectator ions?

The net ionic equation is Ba2+(aq)+SO42−(aq)→BaSO4(s)\text{Ba}^{2+}(aq) + \text{SO}_4^{2-}(aq) \rightarrow \text{BaSO}_4(s). The spectator ions are Mg2+\text{Mg}^{2+} and NO3−\text{NO}_3^-, because nitrates remain universally soluble while barium sulfate precipitates as an insoluble solid.

15
New cards

If 60.0 mL60.0\,\text{mL} of 0.150 M HCl0.150\,\text{M HCl} is mixed with 40.0 mL40.0\,\text{mL} of 0.200 M NaOH0.200\,\text{M NaOH}, is the resulting solution acidic, basic, or neutral?

The solution is acidic. Step 1: Moles of H+=0.0600 L×0.150 mol/L=0.0090 mol\text{H}^+ = 0.0600\,\text{L} \times 0.150\,\text{mol/L} = 0.0090\,\text{mol}. Step 2: Moles of OH−=0.0400 L×0.200 mol/L=0.0080 mol\text{OH}^- = 0.0400\,\text{L} \times 0.200\,\text{mol/L} = 0.0080\,\text{mol}. Step 3: There are more moles of H+\text{H}^+ than OH−\text{OH}^-, leaving excess unneutralized hydronium ions.

16
New cards
<p>In the titration setup shown below, what are the identity, location, and concentration status of the titrant versus the analyte/titrand?</p>

In the titration setup shown below, what are the identity, location, and concentration status of the titrant versus the analyte/titrand?

The titrant is held in the burette and has a known concentration and measured volume. The analyte (or titrand) is held in the conical flask and has a known volume but an unknown concentration.

17
New cards

A 25.00 mL25.00\,\text{mL} sample of oxalic acid (H2C2O4\text{H}_2\text{C}_2\text{O}_4) requires 34.20 mL34.20\,\text{mL} of 0.125 M NaOH0.125\,\text{M NaOH} to reach the equivalence endpoint. What is the molar concentration of the acid?

0.0855 M0.0855\,\text{M}. Step 1: Moles of NaOH=0.03420 L×0.125 M=0.004275 mol\text{NaOH} = 0.03420\,\text{L} \times 0.125\,\text{M} = 0.004275\,\text{mol}. Step 2: Stoichiometric ratio (1 mol H2C2O4:2 mol NaOH1\,\text{mol H}_2\text{C}_2\text{O}_4 : 2\,\text{mol NaOH}) gives 0.0021375 mol H2C2O40.0021375\,\text{mol H}_2\text{C}_2\text{O}_4. Step 3: Molarity =0.0021375 mol0.02500 L=0.0855 M= \frac{0.0021375\,\text{mol}}{0.02500\,\text{L}} = 0.0855\,\text{M}.

18
New cards

What are the oxidation number rules for pure elements, monatomic ions, oxygen, and hydrogen?

Pure elements are always 00. Monatomic ions equal their charge (K+=+1\text{K}^+ = +1, Cl−=−1\text{Cl}^- = -1). Oxygen is −2-2 (except in peroxides like H2O2\text{H}_2\text{O}_2, where it is −1-1). Hydrogen is +1+1 when bonded to nonmetals and −1-1 when bonded to metals.

19
New cards

What is the oxidation number of each chromium (Cr) atom in sodium dichromate (Na2Cr2O7\text{Na}_2\text{Cr}_2\text{O}_7)?

+6+6. In the tracking equation 2(Na)+2(Cr)+7(O)=02(\text{Na}) + 2(\text{Cr}) + 7(\text{O}) = 0, substitute 2(+1)+2(x)+7(−2)=02(+1) + 2(x) + 7(-2) = 0. This simplifies to 2+2x−14=02 + 2x - 14 = 0, 2x=122x = 12, yielding x=+6x = +6.

20
New cards

How are oxidation, reduction, reducing agents, and oxidizing agents defined in redox chemistry?

Oxidation is the loss of electrons (oxidation number increases). Reduction is the gain of electrons (oxidation number decreases). A reducing agent undergoes oxidation and supplies electrons; an oxidizing agent undergoes reduction and accepts electrons.

21
New cards

In the reaction Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)\text{Zn}(s) + \text{Cu}^{2+}(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{Cu}(s), which species is oxidized, which is reduced, and which is the reducing agent?

Zn(s)\text{Zn}(s) is oxidized (00 to +2+2), Cu2+(aq)\text{Cu}^{2+}(aq) is reduced (+2+2 to 00), and Zn(s)\text{Zn}(s) is the reducing agent because it loses electrons and causes the reduction of copper ions.

22
New cards

What does a metal's position on the activity series indicate regarding single displacement reactions?

A metal ranked higher on the activity series is more easily oxidized (more strongly reducing) and can displace any metal ion located beneath it on the list.

23
New cards

A 10.00 mL10.00\,\text{mL} sample of I3−\text{I}_3^- requires 24.55 mL24.55\,\text{mL} of 0.102 M Na2S2O30.102\,\text{M Na}_2\text{S}_2\text{O}_3 to reach the starch endpoint via 2 S2O32−(aq)+I3−(aq)→S4O62−(aq)+3 I−(aq)2\,\text{S}_2\text{O}_3^{2-}(aq) + \text{I}_3^-(aq) \rightarrow \text{S}_4\text{O}_6^{2-}(aq) + 3\,\text{I}^-(aq). What is the molar concentration of I3−\text{I}_3^-?

0.125 M0.125\,\text{M}. First, calculate titrant amount: 0.102 M×24.55 mL=2.5041 mmol S2O32−0.102\,\text{M} \times 24.55\,\text{mL} = 2.5041\,\text{mmol S}_2\text{O}_3^{2-}. Convert to analyte: 2.5041 mmol×1 mol I3−2 mol S2O32−=1.25 mmol I3−2.5041\,\text{mmol} \times \frac{1\,\text{mol I}_3^-}{2\,\text{mol S}_2\text{O}_3^{2-}} = 1.25\,\text{mmol I}_3^-. Calculate concentration: 1.25 mmol10.00 mL=0.125 M\frac{1.25\,\text{mmol}}{10.00\,\text{mL}} = 0.125\,\text{M}.

24
New cards

What is the mathematical relationship between the energy (EE), frequency (ν\nu), and wavelength (λ\lambda) of light?

E=hν=hcλE = h\nu = \frac{hc}{\lambda}. Energy is directly proportional to frequency and inversely proportional to wavelength. High-energy light has a shorter wavelength and higher frequency; low-energy light has a longer wavelength and lower frequency.

25
New cards

How do constructive and destructive wave interference differ?

In constructive interference, crests align with crests, combining to amplify wave amplitude or brightness. In destructive interference, crests align with troughs, causing the waves to cancel each other out to produce dimmer or dark regions.

26
New cards

Why is the de Broglie wavelength (λ=hmv\lambda = \frac{h}{mv}) detectable for electrons but undetectable for macroscopic objects?

Because macroscopic objects have huge masses (mm) relative to subatomic particles, their calculated wavelengths are vanishingly small and impossible to detect. In contrast, an electron's tiny mass yields an observable wavelength visible through diffraction patterns.

27
New cards

What does the Heisenberg Uncertainty Principle state regarding electron motion?

It states that it is fundamentally impossible to simultaneously know both the exact position and the exact momentum of a subatomic particle, meaning electrons do not move along fixed, predictable orbits.

28
New cards

What physical meaning is assigned to the square of the wave function (ψ2\psi^2)?

While the wave function ψ\psi represents the mathematical amplitude of an electron wave, its square (ψ2\psi^2) represents the probability density of finding that electron in a given region of three-dimensional space.

29
New cards

What property of an electron orbital is defined by each of the four quantum numbers (nn, ll, mlm_l, msm_s)?

nn (principal) defines the shell/energy level and size; ll (angular momentum) determines the geometric orbital shape (s,p,d,fs, p, d, f); mlm_l (magnetic) describes the spatial orientation; and msm_s (spin) describes the intrinsic electron spin (+1/2+1/2 or −1/2-1/2).

30
New cards

If an electron shell has principal quantum number n=4n = 4, what are the allowed values of ll and the total number of individual orbitals?

The allowed values for ll range from 00 to n−1n - 1, giving l=0,1,2,3l = 0, 1, 2, 3 (corresponding to s,p,d,fs, p, d, f subshells). The total number of individual orbitals is n2=42=16n^2 = 4^2 = 16 orbitals (one 4s4s, three 4p4p, five 4d4d, and seven 4f4f).