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series convergence theorem
∑(ak) converges IFF ∀ε>0 ∃N∈N s.t. ∀n≥m≥n |∑(ak)|<ε
definition of convergence of an infinite series
if sn=∑k=1n(ak) [sequence of partial sums] converges to s, then ∑k=1∞(ak) [infinite series] converges to s
the divergence test
if lim(ak)≠0 then ∑k=1∞(ak) diverges (note: not IFF; consider harmonic series ∑(1/k))
series convergence with boundedness
a series with nonnegative terms converges iff the sequence of partial sums (sn) is bounded
basic comparison test
Let N0∈N; 1) Suppose |an|≤cn ∀n≥N0 then if ∑(ck) converges, ∑|ak| and ∑(ak) converge; 2) Suppose an≥dn≥0 ∀n≥N0 then if ∑(dk) diverges, ∑(ak) diverges
Algebraic Limit Theorem for sequences
1) if ∑ak converges and c∈R then ∑cak=c∑ak; 2) if ∑ak converges and ∑bk converges then ∑(ak+bk) = ∑ak + ∑bk
Limit Comparison Test
Suppose xn and yn are positive sequences and lim(xn/yn)=r for r≥0 exists. Then, 1) if r>0 then ∑xk converges IFF ∑yk converges; 2) if r=0 then ∑yk converges IFF ∑xk converges
absolute convergence def
∑ak converges absolutely if ∑|ak| converges
conditionally convergent
∑ak converges but NOT absolutely
re-arrangement def
∑bk is a re-arrangement of ∑ak if there exists a bijection f:N→N s.t. ∀k bk=af(k)
Root Test
Let ak be a sequence of nonnegative real numbers. Suppose lim(n√an)=r. Then, r<1 implies ∑ak converges; r>1 implies ∑ak diverges; r=0 is inconclusive
When to use which test?
ALWAYS start with divergence; for powers use root test; for factorials use ratio test; for all else use BCT
Ratio Test
Let ak be a sequence of positive real numbers. Suppose [(an+1)/(an)] converges to λ for some λ∈[0,∞). Then, λ<1 implies ∑ak converges; λ>1 implies ∑ak diverges; λ=1 is inconclusive