Math 521 Midterm 3

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/12

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 4:31 PM on 10/15/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

13 Terms

1
New cards

series convergence theorem

∑(ak) converges IFF ∀ε>0 ∃N∈N s.t. ∀n≥m≥n |∑(ak)|<ε

2
New cards

definition of convergence of an infinite series

if sn=∑k=1n(ak) [sequence of partial sums] converges to s, then ∑k=1∞(ak) [infinite series] converges to s

3
New cards

the divergence test

if lim(ak)≠0 then ∑k=1∞(ak) diverges (note: not IFF; consider harmonic series ∑(1/k))

4
New cards

series convergence with boundedness

a series with nonnegative terms converges iff the sequence of partial sums (sn) is bounded

5
New cards

basic comparison test

Let N0∈N; 1) Suppose |an|≤cn ∀n≥N0 then if ∑(ck) converges, ∑|ak| and ∑(ak) converge; 2) Suppose an≥dn≥0 ∀n≥N0 then if ∑(dk) diverges, ∑(ak) diverges

6
New cards

Algebraic Limit Theorem for sequences

1) if ∑ak converges and c∈R then ∑cak=c∑ak; 2) if ∑ak converges and ∑bk converges then ∑(ak+bk) = ∑ak + ∑bk

7
New cards

Limit Comparison Test

Suppose xn and yn are positive sequences and lim(xn/yn)=r for r≥0 exists. Then, 1) if r>0 then ∑xk converges IFF ∑yk converges; 2) if r=0 then ∑yk converges IFF ∑xk converges

8
New cards

absolute convergence def

∑ak converges absolutely if ∑|ak| converges

9
New cards

conditionally convergent

∑ak converges but NOT absolutely

10
New cards

re-arrangement def

∑bk is a re-arrangement of ∑ak if there exists a bijection f:N→N s.t. ∀k bk=af(k)

11
New cards

Root Test

Let ak be a sequence of nonnegative real numbers. Suppose lim(n√an)=r. Then, r<1 implies ∑ak converges; r>1 implies ∑ak diverges; r=0 is inconclusive

12
New cards

When to use which test?

ALWAYS start with divergence; for powers use root test; for factorials use ratio test; for all else use BCT

13
New cards

Ratio Test

Let ak be a sequence of positive real numbers. Suppose [(an+1)/(an)] converges to λ for some λ∈[0,∞). Then, λ<1 implies ∑ak converges; λ>1 implies ∑ak diverges; λ=1 is inconclusive