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Why does carbon form a large number of compounds? (3)
- Bond to other carbon atoms to form long chains
- Form single, double and triple bonds
- Can form four covalent bonds to other atoms eg. Oxygen, nitrogen, halogens
Define hydrocarbon
A compound containing hydrogen and carbon atoms only
Define homologous series
Compounds with similar chemical properties whose successive members differ by a CH2 group
Define functional group
Part of the organic molecule which dictates its chemical properties
Define general formula
Simplest algebraic formula for any member of a homologous series
Alkanes general formula
CnH2n+2
Alkenes general formula
CnH2n
Alcohols general formula
CnH2n+1OH
Carboxylic acids general formula
CnH2nO2
Ketones general formula
CnH2nO
What does the intersection between two lines represent in the skeletal formula?
Carbon atom
What does the end of a line represent in the skeletal formula?
CH3 group
Define aliphatic
Carbon joined to each other in unbranched, branched or non-aromatic rings
Define alicyclic
Carbons joined to each other in rings (cyclic structures) with or without branches
Define aromatic
Some/all carbon atoms found in a benzene ring
Alkene functional group
c=c
alcohol functional group
O-H
Alcohol prefix
Hydroxy-
Alcohol suffix
-ol
Aldehyde functional group

Aldehyde suffix
-al
Ketone functional group

Ketone suffix
-one
Carboxylic acid functional group

Carboxylic acid suffix
-oic acid
Ester functional group

Ester suffix
-oate
Acyl chloride

Acyl chloride suffix
-oyl chloride
Amine functional group
-NH2
Amine prefix
Amino
Amine suffix
-amine
Nitrile functional group
-CN
Nitrile suffix
-nitrile
Define structural formula
The least amount of detail necessary to show the arrangement of the atoms in a molecule
Define unsaturated
Hydrocarbon containing c-c multiple bonds
Define skeletal formula
A simplified organic formula showing the carbon skeleton and any functional groups
Define displayed formula
Formula showing the relative positioning of all the atoms in a molecule and the bonds between them.