Calculus Formulas (Derivatives, Integrals, FTC)

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44 Terms

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Definition of derivative: f′(x)=\text{Definition of derivative: } f'(x) =

lim⁡h→0f(x+h)−f(x)h\lim_{h\to0}\dfrac{f(x+h)-f(x)}{h}

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Alternate definition: f′(a)=\text{Alternate definition: } f'(a) =

lim⁡x→af(x)−f(a)x−a\lim_{x\to a}\dfrac{f(x)-f(a)}{x-a}

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ddx[c]=\dfrac{d}{dx}[c] =

00

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ddx[fg]=\dfrac{d}{dx}\left[\dfrac{f}{g}\right] =
gf′−fg′g2\dfrac{gf'-fg'}{g^2}
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ddx[fg]=\dfrac{d}{dx}[fg] =
fg′+f′gfg'+f'g
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ddx[ex]=\dfrac{d}{dx}[e^x] =
exe^x
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ddx[x]=\dfrac{d}{dx}[x] =
11
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ddx[u+v]=\dfrac{d}{dx}[u+v] =
u′+v′u'+v'
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ddx[un]=\dfrac{d}{dx}[u^n] =
nun−1 u′nu^{n-1}\,u'
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ddx[cos⁡u]=\dfrac{d}{dx}[\cos u] =
−sin⁡u u′-\sin u\,u'
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ddx[sin⁡u]=\dfrac{d}{dx}[\sin u] =
cos⁡u u′\cos u\,u'
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ddx[sec⁡u]=\dfrac{d}{dx}[\sec u] =
sec⁡utan⁡u u′\sec u\tan u\,u'
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ddx[tan⁡u]=\dfrac{d}{dx}[\tan u] =
sec⁡2u u′\sec^2 u\,u'
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ddx[cot⁡u]=\dfrac{d}{dx}[\cot u] =
−csc⁡2u u′-\csc^2 u\,u'
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ddx[csc⁡u]=\dfrac{d}{dx}[\csc u] =
−csc⁡ucot⁡u u′-\csc u\cot u\,u'
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ddx[ln⁡u]=\dfrac{d}{dx}[\ln u] =
u′u\dfrac{u'}{u}
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ddx[log⁡au]=\dfrac{d}{dx}[\log_a u] =
u′(ln⁡a) u\dfrac{u'}{(\ln a)\,u}
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ddx[au]=\dfrac{d}{dx}[a^u] =
(ln⁡a) au u′(\ln a)\,a^u\,u'
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ddx[arcsin⁡u]=\dfrac{d}{dx}[\arcsin u] =
u′1−u2\dfrac{u'}{\sqrt{1-u^2}}
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ddx[arctan⁡u]=\dfrac{d}{dx}[\arctan u] =
u′1+u2\dfrac{u'}{1+u^2}
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ddx[arcsec⁡u]=\dfrac{d}{dx}[\operatorname{arcsec} u] =
u′∣u∣u2−1\dfrac{u'}{|u|\sqrt{u^2-1}}
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∫k f(x) dx=\int k\,f(x)\,dx =
k∫f(x) dxk\int f(x)\,dx
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∫[f(x)±g(x)] dx=\int [f(x)\pm g(x)]\,dx =
∫f(x) dx±∫g(x) dx\int f(x)\,dx\pm\int g(x)\,dx
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∫dx=\int dx =
x+Cx+C
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∫un du=\int u^n\,du =
un+1n+1+C\dfrac{u^{n+1}}{n+1}+C
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∫duu=\int \dfrac{du}{u} =
ln⁡∣u∣+C\ln|u|+C
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∫eu du=\int e^u\,du =
eu+Ce^u+C
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∫au du=\int a^u\,du =
(1ln⁡a)au+C\left(\dfrac{1}{\ln a}\right)a^u+C
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∫sin⁡u du=\int \sin u\,du =
−cos⁡u+C-\cos u+C
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∫cos⁡u du=\int \cos u\,du =
sin⁡u+C\sin u+C
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∫tan⁡u du=\int \tan u\,du =
−ln⁡∣cos⁡u∣+C-\ln|\cos u|+C
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∫cot⁡u du=\int \cot u\,du =
ln⁡∣sin⁡u∣+C\ln|\sin u|+C
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∫sec⁡u du=\int \sec u\,du =
ln⁡∣sec⁡u+tan⁡u∣+C\ln|\sec u+\tan u|+C
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∫csc⁡u du=\int \csc u\,du =
−ln⁡∣csc⁡u+cot⁡u∣+C-\ln|\csc u+\cot u|+C
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∫sec⁡2u du=\int \sec^2 u\,du =
tan⁡u+C\tan u+C
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∫csc⁡2u du=\int \csc^2 u\,du =
−cot⁡u+C-\cot u+C
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∫sec⁡utan⁡u du=\int \sec u\tan u\,du =
sec⁡u+C\sec u+C
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∫csc⁡ucot⁡u du=\int \csc u\cot u\,du =
−csc⁡u+C-\csc u+C
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∫dua2−u2=\int \dfrac{du}{\sqrt{a^2-u^2}} =
arcsin⁡ua+C\arcsin\dfrac{u}{a}+C
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∫dua2+u2=\int \dfrac{du}{a^2+u^2} =
1aarctan⁡ua+C\dfrac{1}{a}\arctan\dfrac{u}{a}+C
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∫duuu2−a2=\int \dfrac{du}{u\sqrt{u^2-a^2}} =
1aarcsec⁡∣u∣a+C\dfrac{1}{a}\operatorname{arcsec}\dfrac{|u|}{a}+C
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∫ln⁡x dx=\int \ln x\,dx =

xln⁡x−x+Cx\ln x-x+C

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FTC: ∫abf′(x) dx=\text{FTC: } \int_a^b f'(x)\,dx =

f(b)−f(a)f(b)-f(a)

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FTC: if F′(x)=f(x), then ∫abf(x) dx=\text{FTC: if } F'(x)=f(x)\text{, then } \int_a^b f(x)\,dx =

F(b)−F(a)F(b)-F(a)