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Fubini’s Theorem (stronger form)
If f(x,y) is continuous throughout a region D then:
a) If D is defined by
D = { (x,y) | a ≤ x ≤ b, g1(x) ≤ y ≤ g2(x) } [type I regions]
b) If D is defined by
D = { (x,y) | h1(y) ≤ x ≤ h2(y), c ≤ y ≤ d } [type II regions]
The final integral should always be a constant.
![<p>If f(x,y) is continuous throughout a region D then:</p><p>a) If D is defined by </p><p>D = { (x,y) | a ≤ x ≤ b, g<sub>1</sub>(x) ≤ y ≤ g<sub>2</sub>(x) } [type I regions]</p><p></p><p>b) If D is defined by</p><p>D = { (x,y) | h<sub>1</sub>(y) ≤ x ≤ h<sub>2</sub>(y), c ≤ y ≤ d } [type II regions]</p><p>The final integral should always be a constant.</p>](https://assets.knowt.com/user-attachments/a9c2144b-3b87-4669-8a31-2168dfd2cf3b.png)

Solving double integrals
=1

Double reimann sum
Where delta A = deltaX*deltaY

Formula for double integrals (where R = [a,b] x [c,d])
Integral from x=a to x=b (integral from y=c to y=d (f(x,y)dy)dx)
Average value of f(x,y) over R
1/A * double integral of f(x,y)
Double integral in polar

Triple integrals
Use dV = dxdydz
for cylindrical, dV = rdrdθdz
When finding volume, f(x,y,z) = 1
Average of f(x,y,z) over R
Triple integral/Volume of R