ISYE 3770 Midterm 1

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/52

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 11:38 PM on 10/18/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

53 Terms

1
New cards

population

complete set of objects relevent to study

2
New cards

sample

subset of population

-use to make infrences about the whole


3
New cards

Methods to collect data

  • retrospective

  • observational

  • designed experiments


4
New cards

Retrospective study

  • historical data

avantages:

  • existing data

  • low cost

  • doesnt interupt production

drawbacks:

  • limited key factor varation

  • missing data

  • possible recording errors

  • unmeasured variables

  • hard to isolates effects/variables


5
New cards

observational study

  • monitoring process/pop. with minimal interference, recording varibales of interest over period of time

advantages:

  • minimal process distrubance

  • potential to measure additonal variables

  • improved data accuracy and reliability

drawbacks:

  • limited to ability to manipulate factors

  • difficulty isolating individual effects


6
New cards

designed experiments

  • changing controllable variables, observing results, and using statistical principles to identify which factors cause observed effects

advantages:

  • cause-effect relationships

  • enables process improvement and validation of engineering theroies

drawbacks:

  • time consuming


7
New cards

Models

describe how variables in a process are related

two types:

  • mechanistic

  • empirical


8
New cards

Mechanistic models

  • based on known physical laws or mechanisms describing a process

    • ohm’s law (voltage=current x resistance)

  • well understood underlying mechanism

limitation: real data often deviate due to uncontrolled factors

adding variability:

  • real processes rarely behave as theory predicts

    • error term ( ε ) : accounts for environmental fluctuations, operator differences, and measurement noise

    • include error term to account for variability


9
New cards

empirical models

  • developed from observed data when no simple theory exists (data relationships)

  • mechanisms are unclear

    • Product Quality = β₀ + β₁(Conveyor Speed) + β₂(Operator Interventions) + β₃(Machine Temp) + ε

    • Coefficients (β’s) are estimated using regression analysis

  • include error term to account for variability

  • help understand and improve real processes

    • production line


10
New cards

probability model

help quantify risk and uncertainty in decisions

examples:

  • sample size selection

  • process monitoring

  • quality control


discrete model - countable events (defects)

continuous model - measurable data (concentrations)


11
New cards

Why probability models are needed?

  • sampling always involves chance → results may not represent reality

  • measure uncertainty and control the risk of wrong decisions

examples:

  • detecting a defect

  • acceptable risk


12
New cards

probability

  • study of randomness and uncertainty

  • methods to quantify likelihood


13
New cards

random experiment

any activity whose outcome is subject to uncertainty

14
New cards

sample space (S)

set of possible outcomes from the experiment

  • represented as tree diagram


15
New cards

event (E)

  • any subset of sample space (S)

  • simple - one outcome of interest

    • E_1={(0,0)}, … E_n = {(6,6)}

  • compound - mult outcomes of interest

    • A={(0,0), (0,1)}


16
New cards

complement - A’

outcomes in sample space S that are not in A

Let 𝑨 = 𝟎, 𝟏, 𝟐, 𝟑, 𝟒 , 𝑩 = 𝟑, 𝟒, 𝟓, 𝟔 , 𝑪 = 𝟏, 𝟑, 𝟓

𝑨′ = 𝟓, 𝟔

17
New cards

Union - AUB

outcomes in A or B or both

Let 𝑨 = 𝟎, 𝟏, 𝟐, 𝟑, 𝟒 , 𝑩 = 𝟑, 𝟒, 𝟓, 𝟔 , 𝑪 = 𝟏, 𝟑, 𝟓

𝑨 ∪ 𝑩 = 𝟎, 𝟏, 𝟐, 𝟑, 𝟒, 𝟓, 𝟔 = 𝑺

18
New cards

intersection - A∩B

outcomes in both A and B

Let 𝑨 = 𝟎, 𝟏, 𝟐, 𝟑, 𝟒 , 𝑩 = 𝟑, 𝟒, 𝟓, 𝟔 , 𝑪 = 𝟏, 𝟑, 𝟓

𝑨 ∩ 𝑩 = 𝟑, 𝟒

19
New cards

P(A)

prob of A in S

must follow axioms of probabiliy

  • For any event 𝑨, 𝑷 𝐀 + 𝑷 𝐀′ = 𝟏, from which 𝑷 𝐀 = 𝟏 − 𝑷 𝐀′

  • For any event 𝑨, 𝑷 𝑨 ≤ 𝟏

    • When events 𝑨 and 𝑩 are not mutually exclusive, simply adding 𝑷(𝑨) and 𝑷(𝑩) double-counts their intersection

  • (addition rule): For any two events 𝑨 and 𝑩 not mutually exclusive, 𝑷 𝑨 ∪ 𝑩 = 𝑷 𝑨 + 𝑷 𝑩 − 𝑷(𝑨 ∩ 𝑩)

  • For any three events 𝑨, 𝑩, and 𝑪, 𝑷 𝑨 ∪ 𝑩 ∪ 𝑪 = 𝑷 𝑨 + 𝑷 𝑩 + 𝑷 𝑪 − 𝑷 𝑨 ∩ 𝑩 − 𝑷 𝑨 ∩ 𝑪 − 𝑷 𝑩 ∩ 𝑪 + 𝑷(𝑨 ∩ 𝑩 ∩ 𝑪)


20
New cards

Axioms of prob

axiom 1

P(A) >= 0

Axiom 2

P(S)=1

Axiom 3

If 𝑨𝟏, 𝑨𝟐, … is an infinite collection of disjoint events, then

𝑷 (𝑨𝟏 ∪ 𝑨𝟐 ∪ ⋯ )= Sum from i=1 to infinity of P(A_i)

21
New cards

relative frequencies

  • probability

  • as experiemnt is repeated, rel frequency of an event stablizes

  • long run rel frequency defines the P(A) probability


22
New cards

counting techniques

find number of outcomes in sample space or events

23
New cards

permutation

  • ordered arrangement of all elements in set

  • The number of permutations of 𝒏 different elements is 𝒏! where: 𝒏! = 𝒏 × 𝒏 − 𝟏 × 𝒏 − 𝟐 × ⋯ × 𝟐 × 𝟏

  • The number of permutations of subsets of 𝒓 elements selected from a

set of 𝒏 different elements is 𝑷𝒏,r = 𝒏 × (𝒏 − 𝟏) × (𝒏 − 𝟐) × ⋯ × 𝒏 − 𝒓 + 𝟏 =

𝒏!/(𝒏 − 𝒓 )!


permuation of similar objects (not all different)

  • The # of permutations of 𝒏 = 𝒏𝟏 + 𝒏𝟐 + ⋯ + 𝒏𝒓 objects of which 𝒏𝟏 are

of one type up to 𝒏𝒓 of a 𝒓𝒕𝒉 type is 𝒏! /(𝒏𝟏! 𝒏𝟐! … 𝒏𝒓!)


24
New cards

combination

  • selection of r elements when order does not matter

  • Cn,r = (n r) = n!/ r!(n-r)!


  • if random experiemnt where may or may not be replaced → combine combination with multication rule


25
New cards

mult rule (counting techniques)

  • squence of k steps, number of ways to complete step 1 are n1, nuber of ways to complete step 2 are n2

  • total number of ways to complete operation = n1xn2x..nk


26
New cards

conditional prob

  • prob depends on what is known

  • new info may change prob

P(A|B)

prob of A given B

  • B is conditioning event


𝑷 (𝑨 )= 𝑵 (A) / N


For any two events 𝑨 and 𝑩 with 𝑷(𝑩) > 𝟎

P(A|B) = 𝑷(𝑨∩𝑩) / 𝑷(𝑩)


  • P(A|B) is proportional to 𝑷(𝑨 ∩ 𝑩)


multiplication rule for 𝑷(𝑨 ∩ 𝑩) : 𝑷 (𝑨 ∩ 𝑩 )= P(A|B)× 𝑷(𝑩)


27
New cards

Bayes theorem - law of total prob

  • with enough conditional prob, overall event prob can be determined

  • For any event 𝑩, we can write 𝑩 as the union of the part of 𝑩 in 𝑨 and the part of 𝑩 in 𝑨′. That is: 𝑩 = (𝑩 ∩ 𝑨) ∪ (𝑩 ∩ 𝑨′)

  • Because 𝑨 and 𝑨′ are mutually exclusive events, so are 𝑩 ∩ 𝑨 and 𝑩 ∩ 𝑨′, leading to the total probability rule for two events: P(B) = P(𝑩 ∩ 𝑨) + P(𝑩 ∩ 𝑨’) = P(B|A)P(A) + P(B|A’)P(A’)

  • total prb rule for mult events: P(B) = P(𝑩 ∩ E1) + … + P(𝑩 ∩ Ek) = P(A|E1)P(E1) +…+P(A|Ek)P(Ek)


  • 𝑃(𝐴 ∩ 𝐵) = 𝑃(𝐴 | 𝐵)𝑃(𝐵) = 𝑃(𝐵 ∩ 𝐴) = 𝑃(𝐵 | 𝐴)𝑃(𝐴)

  • 𝑃(𝐴 | 𝐵) = 𝑃(𝐵|𝐴)𝑃(𝐴) / 𝑃(𝐵)

  • 𝑃(E1|B)= 𝑷 (𝑩 |𝑬𝟏 )𝑷(𝑬𝟏) / 𝑷 (𝑩| 𝑬𝟏) 𝑷 (𝑬𝟏) + ⋯ + 𝑷 (𝑩| 𝑬𝒌) 𝑷(𝑬𝒌) for P(B)>0


28
New cards

independence

  • Two events A and B are independent when learning that one event occurred does not change the probability of the other

  • Two events 𝑨 and 𝑩 are independent if 𝑷( 𝑨| 𝑩) = 𝑷(𝑨) and are dependent otherwise

  • 𝑨 and 𝑩 are independent if 𝑷(𝑨 ∩ 𝑩) = 𝑷(𝑨) × 𝑷(𝑩)


  • Two events A and B are mutually exclusive if they

    cannot occur at the same time, i.e. 𝑷 𝑨 ∩ 𝑩 = 𝟎


29
New cards

random variable

for given subspace (S), RV is any rule that associates a number with each outcome in S

  • RV is function whose domain is the sample space and range is the set of real numbers

  • denoted with upercase letters (X)

  • lowercase letter (x) id given outcome of X


2 outcomes → S={S,F}

RV in this sample space → X(S)=1, X(F)=0


bernoulli RV - RV whose only possible outcomes are 0 and 1


discrete - possible values form finite set or countable infinite list

continous - possible values lie in one interval or union of intervals

  • no possible vlaue of te varibale has positive prob → P(X=c)=0


30
New cards

prob distr for discrete RV

  • how total prob of mass 1 is distr among possible values of X

    • f(x)

  • prob mass function (PMF) of discrete rv: 𝒇 (𝒙 )= 𝑷 (𝑿 = 𝒙)

    • f(x)>=0, and sum of all x f(x) = 1


31
New cards

PMF - prob mass function

  • distr total prob mass (=1)

  • prob histogram shows how prob mass allocated across values

    • all rectangles share same base width

    • rectangle above each value of x with f(x)>0

    • height is proportional to f(x)


32
New cards

parameter of prob distr

  • fixed numerical value that determines how prob distr assigns prob to outcomes

  • NOT random

  • changing parameter changes shape of distr

  • parameter (p)

    • if p inc → success is more likely

  • 𝑷( 𝑿 = 𝟏) = 𝒑

  • 𝑷 (𝑿 = 𝟎) = 𝟏 − 𝒑

  • f(x) = (1-p)^x-1 p for x=1,2…


33
New cards

cumulative dist function CDF

  • how prob accumulate up to x

  • The CDF 𝑭(𝒙) of a discrete random variable 𝑿 with PMF 𝒇(𝒙) is defined for every number 𝒙 by: 𝑭 𝒙 = 𝑷 (𝑿 ≤ 𝒙) = SUM_y:y<=x for f(y)

  • For any 𝒙, 𝑭(𝒙) is the probability that the observed value of 𝑿 will be at most 𝒙


CDF

  • non-decreasing

  • right cont : each horz step included its left endpoint and extend t the right

  • limits: lim_x→-inf F(x)=0

    • lim_x→+inf F(x)=1


  • For any numbers 𝒂 ≤ 𝒃: 𝑷 (𝒂 ≤ 𝑿 ≤ 𝒃) = 𝑭 (𝒃 )− 𝑭(𝒂−)

    • a- is largest possible value of X less than a

  • If 𝑿 can only take integer values, 𝒂 and 𝒃 are integers; then: 𝑷( 𝒂 ≤ 𝑿 ≤ 𝒃) = 𝑭 (𝒃) − 𝑭 (𝒂 − 𝟏)

  • Special case: 𝒂 = 𝒃 (probability at a single value) :

    • 𝑷( 𝑿 = 𝒂) = 𝑭( 𝒂 )− 𝑭 (𝒂 − 𝟏)


34
New cards

mean

center or middle of prob distr

-Two different distributions can have the same mean and variance


μ= E(X)= SUM_x for 𝑥𝑓(𝑥)

  • E(X) is weighted average

  • the point at which a bar balances


35
New cards

variance

measure of dispersion in distr

-Two different distributions can have the same mean and variance


σ² = V(X) = E(X-μ )² = SUM_x for (X-μ )² f(x) = SUM_x for x²f(x) - μ²

36
New cards

standard deviation

σ = square root of σ²

  • prefered over variance

  • σ is in same units as the data (variance is in unites²)

  • X units away from the mean

  • easier to compare across data sets


37
New cards

binomial distr

  • series of repeated random independent trials

  • rv X i= number of sucesses in n trials

  • parameters: n trials, p=prob of success

  • symmetric shape skewked pepending on n and p

  • counts number of sicesses in a fixed number of tri

  • each trial is success or failure (2 outcomes)

    • success meets criterion

    • prob of success is constant

    • number of trials n is fixed


  • only 2 possible outcomes → bernouilli trial


general prob, 0<p<1

P(X=x) = (n x)(p^x)(1-p)^n-x


  • no closed form for CDF

  • CDF: F(X<=x)= SUM_i=0 to x for (n i)(p^i)(1-p)^n-i

  • mean: E(X)=np

  • variance: V(X): np(1-p)


38
New cards

general prob formula

(n x) = n! / x!(n-x)!


general prob

P(X=x) = (n x)(p^x)(1-p)^n-x

39
New cards

geometric distr

  • series of repeated random independent trials

  • counts number of trials until 1st sucess

  • rv Y=trial number of 1st success

  • parameter: p = success prob

  • shape: always skewed right


  • in bernoulli trials → f(x) = (1-p)^x-1 (p) for x=1,2,…

  • CDF: F(x)= 𝑷 (𝑿 ≤ 𝒙) = 𝟏 − (𝟏 − 𝒑)^x

  • mean: E(X)= 1/p

  • variance: V(X)= (1-p)/p²


lack of memory

  • success can be started at any trial w/o changing prob dist of rv

    • system does not wear out and lacks memory

    • prob of finding defect in next n chips is always the same

    • distr forgets the past: 100 defect free chips doesnt chage prob of next 100 chips beign dfect free

    • each inspection is ind with constant defect prob

    • system doesnt improve or degreafe during operation


40
New cards

negative binomial distr

  • X= number of trials required to obtain r successes

  • Total # of trials to obtain 𝒓 successes is 𝑿𝟏 + 𝑿𝟐 + ⋯ + 𝑿𝒓

  • lack of memory property, each rv follows a geometric distribution with same value of 𝒑

  • shape: right skewed, more skew as p dec


  • bernoulli trials → f(x) = (x-1 r-1) (1-p)^x-r (p^r) , x=r,r+1,….

  • CDF: P(X<=x)= SUM, k=r to x for (k-1 r-1) (1-p)^k-r (p^r)

  • mean: E(X): r/p

  • variance: V(X): r(1-p)/p²


41
New cards

Poission distr

  • number of events occuring in fixed interval (time, space, volume)

  • independent trials

  • at known average rate

  • randomly through interval

    • defect per batch

  • shape: right skewed or symmetric, as λ inc → gets more symmetic


  • for λ>0 → f(x)= (λ^e e^-λ) / x! for x=0,1…

  • CDF: P(X<=x)= SUM, k=r to x for (λ^e e^-λ) / k!

  • mean: E(X): λ

  • variance: V(X): λ

    • mean and variance are the same


when to use: need all 4

  • count discrete events

  • random in time or space

  • events are rare relative to opportunity

  • events dont influence each other


  • per unit quantities

  • rare event in cont domain

  • rate based process


42
New cards

prob density function

  • f(x)>=)

  • ∫−∞ to +∞ 𝒇 (𝒙 )𝒅𝒙 = 𝟏

  • 𝑷 (𝒂 ≤ 𝑿 ≤ 𝒃 )= ∫ 𝒂 to 𝒃 𝒇( 𝒙) 𝒅𝒙 = area under 𝒇(𝒙) from 𝒂 to 𝒃 for any 𝒂 and 𝒃


histograms - approx of pdf

  • area under bar = rel frequency = est of the prob that measurement falls in the interval

  • area under f(x) over interval = true prob meas falls in interval


  • density est at xf(x) = 0

    • assigns mass only over interval → prob at point =0

  • 𝑷 (𝒙𝟏 ≤ 𝑿 ≤ 𝒙𝟐) = 𝑷 (𝒙𝟏 < 𝑿 ≤ 𝒙𝟐) = 𝑷 (𝒙𝟏 ≤ 𝑿 < 𝒙𝟐) = 𝑷(𝒙𝟏 < 𝑿 < 𝒙𝟐)


43
New cards

cumulative distr function

  • F(x)= ∫−∞ to x f(u)du for −∞ <x<+∞

  • density: d/dx (F(x)= ∫−∞ to x f(u)du) = f(x)

    • as long as derv exists


44
New cards

mean of cont rv

E(X)=∫−∞ to +∞ xf(x)dx

45
New cards

variance of cont rv

V(X)=∫−∞ to +∞ (X-μ )² f(x)dx = ∫−∞ to +∞ x²f(x)dx - μ²


standard deviation does not change for cont rv

46
New cards

normal (gaussian) distr

  • model for cont measurements

  • quality control, measurement sys, central limit theorem (many small ind effects add up to normal distr)

  • parameters: − ∞ < μ < ∞ , and 𝝈>0


density: 𝒇( 𝒙) = 𝟏/ ( 𝝈 square root (𝟐𝝅)) • 𝒆^(−(𝒙−𝝁)² / 𝟐𝝈² ). for − ∞ < 𝒙 < ∞

mean: E(X): μ

variance: V(X): 𝝈²

notation: N(μ,𝝈²)


  • from symmetry: 𝑷 (𝑿 < 𝝁) = 𝑷( 𝑿 > 𝝁 )

  • shape: symmestric about 𝝁 and bell shaped

  • center of bell is mean and mediam of distr

  • 𝝁 is location parameter (changing 𝝁 shifts side to side)

  • 𝝈 is scale parameter (changing 𝝈 strenches or compreses curve w/o chanigng shape)

    • lower 𝝈 → taller bell


47
New cards

standard normal distr

  • Computing 𝑷(𝒂 ≤ 𝑿 ≤ 𝒃) requires integrating the pdf which cannot be done by standard integration techniques

  • The probability has been calculated for 𝝁 = 𝟎 and 𝝈 = 𝟏 and tabulated for certain values of 𝒂 and 𝒃 - standard normal rv

  • use table for other mu and sigma probs


  • CDF (Z): 𝚽( 𝒛) = 𝑷(𝒁 ≤ 𝒛)

  • If 𝑿 is a Normal rv with 𝑬 𝑿 = 𝝁 and 𝑽 𝑿 = 𝝈², the rv: 𝒁 = (𝑿 − 𝝁)/𝝈


48
New cards

Normal approx of binomial distr

  • if X is binimal distr with parameters n and p

    • Z=(X-np)/ (square root(np(1-p)))

      • np=E(X)

      • NP(1-p) = V(X)

        • good approx of E(X) and V(X) >5

  • continuity correction:

    • P(X<=x) = 𝑷(𝑿 ≤ 𝒙 + 𝟎. 𝟓) = P(Z<= (x + 0.5 -np)/ (square root(np(1-p)))

    • P(X>=x) = 𝑷(𝑿 >= 𝒙 - 𝟎. 𝟓) =P(Z<= (x - 0.5 -np)/ (square root(np(1-p)))



49
New cards

normal approx to poisson distr

  • If 𝑿 is a Poisson rv with 𝑬 𝑿 = 𝝀 and 𝑽 𝑿 = 𝝀 → Z= (X-𝝀)/ (sqaure root(𝝀))

  • same continutiy correct ad binomial

    • approc is good if 𝝀>5


50
New cards

uniform distr

notation: U(A,b)

application: reandom number generation in simulations, and arrival time withon known interval


density: f(x) = 1/(b-a). for a<=x<=b

mean: E(X): (a+b)/2

variance: V(X)= (a+b)² / 12


51
New cards

exponential distr

  • The rv 𝑿 that equals the distance between successive events from a Poisson process with mean number of events 𝝀 > 𝟎 per unit interval is anexponential rv with parameter 𝝀 and pdf


density: f(x)= 𝝀𝒆^(−𝝀𝒙), for 𝟎 ≤ 𝒙 < inf

Mean: E(X): 1/𝝀

variance: V(X): 1/𝝀²


  • lacks memory

  • For an Exponential rv 𝑿: 𝑷(𝑿 < 𝒕𝟏 + 𝒕𝟐 | 𝑿 > 𝒕𝟏) = 𝑷(𝑿 < 𝒕𝟐)


52
New cards

weibull distr

  • model lifetimes and failure behavoirs (durability and preformance)

  • shape parameter allows to represent inc, dec, constant failure rates

  • parameters:

    • scale: 𝜹 > 𝟎

    • shape: 𝜷 > 𝟎


density: f(x)= (𝜷 / 𝜹) (𝒙 / 𝜹)^(𝜷−𝟏) e𝒙𝒑 [− (𝒙 / 𝜹)^𝜷 ]. for 𝒙 > 𝟎

CDF: 𝑭 (𝒙) = 𝟏 − 𝒆^[-(x / 𝜹)^𝜷 ]

mean: E(X): 𝜹𝚪( 𝟏 + (1/𝜷))

variance: V(X)= 𝜹²𝚪 (𝟏 + (2/𝜷))- 𝜹² [ 𝚪 (𝟏 + (1/𝜷))]²






bathtub curve (failure rates)

  • early life failure (decreasing failure rate, 𝜷 < 𝟏)

    • Cause: Manufacturing defects, poor quality components, assembly errors

  • Useful Life (constant failure rate, 𝜷 = 𝟏)

    • Cause: Random events, external shocks, and human error

    • failure is not related to the age of the component

  • Wear-Out Failures (increasing failure rate, 𝜷 > 𝟏)

    • Cause: Material fatigue, corrosion, and natural aging


53
New cards

not included: lognormal

lognormal