Topic 7.5 Hardy Weinberg Equilibrium

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Flashcards covering Hardy-Weinberg Equilibrium principles, underlying criteria, mathematical variables, equations, and step-by-step problem-solving methods.

Last updated 8:24 PM on 9/28/26
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12 Terms

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Hardy-Weinberg Equilibrium

A theory stating that in the absence of any evolutionary driving forces, the allele frequency in the population will not change over time.

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Conditions for Hardy-Weinberg Equilibrium

The five criteria a population must meet: No Natural Selection, No Gene Flow, No Mutations, No Sexual Selection (Random mating), and No Genetic Drift.

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Variable pp

Represents the frequency of the dominant allele in a population.

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Variable qq

Represents the frequency of the recessive allele in a population.

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Hardy-Weinberg Equation #1

p+q=1p + q = 1, which states that the frequency of the dominant allele plus the frequency of the recessive allele equals 100%100\% of the alleles in the population.

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<p>Hardy-Weinberg Punnett Square</p>

Hardy-Weinberg Punnett Square

A Punnett square showing the genotypes resulting from crossing two heterozygous individuals using allele frequencies pp and qq.

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Variable p2p^2

Represents the frequency of the homozygous dominant genotype (AAAA) in a population.

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Variable 2pq2pq

Represents the frequency of the heterozygous genotype (AaAa) in a population.

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Variable q2q^2

Represents the frequency of the homozygous recessive genotype (aaaa) or the recessive phenotype frequency in a population.

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Hardy-Weinberg Equation #2

p2+2pq+q2=1p^2 + 2pq + q^2 = 1, which states that the sum of the frequencies of the three genotypes equals 100%100\% of the population.

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Frequency of Dominant Phenotype

Calculated as p2+2pqp^2 + 2pq, which combines the frequencies of the homozygous dominant genotype (p2p^2) and heterozygous genotype (2pq2pq).

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Steps to Solve Hardy-Weinberg Problems

Step 1: Read, underline, and write equations and variables. Step 2: Compare given values with terms and write them down. Step 3: Solve for qq. Step 4: Solve for what the question asks.