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A set of vocabulary flashcards covering key concepts, formulas, and problems from the JEE Main 2019 Kinematics lecture.
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Position from Velocity-Time Graph
The position or displacement of a particle starting from the origin calculated by evaluating the area under the velocity-time graph up to time t.
Relative Velocity of Trains
The magnitude of relative speed between two trains of speeds v1 and v2, defined as v1−v2 when traveling in the same direction and v1+v2 when traveling in opposite directions.
Uniform Acceleration Motion Graphs
Graphical curves for constant acceleration motion starting from rest: acceleration vs. time is a horizontal line, velocity vs. time is a straight line through the origin, and position vs. time is a parabola opening upwards from the origin.
Momentum-Height Relation in Vertical Throw
The quadratic relation p2=m2u02−2gm2h describing momentum p as a function of height h for a projectile thrown vertically upwards with initial speed u0.
Zero Acceleration Point
The time instant t=3cb at which acceleration equals zero for position function x(t)=at+bt2−ct3, giving velocity v=a+3cb2.
Relative Overtaking Speed Formula in Car Race
The relation v = \root\frac{}{a_1 a_2} t giving the additional speed v with which Car A crosses the finish line relative to Car B when starting from rest with accelerations a1 and a2 and finishing time difference t.
Speed in 3D Motion
The total speed of a particle moving in 3D space given by v = \root\frac{}{v_x^2 + v_y^2 + v_z^2}, derived by differentiating individual spatial coordinates with respect to time.
Acceleration from Velocity-Position Function
The uniform acceleration a=vdxdv=2b2 obtained from a velocity function v = b \root\frac{}{x}.
Trajectory Equation for Coupled Velocities
The parabolic or hyperbolic path y2=x2+C obtained by integrating the differential relation dxdy=vxvy=yx for velocity components vx=ky and vy=kx.
Maximum Coverage Area of Projectile Guns
The maximum ground area Area=constθ×range2=g2θu4 covered on a 2D plane by firing projectiles in all horizontal directions at a 45o angle, which scales as u4.
Time of Flight on an Inclined Plane
The duration T=gtan(θ)tan(θ)2utan(θ) or T=gtan(θ)2utan(θ) given by T=ay2uy=gtan(θ)2utan(θ), specifically written as T=gtan(θ)2utan(θ) along an incline of angle tan(θ).
Range on an Inclined Plane
The total distance along an incline of slope angle tan(θ) hit by a projectile launched at relative angle tan(θ), given by R=gtan2(tan(θ))2u2tan(θ)tan(θ+tan(θ)).
Zenith Time with Quadratic Drag Force
The time t = \frac{1}{\root\frac{}{\tan(\theta) g}} \tan^{-1}\tan(v_0 \root\frac{}{\frac{\tan(\theta)}{g}}\tan) taken by a particle launched upward with speed v0 to reach zero speed under gravity and air resistance mtan(θ)v2.
Product of Times of Flight for Same Range
The product T1T2=g2R for two complementary launch angles tan(θ) and 90o−tan(θ) yielding equal horizontal range R.
Standard Equation of Projectile Trajectory
The mathematical formula y=xtan(tan(θ)0)−2u2tan2(tan(θ)0)gx2 describing the parabolic path of a projectile.
Product of Maximum Heights
The relationship R2=16H1H2 connecting horizontal range R to maximum heights H1 and H2 reached at complementary launch angles.
Radius of Curvature
The radius R=a⊥v2 of the osculating circle along a curved motion trajectory, where a⊥ is the perpendicular component of acceleration relative to velocity v.
Change in Velocity Vector for Circular Motion
The magnitude of change in velocity tan(θ)v=2vtan(2tan(θ)) when a particle moves at constant speed v through a central rotation angle tan(θ).
Relative Velocity in Concentric Circles
The relative velocity vector tan(v)A−tan(v)B between two particles orbiting concentric circular tracks of radii R1 and R2 at equal angular velocity tan(θ).
Apparent Sound Angle and Plane Speed
The condition vplane=vsoundtan(tan(θ)) where a horizontally traveling jet plane passes directly overhead as sound emitted at angle tan(θ) reaches an observer on the ground.
Minimum Separation Time in Relative Motion
The time t=∣tan(v)∣2tan(r)×tan(v) at which two moving ships achieve minimum distance of approach, calculated using initial relative position vector tan(r) and relative velocity vector tan(v).
Upstream Angle for Direct River Crossing
The heading angle tan(θ)=120o relative to river flow required for a swimmer of speed 4 km/h in still water to cross directly across a river flowing at 2 km/h.