exam 3 practice questions

B₂O₃ + 3 C + 3 Cl₂ → 3 CO + 2 BCl₃ This reaction is an acid-base reaction

False.

B₂O₃ + 3 C + 3 Cl₂ → 3 CO + 2 BCl₃ This reaction is a redox reaction

True.

B₂O₃ + 3 C + 3 Cl₂ → 3 CO + 2 BCl₃ This reaction is a disproportionation reaction

False.

AlF₃ + 3 KF → K₃[AlF₆] This reaction is an acid-base reaction

True.

AlF₃ + 3 KF → K₃[AlF₆] This reaction is a redox reaction

False.

The reaction of silicon tetrachloride and water to generate silicic acid and hydrochloric acid This reaction is a hydrolysis reaction

True.

The reaction of silicon tetrachloride and water to generate silicic acid and hydrochloric acid This reaction is a redox reaction

False.

The reaction of silicon tetrachloride and water to generate silicic acid and hydrochloric acid This reaction is a calcination reaction

False.

The reaction of silicon tetrachloride and water to generate silicic acid and hydrochloric acid This reaction is a hydrolysis reaction / This reaction is a redox reaction / This reaction is a calcination reaction / None of the above

Hydrolysis

The structure and properties of cubic BN are analogues to those of diamond (the cubic allotrope of carbon)

True.

Diamond, carbon nanotubes, graphite, Buckminster-fullerenes, and graphene are all allotropes of carbon

True.

SiO₂ contains four oxygen-silicon single bonds

True: each Si is bonded to four O atoms in the network.

Tin forms a covalent hydride

True: SnH₄.

It is most likely that BiI₅ is much less stable, if existing at all, than BiI₃

True.

PbO₂ is an oxidant but SiO₂ is not

True (under the ordinary conditions intended).

PH₃ can be expected to be a Lewis base

True.

SbCl₅ can be expected to be a Lewis acid

True.

P₄O₆ contains double bonds

False: its cage contains P–O single bonds.

SbCl₄ is the likely product between Sb and elemental Cl₂

False: the usual chlorides are SbCl₃ and SbCl₅, depending on conditions.

Considering the Frost diagram for N₂ and P₄ in acidic solutions shown: H₃PO₄ is a better oxidant than HNO₃.

False.

Considering the Frost diagram for N₂ and P₄ in acidic solutions shown: PH₃ is a reductant.

True.

Considering the Frost diagram for N₂ and P₄ in acidic solutions shown: The reaction H₃PO₂ → H₃PO₃ is an oxidation.

True: P changes from +1 to +3.

Considering the Frost diagram for N₂ and P₄ in acidic solutions shown: The formation of P₄ from H₃PO₃ is exothermic.

Cannot tell from a Frost diagram alone. It gives Gibbs free-energy information, not the enthalpy needed to identify an exothermic reaction.

Explain with very few words why CCl₄ is not a Lewis acid but SiCl₄ is:

SiCl₄ accepts electron pairs to form higher-coordinate adducts; larger Si can accommodate five or six ligands. CCl₄ does not readily form analogous stable adducts.

Explain very few words why the boiling point of SnCl₂ is 652°C but that of SnCl₄ is 114°C:

SnCl₂ has an extended, chloride-bridged structure with strong interactions; SnCl₄ consists of discrete molecules with weaker intermolecular attractions.