Grade 11 Spatial Geometry Review

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Flashcards covering spatial geometry concepts including plane intersections, line-plane intersections, collinearity, segment ratio formulas, Thales's theorem, tangent planes, perpendicularity, and cross-sections.

Last updated 9:09 AM on 10/4/26
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15 Terms

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Intersection line of two planes

The straight line formed where two non-parallel planes intersect, determined by finding 2 common points between the planes.

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Intersection point of a line and a plane

A single point AA where line dd meets plane (P)(P), satisfying A∈dA \in d and A∈(P)A \in (P), written as d∩(P)=Ad \cap (P) = A.

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Collinear points

Three or more points that all lie on the same straight line dd.

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Segment division ratio formula

If point MM divides segment ABAB such that AM:MB=m:nAM : MB = m : n, then AMAB=mm+n\frac{AM}{AB} = \frac{m}{m+n} and MBAB=nm+n\frac{MB}{AB} = \frac{n}{m+n}.

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Thales's Theorem in Spatial Geometry

In △ABC\triangle ABC, if line MNMN is parallel to side BCBC with M∈ABM \in AB and N∈ACN \in AC, then AMAB=ANAC=MNBC\frac{AM}{AB} = \frac{AN}{AC} = \frac{MN}{BC}.

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Converse of Thales's Theorem

In △ABC\triangle ABC, if points M∈ABM \in AB and N∈ACN \in AC satisfy AMAB=ANAC\frac{AM}{AB} = \frac{AN}{AC}, then MN∥BCMN \parallel BC.

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Tangent plane

A plane (P)(P) that touches a sphere (S)(S) at exactly 1 point AA, known as the point of tangency.

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Distance from center to tangent plane

The perpendicular distance from the center OO of a sphere to its tangent plane (P)(P), which equals the radius RR (d(O,(P))=OA=Rd(O, (P)) = OA = R).

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Perpendicularity condition for line and plane

A line dd is perpendicular to plane (P)(P) if dd is perpendicular to two intersecting lines aa and bb contained in (P)(P), written as d⊥(P)d \perp (P).

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Cross-section (Thiết diện)

The closed 2D planar polygon figure formed by the intersection of a cutting plane with a 3D solid figure.

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Parallel cross-section property

If a cutting plane (P)(P) is parallel to base (ABCD)(ABCD) of a solid, the resulting cross-section is similar to the base shape.

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Cross-section ratio property

For a pyramid cross-section with line MNMN parallel to base side ABAB, the side ratios satisfy SMSA=SNSB=MNAB\frac{SM}{SA} = \frac{SN}{SB} = \frac{MN}{AB}.

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Procedure for finding a cross-section

A 4-step method: 1) Identify the cutting plane, 2) Find intersection points with solid edges, 3) Connect points lying on the same face, 4) Close the figure.

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Two-plane intersection rule

Two non-parallel planes intersect along a single line defined by 2 common points.

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Line-plane intersection rule

A line and a plane intersect at a single common point.