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∫ du
u+c
∫ un du
(un+1/n+1)+c
∫ u-1 du
ln|u| +c
∫ cos(u) du
sin(u) +c
∫ sin(u) du
-cos +c
∫ sec2(u) du
tan(u) +c
∫ csc2(u) du
-cot(u) +c
∫ sec(u)tan(u) du
sec(u) +c
∫ csc(u)cot(u) du
-csc(u) +c
∫ eu du
eu +c
∫ au du
au/ln(a) +c
∫ ln(u) du
u ln(u)-u +c
∫ loga(u) du
(u ln(u)-u)/ ln(a) +c
∫ tan(u) du
ln|sec(x)| +c or -ln|cos(x)| +c
Euler’s Method (notation)
xnew = xold+∆x
ynew= yold+∆y(dy/dx|xold,yold)
Solving differential equations
seperate the variable
integrate both sides
if general solution→+c, if particular solution,→find c
solve for y
Simpson’s rule
S=h/3(Y0+4Y1+2Y2+… 2Yn-1+Yn)
Mean Value Theroem
if f is continuous on the interval [a,b] and differentiable on (a,b), then there exists some value x=c on (a,b) where f’(c)=(f(b)-f(a))/(b-a)
when finding antiderivaties
don’t forget +c
Inflection points
where concavity changes; f’’(x) changes signs
solving related rates
differentiate implicitly with respect to time (d/dt)
area by Riemann sums (rectangles)
k=1∑nf(Ck)·∆Xk LRAM, RRAM,MRAM
Integral Notation
a∫b f(x)dx
Integrals
Area between the curve and x-axis
a∫b c dx
c(b-a)
a∫b k·f(x)dx
k·a∫b f(x)dx
a∫b (f(x)±g(x))dx
a∫b f(x)dx ± a∫b g(x)dx
Average Value of a Function
1/(b-a) · a∫b f(x)dx
MVT of integrals
if f is continuous on [a,b], then at some point c in [a,b] f(c)=1/(b-a) · a∫b f(x)dx
Fundamental theorem of Calc (Part 1)
d/dx · a∫x f(t)dt = f(x) if
derivative of an integral
derivative variable matches upper limit
lower limit is a constant
Fundamental theorem of Calc (Part 2)
a∫b f(x)dx= [F(x)]ba=F(b)-F(a)
Trapezoid Rule
T=h/2(Y0+2Y1+2Y2…+2Yn-1+Yn)
d/dx(u·v) (product rule)
u·dv/dx + v·du/dx
d/dx(u/v) (quotient rule)
(v·du/dx - u·dv/dx)/v2
Position
Velocity
Acceleration
s(t)
v(t)=s’(t)
a(t)=v’(t)=s”(t)
Speed
|v(t)|
d/dx sin(x)
cos(x)
d/dx cos(x)
-sin(x)
d/dx tan(x)
sec2(x)
d/dx cot(x)
-csc2(x)
d/dx sec(x)
sec(x)tan(x)
d/dx csc(x)
-csc(x)cot(x)
Derivative of aCompund Function (chain rule)
f’(g(x))·g’(x)
Slope of Parametric Equations
dy/dx = (dy/dt)/(dx/dt)
Implicit differentiation
dy/dx everything
anytime you have a “y”, tack on a dy/dx
put all the dy/dx on the same side and solve for dy/dx
d/dx sin-1(u)
1/√/(1-u2)·dy/dx
d/dx cos-1(u)
-1/√/(1-u2)·dy/dx
d/dx tan-1(u)
1/√(1+u2) · du/dx
d/dx cot-1(u)
-1/√(1+u2) · du/dx
d/dx sec-1(u)
1/(|u|·√(u2-1)) · du/dx
d/dx csc-1(u)
-1/(|u|·√(u2-1)) · du/dx
Derivatives for inverses (let f(x) and g(x) be inverses)
the slopes are reciprocals at inverse points
df-1/dx|x=f(a) = 1/(df/dx)|x=a
d/dx eu
eu · du/dx
d/dx au
au ·ln u · du/dx
d/dx ln u
1/u · du/dx
d/dx loga u
1/(u·ln a) ·du/dx
Extreme Value Theorem
if a function is continuous on a closed interval [a,b] the function will have both a max and a min
critical points (if f is continuous)
any interior point where f’(x) = 0 or DNE
Max and Min can occur at
endpoints or critical points if f’(x) changes sign
limx→c f(x)
if f(x) is nice(no holes/asymptotes)
let x=c, substitute and simplify
if limx→c- f(x) = limx→c+ f(x)
then limx→c exists
Finding horizontal asymptotes
end behavior; find limx→∞ f(x) and limx→-∞ f(x)
Finding Vertical Asymptotes
Find x-values not in domain
the limit at that spot from either side = ±∞