Calc gold sheets

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64 Terms

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∫ du

u+c

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∫ un du

(un+1/n+1)+c

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∫ u-1 du

ln|u| +c

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∫ cos(u) du

sin(u) +c

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∫ sin(u) du

-cos +c

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∫ sec2(u) du

tan(u) +c

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∫ csc2(u) du

-cot(u) +c

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∫ sec(u)tan(u) du

sec(u) +c

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∫ csc(u)cot(u) du

-csc(u) +c

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∫ eu du

eu +c

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∫ au du

au/ln(a) +c

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∫ ln(u) du

u ln(u)-u +c

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∫ loga(u) du

(u ln(u)-u)/ ln(a) +c

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∫ tan(u) du

ln|sec(x)| +c or -ln|cos(x)| +c

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Euler’s Method (notation)

xnew = xold+∆x

ynew= yold+∆y(dy/dx|xold,yold)

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Solving differential equations

  1. seperate the variable

  2. integrate both sides

  3. if general solution→+c, if particular solution,→find c

  4. solve for y


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Simpson’s rule

S=h/3(Y0+4Y1+2Y2+… 2Yn-1+Yn)

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Mean Value Theroem

if f is continuous on the interval [a,b] and differentiable on (a,b), then there exists some value x=c on (a,b) where f’(c)=(f(b)-f(a))/(b-a)

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when finding antiderivaties

don’t forget +c

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Inflection points

where concavity changes; f’’(x) changes signs

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solving related rates

differentiate implicitly with respect to time (d/dt)

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area by Riemann sums (rectangles)

k=1∑nf(Ck)·∆Xk LRAM, RRAM,MRAM

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Integral Notation

a∫b f(x)dx

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Integrals

Area between the curve and x-axis

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a∫b c dx

c(b-a)

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a∫b k·f(x)dx

k·a∫b f(x)dx

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a∫b (f(x)±g(x))dx

a∫b f(x)dx ± a∫b g(x)dx

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Average Value of a Function

1/(b-a) · a∫b f(x)dx

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MVT of integrals

if f is continuous on [a,b], then at some point c in [a,b] f(c)=1/(b-a) · a∫b f(x)dx

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Fundamental theorem of Calc (Part 1)

d/dx · a∫x f(t)dt = f(x) if

  1. derivative of an integral

  2. derivative variable matches upper limit

  3. lower limit is a constant


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Fundamental theorem of Calc (Part 2)

a∫b f(x)dx= [F(x)]ba=F(b)-F(a)

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Trapezoid Rule

T=h/2(Y0+2Y1+2Y2…+2Yn-1+Yn)

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d/dx(u·v) (product rule)

u·dv/dx + v·du/dx

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d/dx(u/v) (quotient rule)

(v·du/dx - u·dv/dx)/v2

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Position

Velocity

Acceleration

s(t)

v(t)=s’(t)

a(t)=v’(t)=s”(t)

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Speed

|v(t)|

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d/dx sin(x)

cos(x)

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d/dx cos(x)

-sin(x)

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d/dx tan(x)

sec2(x)

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d/dx cot(x)

-csc2(x)

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d/dx sec(x)

sec(x)tan(x)

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d/dx csc(x)

-csc(x)cot(x)

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Derivative of aCompund Function (chain rule)

f’(g(x))·g’(x)

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Slope of Parametric Equations

dy/dx = (dy/dt)/(dx/dt)

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Implicit differentiation

  1. dy/dx everything

  2. anytime you have a “y”, tack on a dy/dx

  3. put all the dy/dx on the same side and solve for dy/dx


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d/dx sin-1(u)

1/√/(1-u2)·dy/dx

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d/dx cos-1(u)

-1/√/(1-u2)·dy/dx

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d/dx tan-1(u)

1/√(1+u2) · du/dx

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d/dx cot-1(u)

-1/√(1+u2) · du/dx

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d/dx sec-1(u)

1/(|u|·√(u2-1)) · du/dx

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d/dx csc-1(u)

-1/(|u|·√(u2-1)) · du/dx

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Derivatives for inverses (let f(x) and g(x) be inverses)

the slopes are reciprocals at inverse points

df-1/dx|x=f(a) = 1/(df/dx)|x=a

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d/dx eu

eu · du/dx

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d/dx au

au ·ln u · du/dx

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d/dx ln u

1/u · du/dx

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d/dx loga u

1/(u·ln a) ·du/dx

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Extreme Value Theorem

if a function is continuous on a closed interval [a,b] the function will have both a max and a min

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critical points (if f is continuous)

any interior point where f’(x) = 0 or DNE

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Max and Min can occur at

endpoints or critical points if f’(x) changes sign

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limx→c f(x)

if f(x) is nice(no holes/asymptotes)

let x=c, substitute and simplify

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if limx→c- f(x) = limx→c+ f(x)

then limx→c exists

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Finding horizontal asymptotes

end behavior; find limx→∞ f(x) and limx→-∞ f(x)

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Finding Vertical Asymptotes

Find x-values not in domain

the limit at that spot from either side = ±∞