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Math L3&4 Coordinate Geometry
Math L3&4 Coordinate Geometry
Coordinate Geometry
Coordinate Plane and Points
The coordinate plane consists of two perpendicular lines: the x-axis (horizontal) and the y-axis (vertical).
The intersection of the x and y axes is the origin, denoted as O.
The axes divide the plane into four quadrants (I, II, III, IV).
Points are defined by coordinates (x, y), where x is the horizontal distance from the origin and y is the vertical distance from the origin.
In quadrant I, both x and y are positive (+, +).
In quadrant II, x is negative and y is positive (-, +).
In quadrant III, both x and y are negative (-, -).
In quadrant IV, x is positive and y is negative (+, -).
Distance, Midpoint, and Gradient
Distance Between Points
: The distance d between points P(x
1, y
1) and Q(x
2, y
2) is given by: d = \sqrt{(x
2 - x
1)^2 + (y
2 - y
1)^2}.
Midpoint of a Line
: The midpoint M of a line segment joining points A(x
1, y
1) and B(x
2, y
2) is: M = (\frac{x
1 + x
2}{2}, \frac{y
1 + y
2}{2}).
Gradient (Slope)
: The gradient m of a line segment joining points A(x
1, y
1) and B(x
2, y
2) is: m = \frac{y
2 - y
1}{x
2 - x
1}.
Parallel lines have equal gradients: m
1 = m
2.
Perpendicular lines have gradients that satisfy: m
1m
2 = -1.
Equation of a Straight Line
Point-Slope Form
: y - y
1 = m(x - x
1)
Slope-Intercept Form
: y = mx + c, where m is the slope and c is the y-intercept.
Standard Form
: ax + by = c
Collinearity
: Points P, Q, R are collinear if the gradient of PQ equals the gradient of QR equals the gradient of PR.
Systems of Linear Inequalities
To graph inequalities, first plot the corresponding equation as a line (dotted for strict inequalities, solid for inclusive inequalities).
Determine which side of the line to shade by testing a point (e.g., (0, 0)) in the inequality.
If the point satisfies the inequality, shade that side; otherwise, shade the opposite side.
For systems of inequalities, the solution is the region that satisfies all inequalities simultaneously.
Area of a Triangle
The area A of a triangle with vertices (x
1, y
1), (x
2, y
2), and (x
3, y
3) is given by:
A = \frac{1}{2} |x
1y
2 + x
2y
3 + x
3y
1 - x
2y
1 - x
3y
2 - x
1y
3|
If the area is zero, the points are collinear.
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