CO4-Lesson 1 - Inverse Trigonometric Functions

MAPÚA UNIVERSITY MATH04 PreCalculus Course Outcome 4

  • Lesson 1: Inverse Trigonometric Functions

Inverse Trigonometric Functions

  • Definition: If 𝑓 is a one-to-one function with domain 𝑨 and range 𝑩, then its inverse 𝑓⁻¹ has domain 𝑩 and range 𝑨, defined by 𝑓⁻¹(π‘₯) iff 𝑓(𝑦) = π‘₯.

Characteristics of Inverse Trigonometric Functions

  • One-to-One Requirement: For a function to have an inverse, it must be one-to-one.

  • Trigonometric Functions: Standard trigonometric functions are not one-to-one, thus do not initially have inverses.

  • Domain Restriction: Trigonometric functions must have restricted domains to become one-to-one and achieve their inverses.

Inverse Sine Function and Its Graph

  • Expression: 𝑦 = sin⁻¹(π‘₯) iff π‘₯ = sin(𝑦).

  • Domain: [βˆ’1, 1]

  • Range: [βˆ’πœ‹/2, πœ‹/2]

  • Graph characteristics:

    • -𝜏/2 to 𝜏/2 is the essential portion.

Inverse Cosine Function and Its Graph

  • Expression: 𝑦 = cos⁻¹(π‘₯) iff π‘₯ = cos(𝑦).

  • Domain: [βˆ’1, 1]

  • Range: [0, πœ‹]

  • Graph features:

    • Function is defined on a range between 0 and πœ‹.

Inverse Tangent Function and Its Graph

  • Expression: 𝑦 = tan⁻¹(π‘₯) iff π‘₯ = tan(𝑦).

  • Domain: (βˆ’βˆž, ∞)

  • Range: (βˆ’πœ‹/2, πœ‹/2)

  • Graph spans all real values for π‘₯,

    • Essential range between βˆ’πœ‹/2 and πœ‹/2.

Inverse Cotangent Function and Its Graph

  • Expression: 𝑦 = cot⁻¹(π‘₯) iff π‘₯ = cot(𝑦).

  • Domain: (βˆ’βˆž, ∞)

  • Range: (0, πœ‹)

Inverse Secant Function and Its Graph

  • Expression: 𝑦 = sec⁻¹(π‘₯) iff π‘₯ = sec(𝑦).

  • Domain: (βˆ’βˆž, -1] U [1, ∞)

  • Range: [0, πœ‹], y β‰  πœ‹/2

Inverse Cosecant Function and Its Graph

  • Expression: 𝑦 = csc⁻¹(π‘₯) iff π‘₯ = csc(𝑦).

  • Domain: (βˆ’βˆž, -1] U [1, ∞)

  • Range: [βˆ’πœ‹/2, πœ‹/2], y β‰  0

Domain and Range of Inverse Functions

  • Various inverses with specific domains/ranges:

    • y = sin⁻¹(π‘₯): Domain [βˆ’1, 1], Range [βˆ’πœ‹/2, πœ‹/2]

    • y = cos⁻¹(π‘₯): Domain [βˆ’1, 1], Range [0, πœ‹]

    • y = tan⁻¹(π‘₯): Domain (βˆ’βˆž, ∞), Range (βˆ’πœ‹/2, πœ‹/2)

Evaluating Inverse Trigonometric Functions

  • Process: Find an angle such that the trigonometric function of that angle equals π‘₯ within the range of the inverse function.

    • Example: sin⁻¹(1/2) = πœ‹/6 because sin(πœ‹/6) = 1/2.

  • Evaluation Guide: Use images for common special angles to help derive values.

Special Angles and Values

  • Remember trigonometric values for frequently referenced angles in evaluation:

    • 30Β°: sin = 1/2, cos = √3/2;

    • 45Β°: sin = √2/2, cos = √2/2;

    • 60Β°: sin = √3/2, cos = 1/2;

  • Reference expanded tables for angles.

Compositions of Functions

  • Inverse function properties:

    • 𝑓(𝑓⁻¹(π‘₯)) = π‘₯ and 𝑓⁻¹(𝑓(π‘₯)) = π‘₯.

  • Caution with specific ranges: arcsin(sin(3πœ‹/2)) β‰  3πœ‹/2; valid only if y is in the interval [βˆ’πœ‹/2, πœ‹/2].

Practice Examples

  • Various evaluations showcasing the use of inverse formulas, considering the domains and special angles for accurate results.

  • Application of properties involving inverse identities in specific situations:

    • sin⁻¹(sin(5Ο€/3)) and solving compositions examples.

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