Course Title: Engineering Mechanics: Dynamics, Fifteenth Edition
Chapter Focus: Planar Kinetics of a Rigid Body: Force and Acceleration
Copyright: Copyright © 2022 Pearson Education, Inc. All Rights Reserved
Today’s Objectives:
Determine the mass moment of inertia of rigid bodies.
In-Class Activities:
Check Homework
Reading Quiz
Applications
Mass Moment of Inertia
Parallel-Axis Theorem
Composite Bodies
Concept Quiz
Group Problem Solving
Attention Quiz
Quiz Questions:
Mass moment of inertia measures the resistance of a body to:A) Translational motionB) DeformationC) Angular accelerationD) Impulsive motion
Mass moment of inertia is always:A) A negative quantityB) A positive quantityC) An integer valueD) Zero about an axis perpendicular to the plane of motion
Flywheel Example:
A flywheel connected to a cutter provides uniform motion to the cutting blade.
Important Property: Mass moment of inertia, as mass is most impactful when concentrated near the circumference.
Crank Example:
The crank on an oil-pump rig develops kinetic energy related to mass moment of inertia.
Inquiry: Is the mass moment of inertia about the rotation axis larger or smaller than about its center of mass?
Definition: Mass moment of inertia (MMI) measures a body's resistance to angular acceleration.
Equation: ( T = I \cdot \alpha )
where ( T ) is the torque, ( I ) is the mass moment of inertia about the z-axis, and ( \alpha ) is angular acceleration.
General Formula:
( I = \int r^2 dm )
where ( r ) is the moment arm (perpendicular distance from the axis).
Units: kg⋅m² or slug⋅ft².
Direct Integration:
Focus on symmetric bodies generated by revolving curves.
Shell Element:
Volume element: ( dV = 2 \pi y z dy )
Disk Element:
Volume element: ( dV = \pi y^2 dz )
Mass moment of inertia about a parallel axis: [ I = I_G + md^2 ]
where ( I_G ) is the MMI about the mass center, ( m ) is mass, and ( d ) is the distance between axes.
Radius of Gyration ( (k) ): Measures mass distribution about an axis.
[ I = mk^2 ]
Composite Bodies: MMI can be found by summing individual moments for simple shapes.
Example I: Determine MMI about the y-axis for a given volume.
Example II: Calculate the radius of gyration for a pendulum consisting of a slender rod and a circular plate.
Questions:
The mass moment of inertia of a rod about a transverse axis at its end is: A) ( \frac{1}{12} m L^2 ) B) ( \frac{1}{6} m L^2 ) C) ( \frac{1}{3} m L^2 ) D) ( m L^2 )
The mass moment of inertia of a thin ring about the z-axis is: A) ( \frac{1}{2} m R^2 ) B) ( m R^2 ) C) ( \frac{1}{4} m R^2 ) D) ( 2m R^2 )
Example of a Pendulum:
Given masses of parts, determine radius of gyration using MMI and mass values.
MMI calculations require the use of the parallel-axis theorem.
Example II: Calculate MMI for a composite wheel comprising rings and rods using MMI data and ensure calculations reflect distance from either the center or parallel axes.
Questions:
Mass moment of inertia about the center of mass is always:A) MaximumB) MinimumC) ZeroD) None of the above
For equal mass bodies A and B, if ( k_A ) and ( k_B ) are radii of gyration, then:A) ( I_A = I_B )B) ( I_A = \frac{1}{2} I_B )C) ( I_A = 4 I_B )D) ( I_A = \frac{1}{4} I_B )
This content is protected by U.S. copyright laws and available exclusively for instructional use.