Formula: Ohm's Law: V = I * R
Example Problem: A circuit has a resistance of 10 ohms and the voltage supply is 20 volts. What is the current flowing through the circuit?
Solution:
Using Ohm's Law: V = I * R
Rearranging gives us: I = V / R
Current, I = 20V / 10Ω = 2A
Formula: Power Dissipation: P = I² * R
Example Problem: If the current through a resistor is 3A and the resistance is 5 ohms, what is the power dissipated by the resistor?
Solution:
P = I² * R
P = (3A)² * 5Ω = 9 * 5 = 45 Watts
Formula: Ohm's Law: I = V / R
Example Problem: A circuit section has a voltage of 15 volts and a resistance of 3 ohms. What is the current?
Solution:
I = V / R
I = 15V / 3Ω = 5A
Formula: Kirchhoff's Voltage Law: ΣV = 0
Example Problem: In a loop, you measure voltage sources of 10V and 5V, and drop across resistors of 4V and 6V. Verify if the circuit obeys Kirchhoff's Law.
Solution:
ΣV = 10V - 4V - 5V - 6V = -5V
The sum should equal zero; thus, the measured values indicate an error in circuit design.
Formula: Current: I = V / R
Example Problem: A circuit with a supply voltage of 12V causes a short with negligible resistance. What would be the current?
Solution:
I = V / R
If we assume R approaches 0 (hypothetical), I would approach infinity, indicating a fault in the circuit that needs to be addressed.