Examine inheritance of two traits simultaneously (e.g.
EeVv \times EeVv)
F1 gametes (if genes assort independently): EV,\ Ev,\ eV,\ ev
Punnett square (4×4) → phenotypic ratio 9:3:3:1 for
dominant–dominant : dominant–recessive : recessive–dominant : recessive–recessive
Independent Assortment (Unlinked Genes)
Genes on different chromosomes (or far apart on same chromosome) segregate
independently during meiosis
Dihybrid test cross with unlinked genes (heterozygote BbLl × double‐recessive
bbll) yields 1:1:1:1 phenotypic ratio
Linked Genes
Located close together on the same chromosome → tend to be inherited together
Parental gametes far more frequent than recombinant gametes
Example (rabbit): B = black fur, L = long hair
• Parental chromosomes in heterozygote: \text{BL/bl}
• Test cross BL/bl \times bl/bl gave offspring counts \approx 47\% BL (black-long), \approx 47\% bl (non-black-short), \approx 3\% B l, \approx 3\% b L → linkage confirmed
Dihybrid Test Cross
Definition: cross of double-heterozygote with double-recessive
Uses:
• Detect linkage (deviation from 1:1:1:1)
• Calculate map distance (see below)
Gene Mapping (Map Units / cM)
Recombination frequency = \dfrac{#\,\text{recombinants}}{\text{total offspring}} \times 100
1\,\text{map unit (centiMorgan)} = 1\% recombination
Independent assortment F2 phenotype: 9:3:3:1 (self-cross of dihybrid)
Probability for one specified combo (e.g. black solid dog from BbSs \times BbSs):
P(black) = 3/4;\ P(solid) = 3/4;\ P(black \cap solid) = 3/4 \times 3/4 = 9/16
Test cross with unlinked genes: 1:1:1:1
Problem-Solving Steps
Identify dominance relationships for each gene.
Determine whether genes are linked (use test-cross data).
List possible gametes (consider linkage and crossing-over).
Construct Punnett square or use probability rules.
Derive genotype & phenotype ratios; calculate recombination % if needed.
Terminology
F_1: first filial generation (offspring of parental cross)
Parental vs recombinant types: phenotypes matching vs differing from parents
CentiMorgan (cM): unit of genetic distance equal to 1\% recombination
Wild type: most common phenotype/allele in natural populations