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Dihybrid Crosses & Linked Genes

Dihybrid Crosses

  • Examine inheritance of two traits simultaneously (e.g.
    EeVv \times EeVv)
  • F1 gametes (if genes assort independently): EV,\ Ev,\ eV,\ ev
  • Punnett square (4×4) → phenotypic ratio 9:3:3:1 for
    dominant–dominant : dominant–recessive : recessive–dominant : recessive–recessive

Independent Assortment (Unlinked Genes)

  • Genes on different chromosomes (or far apart on same chromosome) segregate
    independently during meiosis
  • Dihybrid test cross with unlinked genes (heterozygote BbLl × double‐recessive
    bbll) yields 1:1:1:1 phenotypic ratio

Linked Genes

  • Located close together on the same chromosome → tend to be inherited together
  • Parental gametes far more frequent than recombinant gametes
  • Example (rabbit): B = black fur, L = long hair
    • Parental chromosomes in heterozygote: \text{BL/bl}
    • Test cross BL/bl \times bl/bl gave offspring counts \approx 47\% BL (black-long), \approx 47\% bl (non-black-short), \approx 3\% B l, \approx 3\% b L → linkage confirmed

Dihybrid Test Cross

  • Definition: cross of double-heterozygote with double-recessive
  • Uses:
    • Detect linkage (deviation from 1:1:1:1)
    • Calculate map distance (see below)

Gene Mapping (Map Units / cM)

  • Recombination frequency = \dfrac{#\,\text{recombinants}}{\text{total offspring}} \times 100
  • 1\,\text{map unit (centiMorgan)} = 1\% recombination
  • Previous rabbit data: (2+3)/100 \approx 5\% → genes \approx 5\, map units apart

Key Ratios & Probabilities

  • Independent assortment F2 phenotype: 9:3:3:1 (self-cross of dihybrid)
  • Probability for one specified combo (e.g. black solid dog from BbSs \times BbSs):
    P(black) = 3/4;\ P(solid) = 3/4;\ P(black \cap solid) = 3/4 \times 3/4 = 9/16
  • Test cross with unlinked genes: 1:1:1:1

Problem-Solving Steps

  1. Identify dominance relationships for each gene.
  2. Determine whether genes are linked (use test-cross data).
  3. List possible gametes (consider linkage and crossing-over).
  4. Construct Punnett square or use probability rules.
  5. Derive genotype & phenotype ratios; calculate recombination % if needed.

Terminology

  • F_1: first filial generation (offspring of parental cross)
  • Parental vs recombinant types: phenotypes matching vs differing from parents
  • CentiMorgan (cM): unit of genetic distance equal to 1\% recombination
  • Wild type: most common phenotype/allele in natural populations