Chapter 16 Flashcards
16.1-16.3 Common Ion Effect, Buffer Solutions
Common Ion Effect
- The presence of a common ion suppresses the ionization of a weak acid or weak base.
- This phenomenon can be understood through Le Chatelier’s Principle.
- For example, consider what happens to the concentration when is added to a solution of .
Example Calculation: Common Ion Effect
- Calculate the pH of a 0.30 M solution. Also, calculate the pH of a solution containing 0.30 M and 0.20 M . The of is .
Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation simplifies solutions involving the common ion effect.
It assumes that the is small compared to the initial concentration of the acid/conjugate base.
Example Calculation : Henderson-Hasselbalch Equation
- What is the pH of a solution containing 0.5 M and 0.2 M ? The for . To solve for pH, first find pOH with the Henderson-Hasselbalch equation, then convert
Buffer Solutions
- Buffers are chemical systems that resist pH changes by neutralizing added acid or base.
- A buffer contains significant amounts of both a weak acid and its conjugate base (or a weak base and its conjugate acid).
- The weak acid neutralizes added base.
- The conjugate base neutralizes added acid.
- Examples:
Action of a Buffer
- Buffers work through equilibrium. When acid is added, it shifts towards the production of HA. When base is added, it shifts towards the production of .
Calculating pH Changes in Buffers
A 2.0L buffer solution contains 0.1 mol of and 0.1 mol of . The value of for is . Calculate the pH of the buffer:
- First calculate the pH of the buffer before adding KOH. This can be done using the Henderson-Hasselbalch equation:
- First calculate the pH of the buffer before adding KOH. This can be done using the Henderson-Hasselbalch equation:
0. 010 moles of solid KOH are added to the buffer. Calculate the new pH of the buffer:
- Then, calculate the new pH of the buffer after adding KOH. Because you are adding a strong base to a weak acid, this will change the concentration. Treat it like a limiting reagent, so subtract the 0.01 moles from the moles of and add it to the moles of , then do the Henderson-Hasselbalch equation again with the new values.
For comparison, calculate the pH of a 0.01 M solution of just KOH in pure water:
- First, since , , so
Buffer Effectiveness
- Buffer Capacity: The amount of acid or base it can effectively neutralize.
- Most effective when the concentrations of acid and conjugate base are equal.
- Most effective when the concentrations of acid and conjugate base are high.
- Example: A 1.0L buffer solution is 1.0 M in HF and 0.050 M in NaF. Which action will destroy the buffer?
- A) adding 0.05 mol of HCl
- B) adding 0.05 mol of NaF
- C) adding 0.050 mol of NaOH
- The correct answer is C) adding 0.050 mol of NaOH because NaOH will neutralize HF, turning it into . Because is already at 0.050 M, adding 0.050 mol of NaOH will overwhelm the buffering system.
- D) None of the above
Buffer Range
- Buffer Range: The pH range over which a particular acid and conjugate base can be effective.
- The effective range for a buffering system is generally one pH unit on either side of the .
Preparing a Buffer
- Which acid would you choose to combine with its sodium salt to make a solution buffered at pH 4.25?
- 1.
- 2.
- 3.
- 4.
- The best choice would be #3 since it is closest to 4.25
- For the best choice, calculate the ratio of the conjugate base to the acid required to attain the desired pH.