2025 9 Kinetic Molecular Theory

Kinetic Molecular Theory

  • Describes the behavior of gases

  • Key assumptions include:

    • Gas molecules have tiny volumes compared to the collective volume they occupy.

    • They move constantly and randomly.

    • Average kinetic energy is proportional to absolute temperature; at a given temperature, all gases have the same average kinetic energy.

    • Gas molecules engage in elastic collisions with the walls of their container and with each other.

    • They act independently of each other.

Pressure

Definition

  • Pressure (P) is defined as the ratio of force (F) exerted on a surface to the area (A) of that surface:[ P = \frac{F}{A} ]

  • Atmospheric pressure is the force exerted by gases surrounding the Earth on its surface.

Units of Pressure

  • SI units: (\text{Newton/meter}^2 = 1 \text{ Pascal (Pa)})

  • Common conversions:

    • 1 atm = 101,325 Pa

    • 1 atm = 760 mmHg = 760 torr

Converting Units of Pressure

Table of Units

Unit

Conversion

Atmosphere (atm)

1 atm

Millimeter of mercury (torr)

1 atm = 760 mmHg

Pounds per square inch (psi)

1 atm = 14.7 psi

Inches of mercury

1 atm = 29.92 inches of Hg

Boyle’s Law: Relating Pressure and Volume

Principle

  • Pressure increases with the rate of molecular collisions.

  • Gases are compressible: volume decreases as pressure increases.

  • Boyle's Law states that for a constant temperature and number of moles, (PV = \text{constant}).

    • The value of the constant depends on the amount of gas and temperature.

Application

  • The product (PV) remains unchanged for a given mass of gas at constant temperature:[ P_1V_1 = P_2V_2 ]

  • Example: Used in gas cylinders for scuba diving.

Practice: Boyle’s Law

Calculating Volume Change

  • Given:

    • Initial volume (V_1 = 5.00 L)

    • Initial pressure (P_1 = 1.00 atm)

    • Final pressure (P_2 = 0.83 atm)

  • Find final volume (V_2) using Boyle's Law:[ V_2 = \frac{P_1V_1}{P_2} = \frac{(1.00)(5.00)}{0.83} = 6.0 L ]

Charles’s Law: Relating Volume and Temperature

Principle

  • Charles's Law states that for a fixed quantity of gas at constant pressure, the volume is directly proportional to its temperature (in Kelvin):[ V \propto T ]

Practice: Charles's Law

Example Problem

  • Initial volume (V_1 = 2.00 L), increased to (V_2 = 3.00 L) at initial temperature (T_1 = 15°C = 288 K).

  • Solve for final temperature (T_2) using:[ T_2 = \frac{V_2 T_1}{V_1} = \frac{(3.00)(288)}{2.00} = 432 K]

  • Convert (T_2) to Celsius: (T_2 = 432 - 273 = 159°C]

Avogadro’s Law: Relating Volume and Moles (n)

  • States that volume is directly proportional to the number of moles of gas:[ V \propto n ]

  • Increase in moles results in an increase in volume, demonstrating the expansion of gas.

Amonton’s Law: Relating Pressure and Temperature

  • Demonstrates that pressure is proportional to temperature at constant volume:[ P \propto T ]

  • Higher temperatures increase the average velocity of gas molecules, increasing pressure.

Ideal Gas Law

Equation

  • The ideal gas law combines all the above relationships into:[ PV = nRT ]

    • Where:

      • (R = 0.08206 , L , atm/(K , mol))

      • (n = \text{moles of gas})

      • (T = \text{temperature in Kelvin})

Practice: Ideal Gas Law

Example Problem

  • Calculate pressure of 1.2 mol of methane in a 3.3 L container at 25°C (298 K).[ P = \frac{(1.2)(0.08206)(298)}{3.3} = 8.9 , atm ]

Combined Gas Law

  • Combines various gas laws:

    • [ \frac{PV}{T} = \text{constant} ]

  • Represents the relationships between pressure, volume, and temperature of gases.

Reference Points for Gases

Standard Temperature and Pressure (STP)

  • Defined as:

    • P = 1 atm; T = 273 K (0.0 °C)

  • Molar volume of one mole of an ideal gas at STP is 22.4 L.

Practice: Stoichiometry Calculations

Example Problem

  • Determine grams of NaClO3 needed to produce 125 L of O2 gas at 20.0 °C and 1.00 atm.

  • Using ideal gas equation and stoichiometry,

    • Required (5.20 , mol O2) leads to (553 , g NaClO3).

Graham’s Law of Effusion and Diffusion

Definitions

  • Effusion: Gas escaping through a tiny hole.

  • Diffusion: Spread of one substance through another.

  • Faster moving molecules diffuse and effuse more quickly.

Application of Graham's Law

  • The diffusion rate of a gas is inversely proportional to the square root of its molar mass:[ r \propto \frac{1}{\sqrt{M}} ]

Real vs. Ideal Gases

  • Ideal gas assumptions break down at high pressures and low volumes, where attractions between molecules become significant.

Summary

Practice Problems

  • Helium balloon in hot trunk

  • Balloon expands due to increased temperature (Charles’s Law).

  • Helium tank pressure increases with temperature (Amonton’s Law).

  • Kinetic energy of gas atoms increases with temperature; they move faster and collide more with the tank.

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