If P(A) = 0.0084, find the value of P(A) (This is already given as 0.0084).
In an Algebra class, there are:
32 STEM majors
27 non-STEM majors
12 STEM majors are sophomores; rest are freshmen
17 non-STEM majors are freshmen
Total students = 32 + 27 = 59
a. The probability that the student is a STEM major:
P(STEM) = (Number of STEM majors) / (Total students) = 32 / 59 b. The probability that the student is a freshman non-STEM major:
P(Freshman Non-STEM) = (Number of Freshman Non-STEM) / (Total students) = 17 / 59 c. The probability that the student is a sophomore:
P(Sophomore) = (Number of Sophomores) / (Total students) = 12 / 59 d. The probability that the student is a freshman STEM major or a sophomore non-STEM major:
Freshman STEM = 32 - 12 = 20
Total = Freshman STEM + Sophomore Non-STEM = 20 + 27 - 17 = 30
P(Freshman STEM or Sophomore Non-STEM) = 30 / 59
In a batch of 36 cookies, 4 are not cooked all the way. If 2 cookies are selected without replacement, find the probability that both are not cooked:
P(both not cooked) = (4/36) * (3/35) = 12/1260 = 1/105
For two contracts assigned to firms X, Y, Z:
(X, X), (X, Y), (X, Z)
(Y, X), (Y, Y), (Y, Z)
(Z, X), (Z, Y), (Z, Z)
There are 3 outcomes where both contracts go to the same firm out of 9 total.
P(both contracts same firm) = 3/9 = 1/3
Outcomes where Z gets at least one contract: (Z,X), (Z,Y), (Z,Z), (X,Z), (Y,Z) = 5 outcomes
P(Z gets at least one) = 5/9
A bag contains: 5 green, 4 red, 2 white, and 3 blue marbles.
a. The probability of drawing a green marble:
P(Green) = 5/14 b. The probability of drawing a blue or green marble:
P(Blue or Green) = (3 + 5)/14 = 8/14 = 4/7 c. If two marbles are drawn without replacement, the probability both are white:
P(both white) = (2/14) * (1/13) = 2/182 = 1/91 d. The probability that a marble drawn is neither blue nor red:
Remaining marbles = 5 Green + 2 White = 7; P(Not Blue or Red) = 7/14 = 1/2
Continue from Page 1 e. Probability of drawing three white marbles without replacement:
P(3 white) = (2/14) * (1/13) * (0/12) = 0
Rolling a pair of dice: a. Probability that the sum of the dice is 7:
Possible outcomes: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 outcomes
P(sum=7) = 6/36 = 1/6 b. Probability of rolling a sum of 9 or greater:
Outcomes for 9: (3,6), (4,5), (5,4), (6,3) = 4 outcomes
Outcomes for 10: (4,6), (5,5), (6,4) = 3 outcomes
Outcomes for 11: (5,6), (6,5) = 2 outcomes
Outcomes for 12: (6,6) = 1 outcome
Total = 10; P(sum>=9) = 10/36 = 5/18 c. Probability of one die being even and the other odd:
Outcomes: (1,2), (2,1), (1,4)...etc. Total = 18; P(one even, one odd) = 18/36 = 1/2
Cases for radiologist excluding multiple body x-rays:
a. Probability for child arm or hand x-ray = 28/Total px in table b. for adult neck or spine x-ray = 8/Total c. for adult pelvis x-ray = 12/Total d. for arm or hand OR leg or foot = Total arm or hand + Total leg or foot / Total e. for child patient = Total child cases / Total f. for adult pelvis or child neck/spine x-ray = Total combinations of above / Total g. Choosing two adult leg/foot x-rays without replacement; relevant probability = Cases of Adult Leg/Foot / Total; calculate similar for others. h. Two arm or hand x-rays out of selected cases;
Without replacement P(a child & adult arm/hand x-ray). i. With replacement; repeat steps from g and h, but with total cases squared.
Grocery store's generator: a. Probability of generator failing = P(failure) = 0.016 b. Two generators failing: P(both fail) = 0.016 * 0.016 = 0.000256
Table for traffic accidents and questions regarding probability distribution: a. Validity Check: sum of probabilities should equal 1 b. Find mean (E(X)) = Σ [x * P(x)] and standard deviation (σ = (X^2) - (E(X))^2) c. Use range rule for significant intervals; any x outside this is significant. d. Check if 5 accidents/day is significant based on earlier calculation. e. Probability for no more than 2 accidents is Sum of P(X=0) + P(X=1) + P(X=2). f. Probability for at least 4 accidents is P(X>=4), 1 - P(X<4).
Adults sleeping in groups of five and sleepwalking: a. Validity of probability distribution check = sum = 1. b. Expected adults sleepwalking = Mean as calculated previously.
Use probabilities to calculate.
Range Rule for sleepwalkers in groups of 5; decide if 3 is significantly high or not. a. Probability for more than 2 sleepwalkers (P(X>2)). b. Probability for no more than 1 sleepwalker (P(X<=1)).
Probability distribution of nausea: a. P(no more than 6 nausea) = sum of P(0) + P(1) + P(2)... + P(6) b. Is it an unlikely event? Compare to mean. c. Probability of half or more patients experiencing nausea. d. Expected patients experiencing nausea based on trials and distribution. e. Check significance for 8 as high or not. f. Probability of fewer than 4 experiencing nausea; calculate using distribution.
Burglary Statistics from 1980: a. Finding binomial probability of exactly 4 burglaries out of 9 tries using binomial formula; b. Calculate expected number of burglaries in 12 trials from earlier stat (0.23 * 12); mean = 2.76. c. Find probability of at least 6 burglaries from binomial probability.
Rolling a die 600 times;
Find binomial mean = np and standard deviation = sqrt(np(1-p)).
Common return rate for online store:
Estimate return rate based on 17% of sales; apply to total items.
Probability for quiz guessing at least 7 correct out of 10 using binomial probability.