SCH3U - Unit 1 - Practice Questions
Find the number of neutrons, given the atomic mass and atomic number
# of neutrons = atomic mass - atomic number
Example - Neon-20 has an atomic number of 10
# of neutrons = 20 - 10
= 10 neutrons
Find the average atomic mass, given the abundances of isotopes
Multiply each mass by the abundance as a decimal
Add each product together
Use the formula:
Avg. amu = m1p1 + m2p2 +… mn-1pn-1 + mnpn , where n is the number of isotopes, m is the mass, and p is the percent of abundance
Example - Copper’s abundance is made of Copper-63 (62.9296 amu, 69.17%) and Copper-65 (64.9278 amu, 30.83%). What is the average atomic mass?
Avg. amu = (62.9296 amu)(0.6917) + (64.9278 amu)(0.3083)
= (43.5284 amu) + (20.0172 amu)
= 63.5456
Find the abundance of each isotope, given the masses and average atomic mass
Use the formulae:
Avg. amu = m1p1 + m2p2 and p1 + p2 = 1
All of the abundances should equal 1 (or 100%
Substitute the known masses and average amu
Use substitution to isolate for one abundance, and then solve for the other
Find the number of neutrons, given the atomic mass and atomic number
# of neutrons = atomic mass - atomic number
Example - Neon-20 has an atomic number of 10
# of neutrons = 20 - 10
= 10 neutrons
Find the average atomic mass, given the abundances of isotopes
Multiply each mass by the abundance as a decimal
Add each product together
Use the formula:
Avg. amu = m1p1 + m2p2 +… mn-1pn-1 + mnpn , where n is the number of isotopes, m is the mass, and p is the percent of abundance
Example - Copper’s abundance is made of Copper-63 (62.9296 amu, 69.17%) and Copper-65 (64.9278 amu, 30.83%). What is the average atomic mass?
Avg. amu = (62.9296 amu)(0.6917) + (64.9278 amu)(0.3083)
= (43.5284 amu) + (20.0172 amu)
= 63.5456
Find the abundance of each isotope, given the masses and average atomic mass
Use the formulae:
Avg. amu = m1p1 + m2p2 and p1 + p2 = 1
All of the abundances should equal 1 (or 100%
Substitute the known masses and average amu
Use substitution to isolate for one abundance, and then solve for the other