Lecture 13: Focus on Stoichiometry
Quiz 3: Due by 6 PM, Sunday, March 9
Covers material on intermolecular forces, empirical/molecular formulas, and reaction stoichiometry
60 minutes duration, open notes, 2 attempts per question
Important to complete HW7 before taking Quiz 3
Quiz 4: Due by 8 AM, Thursday, March 27
OWL HW7: Due by 8 AM, Tuesday, March 11
Definition: Reorganization of reactant molecules to form product molecules
Process: Involves breaking existing bonds and forming new ones
State Notation:
(g): gas
(l): liquid
(s): solid
(aq): aqueous, indicates reaction occurs in water
Law of Conservation of Mass: Atoms are conserved; reactions must be balanced
Mole Relationships: Mole ratios between reactants and products
Diatomic Elements: Some nonmetals exist as diatomic molecules in nature (e.g., H2, N2, O2, etc.)
Synthesis: Two or more reactants produce one product
Example: 2 H2(g) + O2(g) → 2 H2O(l)
Decomposition: One reactant produces two or more products
Example: (NH4)2Cr2O7(s) → Cr2O3(s) + N2(g) + 4 H2O(g)
Single Displacement: An element replaces another element in a compound
Example: Mg(s) + 2 HCl(aq) → H2(g) + MgCl2(aq)
Double Displacement: Two ions exchange partners
Example: 2 AgNO3(aq) + Na2CO3(aq) → Ag2CO3(s) + 2 NaNO3(aq)
Combustion: Substance reacts with oxygen gas
Example: 2 CH3OH(l) + 3 O2(g) → 2 CO2(g) + 4 H2O(l)
Practice balancing:
NH3(g) synthesis reaction
H2O2(aq) decomposition
thermite reaction (Al and Fe3O4)
gasoline (C8H18) combustion reaction
Balanced chemical reactions imply:
a. Numbers of molecules are conserved in chemical change
b. Numbers of atoms are conserved in chemical change
c. Mass is conserved in chemical change
d. Both b and c are correct
e. All answers are correct
Balanced Equation: 4 A2 + 8 AB → 8 A2B
A2 + 2 AB → 2 A2B
Limiting Reactant: Reactant that runs out first
Synthesis Reaction: 9 H2 + 5 N2 → NH3
Total Molecules Present After Completion:
Options: a. 6, b. 8, c. 10, d. 12, e. 14
Example: 3 H2(g) + N2(g) → 2 NH3(g)
Stoichiometry Question 1:
Reaction: 8 Al(s) + 3 Fe3O4(s) → 4 Al2O3(s) + 9 Fe(s)
If 10.0 g of Fe3O4 reacted, produce: 5.87 g Al2O3
Stoichiometry Question 2:
If 9.45 g of Al2O3 is produced, how much Al reacted? Result: 5.00 g Al
Stoichiometry Question 3:
Reaction with 10.0 g Fe3O4 and 5.00 g Al produced: 5.87 g Al2O3
Stoichiometry Question 4:
When 10.0 g Fe3O4 reacted with 5.00 g Al, leftover: 0 g Fe3O4, 1.89 g Al excess
Complete the sentence: "The limiting reactant in a reaction:"
a. Smallest gram present
b. Smallest coefficient in the balanced equation
c. Smaller molar mass
d. Smallest number of moles present
e. None of the above
Reaction: 8 Al(s) + 3 Fe3O4(s) → 4 Al2O3(s) + 9 Fe(s)
If 4.62 g Al2O3 is produced, calculate percent yield from the amounts in question 3.