Heat Transfer in Zinc and Water
Heat Transfer Between Zinc and Water
- Heat is being transferred from zinc to water.
- The relationship can be expressed as:
- Q1 = -Q2
- Here, ( Q1 ) refers to the heat lost by zinc, while ( Q2 ) is the heat gained by water.
Zinc Properties
- Mass of zinc (unknown, denote as ( m_{Zn} )).
- Specific heat of zinc: 0.39 J/g°C.
- Initial temperature of zinc: 5.2 °C.
- Final temperature of zinc (after energy loss): 42.5 °C.
- Change in temperature for zinc:
- ( \Delta T{Zn} = T{final} - T_{initial} )
- ( \Delta T_{Zn} = 42.5 °C - 5.2 °C = -62.7 °C )
- Sign indicates zinc is losing heat.
Energy Transfer Calculation for Zinc
- Heat lost by zinc can be formulated as:
- Q1 = m{Zn} \times c{Zn} \times \Delta T{Zn}
- Where:
- ( Q_1 ) = energy lost by zinc.
- ( c_{Zn} ) = specific heat of zinc (0.39 J/g°C).
- ( \Delta T_{Zn} ) = -62.7 °C.
Water Properties
- Mass of water (unknown, denote as ( m_{water} )).
- Final temperature of water: 42.5 °C.
- Initial temperature of water (assume a starting temperature, for calculation purposes).
- Change in temperature for water: ( \Delta T{water} = T{final} - T_{initial} )
- Equation for heat gained by water:
- Q2 = m{water} \times c{water} \times \Delta T{water}
- Where:
- ( Q_2 ) = energy gained by water.
- ( c_{water} ) = specific heat of water, typically ( 4.18 J/g°C ) (use if given).
Connecting the Calculations
- Set equations equal based on conservation of energy:
- m{Zn} \times c{Zn} \times (-62.7) = - (m{water} \times c{water} \times \Delta T_{water})
- Helps to reduce complexity by cancelling out negatives when substituting values.