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Gen.-physics-2-Repaired

Electric Charge

  • Atom

is the basic building block of matter.

  • Subatomic particles

Protons are positively charged (+e)

Electrons have negative charges (-e).

Neutrons have no charge or are electrically neutral

Electric Charge

  • An electric charge determines the electric interaction and magnetic interaction between subatomic

particles and other charged particles.

  • This interaction between charges is summarized in the phrase โ€œlike charges repel, unlike charges attract.

A glass rod and a rubber rod are used to demonstrate the interaction between electric charges. It was found out that after rubbing the rubber rod with fur and the glass rod with silk, both pairs of objects acquired charges. Two glass rods are found to repel each other, whereas a glass rod is found to be attracted to the rubber rod.

๐Ÿž‡ In an atom, the subatomic particles provide the net charge. An

electrically neutral atom contains an equal number of protons and electrons.

๐Ÿž‡ An atom that has an imbalance in the number of protons and

electrons is called an ion. Cations are positive (more protons than electrons), and anions are negative ( more electrons than protons).

๐Ÿž‡ As a derived SI (or International System of Units) quantity, an electric charge is represented by the symbol

โ€œqโ€ and measured using the unit

coulomb (C).

๐Ÿž‡ 1 coulomb = 6.242 x 10^18 e

Law of Charges

๐Ÿž‡ Like charges repel each other, and unlike charges attract

each other.

๐Ÿž‡ Macroscopically, a body is electrically charged if the number of positive charges

it has is not equal to the number of the negative charges. In other words, the charge of a particle depends on the sum of its electrical charges.

What is the charge of each atom if it comprises the following particles?

  1. 5 electrons and 6 protons
  2. 14 protons and 11 electrons
  3. 5 electrons and 5 protons
  4. 25 protons and 26 electrons

Compute the charge of the following ions in Coulomb.

a. Ion with a charge of -2e

a. Ion with a charge of +5e

a. Ion with a charge of -3e

  1. Ion with a charge of -7e
  2. Ion with a charge of +6e

Conductors

Conductors

๐Ÿž‡ are materials that allow electrical charges to move from one material to another.

๐Ÿž‡ Conductors may be charged through different methodsโ€” rubbing, conduction, and induction.

Charging by Rubbing

๐Ÿž‡ An electrically neutral body can gain a charge by rubbing or friction.

๐Ÿž‡ Consider two different uncharged bodies. Because of the difference in their material compositions, the nuclei of their atoms pull their electrons with different strengths.

๐Ÿž‡ Rubbing these two bodies will force their atoms to interact with one another, resulting in the โ€œripping offโ€ of electron(s)from the body with a weaker electron hold.

๐Ÿž‡ The โ€œripped offโ€ electrons are then transferred to the other body. After rubbing, one of the bodies will have more electrons, and the other one will have fewer. Thus, both of them will now be electrically charged.

Triboelectric series

๐Ÿž‡ is a list of common materials that were experimented on and found to behave in a predictable way.

๐Ÿž‡ When these materials are rubbed together, those that appear first in the list tend to lose their electrons, making them positive.

๐Ÿž‡ Those latter in the list tend to gain electrons, making them negative.

๐Ÿž‡ In other words, if you rub any two of the materials in the series, the material in the upper part of the list will be positive, and the other material in the lower part will be negative.

๐Ÿž‡ Using the information presented in table 1.1, determine the acquired charges of the bodies in each of the following pairs if

they are rubbed together.

๐Ÿž‡ a. wood and Styrofoam

๐Ÿž‡ wood: +

๐Ÿž‡ Styrofoam: -

  1. glass and leather glass: -

leather: +

  1. rubber and rubber rubber: none

rubber: none

  1. dry hand and PVC dry hand: +

PVC: -

Charging by Conduction

Charging by Conduction

๐Ÿž‡ During charging by conduction, both objects acquire the same type of charge.

๐Ÿž‡ If a negative object is used to charge a neutral object, then objects become charged negatively.

Charging by Induction.

๐Ÿž‡ A negatively charged balloon is placed near (but without physical contact) a neutral tin can. As a result, the positive

charges of the can move to the left, near the negatively charged balloon because of attraction. Meanwhile, the negative charges move to the right side of the tin can, away from the balloon because of repulsion. The excess negative charges at the right side of the tin can are known as induced charges.

Electric Dipoles

Electric Dipoles

๐Ÿž‡ When you bring a neutrally charged body A near a

strongly negative body B, its positive charges will be

drawn near B, and the negative charges will be pushed to the other side. This resulting condition polarizes the body and forms a dipole.

๐Ÿž‡ Polarization is the process wherein an electrically neutral body becomes polar by the rearrangement of its molecules. As the molecules realign or move, particles with similar charges group together and move toward the opposite ends of the body.

๐Ÿž‡ Hence, the body becomes positive at one end and negative on the other, making it a dipole.

๐Ÿž‡ Point dipoles refer to atoms bearing a positive side and a negative side. In such atoms, the electrons

converge or gather on one side and the protons on the other.

๐Ÿž‡ Molecular dipoles. This type of dipole involves a

molecule having a negatively charged side and a

positively charged side. The electronegative atoms of the molecule form the negative end of the molecule, and the electropositive ones are responsible for the positive end.

Another way to classify dipoles is whether they are permanent or temporary(instantaneous). An instantaneous or a temporary dipole is an atom or a molecule with most of its negative charges shifted only to one side as a result of their random movement.

MODULE 2

ELECTROSTATIC FORCE, ELECTRIC FIELD, AND ELECTRIC FLUX

At the end of this module, I can :

๐Ÿž‡ Define electrostatic force using Coulomb's Law.

๐Ÿž‡ Calculate the electrostatic force between two charges using Coulomb's Law.

๐Ÿž‡ Compute the Electric Field at a given distance from a given source charge.

๐Ÿž‡ a push or a pull pertains to force.

๐Ÿž‡ electric charges exert a force on each other as they interact.

๐Ÿž‡ The act of repelling implies pushing and the act of attracting suggests pulling.

Electrostatic Force

Electrostatic Force

๐Ÿž‡ The attraction and repulsion between electric charges comes from a force known as electrostatic force.

๐Ÿž‡ This force can be computed using

Coulombโ€™s law for electrostatics.

Example 1:

๐Ÿž‡ What is the electrostatic force of attraction between a -6.0 ร— 10^-6 C charge and a 4.0 ร— 10^-6 C charge if they are separated by a distance of 3

meters(m)?

0.02 N

Example 2:

๐Ÿž‡ Two identically charged one-peso coins are 1.5 m apart on a table.

What is the charge of one of the coins if each of them experiences a repulsive force of 2.0 N?

2.23 x 10^-5 C

TRY THIS!!!

๐Ÿž‡ Compute the force of attraction between a +1.60 x 10^-19 C and -2.09 x 10^-18C

charge if they are 4.0 x 10^-10 m apart.

0.00000001879 N

TRY THIS!!!

๐Ÿž‡ Calculate the repulsive force between a

-0.71783 electron charge and a -1.49 x

10^-8 C charge if a distance of 2.01 x 10^-20 m separates them.

TRY THIS!!!

๐Ÿž‡ Two ball bearings with same charges are 87.00787 inches apart

on the floor. What are their charges if they are attracted to each other with a force of 8.11 N

?

Electric Field and Its Representation

๐Ÿž‡ An electric field is a region of space where an electric charge experiences a force.

๐Ÿž‡ An electric field is a measurable effect generated

by any charged object.

๐Ÿž‡ An electric field coexists with every electrostatic charge; it associates with each point in space the electrostatic force experienced per unit of electric

charge, by an extremely small (or infinitesimal) test charge at that point.

Electric fields

๐Ÿž‡ predict the behavior of the charges present in any location in space.

๐Ÿž‡ Physicists compute the value of an electric field because of its direct relation with electrostatic force.

๐Ÿž‡ Mathematically, the electric field can be

computed using the equation:

๐Ÿž‡ E - is the electric field,

๐Ÿž‡ Q is the source charge

๐Ÿž‡ r is the distance from the source charge where the electric field is being measured.

๐Ÿž‡ The unit used to measure electric field is newton per coulomb (N/C).

Source and Test Charge

๐Ÿž‡ The charge Q which is producing the

electric field, is called a source charge

and the charge q, which tests the effect the charge of source charge, is called a test charge.

Source charge

๐Ÿž‡ is the charge from where the electric field comes from.

Test Charge

๐Ÿž‡ is a single charge whose behavior is measured or determined based on the

presence of external factors or stimuli. Its presence is arbitrary. For easier computation, a unit of 1 C is used.

Example :

๐Ÿž‡ Calculate the electric field that a test charge will experience on the following distances from the source charge of

+5.02 ร— 10-13 C.

๐Ÿž‡ a. Distance from source charge:

2.04 ร— 10-3 m.

Source charge will experience an electric field of

approximately 1 084.43 N/C

๐Ÿž‡ b. Distance from source charge:

1.55 ร— 10-12 m.

๐Ÿž‡ The source charge will experience an electric field

of approximately 1.88 ร— 1021 N/C.

Answer the following: Copy and Answer.

๐Ÿž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +3.1397 ร— 1015 e

Distance from source charge: 2.33 ร— 10-5 m

  1. Source charge: -4.33 ร— 10-12 C

Distance from source charge: 4.6 ร— 10-19 m

Answer the following: Copy and Answer.

๐Ÿž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +4.05 ร— 10-5 C

Distance from source charge: 3.23 ร— 10-7 m

  1. Source charge: -6.53 ร— 10-10 C

Distance from source charge: 3.7 ร— 10-15 m

  1. Source charge: +5.45 ร— 10-12 C

Distance from source charge: 6.8 ร— 10-17

  1. Source charge: -3.44 ร— 10-16 C

Distance from source charge: 4.43 ร— 10-12

Copy and Answer:

  1. What is the electrostatic force of attraction between a -6.0 ร— 10^-6 C charge and a 4.0 ร— 10^- 6 C charge if they are separated by a distance of 3 meters(m)?
  2. 2. Two ball bearings with opposite charges are

1.11 m apart on the floor. What are their charges if they are attracted to each other with a force of

5.11 N ?

  1. Calculate the repulsive force between a -2.23 x 10^-6 C charge and a -2.49 x 10^-5 C charge if a distance of 3.55 x 10^-21 m separates them.

Continuationโ€ฆ.

๐Ÿž‡ II. Compute the electrostatic force experienced by

-4.43 ร— 10-18 C charge from the following electric

fields:

a.

E = 5 465 N/C

b.

E = 9.5 ร— 1015 N/C

E = 8.97 ร— 1024 N/C

Electric Field Lines

๐Ÿž‡ An electric field can be graphically represented using electric field lines. The

density or thickness of these lines is directly proportional to the strength of the electric field at any region in space.

๐Ÿž‡ If the field lines are close to each other, the electric field is stronger.

Electric field lines are drawn based on the charge being considered.

๐Ÿž‡ Positive charges have field lines drawn from them.

๐Ÿž‡ Negative charges have field lines drawn to them.

Electric field lines from the positive charge going to the negative charge.

Draw electric lines for the following charges.

  1. d.

+ + + + - -

b.

- -

c.

+ + -

Electric Potential

Work and Potential Energy

๐Ÿž‡ Energy is defined as the capacity to do work. A body with energy can do work,

whereas a body without it cannot do work.

Potential energy

๐Ÿž‡ is one of the many forms of energy.

๐Ÿž‡ It is the energy of a body due to its position and normally converted into useful work.

๐Ÿž‡ This is why it is known as the energy at rest.

Gravitational potential energy (GPE)

๐Ÿž‡ a type of potential energy, is due to a

bodyโ€™s elevation from the ground.

๐Ÿž‡ A body placed higher above the ground can do greater work as it moves downward from its initial position.

Electric Potential

๐Ÿž‡ Electric potential is the amount of electric potential energy per unit charge. This is

equivalent to the amount of work needed to move a charge from one reference point to another.

Electric Potential

๐Ÿž‡

Example:

๐Ÿž‡ a. Compute the electric potential from a source charge of +5.02 ร— 10-13 C if a test charge will be placed 2.08 ร— 10-3 m from it.

๐Ÿž‡ The electric potential is approximately 2.17 V

๐Ÿž‡ b. How much is the electric potential from the

+4.02 ร— 10-15 C source charge if a test charge

will be placed 4.55 ร— 10-12 m from it.

๐Ÿž‡ The electric potential is approximately

7.94 ร— 108 V.

Compute the following electric potentials.

Source Charge

Distance from Source Charge

Electric Potential

+4.31 x 103 C

7.11x 10-12 m

-2.33 x 10-13 C

6.45x 10-15 m

๐Ÿž‡ Module 4: Voltage, Current,

and Resistance

Current: Flow of Electrical Charges

๐Ÿž‡ Normally, electrons move to any direction.

๐Ÿž‡ If this flow is regulated and made to move continuously in one direction, then the flow becomes an electric current.

๐Ÿž‡

Example 1:

๐Ÿž‡ a. Compute the current produced by a

+6.5 ร— 10-18 C charge flowing in 15 s.

๐Ÿž‡ The amount of current is approximately

4.33 ร— 10โ€“19 A.

๐Ÿž‡ b. A steady current of 0.6 A flows through a wire. How much charge passes through the wire in 1 minute

(min)?

๐Ÿž‡ In 1 min, a charge of 36 C will pass through the wire.

Example:

๐Ÿž‡ How much current is flowing when 29.3 Coulombs of charges pass a point in 7.84 seconds?

๐Ÿž‡ The amount of current is approximately 3.

74A.

Solve for the following. Copy and

Answer.

  1. Compute the current produced by a

+4.40 ร— 10 14 e charge flowing in 21 min.

  1. How much current is flowing when 4.32 x 10-15 e of charges pass a point in 7.84 seconds?
  2. How much current is flowing when 33.3 Coulombs of charges pass a point in 2 hours?
  3. Calculate the total DC resistance of a 100 metre roll of 2.5mm2 copper wire if the resistivity of copper is 1.72 x 10-8 ฮฉ metre.
  4. A 20 metre length of cable has a cross-sectional area of 1mm2 and a resistance of 5 ohms. Calculate the conductivity of the cable.
Resistance and Resistivity

๐Ÿž‡ An electrical conductor is any material that allows the free flow of electric current.

๐Ÿž‡ A conductor possesses characteristics that either enhance or limit the flow of current passing through it. The limitation to

current flow is referred to as resistance.

๐Ÿž‡ Resistance and electric current are inversely proportional. So a greater

amount of resistance on a conductor results in a lower amount of current passing through the conductor, whereas a lower resistance means less restrictions, allowing more current to flow through the conductor.

Electrical resistivity

๐Ÿž‡ is an intrinsic property of the material that describes how it resists the electric current flowing through it.

๐Ÿž‡ Higher electrical resistivity means higher overall resistance of the material, whereas lower resistivity indicates the materialโ€™s lower

resistance.

๐Ÿž‡ Consequently, current flow is reduced by an increase in the electrical resistivity of the material, whereas a decrease in the resistivity

allows more current to flow through the material.

electrical conductivity

๐Ÿž‡ an increase in the electrical conductivity of the material results in a lower resistance

offered by the material and a higher current flow through it. On the other hand, decreasing the electrical conductivity of the material increases its resistance and lowers the flow of current through it.

Factors or property of the material that affects the resistance and current flow

๐Ÿž‡ Temperature

๐Ÿž‡ Length of Conductor

๐Ÿž‡ Cross-sectional area of conductor

Temperature

๐Ÿž‡ If the conductor has a higher temperature, its resistance increases and the amount of current that can flow through it decreases.

๐Ÿž‡ On the other hand, if the conducting material has a lower temperature, the resistance decreases, thus allowing more current to flow through it

Length of the conductor

๐Ÿž‡ Longer conductors provide more resistance to the flow of current, which means less current can flow through it.

๐Ÿž‡ Shorter conductors provide less resistance, thus allowing more current to flow.

Cross-sectional area of the conductor

๐Ÿž‡ โ€œFatโ€ conductors allow more charges to pass

through them, which means more current can flow.

More current flow also means lower resistance offered by the conductor.

๐Ÿž‡ โ€œThinโ€ conductors, on the other hand, have limited space for current to flow through them, making resistance higher.

๐Ÿž‡

Sample problem1:

๐Ÿž‡ Compute the resistance of a conductor given a resistivity of 10.4 โ„ฆ-m, length of 4 m, and cross- sectional area of 7.85 ร— 10-3 m2.

๐Ÿž‡ The resistance of the conductor is approximately 5

299.36 โ„ฆ

  1. A conductor has a diameter of 2.59 mm. How many meters of this material are needed to yield a resistance of 1 โ„ฆ? The resistivity of the conductor is

1.77 ร— 10-8 โ„ฆ-m.

๐Ÿž‡ To obtain a resistance of 1 โ„ฆ, approximately

297.66 m of the conductor is needed.

Sample problem #2.

๐Ÿž‡ Solve for the resistance of a conductor given a resistivity of 15.3 โ„ฆ-m, length of 6 m, and cross-sectional area of 2.85 ร— 10-2 m2.

Sample Problem #3.

๐Ÿž‡ A copper rod is 3 m long and 4 mm in diameter. Compute its resistance if

the resistivity of the material is 1.76 ร— 10-8 โ„ฆ-m.

Electromotive Force

๐Ÿž‡ Electromotive force , it is the potential energy given to a unit charge to make it flow through a conductor or around a complete circuit.

๐Ÿž‡ The EMF acts like a charge pump that causes charges to flow through a circuit.

๐Ÿž‡ As a measurable quantity, EMF is measured using the unit volt (V)

Potential Difference

๐Ÿž‡ Similar to electromotive force is the potential difference (PD) across a circuit.

๐Ÿž‡ Potential difference is an actual consideration of the potentials in the circuit. The existence of PD also identifies the flow of

charges through the circuit. Without this difference, there will be no electric potential, thus making the flow of charges through the conductor impossible.

๐Ÿž‡ Both the EMF and PD are measured in terms of voltage (V).

Ohmโ€™s Law

๐Ÿž‡ In 1827, Georg Simon Ohm discovered the relationship among voltage, current, and resistance.

๐Ÿž‡ He found out that electricity acts similarly to water in

a pipe. Through this observation, he was able to

summarize the relationship among EMF or voltage (V ), electric current (I ), and resistance (R) through the Ohmโ€™s law.

๐Ÿž‡ In equation form, Ohmโ€™s law is stated as follows:

V = IR

Example 3:

๐Ÿž‡ a. Using Ohmโ€™s law, solve for the electric current of a conductor given a voltage of 25 V and a resistance of 10 โ„ฆ.

๐Ÿž‡ The current is approximately 2.5 A

๐Ÿž‡ b. An electric water heater uses 15 A of current when plugged to a 220-V outlet.

๐Ÿž‡ What is the resistance provided by the appliance?

๐Ÿž‡ The electric water heater provides a

resistance of approximately 14.67 โ„ฆ.

Electric Circuits

Electric Circuit.

๐Ÿž‡ The pathway for the current to move to and from the source and the appliance is called an electric circuit.

๐Ÿž‡ A functional circuit has to be โ€œclosedโ€ or

must form a closed loop.

Circuits

๐Ÿ–‰ In order for electricity to flow we need:

๐Ÿ–‰ Power source

๐Ÿ–‰ Closed circuit

๐Ÿ–‰ Two type of circuits:

๐Ÿ–‰ Series circuit

๐Ÿ–‰ Parallel circuit

Closed circuits

๐Ÿž‡ Closed circuits allow the current to flow from the source of the current to the load where the current is needed.

Open circuits

๐Ÿž‡ an โ€œopenโ€ circuit does not form a closed loop; the resulting circuit would then be nonfunctional.

๐Ÿž‡ Open circuits have gap(s) where current cannot flow.

๐Ÿž‡ Thus, electric current cannot be delivered

to the load where it is needed

The Series Circuit

Series Circuit

๐Ÿ–‰ In a series circuit there is only one path for the electrons to flow.

๐Ÿ–‰ In other words all the components are in series with each other

๐Ÿ–‰ Because there is only one path each charge will go

through each resistor

The Series Circuit

๐Ÿž‡ In a series circuit, all components are connected using a single pathway.

๐Ÿž‡ The current is the same for all the components along this circuit.

๐Ÿž‡ The total voltage is the sum of the individual voltages across the circuit.

๐Ÿž‡ the total resistance of the circuit is the sum of the individual resistances of each circuit load.

These relationships are summarized by the following formulas:

๐Ÿž‡ Vtotal = V1 + V2 + V3 + . . .+ Vn

๐Ÿž‡ Itotal = I1 = I2 = I3 = . . . = In

๐Ÿž‡ Rtotal = R1 + R2 + R3 + . . .+ R

Calculating Resistance in Series Circuits

๐Ÿ–‰The rule for calculating Series Circuits is toโ€ฆ

๐Ÿ–‰Add up the values of each individual in the series.

๐Ÿ–‰R1 + R2 + R3โ€ฆ

๐Ÿ–‰5 + 5 + 10

๐Ÿ–‰20 ฮฉ (ohms)

Calculating Resistance in Series Circuits

1

0

2

0

๐Ÿ–‰Add up the values of each individual in the series.

๐Ÿ–‰R1 + R2 + R3โ€ฆ

๐Ÿ–‰10 + 20 + 10

๐Ÿ–‰40 ฮฉ (ohms)

The Parallel Circuit

๐Ÿž‡ Parallel circuits use branches to allow current to pass through more than one path, unlike in the series circuit.

๐Ÿž‡ Thus, the individual voltages in a parallel circuit are the same as the total voltage.

๐Ÿž‡ The current in each load is not the same

as the total current in the circuit.

Parallel Circuit

๐Ÿ–‰ In a Parallel circuit there are multiple pathways for charge to flow.

๐Ÿ–‰ Each device is placed on itโ€™s own separate

branch

๐Ÿ–‰ Current goes through each of the branches at the

same time

The Parallel Circuit

๐Ÿž‡ The total current is the sum of the individual currents across the resistors.

๐Ÿž‡ The reciprocal of the total resistance in this type of circuit is equal to the sum of

the reciprocals of the individual resistances.

๐Ÿž‡ Always remember that the total resistance is always less than the individual resistances

The following formulas for a parallel circuit:

๐Ÿž‡ Vtotal= V1 = V2 = V3 = . . . = Vn

๐Ÿž‡ Itotal = I1 + I2 + I3 + . . .+ In

Calculating Resistance in Parallel Circuits

๐Ÿ–‰ The rule for calculating

Series Circuits is toโ€ฆ

๐Ÿ–‰ Add up the values of each

individual in the circuit.

๐Ÿ–‰ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

๐Ÿ–‰ 1 1 1 1

-- = -- + -- + --

Rt 4 4 2

๐Ÿ–‰ 1

-- = .25 + .25 + .5

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = Rt

1

๐Ÿ–‰ Rt = 1 ฮฉ (ohms)

2

0

Calculating Resistance in Parallel Circuit

๐Ÿž‡ The rule for calculating

Series Circuits is toโ€ฆ

๐Ÿž‡ Add up the values of each

individual in the circuit.

๐Ÿž‡ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

10

00

๐Ÿž‡ 1 1 1 1

-- = -- + -- + --

Rt 100 200 1000

๐Ÿž‡ 1

2

0

-- = .01 + .005 + .001

Rt

1

2

๐Ÿž‡

1

0

0

๐Ÿž‡

-- = .016

Rt 1

-- = .016

Rt

0

0

  • 1

-- = Rt

.016

  • Rt = 62.5 ฮฉ

(ohms)

GJ

Gen.-physics-2-Repaired

Electric Charge

  • Atom

is the basic building block of matter.

  • Subatomic particles

Protons are positively charged (+e)

Electrons have negative charges (-e).

Neutrons have no charge or are electrically neutral

Electric Charge

  • An electric charge determines the electric interaction and magnetic interaction between subatomic

particles and other charged particles.

  • This interaction between charges is summarized in the phrase โ€œlike charges repel, unlike charges attract.

A glass rod and a rubber rod are used to demonstrate the interaction between electric charges. It was found out that after rubbing the rubber rod with fur and the glass rod with silk, both pairs of objects acquired charges. Two glass rods are found to repel each other, whereas a glass rod is found to be attracted to the rubber rod.

๐Ÿž‡ In an atom, the subatomic particles provide the net charge. An

electrically neutral atom contains an equal number of protons and electrons.

๐Ÿž‡ An atom that has an imbalance in the number of protons and

electrons is called an ion. Cations are positive (more protons than electrons), and anions are negative ( more electrons than protons).

๐Ÿž‡ As a derived SI (or International System of Units) quantity, an electric charge is represented by the symbol

โ€œqโ€ and measured using the unit

coulomb (C).

๐Ÿž‡ 1 coulomb = 6.242 x 10^18 e

Law of Charges

๐Ÿž‡ Like charges repel each other, and unlike charges attract

each other.

๐Ÿž‡ Macroscopically, a body is electrically charged if the number of positive charges

it has is not equal to the number of the negative charges. In other words, the charge of a particle depends on the sum of its electrical charges.

What is the charge of each atom if it comprises the following particles?

  1. 5 electrons and 6 protons
  2. 14 protons and 11 electrons
  3. 5 electrons and 5 protons
  4. 25 protons and 26 electrons

Compute the charge of the following ions in Coulomb.

a. Ion with a charge of -2e

a. Ion with a charge of +5e

a. Ion with a charge of -3e

  1. Ion with a charge of -7e
  2. Ion with a charge of +6e

Conductors

Conductors

๐Ÿž‡ are materials that allow electrical charges to move from one material to another.

๐Ÿž‡ Conductors may be charged through different methodsโ€” rubbing, conduction, and induction.

Charging by Rubbing

๐Ÿž‡ An electrically neutral body can gain a charge by rubbing or friction.

๐Ÿž‡ Consider two different uncharged bodies. Because of the difference in their material compositions, the nuclei of their atoms pull their electrons with different strengths.

๐Ÿž‡ Rubbing these two bodies will force their atoms to interact with one another, resulting in the โ€œripping offโ€ of electron(s)from the body with a weaker electron hold.

๐Ÿž‡ The โ€œripped offโ€ electrons are then transferred to the other body. After rubbing, one of the bodies will have more electrons, and the other one will have fewer. Thus, both of them will now be electrically charged.

Triboelectric series

๐Ÿž‡ is a list of common materials that were experimented on and found to behave in a predictable way.

๐Ÿž‡ When these materials are rubbed together, those that appear first in the list tend to lose their electrons, making them positive.

๐Ÿž‡ Those latter in the list tend to gain electrons, making them negative.

๐Ÿž‡ In other words, if you rub any two of the materials in the series, the material in the upper part of the list will be positive, and the other material in the lower part will be negative.

๐Ÿž‡ Using the information presented in table 1.1, determine the acquired charges of the bodies in each of the following pairs if

they are rubbed together.

๐Ÿž‡ a. wood and Styrofoam

๐Ÿž‡ wood: +

๐Ÿž‡ Styrofoam: -

  1. glass and leather glass: -

leather: +

  1. rubber and rubber rubber: none

rubber: none

  1. dry hand and PVC dry hand: +

PVC: -

Charging by Conduction

Charging by Conduction

๐Ÿž‡ During charging by conduction, both objects acquire the same type of charge.

๐Ÿž‡ If a negative object is used to charge a neutral object, then objects become charged negatively.

Charging by Induction.

๐Ÿž‡ A negatively charged balloon is placed near (but without physical contact) a neutral tin can. As a result, the positive

charges of the can move to the left, near the negatively charged balloon because of attraction. Meanwhile, the negative charges move to the right side of the tin can, away from the balloon because of repulsion. The excess negative charges at the right side of the tin can are known as induced charges.

Electric Dipoles

Electric Dipoles

๐Ÿž‡ When you bring a neutrally charged body A near a

strongly negative body B, its positive charges will be

drawn near B, and the negative charges will be pushed to the other side. This resulting condition polarizes the body and forms a dipole.

๐Ÿž‡ Polarization is the process wherein an electrically neutral body becomes polar by the rearrangement of its molecules. As the molecules realign or move, particles with similar charges group together and move toward the opposite ends of the body.

๐Ÿž‡ Hence, the body becomes positive at one end and negative on the other, making it a dipole.

๐Ÿž‡ Point dipoles refer to atoms bearing a positive side and a negative side. In such atoms, the electrons

converge or gather on one side and the protons on the other.

๐Ÿž‡ Molecular dipoles. This type of dipole involves a

molecule having a negatively charged side and a

positively charged side. The electronegative atoms of the molecule form the negative end of the molecule, and the electropositive ones are responsible for the positive end.

Another way to classify dipoles is whether they are permanent or temporary(instantaneous). An instantaneous or a temporary dipole is an atom or a molecule with most of its negative charges shifted only to one side as a result of their random movement.

MODULE 2

ELECTROSTATIC FORCE, ELECTRIC FIELD, AND ELECTRIC FLUX

At the end of this module, I can :

๐Ÿž‡ Define electrostatic force using Coulomb's Law.

๐Ÿž‡ Calculate the electrostatic force between two charges using Coulomb's Law.

๐Ÿž‡ Compute the Electric Field at a given distance from a given source charge.

๐Ÿž‡ a push or a pull pertains to force.

๐Ÿž‡ electric charges exert a force on each other as they interact.

๐Ÿž‡ The act of repelling implies pushing and the act of attracting suggests pulling.

Electrostatic Force

Electrostatic Force

๐Ÿž‡ The attraction and repulsion between electric charges comes from a force known as electrostatic force.

๐Ÿž‡ This force can be computed using

Coulombโ€™s law for electrostatics.

Example 1:

๐Ÿž‡ What is the electrostatic force of attraction between a -6.0 ร— 10^-6 C charge and a 4.0 ร— 10^-6 C charge if they are separated by a distance of 3

meters(m)?

0.02 N

Example 2:

๐Ÿž‡ Two identically charged one-peso coins are 1.5 m apart on a table.

What is the charge of one of the coins if each of them experiences a repulsive force of 2.0 N?

2.23 x 10^-5 C

TRY THIS!!!

๐Ÿž‡ Compute the force of attraction between a +1.60 x 10^-19 C and -2.09 x 10^-18C

charge if they are 4.0 x 10^-10 m apart.

0.00000001879 N

TRY THIS!!!

๐Ÿž‡ Calculate the repulsive force between a

-0.71783 electron charge and a -1.49 x

10^-8 C charge if a distance of 2.01 x 10^-20 m separates them.

TRY THIS!!!

๐Ÿž‡ Two ball bearings with same charges are 87.00787 inches apart

on the floor. What are their charges if they are attracted to each other with a force of 8.11 N

?

Electric Field and Its Representation

๐Ÿž‡ An electric field is a region of space where an electric charge experiences a force.

๐Ÿž‡ An electric field is a measurable effect generated

by any charged object.

๐Ÿž‡ An electric field coexists with every electrostatic charge; it associates with each point in space the electrostatic force experienced per unit of electric

charge, by an extremely small (or infinitesimal) test charge at that point.

Electric fields

๐Ÿž‡ predict the behavior of the charges present in any location in space.

๐Ÿž‡ Physicists compute the value of an electric field because of its direct relation with electrostatic force.

๐Ÿž‡ Mathematically, the electric field can be

computed using the equation:

๐Ÿž‡ E - is the electric field,

๐Ÿž‡ Q is the source charge

๐Ÿž‡ r is the distance from the source charge where the electric field is being measured.

๐Ÿž‡ The unit used to measure electric field is newton per coulomb (N/C).

Source and Test Charge

๐Ÿž‡ The charge Q which is producing the

electric field, is called a source charge

and the charge q, which tests the effect the charge of source charge, is called a test charge.

Source charge

๐Ÿž‡ is the charge from where the electric field comes from.

Test Charge

๐Ÿž‡ is a single charge whose behavior is measured or determined based on the

presence of external factors or stimuli. Its presence is arbitrary. For easier computation, a unit of 1 C is used.

Example :

๐Ÿž‡ Calculate the electric field that a test charge will experience on the following distances from the source charge of

+5.02 ร— 10-13 C.

๐Ÿž‡ a. Distance from source charge:

2.04 ร— 10-3 m.

Source charge will experience an electric field of

approximately 1 084.43 N/C

๐Ÿž‡ b. Distance from source charge:

1.55 ร— 10-12 m.

๐Ÿž‡ The source charge will experience an electric field

of approximately 1.88 ร— 1021 N/C.

Answer the following: Copy and Answer.

๐Ÿž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +3.1397 ร— 1015 e

Distance from source charge: 2.33 ร— 10-5 m

  1. Source charge: -4.33 ร— 10-12 C

Distance from source charge: 4.6 ร— 10-19 m

Answer the following: Copy and Answer.

๐Ÿž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +4.05 ร— 10-5 C

Distance from source charge: 3.23 ร— 10-7 m

  1. Source charge: -6.53 ร— 10-10 C

Distance from source charge: 3.7 ร— 10-15 m

  1. Source charge: +5.45 ร— 10-12 C

Distance from source charge: 6.8 ร— 10-17

  1. Source charge: -3.44 ร— 10-16 C

Distance from source charge: 4.43 ร— 10-12

Copy and Answer:

  1. What is the electrostatic force of attraction between a -6.0 ร— 10^-6 C charge and a 4.0 ร— 10^- 6 C charge if they are separated by a distance of 3 meters(m)?
  2. 2. Two ball bearings with opposite charges are

1.11 m apart on the floor. What are their charges if they are attracted to each other with a force of

5.11 N ?

  1. Calculate the repulsive force between a -2.23 x 10^-6 C charge and a -2.49 x 10^-5 C charge if a distance of 3.55 x 10^-21 m separates them.

Continuationโ€ฆ.

๐Ÿž‡ II. Compute the electrostatic force experienced by

-4.43 ร— 10-18 C charge from the following electric

fields:

a.

E = 5 465 N/C

b.

E = 9.5 ร— 1015 N/C

E = 8.97 ร— 1024 N/C

Electric Field Lines

๐Ÿž‡ An electric field can be graphically represented using electric field lines. The

density or thickness of these lines is directly proportional to the strength of the electric field at any region in space.

๐Ÿž‡ If the field lines are close to each other, the electric field is stronger.

Electric field lines are drawn based on the charge being considered.

๐Ÿž‡ Positive charges have field lines drawn from them.

๐Ÿž‡ Negative charges have field lines drawn to them.

Electric field lines from the positive charge going to the negative charge.

Draw electric lines for the following charges.

  1. d.

+ + + + - -

b.

- -

c.

+ + -

Electric Potential

Work and Potential Energy

๐Ÿž‡ Energy is defined as the capacity to do work. A body with energy can do work,

whereas a body without it cannot do work.

Potential energy

๐Ÿž‡ is one of the many forms of energy.

๐Ÿž‡ It is the energy of a body due to its position and normally converted into useful work.

๐Ÿž‡ This is why it is known as the energy at rest.

Gravitational potential energy (GPE)

๐Ÿž‡ a type of potential energy, is due to a

bodyโ€™s elevation from the ground.

๐Ÿž‡ A body placed higher above the ground can do greater work as it moves downward from its initial position.

Electric Potential

๐Ÿž‡ Electric potential is the amount of electric potential energy per unit charge. This is

equivalent to the amount of work needed to move a charge from one reference point to another.

Electric Potential

๐Ÿž‡

Example:

๐Ÿž‡ a. Compute the electric potential from a source charge of +5.02 ร— 10-13 C if a test charge will be placed 2.08 ร— 10-3 m from it.

๐Ÿž‡ The electric potential is approximately 2.17 V

๐Ÿž‡ b. How much is the electric potential from the

+4.02 ร— 10-15 C source charge if a test charge

will be placed 4.55 ร— 10-12 m from it.

๐Ÿž‡ The electric potential is approximately

7.94 ร— 108 V.

Compute the following electric potentials.

Source Charge

Distance from Source Charge

Electric Potential

+4.31 x 103 C

7.11x 10-12 m

-2.33 x 10-13 C

6.45x 10-15 m

๐Ÿž‡ Module 4: Voltage, Current,

and Resistance

Current: Flow of Electrical Charges

๐Ÿž‡ Normally, electrons move to any direction.

๐Ÿž‡ If this flow is regulated and made to move continuously in one direction, then the flow becomes an electric current.

๐Ÿž‡

Example 1:

๐Ÿž‡ a. Compute the current produced by a

+6.5 ร— 10-18 C charge flowing in 15 s.

๐Ÿž‡ The amount of current is approximately

4.33 ร— 10โ€“19 A.

๐Ÿž‡ b. A steady current of 0.6 A flows through a wire. How much charge passes through the wire in 1 minute

(min)?

๐Ÿž‡ In 1 min, a charge of 36 C will pass through the wire.

Example:

๐Ÿž‡ How much current is flowing when 29.3 Coulombs of charges pass a point in 7.84 seconds?

๐Ÿž‡ The amount of current is approximately 3.

74A.

Solve for the following. Copy and

Answer.

  1. Compute the current produced by a

+4.40 ร— 10 14 e charge flowing in 21 min.

  1. How much current is flowing when 4.32 x 10-15 e of charges pass a point in 7.84 seconds?
  2. How much current is flowing when 33.3 Coulombs of charges pass a point in 2 hours?
  3. Calculate the total DC resistance of a 100 metre roll of 2.5mm2 copper wire if the resistivity of copper is 1.72 x 10-8 ฮฉ metre.
  4. A 20 metre length of cable has a cross-sectional area of 1mm2 and a resistance of 5 ohms. Calculate the conductivity of the cable.
Resistance and Resistivity

๐Ÿž‡ An electrical conductor is any material that allows the free flow of electric current.

๐Ÿž‡ A conductor possesses characteristics that either enhance or limit the flow of current passing through it. The limitation to

current flow is referred to as resistance.

๐Ÿž‡ Resistance and electric current are inversely proportional. So a greater

amount of resistance on a conductor results in a lower amount of current passing through the conductor, whereas a lower resistance means less restrictions, allowing more current to flow through the conductor.

Electrical resistivity

๐Ÿž‡ is an intrinsic property of the material that describes how it resists the electric current flowing through it.

๐Ÿž‡ Higher electrical resistivity means higher overall resistance of the material, whereas lower resistivity indicates the materialโ€™s lower

resistance.

๐Ÿž‡ Consequently, current flow is reduced by an increase in the electrical resistivity of the material, whereas a decrease in the resistivity

allows more current to flow through the material.

electrical conductivity

๐Ÿž‡ an increase in the electrical conductivity of the material results in a lower resistance

offered by the material and a higher current flow through it. On the other hand, decreasing the electrical conductivity of the material increases its resistance and lowers the flow of current through it.

Factors or property of the material that affects the resistance and current flow

๐Ÿž‡ Temperature

๐Ÿž‡ Length of Conductor

๐Ÿž‡ Cross-sectional area of conductor

Temperature

๐Ÿž‡ If the conductor has a higher temperature, its resistance increases and the amount of current that can flow through it decreases.

๐Ÿž‡ On the other hand, if the conducting material has a lower temperature, the resistance decreases, thus allowing more current to flow through it

Length of the conductor

๐Ÿž‡ Longer conductors provide more resistance to the flow of current, which means less current can flow through it.

๐Ÿž‡ Shorter conductors provide less resistance, thus allowing more current to flow.

Cross-sectional area of the conductor

๐Ÿž‡ โ€œFatโ€ conductors allow more charges to pass

through them, which means more current can flow.

More current flow also means lower resistance offered by the conductor.

๐Ÿž‡ โ€œThinโ€ conductors, on the other hand, have limited space for current to flow through them, making resistance higher.

๐Ÿž‡

Sample problem1:

๐Ÿž‡ Compute the resistance of a conductor given a resistivity of 10.4 โ„ฆ-m, length of 4 m, and cross- sectional area of 7.85 ร— 10-3 m2.

๐Ÿž‡ The resistance of the conductor is approximately 5

299.36 โ„ฆ

  1. A conductor has a diameter of 2.59 mm. How many meters of this material are needed to yield a resistance of 1 โ„ฆ? The resistivity of the conductor is

1.77 ร— 10-8 โ„ฆ-m.

๐Ÿž‡ To obtain a resistance of 1 โ„ฆ, approximately

297.66 m of the conductor is needed.

Sample problem #2.

๐Ÿž‡ Solve for the resistance of a conductor given a resistivity of 15.3 โ„ฆ-m, length of 6 m, and cross-sectional area of 2.85 ร— 10-2 m2.

Sample Problem #3.

๐Ÿž‡ A copper rod is 3 m long and 4 mm in diameter. Compute its resistance if

the resistivity of the material is 1.76 ร— 10-8 โ„ฆ-m.

Electromotive Force

๐Ÿž‡ Electromotive force , it is the potential energy given to a unit charge to make it flow through a conductor or around a complete circuit.

๐Ÿž‡ The EMF acts like a charge pump that causes charges to flow through a circuit.

๐Ÿž‡ As a measurable quantity, EMF is measured using the unit volt (V)

Potential Difference

๐Ÿž‡ Similar to electromotive force is the potential difference (PD) across a circuit.

๐Ÿž‡ Potential difference is an actual consideration of the potentials in the circuit. The existence of PD also identifies the flow of

charges through the circuit. Without this difference, there will be no electric potential, thus making the flow of charges through the conductor impossible.

๐Ÿž‡ Both the EMF and PD are measured in terms of voltage (V).

Ohmโ€™s Law

๐Ÿž‡ In 1827, Georg Simon Ohm discovered the relationship among voltage, current, and resistance.

๐Ÿž‡ He found out that electricity acts similarly to water in

a pipe. Through this observation, he was able to

summarize the relationship among EMF or voltage (V ), electric current (I ), and resistance (R) through the Ohmโ€™s law.

๐Ÿž‡ In equation form, Ohmโ€™s law is stated as follows:

V = IR

Example 3:

๐Ÿž‡ a. Using Ohmโ€™s law, solve for the electric current of a conductor given a voltage of 25 V and a resistance of 10 โ„ฆ.

๐Ÿž‡ The current is approximately 2.5 A

๐Ÿž‡ b. An electric water heater uses 15 A of current when plugged to a 220-V outlet.

๐Ÿž‡ What is the resistance provided by the appliance?

๐Ÿž‡ The electric water heater provides a

resistance of approximately 14.67 โ„ฆ.

Electric Circuits

Electric Circuit.

๐Ÿž‡ The pathway for the current to move to and from the source and the appliance is called an electric circuit.

๐Ÿž‡ A functional circuit has to be โ€œclosedโ€ or

must form a closed loop.

Circuits

๐Ÿ–‰ In order for electricity to flow we need:

๐Ÿ–‰ Power source

๐Ÿ–‰ Closed circuit

๐Ÿ–‰ Two type of circuits:

๐Ÿ–‰ Series circuit

๐Ÿ–‰ Parallel circuit

Closed circuits

๐Ÿž‡ Closed circuits allow the current to flow from the source of the current to the load where the current is needed.

Open circuits

๐Ÿž‡ an โ€œopenโ€ circuit does not form a closed loop; the resulting circuit would then be nonfunctional.

๐Ÿž‡ Open circuits have gap(s) where current cannot flow.

๐Ÿž‡ Thus, electric current cannot be delivered

to the load where it is needed

The Series Circuit

Series Circuit

๐Ÿ–‰ In a series circuit there is only one path for the electrons to flow.

๐Ÿ–‰ In other words all the components are in series with each other

๐Ÿ–‰ Because there is only one path each charge will go

through each resistor

The Series Circuit

๐Ÿž‡ In a series circuit, all components are connected using a single pathway.

๐Ÿž‡ The current is the same for all the components along this circuit.

๐Ÿž‡ The total voltage is the sum of the individual voltages across the circuit.

๐Ÿž‡ the total resistance of the circuit is the sum of the individual resistances of each circuit load.

These relationships are summarized by the following formulas:

๐Ÿž‡ Vtotal = V1 + V2 + V3 + . . .+ Vn

๐Ÿž‡ Itotal = I1 = I2 = I3 = . . . = In

๐Ÿž‡ Rtotal = R1 + R2 + R3 + . . .+ R

Calculating Resistance in Series Circuits

๐Ÿ–‰The rule for calculating Series Circuits is toโ€ฆ

๐Ÿ–‰Add up the values of each individual in the series.

๐Ÿ–‰R1 + R2 + R3โ€ฆ

๐Ÿ–‰5 + 5 + 10

๐Ÿ–‰20 ฮฉ (ohms)

Calculating Resistance in Series Circuits

1

0

2

0

๐Ÿ–‰Add up the values of each individual in the series.

๐Ÿ–‰R1 + R2 + R3โ€ฆ

๐Ÿ–‰10 + 20 + 10

๐Ÿ–‰40 ฮฉ (ohms)

The Parallel Circuit

๐Ÿž‡ Parallel circuits use branches to allow current to pass through more than one path, unlike in the series circuit.

๐Ÿž‡ Thus, the individual voltages in a parallel circuit are the same as the total voltage.

๐Ÿž‡ The current in each load is not the same

as the total current in the circuit.

Parallel Circuit

๐Ÿ–‰ In a Parallel circuit there are multiple pathways for charge to flow.

๐Ÿ–‰ Each device is placed on itโ€™s own separate

branch

๐Ÿ–‰ Current goes through each of the branches at the

same time

The Parallel Circuit

๐Ÿž‡ The total current is the sum of the individual currents across the resistors.

๐Ÿž‡ The reciprocal of the total resistance in this type of circuit is equal to the sum of

the reciprocals of the individual resistances.

๐Ÿž‡ Always remember that the total resistance is always less than the individual resistances

The following formulas for a parallel circuit:

๐Ÿž‡ Vtotal= V1 = V2 = V3 = . . . = Vn

๐Ÿž‡ Itotal = I1 + I2 + I3 + . . .+ In

Calculating Resistance in Parallel Circuits

๐Ÿ–‰ The rule for calculating

Series Circuits is toโ€ฆ

๐Ÿ–‰ Add up the values of each

individual in the circuit.

๐Ÿ–‰ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

๐Ÿ–‰ 1 1 1 1

-- = -- + -- + --

Rt 4 4 2

๐Ÿ–‰ 1

-- = .25 + .25 + .5

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = 1

Rt

๐Ÿ–‰ 1

-- = Rt

1

๐Ÿ–‰ Rt = 1 ฮฉ (ohms)

2

0

Calculating Resistance in Parallel Circuit

๐Ÿž‡ The rule for calculating

Series Circuits is toโ€ฆ

๐Ÿž‡ Add up the values of each

individual in the circuit.

๐Ÿž‡ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

10

00

๐Ÿž‡ 1 1 1 1

-- = -- + -- + --

Rt 100 200 1000

๐Ÿž‡ 1

2

0

-- = .01 + .005 + .001

Rt

1

2

๐Ÿž‡

1

0

0

๐Ÿž‡

-- = .016

Rt 1

-- = .016

Rt

0

0

  • 1

-- = Rt

.016

  • Rt = 62.5 ฮฉ

(ohms)

robot