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Gen.-physics-2-Repaired

Electric Charge

  • Atom

is the basic building block of matter.

  • Subatomic particles

Protons are positively charged (+e)

Electrons have negative charges (-e).

Neutrons have no charge or are electrically neutral

Electric Charge

  • An electric charge determines the electric interaction and magnetic interaction between subatomic

particles and other charged particles.

  • This interaction between charges is summarized in the phrase β€œlike charges repel, unlike charges attract.

A glass rod and a rubber rod are used to demonstrate the interaction between electric charges. It was found out that after rubbing the rubber rod with fur and the glass rod with silk, both pairs of objects acquired charges. Two glass rods are found to repel each other, whereas a glass rod is found to be attracted to the rubber rod.

πŸž‡ In an atom, the subatomic particles provide the net charge. An

electrically neutral atom contains an equal number of protons and electrons.

πŸž‡ An atom that has an imbalance in the number of protons and

electrons is called an ion. Cations are positive (more protons than electrons), and anions are negative ( more electrons than protons).

πŸž‡ As a derived SI (or International System of Units) quantity, an electric charge is represented by the symbol

β€œq” and measured using the unit

coulomb (C).

πŸž‡ 1 coulomb = 6.242 x 10^18 e

Law of Charges

πŸž‡ Like charges repel each other, and unlike charges attract

each other.

πŸž‡ Macroscopically, a body is electrically charged if the number of positive charges

it has is not equal to the number of the negative charges. In other words, the charge of a particle depends on the sum of its electrical charges.

What is the charge of each atom if it comprises the following particles?

  1. 5 electrons and 6 protons
  2. 14 protons and 11 electrons
  3. 5 electrons and 5 protons
  4. 25 protons and 26 electrons

Compute the charge of the following ions in Coulomb.

a. Ion with a charge of -2e

a. Ion with a charge of +5e

a. Ion with a charge of -3e

  1. Ion with a charge of -7e
  2. Ion with a charge of +6e

Conductors

Conductors

πŸž‡ are materials that allow electrical charges to move from one material to another.

πŸž‡ Conductors may be charged through different methodsβ€” rubbing, conduction, and induction.

Charging by Rubbing

πŸž‡ An electrically neutral body can gain a charge by rubbing or friction.

πŸž‡ Consider two different uncharged bodies. Because of the difference in their material compositions, the nuclei of their atoms pull their electrons with different strengths.

πŸž‡ Rubbing these two bodies will force their atoms to interact with one another, resulting in the β€œripping off” of electron(s)from the body with a weaker electron hold.

πŸž‡ The β€œripped off” electrons are then transferred to the other body. After rubbing, one of the bodies will have more electrons, and the other one will have fewer. Thus, both of them will now be electrically charged.

Triboelectric series

πŸž‡ is a list of common materials that were experimented on and found to behave in a predictable way.

πŸž‡ When these materials are rubbed together, those that appear first in the list tend to lose their electrons, making them positive.

πŸž‡ Those latter in the list tend to gain electrons, making them negative.

πŸž‡ In other words, if you rub any two of the materials in the series, the material in the upper part of the list will be positive, and the other material in the lower part will be negative.

πŸž‡ Using the information presented in table 1.1, determine the acquired charges of the bodies in each of the following pairs if

they are rubbed together.

πŸž‡ a. wood and Styrofoam

πŸž‡ wood: +

πŸž‡ Styrofoam: -

  1. glass and leather glass: -

leather: +

  1. rubber and rubber rubber: none

rubber: none

  1. dry hand and PVC dry hand: +

PVC: -

Charging by Conduction

Charging by Conduction

πŸž‡ During charging by conduction, both objects acquire the same type of charge.

πŸž‡ If a negative object is used to charge a neutral object, then objects become charged negatively.

Charging by Induction.

πŸž‡ A negatively charged balloon is placed near (but without physical contact) a neutral tin can. As a result, the positive

charges of the can move to the left, near the negatively charged balloon because of attraction. Meanwhile, the negative charges move to the right side of the tin can, away from the balloon because of repulsion. The excess negative charges at the right side of the tin can are known as induced charges.

Electric Dipoles

Electric Dipoles

πŸž‡ When you bring a neutrally charged body A near a

strongly negative body B, its positive charges will be

drawn near B, and the negative charges will be pushed to the other side. This resulting condition polarizes the body and forms a dipole.

πŸž‡ Polarization is the process wherein an electrically neutral body becomes polar by the rearrangement of its molecules. As the molecules realign or move, particles with similar charges group together and move toward the opposite ends of the body.

πŸž‡ Hence, the body becomes positive at one end and negative on the other, making it a dipole.

πŸž‡ Point dipoles refer to atoms bearing a positive side and a negative side. In such atoms, the electrons

converge or gather on one side and the protons on the other.

πŸž‡ Molecular dipoles. This type of dipole involves a

molecule having a negatively charged side and a

positively charged side. The electronegative atoms of the molecule form the negative end of the molecule, and the electropositive ones are responsible for the positive end.

Another way to classify dipoles is whether they are permanent or temporary(instantaneous). An instantaneous or a temporary dipole is an atom or a molecule with most of its negative charges shifted only to one side as a result of their random movement.

MODULE 2

ELECTROSTATIC FORCE, ELECTRIC FIELD, AND ELECTRIC FLUX

At the end of this module, I can :

πŸž‡ Define electrostatic force using Coulomb's Law.

πŸž‡ Calculate the electrostatic force between two charges using Coulomb's Law.

πŸž‡ Compute the Electric Field at a given distance from a given source charge.

πŸž‡ a push or a pull pertains to force.

πŸž‡ electric charges exert a force on each other as they interact.

πŸž‡ The act of repelling implies pushing and the act of attracting suggests pulling.

Electrostatic Force

Electrostatic Force

πŸž‡ The attraction and repulsion between electric charges comes from a force known as electrostatic force.

πŸž‡ This force can be computed using

Coulomb’s law for electrostatics.

Example 1:

πŸž‡ What is the electrostatic force of attraction between a -6.0 Γ— 10^-6 C charge and a 4.0 Γ— 10^-6 C charge if they are separated by a distance of 3

meters(m)?

0.02 N

Example 2:

πŸž‡ Two identically charged one-peso coins are 1.5 m apart on a table.

What is the charge of one of the coins if each of them experiences a repulsive force of 2.0 N?

2.23 x 10^-5 C

TRY THIS!!!

πŸž‡ Compute the force of attraction between a +1.60 x 10^-19 C and -2.09 x 10^-18C

charge if they are 4.0 x 10^-10 m apart.

0.00000001879 N

TRY THIS!!!

πŸž‡ Calculate the repulsive force between a

-0.71783 electron charge and a -1.49 x

10^-8 C charge if a distance of 2.01 x 10^-20 m separates them.

TRY THIS!!!

πŸž‡ Two ball bearings with same charges are 87.00787 inches apart

on the floor. What are their charges if they are attracted to each other with a force of 8.11 N

?

Electric Field and Its Representation

πŸž‡ An electric field is a region of space where an electric charge experiences a force.

πŸž‡ An electric field is a measurable effect generated

by any charged object.

πŸž‡ An electric field coexists with every electrostatic charge; it associates with each point in space the electrostatic force experienced per unit of electric

charge, by an extremely small (or infinitesimal) test charge at that point.

Electric fields

πŸž‡ predict the behavior of the charges present in any location in space.

πŸž‡ Physicists compute the value of an electric field because of its direct relation with electrostatic force.

πŸž‡ Mathematically, the electric field can be

computed using the equation:

πŸž‡ E - is the electric field,

πŸž‡ Q is the source charge

πŸž‡ r is the distance from the source charge where the electric field is being measured.

πŸž‡ The unit used to measure electric field is newton per coulomb (N/C).

Source and Test Charge

πŸž‡ The charge Q which is producing the

electric field, is called a source charge

and the charge q, which tests the effect the charge of source charge, is called a test charge.

Source charge

πŸž‡ is the charge from where the electric field comes from.

Test Charge

πŸž‡ is a single charge whose behavior is measured or determined based on the

presence of external factors or stimuli. Its presence is arbitrary. For easier computation, a unit of 1 C is used.

Example :

πŸž‡ Calculate the electric field that a test charge will experience on the following distances from the source charge of

+5.02 Γ— 10-13 C.

πŸž‡ a. Distance from source charge:

2.04 Γ— 10-3 m.

Source charge will experience an electric field of

approximately 1 084.43 N/C

πŸž‡ b. Distance from source charge:

1.55 Γ— 10-12 m.

πŸž‡ The source charge will experience an electric field

of approximately 1.88 Γ— 1021 N/C.

Answer the following: Copy and Answer.

πŸž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +3.1397 Γ— 1015 e

Distance from source charge: 2.33 Γ— 10-5 m

  1. Source charge: -4.33 Γ— 10-12 C

Distance from source charge: 4.6 Γ— 10-19 m

Answer the following: Copy and Answer.

πŸž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +4.05 Γ— 10-5 C

Distance from source charge: 3.23 Γ— 10-7 m

  1. Source charge: -6.53 Γ— 10-10 C

Distance from source charge: 3.7 Γ— 10-15 m

  1. Source charge: +5.45 Γ— 10-12 C

Distance from source charge: 6.8 Γ— 10-17

  1. Source charge: -3.44 Γ— 10-16 C

Distance from source charge: 4.43 Γ— 10-12

Copy and Answer:

  1. What is the electrostatic force of attraction between a -6.0 Γ— 10^-6 C charge and a 4.0 Γ— 10^- 6 C charge if they are separated by a distance of 3 meters(m)?
  2. 2. Two ball bearings with opposite charges are

1.11 m apart on the floor. What are their charges if they are attracted to each other with a force of

5.11 N ?

  1. Calculate the repulsive force between a -2.23 x 10^-6 C charge and a -2.49 x 10^-5 C charge if a distance of 3.55 x 10^-21 m separates them.

Continuation….

πŸž‡ II. Compute the electrostatic force experienced by

-4.43 Γ— 10-18 C charge from the following electric

fields:

a.

E = 5 465 N/C

b.

E = 9.5 Γ— 1015 N/C

E = 8.97 Γ— 1024 N/C

Electric Field Lines

πŸž‡ An electric field can be graphically represented using electric field lines. The

density or thickness of these lines is directly proportional to the strength of the electric field at any region in space.

πŸž‡ If the field lines are close to each other, the electric field is stronger.

Electric field lines are drawn based on the charge being considered.

πŸž‡ Positive charges have field lines drawn from them.

πŸž‡ Negative charges have field lines drawn to them.

Electric field lines from the positive charge going to the negative charge.

Draw electric lines for the following charges.

  1. d.

+ + + + - -

b.

- -

c.

+ + -

Electric Potential

Work and Potential Energy

πŸž‡ Energy is defined as the capacity to do work. A body with energy can do work,

whereas a body without it cannot do work.

Potential energy

πŸž‡ is one of the many forms of energy.

πŸž‡ It is the energy of a body due to its position and normally converted into useful work.

πŸž‡ This is why it is known as the energy at rest.

Gravitational potential energy (GPE)

πŸž‡ a type of potential energy, is due to a

body’s elevation from the ground.

πŸž‡ A body placed higher above the ground can do greater work as it moves downward from its initial position.

Electric Potential

πŸž‡ Electric potential is the amount of electric potential energy per unit charge. This is

equivalent to the amount of work needed to move a charge from one reference point to another.

Electric Potential

πŸž‡

Example:

πŸž‡ a. Compute the electric potential from a source charge of +5.02 Γ— 10-13 C if a test charge will be placed 2.08 Γ— 10-3 m from it.

πŸž‡ The electric potential is approximately 2.17 V

πŸž‡ b. How much is the electric potential from the

+4.02 Γ— 10-15 C source charge if a test charge

will be placed 4.55 Γ— 10-12 m from it.

πŸž‡ The electric potential is approximately

7.94 Γ— 108 V.

Compute the following electric potentials.

Source Charge

Distance from Source Charge

Electric Potential

+4.31 x 103 C

7.11x 10-12 m

-2.33 x 10-13 C

6.45x 10-15 m

πŸž‡ Module 4: Voltage, Current,

and Resistance

Current: Flow of Electrical Charges

πŸž‡ Normally, electrons move to any direction.

πŸž‡ If this flow is regulated and made to move continuously in one direction, then the flow becomes an electric current.

πŸž‡

Example 1:

πŸž‡ a. Compute the current produced by a

+6.5 Γ— 10-18 C charge flowing in 15 s.

πŸž‡ The amount of current is approximately

4.33 Γ— 10–19 A.

πŸž‡ b. A steady current of 0.6 A flows through a wire. How much charge passes through the wire in 1 minute

(min)?

πŸž‡ In 1 min, a charge of 36 C will pass through the wire.

Example:

πŸž‡ How much current is flowing when 29.3 Coulombs of charges pass a point in 7.84 seconds?

πŸž‡ The amount of current is approximately 3.

74A.

Solve for the following. Copy and

Answer.

  1. Compute the current produced by a

+4.40 Γ— 10 14 e charge flowing in 21 min.

  1. How much current is flowing when 4.32 x 10-15 e of charges pass a point in 7.84 seconds?
  2. How much current is flowing when 33.3 Coulombs of charges pass a point in 2 hours?
  3. Calculate the total DC resistance of a 100 metre roll of 2.5mm2 copper wire if the resistivity of copper is 1.72 x 10-8 Ξ© metre.
  4. A 20 metre length of cable has a cross-sectional area of 1mm2 and a resistance of 5 ohms. Calculate the conductivity of the cable.
Resistance and Resistivity

πŸž‡ An electrical conductor is any material that allows the free flow of electric current.

πŸž‡ A conductor possesses characteristics that either enhance or limit the flow of current passing through it. The limitation to

current flow is referred to as resistance.

πŸž‡ Resistance and electric current are inversely proportional. So a greater

amount of resistance on a conductor results in a lower amount of current passing through the conductor, whereas a lower resistance means less restrictions, allowing more current to flow through the conductor.

Electrical resistivity

πŸž‡ is an intrinsic property of the material that describes how it resists the electric current flowing through it.

πŸž‡ Higher electrical resistivity means higher overall resistance of the material, whereas lower resistivity indicates the material’s lower

resistance.

πŸž‡ Consequently, current flow is reduced by an increase in the electrical resistivity of the material, whereas a decrease in the resistivity

allows more current to flow through the material.

electrical conductivity

πŸž‡ an increase in the electrical conductivity of the material results in a lower resistance

offered by the material and a higher current flow through it. On the other hand, decreasing the electrical conductivity of the material increases its resistance and lowers the flow of current through it.

Factors or property of the material that affects the resistance and current flow

πŸž‡ Temperature

πŸž‡ Length of Conductor

πŸž‡ Cross-sectional area of conductor

Temperature

πŸž‡ If the conductor has a higher temperature, its resistance increases and the amount of current that can flow through it decreases.

πŸž‡ On the other hand, if the conducting material has a lower temperature, the resistance decreases, thus allowing more current to flow through it

Length of the conductor

πŸž‡ Longer conductors provide more resistance to the flow of current, which means less current can flow through it.

πŸž‡ Shorter conductors provide less resistance, thus allowing more current to flow.

Cross-sectional area of the conductor

πŸž‡ β€œFat” conductors allow more charges to pass

through them, which means more current can flow.

More current flow also means lower resistance offered by the conductor.

πŸž‡ β€œThin” conductors, on the other hand, have limited space for current to flow through them, making resistance higher.

πŸž‡

Sample problem1:

πŸž‡ Compute the resistance of a conductor given a resistivity of 10.4 Ω-m, length of 4 m, and cross- sectional area of 7.85 Γ— 10-3 m2.

πŸž‡ The resistance of the conductor is approximately 5

299.36 Ω

  1. A conductor has a diameter of 2.59 mm. How many meters of this material are needed to yield a resistance of 1 Ω? The resistivity of the conductor is

1.77 Γ— 10-8 Ω-m.

πŸž‡ To obtain a resistance of 1 Ω, approximately

297.66 m of the conductor is needed.

Sample problem #2.

πŸž‡ Solve for the resistance of a conductor given a resistivity of 15.3 Ω-m, length of 6 m, and cross-sectional area of 2.85 Γ— 10-2 m2.

Sample Problem #3.

πŸž‡ A copper rod is 3 m long and 4 mm in diameter. Compute its resistance if

the resistivity of the material is 1.76 Γ— 10-8 Ω-m.

Electromotive Force

πŸž‡ Electromotive force , it is the potential energy given to a unit charge to make it flow through a conductor or around a complete circuit.

πŸž‡ The EMF acts like a charge pump that causes charges to flow through a circuit.

πŸž‡ As a measurable quantity, EMF is measured using the unit volt (V)

Potential Difference

πŸž‡ Similar to electromotive force is the potential difference (PD) across a circuit.

πŸž‡ Potential difference is an actual consideration of the potentials in the circuit. The existence of PD also identifies the flow of

charges through the circuit. Without this difference, there will be no electric potential, thus making the flow of charges through the conductor impossible.

πŸž‡ Both the EMF and PD are measured in terms of voltage (V).

Ohm’s Law

πŸž‡ In 1827, Georg Simon Ohm discovered the relationship among voltage, current, and resistance.

πŸž‡ He found out that electricity acts similarly to water in

a pipe. Through this observation, he was able to

summarize the relationship among EMF or voltage (V ), electric current (I ), and resistance (R) through the Ohm’s law.

πŸž‡ In equation form, Ohm’s law is stated as follows:

V = IR

Example 3:

πŸž‡ a. Using Ohm’s law, solve for the electric current of a conductor given a voltage of 25 V and a resistance of 10 Ω.

πŸž‡ The current is approximately 2.5 A

πŸž‡ b. An electric water heater uses 15 A of current when plugged to a 220-V outlet.

πŸž‡ What is the resistance provided by the appliance?

πŸž‡ The electric water heater provides a

resistance of approximately 14.67 Ω.

Electric Circuits

Electric Circuit.

πŸž‡ The pathway for the current to move to and from the source and the appliance is called an electric circuit.

πŸž‡ A functional circuit has to be β€œclosed” or

must form a closed loop.

Circuits

πŸ–‰ In order for electricity to flow we need:

πŸ–‰ Power source

πŸ–‰ Closed circuit

πŸ–‰ Two type of circuits:

πŸ–‰ Series circuit

πŸ–‰ Parallel circuit

Closed circuits

πŸž‡ Closed circuits allow the current to flow from the source of the current to the load where the current is needed.

Open circuits

πŸž‡ an β€œopen” circuit does not form a closed loop; the resulting circuit would then be nonfunctional.

πŸž‡ Open circuits have gap(s) where current cannot flow.

πŸž‡ Thus, electric current cannot be delivered

to the load where it is needed

The Series Circuit

Series Circuit

πŸ–‰ In a series circuit there is only one path for the electrons to flow.

πŸ–‰ In other words all the components are in series with each other

πŸ–‰ Because there is only one path each charge will go

through each resistor

The Series Circuit

πŸž‡ In a series circuit, all components are connected using a single pathway.

πŸž‡ The current is the same for all the components along this circuit.

πŸž‡ The total voltage is the sum of the individual voltages across the circuit.

πŸž‡ the total resistance of the circuit is the sum of the individual resistances of each circuit load.

These relationships are summarized by the following formulas:

πŸž‡ Vtotal = V1 + V2 + V3 + . . .+ Vn

πŸž‡ Itotal = I1 = I2 = I3 = . . . = In

πŸž‡ Rtotal = R1 + R2 + R3 + . . .+ R

Calculating Resistance in Series Circuits

πŸ–‰The rule for calculating Series Circuits is to…

πŸ–‰Add up the values of each individual in the series.

πŸ–‰R1 + R2 + R3…

πŸ–‰5 + 5 + 10

πŸ–‰20 Ξ© (ohms)

Calculating Resistance in Series Circuits

1

0

2

0

πŸ–‰Add up the values of each individual in the series.

πŸ–‰R1 + R2 + R3…

πŸ–‰10 + 20 + 10

πŸ–‰40 Ξ© (ohms)

The Parallel Circuit

πŸž‡ Parallel circuits use branches to allow current to pass through more than one path, unlike in the series circuit.

πŸž‡ Thus, the individual voltages in a parallel circuit are the same as the total voltage.

πŸž‡ The current in each load is not the same

as the total current in the circuit.

Parallel Circuit

πŸ–‰ In a Parallel circuit there are multiple pathways for charge to flow.

πŸ–‰ Each device is placed on it’s own separate

branch

πŸ–‰ Current goes through each of the branches at the

same time

The Parallel Circuit

πŸž‡ The total current is the sum of the individual currents across the resistors.

πŸž‡ The reciprocal of the total resistance in this type of circuit is equal to the sum of

the reciprocals of the individual resistances.

πŸž‡ Always remember that the total resistance is always less than the individual resistances

The following formulas for a parallel circuit:

πŸž‡ Vtotal= V1 = V2 = V3 = . . . = Vn

πŸž‡ Itotal = I1 + I2 + I3 + . . .+ In

Calculating Resistance in Parallel Circuits

πŸ–‰ The rule for calculating

Series Circuits is to…

πŸ–‰ Add up the values of each

individual in the circuit.

πŸ–‰ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

πŸ–‰ 1 1 1 1

-- = -- + -- + --

Rt 4 4 2

πŸ–‰ 1

-- = .25 + .25 + .5

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = Rt

1

πŸ–‰ Rt = 1 Ξ© (ohms)

2

0

Calculating Resistance in Parallel Circuit

πŸž‡ The rule for calculating

Series Circuits is to…

πŸž‡ Add up the values of each

individual in the circuit.

πŸž‡ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

10

00

πŸž‡ 1 1 1 1

-- = -- + -- + --

Rt 100 200 1000

πŸž‡ 1

2

0

-- = .01 + .005 + .001

Rt

1

2

πŸž‡

1

0

0

πŸž‡

-- = .016

Rt 1

-- = .016

Rt

0

0

  • 1

-- = Rt

.016

  • Rt = 62.5 Ξ©

(ohms)

GJ

Gen.-physics-2-Repaired

Electric Charge

  • Atom

is the basic building block of matter.

  • Subatomic particles

Protons are positively charged (+e)

Electrons have negative charges (-e).

Neutrons have no charge or are electrically neutral

Electric Charge

  • An electric charge determines the electric interaction and magnetic interaction between subatomic

particles and other charged particles.

  • This interaction between charges is summarized in the phrase β€œlike charges repel, unlike charges attract.

A glass rod and a rubber rod are used to demonstrate the interaction between electric charges. It was found out that after rubbing the rubber rod with fur and the glass rod with silk, both pairs of objects acquired charges. Two glass rods are found to repel each other, whereas a glass rod is found to be attracted to the rubber rod.

πŸž‡ In an atom, the subatomic particles provide the net charge. An

electrically neutral atom contains an equal number of protons and electrons.

πŸž‡ An atom that has an imbalance in the number of protons and

electrons is called an ion. Cations are positive (more protons than electrons), and anions are negative ( more electrons than protons).

πŸž‡ As a derived SI (or International System of Units) quantity, an electric charge is represented by the symbol

β€œq” and measured using the unit

coulomb (C).

πŸž‡ 1 coulomb = 6.242 x 10^18 e

Law of Charges

πŸž‡ Like charges repel each other, and unlike charges attract

each other.

πŸž‡ Macroscopically, a body is electrically charged if the number of positive charges

it has is not equal to the number of the negative charges. In other words, the charge of a particle depends on the sum of its electrical charges.

What is the charge of each atom if it comprises the following particles?

  1. 5 electrons and 6 protons
  2. 14 protons and 11 electrons
  3. 5 electrons and 5 protons
  4. 25 protons and 26 electrons

Compute the charge of the following ions in Coulomb.

a. Ion with a charge of -2e

a. Ion with a charge of +5e

a. Ion with a charge of -3e

  1. Ion with a charge of -7e
  2. Ion with a charge of +6e

Conductors

Conductors

πŸž‡ are materials that allow electrical charges to move from one material to another.

πŸž‡ Conductors may be charged through different methodsβ€” rubbing, conduction, and induction.

Charging by Rubbing

πŸž‡ An electrically neutral body can gain a charge by rubbing or friction.

πŸž‡ Consider two different uncharged bodies. Because of the difference in their material compositions, the nuclei of their atoms pull their electrons with different strengths.

πŸž‡ Rubbing these two bodies will force their atoms to interact with one another, resulting in the β€œripping off” of electron(s)from the body with a weaker electron hold.

πŸž‡ The β€œripped off” electrons are then transferred to the other body. After rubbing, one of the bodies will have more electrons, and the other one will have fewer. Thus, both of them will now be electrically charged.

Triboelectric series

πŸž‡ is a list of common materials that were experimented on and found to behave in a predictable way.

πŸž‡ When these materials are rubbed together, those that appear first in the list tend to lose their electrons, making them positive.

πŸž‡ Those latter in the list tend to gain electrons, making them negative.

πŸž‡ In other words, if you rub any two of the materials in the series, the material in the upper part of the list will be positive, and the other material in the lower part will be negative.

πŸž‡ Using the information presented in table 1.1, determine the acquired charges of the bodies in each of the following pairs if

they are rubbed together.

πŸž‡ a. wood and Styrofoam

πŸž‡ wood: +

πŸž‡ Styrofoam: -

  1. glass and leather glass: -

leather: +

  1. rubber and rubber rubber: none

rubber: none

  1. dry hand and PVC dry hand: +

PVC: -

Charging by Conduction

Charging by Conduction

πŸž‡ During charging by conduction, both objects acquire the same type of charge.

πŸž‡ If a negative object is used to charge a neutral object, then objects become charged negatively.

Charging by Induction.

πŸž‡ A negatively charged balloon is placed near (but without physical contact) a neutral tin can. As a result, the positive

charges of the can move to the left, near the negatively charged balloon because of attraction. Meanwhile, the negative charges move to the right side of the tin can, away from the balloon because of repulsion. The excess negative charges at the right side of the tin can are known as induced charges.

Electric Dipoles

Electric Dipoles

πŸž‡ When you bring a neutrally charged body A near a

strongly negative body B, its positive charges will be

drawn near B, and the negative charges will be pushed to the other side. This resulting condition polarizes the body and forms a dipole.

πŸž‡ Polarization is the process wherein an electrically neutral body becomes polar by the rearrangement of its molecules. As the molecules realign or move, particles with similar charges group together and move toward the opposite ends of the body.

πŸž‡ Hence, the body becomes positive at one end and negative on the other, making it a dipole.

πŸž‡ Point dipoles refer to atoms bearing a positive side and a negative side. In such atoms, the electrons

converge or gather on one side and the protons on the other.

πŸž‡ Molecular dipoles. This type of dipole involves a

molecule having a negatively charged side and a

positively charged side. The electronegative atoms of the molecule form the negative end of the molecule, and the electropositive ones are responsible for the positive end.

Another way to classify dipoles is whether they are permanent or temporary(instantaneous). An instantaneous or a temporary dipole is an atom or a molecule with most of its negative charges shifted only to one side as a result of their random movement.

MODULE 2

ELECTROSTATIC FORCE, ELECTRIC FIELD, AND ELECTRIC FLUX

At the end of this module, I can :

πŸž‡ Define electrostatic force using Coulomb's Law.

πŸž‡ Calculate the electrostatic force between two charges using Coulomb's Law.

πŸž‡ Compute the Electric Field at a given distance from a given source charge.

πŸž‡ a push or a pull pertains to force.

πŸž‡ electric charges exert a force on each other as they interact.

πŸž‡ The act of repelling implies pushing and the act of attracting suggests pulling.

Electrostatic Force

Electrostatic Force

πŸž‡ The attraction and repulsion between electric charges comes from a force known as electrostatic force.

πŸž‡ This force can be computed using

Coulomb’s law for electrostatics.

Example 1:

πŸž‡ What is the electrostatic force of attraction between a -6.0 Γ— 10^-6 C charge and a 4.0 Γ— 10^-6 C charge if they are separated by a distance of 3

meters(m)?

0.02 N

Example 2:

πŸž‡ Two identically charged one-peso coins are 1.5 m apart on a table.

What is the charge of one of the coins if each of them experiences a repulsive force of 2.0 N?

2.23 x 10^-5 C

TRY THIS!!!

πŸž‡ Compute the force of attraction between a +1.60 x 10^-19 C and -2.09 x 10^-18C

charge if they are 4.0 x 10^-10 m apart.

0.00000001879 N

TRY THIS!!!

πŸž‡ Calculate the repulsive force between a

-0.71783 electron charge and a -1.49 x

10^-8 C charge if a distance of 2.01 x 10^-20 m separates them.

TRY THIS!!!

πŸž‡ Two ball bearings with same charges are 87.00787 inches apart

on the floor. What are their charges if they are attracted to each other with a force of 8.11 N

?

Electric Field and Its Representation

πŸž‡ An electric field is a region of space where an electric charge experiences a force.

πŸž‡ An electric field is a measurable effect generated

by any charged object.

πŸž‡ An electric field coexists with every electrostatic charge; it associates with each point in space the electrostatic force experienced per unit of electric

charge, by an extremely small (or infinitesimal) test charge at that point.

Electric fields

πŸž‡ predict the behavior of the charges present in any location in space.

πŸž‡ Physicists compute the value of an electric field because of its direct relation with electrostatic force.

πŸž‡ Mathematically, the electric field can be

computed using the equation:

πŸž‡ E - is the electric field,

πŸž‡ Q is the source charge

πŸž‡ r is the distance from the source charge where the electric field is being measured.

πŸž‡ The unit used to measure electric field is newton per coulomb (N/C).

Source and Test Charge

πŸž‡ The charge Q which is producing the

electric field, is called a source charge

and the charge q, which tests the effect the charge of source charge, is called a test charge.

Source charge

πŸž‡ is the charge from where the electric field comes from.

Test Charge

πŸž‡ is a single charge whose behavior is measured or determined based on the

presence of external factors or stimuli. Its presence is arbitrary. For easier computation, a unit of 1 C is used.

Example :

πŸž‡ Calculate the electric field that a test charge will experience on the following distances from the source charge of

+5.02 Γ— 10-13 C.

πŸž‡ a. Distance from source charge:

2.04 Γ— 10-3 m.

Source charge will experience an electric field of

approximately 1 084.43 N/C

πŸž‡ b. Distance from source charge:

1.55 Γ— 10-12 m.

πŸž‡ The source charge will experience an electric field

of approximately 1.88 Γ— 1021 N/C.

Answer the following: Copy and Answer.

πŸž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +3.1397 Γ— 1015 e

Distance from source charge: 2.33 Γ— 10-5 m

  1. Source charge: -4.33 Γ— 10-12 C

Distance from source charge: 4.6 Γ— 10-19 m

Answer the following: Copy and Answer.

πŸž‡ I. Calculate the electric field experienced by a test charge given the following conditions:

  1. Source charge: +4.05 Γ— 10-5 C

Distance from source charge: 3.23 Γ— 10-7 m

  1. Source charge: -6.53 Γ— 10-10 C

Distance from source charge: 3.7 Γ— 10-15 m

  1. Source charge: +5.45 Γ— 10-12 C

Distance from source charge: 6.8 Γ— 10-17

  1. Source charge: -3.44 Γ— 10-16 C

Distance from source charge: 4.43 Γ— 10-12

Copy and Answer:

  1. What is the electrostatic force of attraction between a -6.0 Γ— 10^-6 C charge and a 4.0 Γ— 10^- 6 C charge if they are separated by a distance of 3 meters(m)?
  2. 2. Two ball bearings with opposite charges are

1.11 m apart on the floor. What are their charges if they are attracted to each other with a force of

5.11 N ?

  1. Calculate the repulsive force between a -2.23 x 10^-6 C charge and a -2.49 x 10^-5 C charge if a distance of 3.55 x 10^-21 m separates them.

Continuation….

πŸž‡ II. Compute the electrostatic force experienced by

-4.43 Γ— 10-18 C charge from the following electric

fields:

a.

E = 5 465 N/C

b.

E = 9.5 Γ— 1015 N/C

E = 8.97 Γ— 1024 N/C

Electric Field Lines

πŸž‡ An electric field can be graphically represented using electric field lines. The

density or thickness of these lines is directly proportional to the strength of the electric field at any region in space.

πŸž‡ If the field lines are close to each other, the electric field is stronger.

Electric field lines are drawn based on the charge being considered.

πŸž‡ Positive charges have field lines drawn from them.

πŸž‡ Negative charges have field lines drawn to them.

Electric field lines from the positive charge going to the negative charge.

Draw electric lines for the following charges.

  1. d.

+ + + + - -

b.

- -

c.

+ + -

Electric Potential

Work and Potential Energy

πŸž‡ Energy is defined as the capacity to do work. A body with energy can do work,

whereas a body without it cannot do work.

Potential energy

πŸž‡ is one of the many forms of energy.

πŸž‡ It is the energy of a body due to its position and normally converted into useful work.

πŸž‡ This is why it is known as the energy at rest.

Gravitational potential energy (GPE)

πŸž‡ a type of potential energy, is due to a

body’s elevation from the ground.

πŸž‡ A body placed higher above the ground can do greater work as it moves downward from its initial position.

Electric Potential

πŸž‡ Electric potential is the amount of electric potential energy per unit charge. This is

equivalent to the amount of work needed to move a charge from one reference point to another.

Electric Potential

πŸž‡

Example:

πŸž‡ a. Compute the electric potential from a source charge of +5.02 Γ— 10-13 C if a test charge will be placed 2.08 Γ— 10-3 m from it.

πŸž‡ The electric potential is approximately 2.17 V

πŸž‡ b. How much is the electric potential from the

+4.02 Γ— 10-15 C source charge if a test charge

will be placed 4.55 Γ— 10-12 m from it.

πŸž‡ The electric potential is approximately

7.94 Γ— 108 V.

Compute the following electric potentials.

Source Charge

Distance from Source Charge

Electric Potential

+4.31 x 103 C

7.11x 10-12 m

-2.33 x 10-13 C

6.45x 10-15 m

πŸž‡ Module 4: Voltage, Current,

and Resistance

Current: Flow of Electrical Charges

πŸž‡ Normally, electrons move to any direction.

πŸž‡ If this flow is regulated and made to move continuously in one direction, then the flow becomes an electric current.

πŸž‡

Example 1:

πŸž‡ a. Compute the current produced by a

+6.5 Γ— 10-18 C charge flowing in 15 s.

πŸž‡ The amount of current is approximately

4.33 Γ— 10–19 A.

πŸž‡ b. A steady current of 0.6 A flows through a wire. How much charge passes through the wire in 1 minute

(min)?

πŸž‡ In 1 min, a charge of 36 C will pass through the wire.

Example:

πŸž‡ How much current is flowing when 29.3 Coulombs of charges pass a point in 7.84 seconds?

πŸž‡ The amount of current is approximately 3.

74A.

Solve for the following. Copy and

Answer.

  1. Compute the current produced by a

+4.40 Γ— 10 14 e charge flowing in 21 min.

  1. How much current is flowing when 4.32 x 10-15 e of charges pass a point in 7.84 seconds?
  2. How much current is flowing when 33.3 Coulombs of charges pass a point in 2 hours?
  3. Calculate the total DC resistance of a 100 metre roll of 2.5mm2 copper wire if the resistivity of copper is 1.72 x 10-8 Ξ© metre.
  4. A 20 metre length of cable has a cross-sectional area of 1mm2 and a resistance of 5 ohms. Calculate the conductivity of the cable.
Resistance and Resistivity

πŸž‡ An electrical conductor is any material that allows the free flow of electric current.

πŸž‡ A conductor possesses characteristics that either enhance or limit the flow of current passing through it. The limitation to

current flow is referred to as resistance.

πŸž‡ Resistance and electric current are inversely proportional. So a greater

amount of resistance on a conductor results in a lower amount of current passing through the conductor, whereas a lower resistance means less restrictions, allowing more current to flow through the conductor.

Electrical resistivity

πŸž‡ is an intrinsic property of the material that describes how it resists the electric current flowing through it.

πŸž‡ Higher electrical resistivity means higher overall resistance of the material, whereas lower resistivity indicates the material’s lower

resistance.

πŸž‡ Consequently, current flow is reduced by an increase in the electrical resistivity of the material, whereas a decrease in the resistivity

allows more current to flow through the material.

electrical conductivity

πŸž‡ an increase in the electrical conductivity of the material results in a lower resistance

offered by the material and a higher current flow through it. On the other hand, decreasing the electrical conductivity of the material increases its resistance and lowers the flow of current through it.

Factors or property of the material that affects the resistance and current flow

πŸž‡ Temperature

πŸž‡ Length of Conductor

πŸž‡ Cross-sectional area of conductor

Temperature

πŸž‡ If the conductor has a higher temperature, its resistance increases and the amount of current that can flow through it decreases.

πŸž‡ On the other hand, if the conducting material has a lower temperature, the resistance decreases, thus allowing more current to flow through it

Length of the conductor

πŸž‡ Longer conductors provide more resistance to the flow of current, which means less current can flow through it.

πŸž‡ Shorter conductors provide less resistance, thus allowing more current to flow.

Cross-sectional area of the conductor

πŸž‡ β€œFat” conductors allow more charges to pass

through them, which means more current can flow.

More current flow also means lower resistance offered by the conductor.

πŸž‡ β€œThin” conductors, on the other hand, have limited space for current to flow through them, making resistance higher.

πŸž‡

Sample problem1:

πŸž‡ Compute the resistance of a conductor given a resistivity of 10.4 Ω-m, length of 4 m, and cross- sectional area of 7.85 Γ— 10-3 m2.

πŸž‡ The resistance of the conductor is approximately 5

299.36 Ω

  1. A conductor has a diameter of 2.59 mm. How many meters of this material are needed to yield a resistance of 1 Ω? The resistivity of the conductor is

1.77 Γ— 10-8 Ω-m.

πŸž‡ To obtain a resistance of 1 Ω, approximately

297.66 m of the conductor is needed.

Sample problem #2.

πŸž‡ Solve for the resistance of a conductor given a resistivity of 15.3 Ω-m, length of 6 m, and cross-sectional area of 2.85 Γ— 10-2 m2.

Sample Problem #3.

πŸž‡ A copper rod is 3 m long and 4 mm in diameter. Compute its resistance if

the resistivity of the material is 1.76 Γ— 10-8 Ω-m.

Electromotive Force

πŸž‡ Electromotive force , it is the potential energy given to a unit charge to make it flow through a conductor or around a complete circuit.

πŸž‡ The EMF acts like a charge pump that causes charges to flow through a circuit.

πŸž‡ As a measurable quantity, EMF is measured using the unit volt (V)

Potential Difference

πŸž‡ Similar to electromotive force is the potential difference (PD) across a circuit.

πŸž‡ Potential difference is an actual consideration of the potentials in the circuit. The existence of PD also identifies the flow of

charges through the circuit. Without this difference, there will be no electric potential, thus making the flow of charges through the conductor impossible.

πŸž‡ Both the EMF and PD are measured in terms of voltage (V).

Ohm’s Law

πŸž‡ In 1827, Georg Simon Ohm discovered the relationship among voltage, current, and resistance.

πŸž‡ He found out that electricity acts similarly to water in

a pipe. Through this observation, he was able to

summarize the relationship among EMF or voltage (V ), electric current (I ), and resistance (R) through the Ohm’s law.

πŸž‡ In equation form, Ohm’s law is stated as follows:

V = IR

Example 3:

πŸž‡ a. Using Ohm’s law, solve for the electric current of a conductor given a voltage of 25 V and a resistance of 10 Ω.

πŸž‡ The current is approximately 2.5 A

πŸž‡ b. An electric water heater uses 15 A of current when plugged to a 220-V outlet.

πŸž‡ What is the resistance provided by the appliance?

πŸž‡ The electric water heater provides a

resistance of approximately 14.67 Ω.

Electric Circuits

Electric Circuit.

πŸž‡ The pathway for the current to move to and from the source and the appliance is called an electric circuit.

πŸž‡ A functional circuit has to be β€œclosed” or

must form a closed loop.

Circuits

πŸ–‰ In order for electricity to flow we need:

πŸ–‰ Power source

πŸ–‰ Closed circuit

πŸ–‰ Two type of circuits:

πŸ–‰ Series circuit

πŸ–‰ Parallel circuit

Closed circuits

πŸž‡ Closed circuits allow the current to flow from the source of the current to the load where the current is needed.

Open circuits

πŸž‡ an β€œopen” circuit does not form a closed loop; the resulting circuit would then be nonfunctional.

πŸž‡ Open circuits have gap(s) where current cannot flow.

πŸž‡ Thus, electric current cannot be delivered

to the load where it is needed

The Series Circuit

Series Circuit

πŸ–‰ In a series circuit there is only one path for the electrons to flow.

πŸ–‰ In other words all the components are in series with each other

πŸ–‰ Because there is only one path each charge will go

through each resistor

The Series Circuit

πŸž‡ In a series circuit, all components are connected using a single pathway.

πŸž‡ The current is the same for all the components along this circuit.

πŸž‡ The total voltage is the sum of the individual voltages across the circuit.

πŸž‡ the total resistance of the circuit is the sum of the individual resistances of each circuit load.

These relationships are summarized by the following formulas:

πŸž‡ Vtotal = V1 + V2 + V3 + . . .+ Vn

πŸž‡ Itotal = I1 = I2 = I3 = . . . = In

πŸž‡ Rtotal = R1 + R2 + R3 + . . .+ R

Calculating Resistance in Series Circuits

πŸ–‰The rule for calculating Series Circuits is to…

πŸ–‰Add up the values of each individual in the series.

πŸ–‰R1 + R2 + R3…

πŸ–‰5 + 5 + 10

πŸ–‰20 Ξ© (ohms)

Calculating Resistance in Series Circuits

1

0

2

0

πŸ–‰Add up the values of each individual in the series.

πŸ–‰R1 + R2 + R3…

πŸ–‰10 + 20 + 10

πŸ–‰40 Ξ© (ohms)

The Parallel Circuit

πŸž‡ Parallel circuits use branches to allow current to pass through more than one path, unlike in the series circuit.

πŸž‡ Thus, the individual voltages in a parallel circuit are the same as the total voltage.

πŸž‡ The current in each load is not the same

as the total current in the circuit.

Parallel Circuit

πŸ–‰ In a Parallel circuit there are multiple pathways for charge to flow.

πŸ–‰ Each device is placed on it’s own separate

branch

πŸ–‰ Current goes through each of the branches at the

same time

The Parallel Circuit

πŸž‡ The total current is the sum of the individual currents across the resistors.

πŸž‡ The reciprocal of the total resistance in this type of circuit is equal to the sum of

the reciprocals of the individual resistances.

πŸž‡ Always remember that the total resistance is always less than the individual resistances

The following formulas for a parallel circuit:

πŸž‡ Vtotal= V1 = V2 = V3 = . . . = Vn

πŸž‡ Itotal = I1 + I2 + I3 + . . .+ In

Calculating Resistance in Parallel Circuits

πŸ–‰ The rule for calculating

Series Circuits is to…

πŸ–‰ Add up the values of each

individual in the circuit.

πŸ–‰ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

πŸ–‰ 1 1 1 1

-- = -- + -- + --

Rt 4 4 2

πŸ–‰ 1

-- = .25 + .25 + .5

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = 1

Rt

πŸ–‰ 1

-- = Rt

1

πŸ–‰ Rt = 1 Ξ© (ohms)

2

0

Calculating Resistance in Parallel Circuit

πŸž‡ The rule for calculating

Series Circuits is to…

πŸž‡ Add up the values of each

individual in the circuit.

πŸž‡ 1 1 1 1

-- = -- + -- + -- Rt R1 R2 R3

10

00

πŸž‡ 1 1 1 1

-- = -- + -- + --

Rt 100 200 1000

πŸž‡ 1

2

0

-- = .01 + .005 + .001

Rt

1

2

πŸž‡

1

0

0

πŸž‡

-- = .016

Rt 1

-- = .016

Rt

0

0

  • 1

-- = Rt

.016

  • Rt = 62.5 Ξ©

(ohms)

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