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SCH3U - Unit 2 - Chemical Reactions

Text pg 462-473, Text pg 476-484, Text 5.1 and 5.2, Text 5.3

Lesson 1 - Organic Compounds and Naming

  • Organic compounds are made of carbon, hydrogen, and other atoms like oxygen, nitrogen, sulfur, and halogens

  • To name an organic compound, use the following steps:

    • Use the prefix that indicates the number of carbons in the main carbon chain

    • Then, use the suffix that indicates the functional groups

      • Functional groups either branch off the main chain, or have multiple bonds

    • A chain may have to be drawn

      • Each carbon present is a point that is connected by a straight line segment

      • Do not include hydrogens

      • Draw extra connecting lines to indicate bonds

      • Include any functional group that may branch off

    • Number the longest carbon chain so that the functional groups have the lowest number

    • Write each group as X-, prefix, suffix, where X is the number of the carbon it is found on

      • If X is 1, do not include it

    • If it is in a ring, include “cyclo-” in front of the prefix

      • Benzene Ring - A ring of 6 carbons, with alternating double bonds

    • The functional group with less carbon goes first, and ends in -yl

Prefix

Number of Carbons

Prefix

Number of Carbons

Meth-

1

Hex-

6

Eth-

2

Hept-

7

Prop-

3

Oct-

8

But-

4

Non-

9

Pent-

5

Dec-

10

Functional Group

Suffix

Addition

Structure

Alkanes

-ane

Only single bonds

R - C - C - R

Alkenes

-ene

At least one double bond

C = C

Alkynes

-yne

At least one triple bond

R - C ≡ C - R

Alcohols

-ol

Has OH

R - C - OH

Carboxylic Acid

-oic acid

Has COOH

R - C - OH | O

Lesson 2 - Chemical Reactions

  • Synthesis - 2 or more reactants combine to form a single product

    • A + B → C

  • Decomposition - A single reactant breaks down into 2 or more compounds

    • C → A + B

  • Combustion reactions produce heat, and require fuel, oxygen gas, and a spark

    • Complete Combustion - A hydrocarbon burns in the presence of oxygen to produce carbon dioxide and water vapour

      • CxHy + O2 → CO2 + H2O

    • Incomplete Combustion - A hydrocarbon burns in the presence of insufficient oxygen to produce carbon dioxide, and/or carbon monoxide, and/or soot, and/or water vapour

      • CxHy + O2 → CO2 + H2O + C + CO

  • Single Displacement - A single element displaces its counterpart in a compound when it is more reactive

    • A + BC → B + AC

    • The compounds are usually aqueous, and the individual element is its natural state

  • Double Displacement - Two counterpart elements in a compound replace one another

    • AB + CD → AD + CB

    • The starting products are both aqueous, and the products are dictated by the solubility table

    • If two products are aqueous, no reaction has occurred

  • Predicting states

    • Aqueous - When something is soluble in water

      • Ions are soluble, and will be dispersed in water

      • Ions can only conduct electricity when able to move in an aqueous state

  • To balance a reaction, consider the total number of unique atoms on each side, and add coefficients when necessary to balance the equation

Lesson 3 - Net Ionic Equations and Particulate Diagrams

  • Law of Conservation of Mass - The total mass of substances does not change during a chemical reaction

  • Law of Definite Composition - No matter what its source, a particular compound is composed of the same elements in the same parts by mass

  • Particulate diagrams:

    • Particles can be atoms, molecules, or ions

    • Use shapes or patterns to denote what each present particle represents

    • Draw the reaction happening, with the balanced amount of particles on each side

  • Some combinations of ions are insoluble, so they can be written in a net ionic equation

    • Write out the entire balanced equation

    • Separate every aqueous compound into ions, but leave the insoluble product as is, to form the total ionic equation

    • Cross out the “spectator” ions that are not included in the insoluble product

    • Rewrite the equation as the two ions forming the insoluble product to form the net ionic equation

Lesson 4 - Redox Reactions

  • Oxidation - The loss of electrons

    • Reducing Agent - The particle that causes another particle to be reduced

  • Reduction - The gain of electrons

    • Oxidizing Agent - The particle that causes another particle to be oxidized

  • Oxidation Number - The charge the atom would have if electrons were not shared but transferred completely

    • Written with the sign before the number

    • An atom in its elemental form has an ON = 0

    • A monoatomic ion has an ON = ionic charge

    • The sum of ON values for atoms in a molecule = 0

    • The sum of ON values in a polyatomic ion = ionic charge

    • Follow the group-specific rules in this order, as applicable

      • Oxygen: -2 (except for -1 in peroxides)

      • Hydrogen: -1 with metals, +1 with nonmetals

      • Halogens: -1 with metals and nonmetals, but will be positive when with oxygen

      • Alkaline Earth Metals: +2 in all compounds

      • Alkali Metals: +1 in all compounds

    • Use the group-specific rules first, then apply all remaining oxidation numbers so as to balance the oxidation numbers in a given atom or molecule

      • Assign oxidation numbers as if it were for only one of that atom, not the total number of that atom

        • Ex. For 2Na, the oxidation number is +1, not +2

      • Only consider subscripts and coefficients when considering oxidation number balancing

        • Ex. For SO3, oxygen has an oxidation number of -2. Because there is no charge on the molecule, sulfur must have an oxidation number equal to -2×3

  • To determine if it is a redox reaction:

    • Assign oxidation numbers to all elements

    • Determine if any changes in oxidation number has occurred

    • Redox Reaction - The simultaneous increase and decrease of electrons in a reaction

  • To write a half reaction, write the reaction as either:

    • An element, which decomposes into an ion and electrons

    • An ion and electrons, which produce an element

  • To find the transfer of electrons:

    • Multiply the oxidation number on both sides by any applicable coefficients and subscripts

    • Compare the total amount of electrons on the reactant and product side

    • The total amount of electrons gained by the reduced products should equal the total amount lost by the oxidized product

Lesson 5 - Nuclear Reactions

  • Larger atoms tend to be more unstable

    • The more unstable the element, the less time it can remain present for

  • Radioisotope - Isotopes of an element that are radioactive

  • Radioactive - When an element gives off high energy particles and rays, such as alpha, beta, and gamma

Symbol

Meaning/Use

Symbol

Meaning/Use

10n

Neutron; fission

0+1β

Positron; fusion

11P

Proton; fusion

0-1β

Electron; negative beta decay

42He

Helium-4; alpha decay

00γ

Photon; gamma decay

  • Alpha Decay - The least damaging form of radioactive decay, in which helium-4 particles are emitted, and the atomic number and mass are changed

    • mpX → 42He + m-4p-2Y

  • Beta Decay - The form of radioactive decay in which high speed electrons are released from the nucleus, which converts neutrons into a proton, and where only the atomic number changes

    • mpX → 0-1β + mp+1Y

  • Gamma Decay - The most damaging form of radioactive decay, in which high energy photons are emitted, but the atomic number or mass is unchanged

    • mpX → 00γ + mpY

  • For decay, the total mass and atomic number on both sides should be equal

  • There are two types of nuclear reaction

    • Fusion - The nuclear reaction where two lighter, unstable nuclei combine to form a heavier, more stable one, and energy is released

      • element + element → element with greater mass + positrons

      • element + element → element with greater mass and atomic number

      • element + element → element with greater mass + proton

    • Fission - An unstable, heavier nucleus is split into lighter, more stable ones, and energy is released

      • element + neutron → smaller element + smaller element + neutrons

  • Half Life - The time it takes for half of any given quantity of a substance to react

    • The shorter the half life, the faster the decay

    • To find the linear curve of half life, use:

      • ln(Nt/N0) = -kt, where:

        • Nt = number remaining

        • N0 = initial number

        • k = decay constant

        • t = time interval

    • To find the half life, use:

      • At = Ao(1/2)t/t1/2, where:

        • At = mass at given time “t”

        • Ao = original mass

        • t = given time

        • t1/2 = the half life, in the same units as t

      • Use logarithms to solve for any of the exponents

        • by=x, and logbx = y

        • logbx = (log x)/(log b)

      • If the mass at the given time is a percent, multiply the original mass (possibly as a variable) by the remaining percent

        • Ex. If Ao is 40% decayed, then At = Ao(0.60)

        • Ex. If 40% of Ao remains, then At = Ao(0.40)

LC

SCH3U - Unit 2 - Chemical Reactions

Text pg 462-473, Text pg 476-484, Text 5.1 and 5.2, Text 5.3

Lesson 1 - Organic Compounds and Naming

  • Organic compounds are made of carbon, hydrogen, and other atoms like oxygen, nitrogen, sulfur, and halogens

  • To name an organic compound, use the following steps:

    • Use the prefix that indicates the number of carbons in the main carbon chain

    • Then, use the suffix that indicates the functional groups

      • Functional groups either branch off the main chain, or have multiple bonds

    • A chain may have to be drawn

      • Each carbon present is a point that is connected by a straight line segment

      • Do not include hydrogens

      • Draw extra connecting lines to indicate bonds

      • Include any functional group that may branch off

    • Number the longest carbon chain so that the functional groups have the lowest number

    • Write each group as X-, prefix, suffix, where X is the number of the carbon it is found on

      • If X is 1, do not include it

    • If it is in a ring, include “cyclo-” in front of the prefix

      • Benzene Ring - A ring of 6 carbons, with alternating double bonds

    • The functional group with less carbon goes first, and ends in -yl

Prefix

Number of Carbons

Prefix

Number of Carbons

Meth-

1

Hex-

6

Eth-

2

Hept-

7

Prop-

3

Oct-

8

But-

4

Non-

9

Pent-

5

Dec-

10

Functional Group

Suffix

Addition

Structure

Alkanes

-ane

Only single bonds

R - C - C - R

Alkenes

-ene

At least one double bond

C = C

Alkynes

-yne

At least one triple bond

R - C ≡ C - R

Alcohols

-ol

Has OH

R - C - OH

Carboxylic Acid

-oic acid

Has COOH

R - C - OH | O

Lesson 2 - Chemical Reactions

  • Synthesis - 2 or more reactants combine to form a single product

    • A + B → C

  • Decomposition - A single reactant breaks down into 2 or more compounds

    • C → A + B

  • Combustion reactions produce heat, and require fuel, oxygen gas, and a spark

    • Complete Combustion - A hydrocarbon burns in the presence of oxygen to produce carbon dioxide and water vapour

      • CxHy + O2 → CO2 + H2O

    • Incomplete Combustion - A hydrocarbon burns in the presence of insufficient oxygen to produce carbon dioxide, and/or carbon monoxide, and/or soot, and/or water vapour

      • CxHy + O2 → CO2 + H2O + C + CO

  • Single Displacement - A single element displaces its counterpart in a compound when it is more reactive

    • A + BC → B + AC

    • The compounds are usually aqueous, and the individual element is its natural state

  • Double Displacement - Two counterpart elements in a compound replace one another

    • AB + CD → AD + CB

    • The starting products are both aqueous, and the products are dictated by the solubility table

    • If two products are aqueous, no reaction has occurred

  • Predicting states

    • Aqueous - When something is soluble in water

      • Ions are soluble, and will be dispersed in water

      • Ions can only conduct electricity when able to move in an aqueous state

  • To balance a reaction, consider the total number of unique atoms on each side, and add coefficients when necessary to balance the equation

Lesson 3 - Net Ionic Equations and Particulate Diagrams

  • Law of Conservation of Mass - The total mass of substances does not change during a chemical reaction

  • Law of Definite Composition - No matter what its source, a particular compound is composed of the same elements in the same parts by mass

  • Particulate diagrams:

    • Particles can be atoms, molecules, or ions

    • Use shapes or patterns to denote what each present particle represents

    • Draw the reaction happening, with the balanced amount of particles on each side

  • Some combinations of ions are insoluble, so they can be written in a net ionic equation

    • Write out the entire balanced equation

    • Separate every aqueous compound into ions, but leave the insoluble product as is, to form the total ionic equation

    • Cross out the “spectator” ions that are not included in the insoluble product

    • Rewrite the equation as the two ions forming the insoluble product to form the net ionic equation

Lesson 4 - Redox Reactions

  • Oxidation - The loss of electrons

    • Reducing Agent - The particle that causes another particle to be reduced

  • Reduction - The gain of electrons

    • Oxidizing Agent - The particle that causes another particle to be oxidized

  • Oxidation Number - The charge the atom would have if electrons were not shared but transferred completely

    • Written with the sign before the number

    • An atom in its elemental form has an ON = 0

    • A monoatomic ion has an ON = ionic charge

    • The sum of ON values for atoms in a molecule = 0

    • The sum of ON values in a polyatomic ion = ionic charge

    • Follow the group-specific rules in this order, as applicable

      • Oxygen: -2 (except for -1 in peroxides)

      • Hydrogen: -1 with metals, +1 with nonmetals

      • Halogens: -1 with metals and nonmetals, but will be positive when with oxygen

      • Alkaline Earth Metals: +2 in all compounds

      • Alkali Metals: +1 in all compounds

    • Use the group-specific rules first, then apply all remaining oxidation numbers so as to balance the oxidation numbers in a given atom or molecule

      • Assign oxidation numbers as if it were for only one of that atom, not the total number of that atom

        • Ex. For 2Na, the oxidation number is +1, not +2

      • Only consider subscripts and coefficients when considering oxidation number balancing

        • Ex. For SO3, oxygen has an oxidation number of -2. Because there is no charge on the molecule, sulfur must have an oxidation number equal to -2×3

  • To determine if it is a redox reaction:

    • Assign oxidation numbers to all elements

    • Determine if any changes in oxidation number has occurred

    • Redox Reaction - The simultaneous increase and decrease of electrons in a reaction

  • To write a half reaction, write the reaction as either:

    • An element, which decomposes into an ion and electrons

    • An ion and electrons, which produce an element

  • To find the transfer of electrons:

    • Multiply the oxidation number on both sides by any applicable coefficients and subscripts

    • Compare the total amount of electrons on the reactant and product side

    • The total amount of electrons gained by the reduced products should equal the total amount lost by the oxidized product

Lesson 5 - Nuclear Reactions

  • Larger atoms tend to be more unstable

    • The more unstable the element, the less time it can remain present for

  • Radioisotope - Isotopes of an element that are radioactive

  • Radioactive - When an element gives off high energy particles and rays, such as alpha, beta, and gamma

Symbol

Meaning/Use

Symbol

Meaning/Use

10n

Neutron; fission

0+1β

Positron; fusion

11P

Proton; fusion

0-1β

Electron; negative beta decay

42He

Helium-4; alpha decay

00γ

Photon; gamma decay

  • Alpha Decay - The least damaging form of radioactive decay, in which helium-4 particles are emitted, and the atomic number and mass are changed

    • mpX → 42He + m-4p-2Y

  • Beta Decay - The form of radioactive decay in which high speed electrons are released from the nucleus, which converts neutrons into a proton, and where only the atomic number changes

    • mpX → 0-1β + mp+1Y

  • Gamma Decay - The most damaging form of radioactive decay, in which high energy photons are emitted, but the atomic number or mass is unchanged

    • mpX → 00γ + mpY

  • For decay, the total mass and atomic number on both sides should be equal

  • There are two types of nuclear reaction

    • Fusion - The nuclear reaction where two lighter, unstable nuclei combine to form a heavier, more stable one, and energy is released

      • element + element → element with greater mass + positrons

      • element + element → element with greater mass and atomic number

      • element + element → element with greater mass + proton

    • Fission - An unstable, heavier nucleus is split into lighter, more stable ones, and energy is released

      • element + neutron → smaller element + smaller element + neutrons

  • Half Life - The time it takes for half of any given quantity of a substance to react

    • The shorter the half life, the faster the decay

    • To find the linear curve of half life, use:

      • ln(Nt/N0) = -kt, where:

        • Nt = number remaining

        • N0 = initial number

        • k = decay constant

        • t = time interval

    • To find the half life, use:

      • At = Ao(1/2)t/t1/2, where:

        • At = mass at given time “t”

        • Ao = original mass

        • t = given time

        • t1/2 = the half life, in the same units as t

      • Use logarithms to solve for any of the exponents

        • by=x, and logbx = y

        • logbx = (log x)/(log b)

      • If the mass at the given time is a percent, multiply the original mass (possibly as a variable) by the remaining percent

        • Ex. If Ao is 40% decayed, then At = Ao(0.60)

        • Ex. If 40% of Ao remains, then At = Ao(0.40)

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