SCH3U - Unit 2 - Chemical Reactions
Text pg 462-473, Text pg 476-484, Text 5.1 and 5.2, Text 5.3
Organic compounds are made of carbon, hydrogen, and other atoms like oxygen, nitrogen, sulfur, and halogens
To name an organic compound, use the following steps:
Use the prefix that indicates the number of carbons in the main carbon chain
Then, use the suffix that indicates the functional groups
Functional groups either branch off the main chain, or have multiple bonds
A chain may have to be drawn
Each carbon present is a point that is connected by a straight line segment
Do not include hydrogens
Draw extra connecting lines to indicate bonds
Include any functional group that may branch off
Number the longest carbon chain so that the functional groups have the lowest number
Write each group as X-, prefix, suffix, where X is the number of the carbon it is found on
If X is 1, do not include it
If it is in a ring, include “cyclo-” in front of the prefix
Benzene Ring - A ring of 6 carbons, with alternating double bonds
The functional group with less carbon goes first, and ends in -yl
Prefix | Number of Carbons | Prefix | Number of Carbons |
Meth- | 1 | Hex- | 6 |
Eth- | 2 | Hept- | 7 |
Prop- | 3 | Oct- | 8 |
But- | 4 | Non- | 9 |
Pent- | 5 | Dec- | 10 |
Functional Group | Suffix | Addition | Structure |
Alkanes | -ane | Only single bonds | R - C - C - R |
Alkenes | -ene | At least one double bond | C = C |
Alkynes | -yne | At least one triple bond | R - C ≡ C - R |
Alcohols | -ol | Has OH | R - C - OH |
Carboxylic Acid | -oic acid | Has COOH | R - C - OH | O |
Synthesis - 2 or more reactants combine to form a single product
A + B → C
Decomposition - A single reactant breaks down into 2 or more compounds
C → A + B
Combustion reactions produce heat, and require fuel, oxygen gas, and a spark
Complete Combustion - A hydrocarbon burns in the presence of oxygen to produce carbon dioxide and water vapour
CxHy + O2 → CO2 + H2O
Incomplete Combustion - A hydrocarbon burns in the presence of insufficient oxygen to produce carbon dioxide, and/or carbon monoxide, and/or soot, and/or water vapour
CxHy + O2 → CO2 + H2O + C + CO
Single Displacement - A single element displaces its counterpart in a compound when it is more reactive
A + BC → B + AC
The compounds are usually aqueous, and the individual element is its natural state
Double Displacement - Two counterpart elements in a compound replace one another
AB + CD → AD + CB
The starting products are both aqueous, and the products are dictated by the solubility table
If two products are aqueous, no reaction has occurred
Predicting states
Aqueous - When something is soluble in water
Ions are soluble, and will be dispersed in water
Ions can only conduct electricity when able to move in an aqueous state
To balance a reaction, consider the total number of unique atoms on each side, and add coefficients when necessary to balance the equation
Law of Conservation of Mass - The total mass of substances does not change during a chemical reaction
Law of Definite Composition - No matter what its source, a particular compound is composed of the same elements in the same parts by mass
Particulate diagrams:
Particles can be atoms, molecules, or ions
Use shapes or patterns to denote what each present particle represents
Draw the reaction happening, with the balanced amount of particles on each side
Some combinations of ions are insoluble, so they can be written in a net ionic equation
Write out the entire balanced equation
Separate every aqueous compound into ions, but leave the insoluble product as is, to form the total ionic equation
Cross out the “spectator” ions that are not included in the insoluble product
Rewrite the equation as the two ions forming the insoluble product to form the net ionic equation
Oxidation - The loss of electrons
Reducing Agent - The particle that causes another particle to be reduced
Reduction - The gain of electrons
Oxidizing Agent - The particle that causes another particle to be oxidized
Oxidation Number - The charge the atom would have if electrons were not shared but transferred completely
Written with the sign before the number
An atom in its elemental form has an ON = 0
A monoatomic ion has an ON = ionic charge
The sum of ON values for atoms in a molecule = 0
The sum of ON values in a polyatomic ion = ionic charge
Follow the group-specific rules in this order, as applicable
Oxygen: -2 (except for -1 in peroxides)
Hydrogen: -1 with metals, +1 with nonmetals
Halogens: -1 with metals and nonmetals, but will be positive when with oxygen
Alkaline Earth Metals: +2 in all compounds
Alkali Metals: +1 in all compounds
Use the group-specific rules first, then apply all remaining oxidation numbers so as to balance the oxidation numbers in a given atom or molecule
Assign oxidation numbers as if it were for only one of that atom, not the total number of that atom
Ex. For 2Na, the oxidation number is +1, not +2
Only consider subscripts and coefficients when considering oxidation number balancing
Ex. For SO3, oxygen has an oxidation number of -2. Because there is no charge on the molecule, sulfur must have an oxidation number equal to -2×3
To determine if it is a redox reaction:
Assign oxidation numbers to all elements
Determine if any changes in oxidation number has occurred
Redox Reaction - The simultaneous increase and decrease of electrons in a reaction
To write a half reaction, write the reaction as either:
An element, which decomposes into an ion and electrons
An ion and electrons, which produce an element
To find the transfer of electrons:
Multiply the oxidation number on both sides by any applicable coefficients and subscripts
Compare the total amount of electrons on the reactant and product side
The total amount of electrons gained by the reduced products should equal the total amount lost by the oxidized product
Larger atoms tend to be more unstable
The more unstable the element, the less time it can remain present for
Radioisotope - Isotopes of an element that are radioactive
Radioactive - When an element gives off high energy particles and rays, such as alpha, beta, and gamma
Symbol | Meaning/Use | Symbol | Meaning/Use |
10n | Neutron; fission | 0+1β | Positron; fusion |
11P | Proton; fusion | 0-1β | Electron; negative beta decay |
42He | Helium-4; alpha decay | 00γ | Photon; gamma decay |
Alpha Decay - The least damaging form of radioactive decay, in which helium-4 particles are emitted, and the atomic number and mass are changed
mpX → 42He + m-4p-2Y
Beta Decay - The form of radioactive decay in which high speed electrons are released from the nucleus, which converts neutrons into a proton, and where only the atomic number changes
mpX → 0-1β + mp+1Y
Gamma Decay - The most damaging form of radioactive decay, in which high energy photons are emitted, but the atomic number or mass is unchanged
mpX → 00γ + mpY
For decay, the total mass and atomic number on both sides should be equal
There are two types of nuclear reaction
Fusion - The nuclear reaction where two lighter, unstable nuclei combine to form a heavier, more stable one, and energy is released
element + element → element with greater mass + positrons
element + element → element with greater mass and atomic number
element + element → element with greater mass + proton
Fission - An unstable, heavier nucleus is split into lighter, more stable ones, and energy is released
element + neutron → smaller element + smaller element + neutrons
Half Life - The time it takes for half of any given quantity of a substance to react
The shorter the half life, the faster the decay
To find the linear curve of half life, use:
ln(Nt/N0) = -kt, where:
Nt = number remaining
N0 = initial number
k = decay constant
t = time interval
To find the half life, use:
At = Ao(1/2)t/t1/2, where:
At = mass at given time “t”
Ao = original mass
t = given time
t1/2 = the half life, in the same units as t
Use logarithms to solve for any of the exponents
by=x, and logbx = y
logbx = (log x)/(log b)
If the mass at the given time is a percent, multiply the original mass (possibly as a variable) by the remaining percent
Ex. If Ao is 40% decayed, then At = Ao(0.60)
Ex. If 40% of Ao remains, then At = Ao(0.40)
Text pg 462-473, Text pg 476-484, Text 5.1 and 5.2, Text 5.3
Organic compounds are made of carbon, hydrogen, and other atoms like oxygen, nitrogen, sulfur, and halogens
To name an organic compound, use the following steps:
Use the prefix that indicates the number of carbons in the main carbon chain
Then, use the suffix that indicates the functional groups
Functional groups either branch off the main chain, or have multiple bonds
A chain may have to be drawn
Each carbon present is a point that is connected by a straight line segment
Do not include hydrogens
Draw extra connecting lines to indicate bonds
Include any functional group that may branch off
Number the longest carbon chain so that the functional groups have the lowest number
Write each group as X-, prefix, suffix, where X is the number of the carbon it is found on
If X is 1, do not include it
If it is in a ring, include “cyclo-” in front of the prefix
Benzene Ring - A ring of 6 carbons, with alternating double bonds
The functional group with less carbon goes first, and ends in -yl
Prefix | Number of Carbons | Prefix | Number of Carbons |
Meth- | 1 | Hex- | 6 |
Eth- | 2 | Hept- | 7 |
Prop- | 3 | Oct- | 8 |
But- | 4 | Non- | 9 |
Pent- | 5 | Dec- | 10 |
Functional Group | Suffix | Addition | Structure |
Alkanes | -ane | Only single bonds | R - C - C - R |
Alkenes | -ene | At least one double bond | C = C |
Alkynes | -yne | At least one triple bond | R - C ≡ C - R |
Alcohols | -ol | Has OH | R - C - OH |
Carboxylic Acid | -oic acid | Has COOH | R - C - OH | O |
Synthesis - 2 or more reactants combine to form a single product
A + B → C
Decomposition - A single reactant breaks down into 2 or more compounds
C → A + B
Combustion reactions produce heat, and require fuel, oxygen gas, and a spark
Complete Combustion - A hydrocarbon burns in the presence of oxygen to produce carbon dioxide and water vapour
CxHy + O2 → CO2 + H2O
Incomplete Combustion - A hydrocarbon burns in the presence of insufficient oxygen to produce carbon dioxide, and/or carbon monoxide, and/or soot, and/or water vapour
CxHy + O2 → CO2 + H2O + C + CO
Single Displacement - A single element displaces its counterpart in a compound when it is more reactive
A + BC → B + AC
The compounds are usually aqueous, and the individual element is its natural state
Double Displacement - Two counterpart elements in a compound replace one another
AB + CD → AD + CB
The starting products are both aqueous, and the products are dictated by the solubility table
If two products are aqueous, no reaction has occurred
Predicting states
Aqueous - When something is soluble in water
Ions are soluble, and will be dispersed in water
Ions can only conduct electricity when able to move in an aqueous state
To balance a reaction, consider the total number of unique atoms on each side, and add coefficients when necessary to balance the equation
Law of Conservation of Mass - The total mass of substances does not change during a chemical reaction
Law of Definite Composition - No matter what its source, a particular compound is composed of the same elements in the same parts by mass
Particulate diagrams:
Particles can be atoms, molecules, or ions
Use shapes or patterns to denote what each present particle represents
Draw the reaction happening, with the balanced amount of particles on each side
Some combinations of ions are insoluble, so they can be written in a net ionic equation
Write out the entire balanced equation
Separate every aqueous compound into ions, but leave the insoluble product as is, to form the total ionic equation
Cross out the “spectator” ions that are not included in the insoluble product
Rewrite the equation as the two ions forming the insoluble product to form the net ionic equation
Oxidation - The loss of electrons
Reducing Agent - The particle that causes another particle to be reduced
Reduction - The gain of electrons
Oxidizing Agent - The particle that causes another particle to be oxidized
Oxidation Number - The charge the atom would have if electrons were not shared but transferred completely
Written with the sign before the number
An atom in its elemental form has an ON = 0
A monoatomic ion has an ON = ionic charge
The sum of ON values for atoms in a molecule = 0
The sum of ON values in a polyatomic ion = ionic charge
Follow the group-specific rules in this order, as applicable
Oxygen: -2 (except for -1 in peroxides)
Hydrogen: -1 with metals, +1 with nonmetals
Halogens: -1 with metals and nonmetals, but will be positive when with oxygen
Alkaline Earth Metals: +2 in all compounds
Alkali Metals: +1 in all compounds
Use the group-specific rules first, then apply all remaining oxidation numbers so as to balance the oxidation numbers in a given atom or molecule
Assign oxidation numbers as if it were for only one of that atom, not the total number of that atom
Ex. For 2Na, the oxidation number is +1, not +2
Only consider subscripts and coefficients when considering oxidation number balancing
Ex. For SO3, oxygen has an oxidation number of -2. Because there is no charge on the molecule, sulfur must have an oxidation number equal to -2×3
To determine if it is a redox reaction:
Assign oxidation numbers to all elements
Determine if any changes in oxidation number has occurred
Redox Reaction - The simultaneous increase and decrease of electrons in a reaction
To write a half reaction, write the reaction as either:
An element, which decomposes into an ion and electrons
An ion and electrons, which produce an element
To find the transfer of electrons:
Multiply the oxidation number on both sides by any applicable coefficients and subscripts
Compare the total amount of electrons on the reactant and product side
The total amount of electrons gained by the reduced products should equal the total amount lost by the oxidized product
Larger atoms tend to be more unstable
The more unstable the element, the less time it can remain present for
Radioisotope - Isotopes of an element that are radioactive
Radioactive - When an element gives off high energy particles and rays, such as alpha, beta, and gamma
Symbol | Meaning/Use | Symbol | Meaning/Use |
10n | Neutron; fission | 0+1β | Positron; fusion |
11P | Proton; fusion | 0-1β | Electron; negative beta decay |
42He | Helium-4; alpha decay | 00γ | Photon; gamma decay |
Alpha Decay - The least damaging form of radioactive decay, in which helium-4 particles are emitted, and the atomic number and mass are changed
mpX → 42He + m-4p-2Y
Beta Decay - The form of radioactive decay in which high speed electrons are released from the nucleus, which converts neutrons into a proton, and where only the atomic number changes
mpX → 0-1β + mp+1Y
Gamma Decay - The most damaging form of radioactive decay, in which high energy photons are emitted, but the atomic number or mass is unchanged
mpX → 00γ + mpY
For decay, the total mass and atomic number on both sides should be equal
There are two types of nuclear reaction
Fusion - The nuclear reaction where two lighter, unstable nuclei combine to form a heavier, more stable one, and energy is released
element + element → element with greater mass + positrons
element + element → element with greater mass and atomic number
element + element → element with greater mass + proton
Fission - An unstable, heavier nucleus is split into lighter, more stable ones, and energy is released
element + neutron → smaller element + smaller element + neutrons
Half Life - The time it takes for half of any given quantity of a substance to react
The shorter the half life, the faster the decay
To find the linear curve of half life, use:
ln(Nt/N0) = -kt, where:
Nt = number remaining
N0 = initial number
k = decay constant
t = time interval
To find the half life, use:
At = Ao(1/2)t/t1/2, where:
At = mass at given time “t”
Ao = original mass
t = given time
t1/2 = the half life, in the same units as t
Use logarithms to solve for any of the exponents
by=x, and logbx = y
logbx = (log x)/(log b)
If the mass at the given time is a percent, multiply the original mass (possibly as a variable) by the remaining percent
Ex. If Ao is 40% decayed, then At = Ao(0.60)
Ex. If 40% of Ao remains, then At = Ao(0.40)