Lecturer: Do Duc Tan
Email: tan.dd@vgu.edu.vn
Office: Academic Cluster 1, Room 211
Office Hours: By appointments
Introduction to Probability Theory and Statistics
Explores concepts of chance and uncertainty
Provides foundation for statistical inference through experimentation and data analysis
Relevant in a quantitative world
Attendance: 10%
Tutorials: 30%, includes 15 tutorials
Exam: 60%, date will be announced
Retake Policy: Available for students receiving either a Fail or Pass grade
Cheating and plagiarism considered serious offenses
Consequences include failing the course
Refer to Syllabus for more details
Probability: experiments, outcomes, sample spaces, Venn diagrams, probability values
Probability as a mathematical branch handling chance and uncertainty
Basis for statistical inference via experiments and data analysis
Experiment: A process producing outcomes
Sample Space (S): All possible outcomes of an experiment
Sample space S = {electrical, mechanical, misuse}
Uncertainty in breakdown causes
Sample space S = {0 defectives, 1 defective, ..., 500 defectives}
Supervised by a manager; each can be generating (1) or idle (0)
Sample space: S = {(0,0,0),(1,0,0),(0,1,0),(0,0,1),(1,1,0),(1,0,1),(0,1,1),(1,1,1)}
Sample space for single toss: S = {head, tail}
Sample space for two tosses: S = {(head, head), (head, tail), (tail, head), (tail, tail)}
Sample space for a single die: S = {1, 2, 3, 4, 5, 6}
When two dice are rolled, consider all combinations for outcomes
Sample space from a standard deck of 52 cards
Sample space comprises 2704 combinations
Specific outcome like (A♡, A♡) is possible
Total outcomes reduce to 2652; outcomes like (A♡, A♡) are not possible
Probability values assigned to elements of sample space
Conditions: 0 ≤ p1, p2, ..., pn ≤ 1 and p1 + p2 + ... + pn = 1
P(electrical) = 0.2, P(mechanical) = 0.5, P(misuse) = 0.3
Interpretation of probabilities indicates likelihood of breakdown reasons
Derived from collection of data and prior experiences
Fair coin: P(head) = P(tail) = 0.5
Biased coin example with p = 0.4
Fair die, all outcomes equally likely: P(1) = P(2) = ... = P(6) = 1/6
Initial card drawn has 52 outcomes, P = 1/52
If drawn with replacement, each outcome still equally likely
Without replacement alters total outcomes affecting probability distribution